A busy candy store is going to replace their current gumball machine
with a giant gumball machine. The globe on their current gumball
machine is 22" in diameter and its volume is 5,575 cubic inches.
Compared to what has been ordered, the current gumball machine's
volume is 532 cubic inches less than one-fourth the volume of the
globe of the giant gumball machine.
Use the information given to explore some of the mathematical concepts you have practiced so
far by answering the questions below. The formula for the volume of a sphere is .
1. Rewrite the formula for the volume of a sphere so that it is solved for r. Show all your work.
2. Use your answer to question 1 and the information given in the scenario to develop a plan
that you can use to solve for the volume of the globe on the new, giant gumball machine.
I’m

Answers

Answer 1

don't know if this is actually the answers but:

1.) V=4/3pi r^3

3V= 4pi r^3

3V/4pi = r^3

3√3V/4 pi = 3√r^3

Answer: r = 3√3V/4pi

2.) Answer: 1/4V - 532 = 4/3pi 22^3

Answer 2

The sphere is a three-dimensional figure where the volume is given as

= 4/3 x πr³

4/3 x πr³ = 5575

The radius of the current gumball is ∛(117075/88) inches

5575 = (1/4)V - 532

The volume of the giant gumball is 24428 cubic inches.

What is a sphere?

It is a three-dimensional figure where the volume is given as

= 4/3 x πr³

We have,

Current gumball machine.

Diameter = 22 inches

Radius = 22/2 = 11 inches

Volume = 5,575 cubic inches

The volume can be written as,

4/3 x πr³ = 5575

4/3 x 22/7 x r³ = 5575

r³ = (5575 x 3 x 7) / (4 x 22)

r = ∛(117075/88) inches

Giant gumball machine.

Volume = V

5575 = (1/4)V - 532

(5575 + 532) x 4 = V

V = 24428 cubic inches.

Thus,

The radius of the current gumball is ∛(117075/88) inches

The volume of the giant gumball is 24428 cubic inches.

Learn more about sphere here:

https://brainly.com/question/12390313

#SPJ2


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