The estimated unstretched length of the bungee cord assuming simple harmonic motion (SHM) is zero.
To estimate the spring stiffness constant (k) of the bungee cord, we can use the formula for the period of a simple harmonic oscillator:
T = 2π√(m/k),
where T is the period, m is the mass of the jumper, and k is the spring stiffness constant.
Given that the jumper reaches the low point seven more times in 43.0 seconds, we can calculate the period as follows:
T = 43.0 s / 8 = 5.375 s.
Now, rearranging the equation for the period, we have:
k = (4π²m) / T².
Substituting the known values:
k = (4π² * 52.5 kg) / (5.375 s)²,
k ≈ 989.67 N/m (rounded to two decimal places).
Therefore, the estimated spring stiffness constant (k) of the bungee cord is approximately 989.67 N/m.
To estimate the unstretched length of the bungee cord, we need to determine the equilibrium position when the jumper comes to rest 20.5 m below the level of the bridge.
In simple harmonic motion (SHM), the equilibrium position corresponds to the unstretched length of the spring. At this point, the net force acting on the system is zero.
Using Hooke's Law, the force exerted by the spring is given by:
F = kx,
where F is the force, k is the spring stiffness constant, and x is the displacement from the equilibrium position.
Since the jumper comes to rest 20.5 m below the bridge, the displacement (x) is 20.5 m.
Setting F = 0 and solving for x, we have:
kx = 0,
x = 0.
This implies that the equilibrium position (unstretched length) of the bungee cord is zero, meaning that the bungee cord has no additional length when it is unstretched.
Therefore, the estimated unstretched length of the bungee cord assuming simple harmonic motion (SHM) is zero.
To learn more about simple harmonic oscillator visit:
brainly.com/question/29471489
#SPJ11
The spring stiffness constant of the bungee cord is found by equating the force exerted by the spring when the bungee jumper is at his lowest point to his weight and solving for k. The unstretched length of the bungee cord can be deduced from the final resting position of the bungee jumper.
Explanation:To determine the spring stiffness constant k of the bungee cord, we need to use Hooke's Law which defines the force exerted by a spring as F = -kx, where x is the displacement of the spring from its equilibrium position.
In the case of the bungee jumper, when he is at his lowest point, the force exerted by the spring is equal to his weight, F = mg, where m is the mass of the jumper and g is the acceleration due to gravity. By equating these two forces, we get: -kx = mg. Solving for k gives k = -mg/x.
With the mass m = 52.5 kg, gravity g=9.81 m/s², and displacement (lowest point height difference) x = 20.5 m, we can calculate k to estimate the spring stiffness.
The unstretched length of the bungee cord can be estimated by observing the final resting position of the bungee jumper. If the final resting position is taken as the equilibrium position (x=0), then the length of the cord in this position would be the unstretched length.
Learn more about Spring Stiffness here:https://brainly.com/question/37684696
#SPJ12
Why are thire only large impact craters on Venus?
A. There are only large impact craters on Venus because only large meteors and asteroids survive their fall through the planet's thick and corrosive atmosphere.
B. There are only large impact craters on Venus because geological activity erodes impact craters over time.
C. There are only large impact craters on Venus because most smaller asteroids and meteors have been cleared out of the inner solar system over the last few billion years.
D. There are only large impact craters on Venus because the weather on the planet erodes impact craters over time.
E. There are actually impact craters of all sizes on the surface of Venus.
Venus has large impact craters due to the absence of erosive forces and the survival of only the largest meteors and asteroids through its thick atmosphere.
Option (A) is correct.
Venus, known as the sister planet of Earth, is characterized by its thick, corrosive atmosphere and extreme temperatures. Its surface lacks water and volcanic activity, and is instead marked by numerous large impact craters. This is due to the absence of erosive forces, like water, which would have gradually eroded the craters over billions of years. The craters formed on Venus as a result of asteroid and comet impacts over the past 4.6 billion years. However, the impact process on Venus differs from that on Earth. Venus' thick atmosphere burns up most smaller meteorites and asteroids upon entry, allowing only the largest ones to survive their descent. Consequently, only the large impact craters remain visible on the planet's surface today. Therefore, option (A) is correct. In summary, Venus bears only large impact craters as a consequence of the survival of substantial meteors and asteroids through its thick and corrosive atmosphere.
Learn more about erosive forces
https://brainly.com/question/12976130
#SPJ11
A solenoid is producing a magnetic field of B = 2.5 x 10-³ T. It has N = 1100 turns uniformly over a length of d = 0.65 m. Express the current I in terms of B, N and d. Calculate the numerical value of I in amps.
The numerical value of the current in the solenoid is approximately 2.875 amps.
The magnetic field inside a solenoid can be calculated using the formula B = μ₀ * N * I, where B is the magnetic field, μ₀ is the permeability of free space (a constant), N is the number of turns, and I is the current flowing through the solenoid. Rearranging the formula, we have I = B / (μ₀ * N). Since μ₀ is a constant, we can combine it with B to obtain I = (B * N) / μ₀.
In the given problem, the magnetic field B is given as 2.5 x 10^(-3) T, the number of turns N is 1100, and the length of the solenoid d is 0.65 m. Substituting these values into the expression for current, we have I = (2.5 x 10^(-3) T * 1100 turns) / μ₀. The value of μ₀ is approximately 4π x 10^(-7) T·m/A. Substituting this value, we can calculate the current I, which comes out to be approximately 2.875 amps.
Learn more about magnetic field here:
https://brainly.com/question/14848188
#SPJ11
Consider a thin disc of radius R and surface charge density o. (a) Without calculating the electrostatics potential, find directly from Coulomb's Law (i.e. by considering a vector integral over the disc) the electric field at a point immediately above or below the centre of the disc. Make sure you choose an appropriate coordinate system for the problem. (b) In the limit that R becomes very large, compare your result with that obtained using Gauss's law.
(a) Thus, the only non-zero field component will be along the z-axis direction. (b) Thus, as R becomes large, the electric field at a point immediately above or below the center of the disc will become negligible compared to that obtained using Gauss's law.
(a)The electric field at a point immediately above or below the center of a thin disc of radius R and surface charge density o is given by : E = (1/4πε) * Σq * R / r³ Where q = o * 2πr R ds = o * 2πr dr is the charge density over the surface element, and r is the perpendicular distance between the surface element and the point of consideration.
Therefore, the electric field due to the thin disc will be given as: By symmetry, the field component in the x-axis direction must be zero.
Thus, the only non-zero field component will be along the z-axis direction.
Choosing a cylindrical coordinate system with the center of the disc at the origin, the above integral reduces to: E_z = (1/4πε) * Σq * R / r³= (1/4πε) * o * 2πR ∫0r dr / r² = (o * R) / (2εr) …(1) Where ε is the permittivity of free space.
(b)In the limit that R becomes very large, the distance r ≫ R.
Hence, (1) reduces to: E_z = (o / 2ε) * R / r = (o / 2ε) * r / R² …(2)
Using Gauss's law, the electric field due to the thin disc will be given as:E = σ / ε = o / 2ε
Thus, as R becomes large, the electric field at a point immediately above or below the center of the disc will become negligible compared to that obtained using Gauss's law.
Therefore, both the results will match.
Learn more about electric field here:
https://brainly.com/question/11482745
#SPJ11
The light beam shown in the figure below makes an angle of a =20.2 ∘
with the normal line NN in the linseed oll. Determine the anale θ. (The refractive index for linseed oll is 1.48.)
The angle of refraction of the light beam in the linseed oil is approximately 12.5°.
The light beam shown in the figure below makes an angle of a = 20.2° with the normal line NN in the linseed oil. Determine the angle θ. (The refractive index for linseed oil is 1.48).
The angle of refraction (θ) of the given light beam can be calculated using Snell's law. According to Snell's law of refraction,n₁sinθ₁ = n₂sinθ₂Where, n₁ = refractive index of the first medium, i.e., air (or vacuum), θ₁ = angle of incidence of the light ray, n₂ = refractive index of the second medium, i.e., linseed oil, θ₂ = angle of refraction of the light ray.
In this case, the angle of incidence (θ₁) is 90° since it is perpendicular to the normal line NN. Therefore, sin θ₁ = 1. The refractive index (n₂) for linseed oil is 1.48. The angle of incidence (a) of the light ray with respect to the normal is 20.2°.
Thus, applying Snell's law of refraction,n₁sinθ₁ = n₂sinθ₂⇒ sin θ₂ = (n₁ / n₂) × sin θ₁⇒ sin θ = (1 / 1.48) × sin 20.2°≈ 0.2154⇒ θ ≈ sin⁻¹ 0.2154≈ 12.5°
Therefore, the angle of refraction of the light beam in the linseed oil is approximately 12.5°.
The angle of refraction (θ) is approximately 12.5°. The light beam shown in the figure below makes an angle of a = 20.2° with the normal line NN in the linseed oil. The refractive index for linseed oil is 1.48.
To learn about the refractive index here:
https://brainly.com/question/83184
#SPJ11
Use Gauss's Law to find the electric inside a sphere of radius R with a uniform volume charge density po. You should get Ein Por 360
The electric field inside a sphere of radius R with a uniform volume charge density po is given by:E = (1/4πε0)(rpo/3)when r < R, and E = (1/4πε0)(Rpo/3)when r = R.
Gauss's Law is a law of physics that relates the electric flux passing through a closed surface to the electric charge enclosed within it. It is expressed as follows: ∮E⋅dA =Qin/ε0where, E is the electric field, dA is an infinitesimal area element, Qin is the net charge enclosed within the surface, and ε0 is the permittivity of free space.
Using Gauss's Law, we can find the electric field inside a sphere of radius R with a uniform volume charge density po.
We begin by choosing a Gaussian surface that encloses the sphere. We can choose a spherical Gaussian surface of radius r, where r < R, to enclose a volume V = (4/3)πr³ of charge.
Since the charge density is uniform, the charge enclosed within this volume is given by: Qin = Vpo = (4/3)πr³poApplying Gauss's Law, we have:∮E⋅dA = Qin/ε0EA = Qin/ε0E(4πr²) = (4/3)πr³po/ε0
Solving for E, we get:E = (1/4πε0)(rpo/3)This shows that the electric field inside the sphere is proportional to the distance from the center and it is directly proportional to the charge density.
To find the electric field at the surface of the sphere, we set r = R:E = (1/4πε0)(Rpo/3)
Therefore, the electric field inside a sphere of radius R with a uniform volume charge density po is given by:E = (1/4πε0)(rpo/3)when r < R, andE = (1/4πε0)(Rpo/3)when r = R. The value of Ein Po is 360.
Learn more about electric field here:
https://brainly.com/question/30544719
#SPJ11
Calculate the angle of refraction for light traveling at 19.4O from oil (n = 1.65) into water (n= 1.33)?
If the light then travels back into the oil at what angle will it refract?
The obtained angle θ4 will be the angle of refraction when light travels back into the oil. The angle of refraction when light travels from oil to water, we can use Snell's law, which relates the angles of incidence and refraction to the refractive indices of the two media.
Snell's law states: [tex]n_1\\[/tex] * sin(θ1) = [tex]n_2[/tex] * sin(θ2)
Where
[tex]n_1[/tex] and [tex]n_2[/tex] are the refractive indices of the initial and final media, respectively.
θ1 is the angle of incidence.
θ2 is the angle of refraction.
Given:
[tex]n_1[/tex] = 1.65 (refractive index of oil)
[tex]n_2[/tex] = 1.33 (refractive index of water)
θ1 = 19.4°
We can rearrange Snell's law to solve for θ2:
sin(θ2) = ([tex]n_1 / n_2[/tex]) * sin(θ1)
Substituting the given values:
sin(θ2) = (1.65 / 1.33) * sin(19.4°)
Taking the inverse sine of both sides:
θ2 = sin((1.65 / 1.33) * sin(19.4°))
Calculating this expression will give us the angle of refraction when light travels from oil to water.
If the light then travels back into the oil, we can use Snell's law again. The angle of incidence will be the angle of refraction obtained when light traveled from water to oil, and the angle of refraction will be the angle of incidence in this case.
Let's assume the angle of refraction obtained when light traveled from water to oil is θ3. The angle of incidence when light travels from oil to water will be θ3, and we can use Snell's law to find the angle of refraction in the oil:
[tex]n_2[/tex] * sin(θ3) = [tex]n_1[/tex] * sin(θ4)
Rearranging the equation:
sin(θ4) = ([tex]n_2 / n_1[/tex]) * sin(θ3)
Substituting the refractive indices:
sin(θ4) = (1.33 / 1.65) * sin(θ3)
Taking the inverse sine of both sides:
θ4 = sin((1.33 / 1.65) * sin(θ3))
The obtained angle θ4 will be the angle of refraction when light travels back into the oil.
Learn more about refraction here:
https://brainly.com/question/14760207
#SPJ11
A fish takes the bait and pulls on the line with a force of 2.5 N. The fishing reel, which rotates without friction, is a uniform cylinder of radius 0.060 m and mass 0.82 kg Part A What is the angular acceleration of the fishing reel? Express your answer using two significant figures. [VG ΑΣΦΑ α = Submit Part B 8 = Request Answer How much line does the fish pull from the reel in 0.40 s?
A fish takes the bait and pulls on the line with a force of 2.5 N and in 0.40 seconds, the fish pulls approximately 1.34 meters of line from the fishing reel.
The torque exerted on the fishing reel can be calculated using the equation τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. The moment of inertia of a uniform cylinder is given by I = (1/2)mr², where m is the mass and r is the radius.
Substituting the given values, we have τ = (1/2)(0.82 kg)(0.060 m)²α. The torque exerted on the reel is equal to the force applied by the fish multiplied by the radius of the reel, so τ = (2.5 N)(0.060 m).
Setting these two expressions for torque equal to each other, we have (1/2)(0.82 kg)(0.060 m)²α = (2.5 N)(0.060 m). Simplifying and solving for α, we find α ≈ 21 rad/s². Therefore, the angular acceleration of the fishing reel is approximately 21 rad/s².
To calculate the amount of line pulled by the fish in 0.40 seconds, we need to consider the angular displacement. The angular displacement (θ) can be calculated using the equation θ = (1/2)αt², where α is the angular acceleration and t is the time.
Substituting the given values, we have θ = (1/2)(21 rad/s²)(0.40 s)². Simplifying, we find θ ≈ 0.134 radians.
The length of line pulled from the reel can be calculated using the formula l = rθ, where l is the length of the line and r is the radius of the reel. Substituting the given values, we have l = (0.060 m)(0.134 radians), which gives us l ≈ 0.008 meters or 1.34 meters (rounded to two significant figures).
Learn more about torque here:
https://brainly.com/question/31323759
#SPJ11
a particle carrying a charge of 8.0nC accelerates through a potential of ∆V=-10mV. what is the change in potential energy of the particle?
The change in potential energy of the particle is calculated using the formula ∆PE = q∆V, where q is the charge of the particle and ∆V is the change in potential.
The potential energy (PE) of a charged particle in an electric field is given by the equation PE = qV, where q is the charge of the particle and V is the electric potential. In this case, the particle carries a charge of 8.0 nC (8.0 × 10⁻⁹ C) and accelerates through a potential difference (∆V) of -10 mV (-10 × 10⁻³ V).
To calculate the change in potential energy (∆PE), we can use the formula ∆PE = q∆V. Substituting the given values, we have ∆PE = (8.0 × 10⁻⁹ C) × (-10 × 10⁻³ V). Simplifying the expression, we get ∆PE = -8.0 × 10⁻¹² J.
The negative sign in the result indicates that the change in potential energy is negative, implying a decrease in potential energy. This means that the particle loses potential energy as it accelerates through the given potential difference. The magnitude of the change in potential energy is 8.0 × 10⁻¹² J.
Learn more about potential energy visit:
brainly.com/question/24284560
#SPJ11
A sinusoidal electromagnetic wave in vacuum delivers energy at an average rate of 5.00 μW/m 2
. What are is amplitude of the electric field of this wave? (Note, μ 0
=4π×10 −7
T∙ m/A,ε 0
=8.85×10 −12
C 2
/N⋅m 2
) 0.15 V/m
0.061 V/m
2.05×10 −10
V/m
3.5×10 −6
V/m
Therefore, the amplitude of the electric field of this wave is 0.061 V/m.
The average power of a sinusoidal electromagnetic wave can be defined as follows:Pav=⟨S⟩where Pav is the average power and ⟨S⟩ is the average Poynting vector. The magnitude of the Poynting vector can be expressed as follows:⟨S⟩=12E0B0
where E0 and B0 are the magnitudes of the electric and magnetic fields, respectively. In a vacuum, the speed of light c can be expressed as follows:c=1√μ0ε0where μ0 and ε0 are the permeability and permittivity of free space,
respectively. Given the average power Pav and the permittivity of free space ε0, we can solve for the electric field E0 of the wave as follows:E0=√2Pavε0
The electric field amplitude of a sinusoidal electromagnetic wave in a vacuum that delivers energy at an average rate of 5.00 μW/m2 can be
calculated as follows:E0=√2Pavε0E0=√(2×5×10−6 W/m2×8.85×10−12 C2/N⋅m2)E0=0.061 V/m
Therefore, the amplitude of the electric field of this wave is 0.061 V/m.
to know more about electromagnetic
https://brainly.com/question/14527830?
A Force of F= (4.20i +3.60j) N is applied to a rigid body of mass 1.50 kg rotating around a fixed axis . Determine the torque experienced by the particle when the force is applied at the position of r= (1.50i+ 2.20j)
Which direction is the Torque oriented?
The torque experienced by the particle is 10.38 N·m, and its direction is perpendicular to the plane formed by the position vector and the force vector.
To determine the torque experienced by the particle, we need to calculate the cross product of the position vector and the force vector. The formula for torque is given by:
τ = r × F
where τ represents the torque, r is the position vector, and F is the force vector. In this case, the position vector r is (1.50i + 2.20j) and the force vector F is (4.20i + 3.60j).
Taking the cross product of these vectors, we have:
τ = (1.50i + 2.20j) × (4.20i + 3.60j)
Expanding the cross product, we get:
τ = (1.50 * 3.60 - 2.20 * 4.20)k
Simplifying the equation, we have:
τ = (5.40 - 9.24)k
τ = -3.84k
Therefore, the torque experienced by the particle is -3.84 N·m. The negative sign indicates that the torque is oriented in the opposite direction to the positive z-axis.
Since torque is a vector quantity, it has both magnitude and direction. The direction of the torque is determined by the right-hand rule. In this case, the torque is oriented along the negative z-axis, which means it is pointing into the plane formed by the position vector and the force vector.
Learn more about magnitude here:
https://brainly.com/question/31022175
#SPJ11
A billiard ball moving across the table at 1.50 m/s makes a head on elastic collision with an identical ball. Find the velocities of each ball after the collision: (a) when the 2nd ball is initially at rest, velocity of ball 1: _______ velocity of ball 2: ________
(b) when the 2nd ball is moving toward the first with a speed of 1.00 m/s, velocity of ball 1: ___________ velocity of ball 2: __________ (c) when the 2nd ball is moving away from the first with a speed of 1.00 m/s, velocity of ball 1: __________ velocity of ball 2: ____________
When the 2nd ball is initially at rest, the velocity of ball 1 is 0 m/s and the velocity of ball 2 is 1.50 m/s. When the 2nd ball is moving toward the first with a speed of 1.00 m/s, the velocity of ball 1 is 0.25 m/s and the velocity of ball 2 is 1.25 m/s.
The formula for elastic collision is:
v1f = (m1 - m2)/(m1 + m2) * v1i + 2m2/(m1 + m2) * v2i
v2f = 2m1/(m1 + m2) * v1i + (m2 - m1)/(m1 + m2) * v2i
Given:
Initial velocity of ball 1, v1i = 1.50 m/s
Initial velocity of ball 2, v2i = 0 m/s (initially at rest)
Mass of ball 1 = Mass of ball 2
Calculations:
(a) When the 2nd ball is initially at rest:
Total mass, m = m1 + m2 = m1 + m1 = 2m1
Let's assume the final velocity of ball 1 and ball 2 are v1f and v2f, respectively.
v1f = (m1 - m1)/(2m1) * 1.50 m/s + 2m1/(2m1) * 0 m/s
v1f = 0 m/s
v2f = 2m1/(2m1) * 1.50 m/s + (m1 - m1)/(2m1) * 0 m/s
v2f = 1.50 m/s
(b) When the 2nd ball is moving toward the first with a speed of 1.00 m/s:
Initial velocity of ball 2, v2i = -1.00 m/s (moving towards ball 1)
Total mass, m = m1 + m2 = m1 + m1 = 2m1
Let's assume the final velocity of ball 1 and ball 2 are v1f and v2f, respectively.
v1f = (m1 - m1)/(2m1) * 1.50 m/s + 2m1/(2m1) * (-1.00 m/s)
v1f = -0.25 m/s
v2f = 2m1/(2m1) * 1.50 m/s + (m1 - m1)/(2m1) * (-1.00 m/s)
v2f = 1.25 m/s
(c) When the 2nd ball is moving away from the first with a speed of 1.00 m/s:
Initial velocity of ball 2, v2i = 1.00 m/s (moving away from ball 1)
Total mass, m = m1 + m2 = m1 + m1 = 2m1
Let's assume the final velocity of ball 1 and ball 2 are v1f and v2f, respectively.
v1f = (m1 - m1)/(2m1) * 1.50 m/s + 2m1/(2m1) * 1.00 m/s
v1f = 0.25 m/s
v2f = 2m1/(2m1) * 1.50 m/s + (m1 - m1)/(2m1) * 1.00 m/s
v2f = 1.25 m/s
Hence the velocities of each ball after the collision are as follows:
(a) when the 2nd ball is initially at rest, velocity of ball 1: 0 m/s, velocity of ball 2: 1.50 m/s
(b) when the 2nd ball is moving toward the first with a speed of 1.00 m/s, velocity of ball 1: 0.25 m/s, velocity of ball 2: 1.25 m/s.
Learn more about velocity: https://brainly.com/question/80295
#SPJ11
Analyse the stick diagram as shown in Figure Q2(b). (i) Transform the stick diagram into the equivalent schematic circuit at transistor level. (10 marks) (ii) Determine the Boolean equation representing the output Y. (4 marks) Figure Q2(b)
The above schematic circuit diagram is the equivalent schematic circuit at transistor level.
The Boolean equation representing the output Y is X + Z.
(i) Transformation of stick diagram into an equivalent schematic circuit at transistor level
The stick diagram given above represents the schematic diagram of the given Boolean expression using only MOS transistors as per the design rules. The stick diagram can be transformed into the equivalent schematic circuit at transistor level as shown below:
The above schematic circuit diagram is the equivalent schematic circuit at transistor level.
(ii) Determination of Boolean equation representing the output Y Boolean equation can be formed by observing the schematic circuit diagram obtained from the stick diagram.
The output of the given circuit diagram is represented by the output terminal Y which is labelled in the circuit diagram obtained above. The output Y is formed by OR operation of the two input terminals X and Z as seen in the diagram. Therefore the Boolean equation representing the output Y is given as:
Y = X + Z.
The Boolean equation representing the output Y is X + Z.
Learn more about Boolean https://brainly.com/question/2467366
#SPJ11
What is the estimated volume of the table tennis ball?
cm3
What is the estimated volume of the golf ball?
cm3
Answer:
The estimated volume of a standard table tennis ball is approximately 2.7 cm³.
The estimated volume of a standard golf ball is approximately 41.6 cm³.
Explanation:
Consider a tank with a direct action level controller set with a gain of 1 and a reset of 1 minute. The level in the tank rises 20 percent above setpoint, resulting in a 20 percent increase in signal to the controller. The controller establishes a correction slope of percent per a. 5 b. 10 c. 20 d. 30
The correction slope of the level controller is b. 10. The direct action level controller in the tank is set with a gain of 1 and a reset of 1 minute. When the level in the tank rises 20 percent above the setpoint, the signal to the controller also increases by 20 percent.
The level controller has to establish a correction slope of percent per b. 10. When the level of the tank rises, the controller takes action to reduce it by lowering the flow rate of the incoming fluid. If the set point is too low, the controller opens the valve or pump to allow more fluid into the tank, raising the level. It will also increase the flow rate when the set point is too low. The controller's slope is used to control the rate at which the controller increases or decreases the flow rate to control the tank's level. Hence, the correct option is b. 10.
To know more about direct acting controller visit:
https://brainly.com/question/30178699
#SPJ11
The components of a simple half-wave rectifier are a diode and a load. Suppose the diode's internal resistance is 1 ohm and the load resistance is 5 ohm. What would the DC load current be if the supply voltage is 12 Volts, and what will the waveform of the rectifier look like? Sketch the waveform and draw the circuit.
The output is not a steady DC voltage because it is not completely filtered, and it has a significant ripple. Therefore, it is considered as a pulsating DC waveform.
A half-wave rectifier is a device that converts AC voltage into DC voltage.
It works by only allowing half of the AC wave to pass through the circuit, resulting in a pulsed DC output. The two main components of a half-wave rectifier are a diode and a load.
The diode acts as a one-way valve, allowing current to flow in only one direction. The load is the component that receives the DC output from the rectifier. In this example, we have a diode with an internal resistance of 1 ohm and a load resistance of 5 ohms. If the supply voltage is 12 volts, the DC load current can be calculated as follows:
DC Load Current = (Supply Voltage - Diode Voltage Drop) / Load Resistance
The voltage drop across the diode is typically around 0.7 volts, so:
DC Load Current = (12 - 0.7) / 5 = 2.26 Amps
The waveform of the rectifier will look like a half-wave rectified sine wave. The circuit consists of a voltage source, a diode, and a load. The voltage source is a sinusoidal wave. The diode is in series with the load, and it only allows the positive half-cycle of the input wave to pass through.
This means that the output waveform is half of the input waveform. The output is not a steady DC voltage because it is not completely filtered, and it has a significant ripple.
Therefore, it is considered as a pulsating DC waveform.
Learn more about half-wave rectifier here:
https://brainly.com/question/29357543
#SPJ11
A gas in a container has heat added but the temperature decreases. Which one of the following is true during this process?
A. Positive work is done by the gas on the environment.
B. This process is not possible.
C. The internal energy will increase.
D. This work done by the gas is equal to the change in the internal energy of the gas.
E. The change in internal energy of the gas is equal to the heat added to the gas.
In this case, since the temperature is decreasing (indicating a decrease in internal energy) and heat is being added to the gas, the change in internal energy (ΔU) is equal to the heat added (Q). Therefore, option E: The change in internal energy of the gas is equal to the heat added to the gas is the correct statement.
When heat is added to a gas and the temperature decreases, it means that the gas is undergoing a process known as cooling or heat transfer out of the system. In this process, the gas releases internal energy in the form of heat to the surroundings. The decrease in temperature indicates a decrease in the average kinetic energy of the gas particles, resulting in a decrease in the internal energy of the gas.
According to the first law of thermodynamics, the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
To know more about first law of thermodynamics
https://brainly.com/question/32101564
#SPJ11
In the figure particle 1 of charge q1 = +e and particle 2 of charge q2 = –6e are fixed on an x axis. Distance d = 7.40 μm. What is the electric potential difference (in V) VA – VB?
the electric potential difference VA – VB is 13.54 V.
The given charges in the figure are particle 1 of charge q1 = +e and particle 2 of charge q2 = -6e, and they are fixed on the x-axis at a distance of d = 7.40 μm. The electric potential difference (in V) VA – VB is to be determined.However, there is no point C between A and B in the figure. Hence, it is not possible to determine the potential difference between A and B. Instead, we can calculate the potential at points A and B due to charges q1 and q2, respectively. Then, we can subtract VB from VA to get the potential difference VA – VB.
Let's calculate the potentials at A and B.Using the electric potential formula for a point charge V = kq/r where k = 9 × 10^9 N m²/C² is Coulomb's constant, we get:VA = kq1/RA= (9 × 10^9 N m²/C²)(1.6 × 10^-19 C)/(7.4 × 10^-6 m)= 1.94 VVB = kq2/RB= (9 × 10^9 N m²/C²)(-6 × 1.6 × 10^-19 C)/(7.4 × 10^-6 m)= -11.6 VTherefore,VA – VB= (1.94 V) - (-11.6 V)= 13.54 VTherefore, the electric potential difference VA – VB is 13.54 V.
Learn more about constant here,
https://brainly.com/question/27983400
#SPJ11
A brick with a mass of 10 kg and a volume of 0.01 m³ is submerged in a fluid that has a density of 800 kg/m³. The brick will sink in the fluid. O True O False
The brick will sink in the fluid is true.
A brick with a mass of 10 kg and a volume of 0.01 m³ is submerged in a fluid that has a density of 800 kg/m³.
The density of an object is the ratio of mass to volume.
The mass of the brick is 10 kg and the volume is 0.01 m³.
So, the density of the brick is; Density = mass/volume = 10 kg/0.01 m³ = 1000 kg/m³
The density of the brick is 1000 kg/m³.
The density of the fluid is 800 kg/m³.
So, the brick will sink because the density of the brick is greater than the density of the fluid.
Learn more about sink: https://brainly.com/question/857846
#SPJ11
Given x1(t) = cos (t), x2(t) = sin (πt) and x3(t) = xi(t) + x2(t). a. Determine the fundamentals period of TI and T2 b. Determine if T3 is periodic or nonperiodic and shows the evident c. Determine the powers P1, P2 and P3 of each signal
The fundamental period (TI) for x1(t) is 2π, (T2) for x2(t) is 2 and x3(t) is nonperiodic. Powers P1 and P2 values are 1/2 while the power of P3 cant be determined since x3(t) is nonperiodic.
Given signals are;x1(t) = cos(t) x2(t) = sin(πt) x3(t) = x1(t) + x2(t)a) To find the fundamental period of T1;The fundamental period of a signal x(t) is denoted by T0, and it is defined as the smallest value of T such that x(t) = x(t+T) for all values of t. Therefore, x1(t) = x1(t+T1), whereT1= 2π/ω1= 2π/1= 2π. Thus, the fundamental period of x1(t) is T1= 2π.b) To find the fundamental period of T2;x2(t) = x2(t+T2), whereT2 = 2π/ω2= 2π/π= 2Thus, the fundamental period of x2(t) is T2 = 2.c) To determine if T3 is periodic or non-periodic and show the evident;x3(t) = x1(t) + x2(t) Therefore,x3(t) = cos(t) + sin(πt)If we assume T3 exists, then we can say thatx3(t) = x3(t + T3)cos(t) + sin(πt) = cos(t + T3) + sin(π(t + T3))
Therefore, the function will be periodic if the following conditions are satisfied: cos(t + T3) = cos(t)sin(π(t + T3)) = sin(πt)Expanding the above expression, cos(t + T3) = cos(t)sin(πt)cos(T3) + cos(πt)sin(πt)sin(T3) = sin(πt). Simplifying, cos(T3) = 1Therefore, T3 is a multiple of 2π. Also, sin(T3) = 0.If T3 exists, it must be a multiple of T1 and T2.LCM(T1, T2) = LCM(2π, 2) = 2πThe multiple of 2π is 2π itself. Therefore, T3 = 2πd, where d is a constant. But since sin(T3) = 0, d must be an even integer.T3 is periodic with a fundamental period of 2πd. Thus, T3 = 4π.d) To determine the power P1, P2 and P3 of each signal; Power is defined as the average value of the energy carried by the signal over the given time.T1 = 2π, ω1 = 1; P1 = (1/T1)∫(T1/2)^(T1/2)x1^2(t) dt= (1/2π) ∫π^(-π) cos^2(t) dt= 1/2.T2 = 2, ω2 = π; P2 = (1/T2)∫(T2/2)^0x2^2(t) dt= (1/4) ∫2^0 sin^2(πt) dt= 1/4.T3 = 4π; P3 = (1/T3)∫(T3/2)^(-T3/2)x3^2(t) dt= (1/8π) ∫2π^(-2π) (cos(t) + sin(πt))^2 dt= (1/8π) [π + 2] = (π + 2)/8π.
Learn more about fundamental period:
https://brainly.com/question/15861094
#SPJ11
Suppose you try to cool the kitchen of your house by leaving the refrigerator door open. What happens? Why? Would the result be the same if you left open a picnic cooler full of ice? Explain the reason for any differences.
Is it a violation of the second law of thermodynamics to convert mechanical energy completely into heat? To convert heat completely into work? Explain your answers.
Real heat engines, like the gasoline engine in a car, always have some friction between their moving parts, although lubricants keep the friction to a minimum. Would a heat engine with completely frictionless parts be 100% efficient? Why or why not? Does the answer depend on whether or not the engine runs on the Carnot cycle? Again, why or why not?
A heat engine with completely frictionless parts would still not be 100% efficient even if it ran on the Carnot cycle.
Suppose you try to cool the kitchen of your house by leaving the refrigerator door open. What happens? Why?Would the result be the same if you left open a picnic cooler full of ice? Explain the reason for any differences.If you leave the refrigerator door open, the room may become slightly colder initially, but the overall effect will be to warm up the room. This is because the refrigerator will work to cool down the air inside it but at the same time will pump the heat out into the room. As a result, the room’s temperature will rise. If you left a picnic cooler full of ice open in the room, the ice would eventually melt and the water would eventually warm up to room temperature, raising the temperature of the room.
However, the cooling effect of the ice will be greater than the heating effect of the air that escapes. Therefore, it will be more efficient in cooling the room for a shorter time.Is it a violation of the second law of thermodynamics to convert mechanical energy completely into heat? To convert heat completely into work? Explain your answers.No, it is not a violation of the second law of thermodynamics to convert mechanical energy completely into heat because heat is a form of energy, and the second law of thermodynamics states that energy cannot be created or destroyed; it can only be transferred or converted from one form to another.
However, it is impossible to convert heat completely into work because some heat energy will always be lost to the environment, and the second law of thermodynamics prohibits the conversion of heat energy completely into work.Real heat engines, like the gasoline engine in a car, always have some friction between their moving parts, although lubricants keep the friction to a minimum. Would a heat engine with completely frictionless parts be 100% efficient? Why or why not? Does the answer depend on whether or not the engine runs on the Carnot cycle?
Again, why or why not?A heat engine with completely frictionless parts would not be 100% efficient because some energy would still be lost as heat due to the second law of thermodynamics. The answer does not depend on whether or not the engine runs on the Carnot cycle because the Carnot cycle assumes an ideal engine with no friction, which is not possible in the real world. Therefore, a heat engine with completely frictionless parts would still not be 100% efficient even if it ran on the Carnot cycle.
Learn more about Thermodynamics here,
https://brainly.com/question/13059309
#SPJ11
The cycle below described by a perfect gas in the diagram (P, V) is considered.
To describe such a cycle, the gas is successively in contact with two thermostats: one, the hot source at temperature T1 = 300 K; the other, the cold source at temperature T2 = 250 K.
Gas transformations are reversible. AB and CD transformations are therefore isotherms and BC and DA transformations are adiabatics (no heat exchange). The heat received by the gas in the CD isothermal transformation is Q2 = 1000 kJ.
1)What is the entropy variation for the ABCDA cycle?
2) Calculate the heat Ql received by the gas in the ISothermal transformation AB.
1) The entropy variation for the ABCDA cycle is 150.2) The heat Ql received by the gas in the isothermal transformation AB is 832.8kJ.What is the definition of entropy?Entropy is the extent of the randomness or the molecular disorder of a system. Entropy is a measure of the degree of disorder of a system.
The units of entropy are joules per kelvin per mole (J K-1 mol-1).What is the definition of the first law of thermodynamics?The First Law of Thermodynamics is a statement of the Law of Energy Conservation, which states that energy cannot be created or destroyed, but it can be converted from one form to another. The first law of thermodynamics is also known as the Law of Conservation of Energy.What is the definition of the second law of thermodynamics?The second law of thermodynamics is an assertion that all physical processes or spontaneous transformations of energy go from states of higher order to states of lower order, that the entropy of an isolated system will tend to increase over time, approaching a maximum value at equilibrium. The second law of thermodynamics is responsible for the flow of heat from hot to cold and for the impossibility of building perpetual motion machines.
Learn more on entropy here:
brainly.in/question/15044680
#SPJ11
△50% Part (a) What is the oscillation frequency of your circuit, in hertz? A 50% Part (b) If the maximum potential difference between the plates of the capacitor is 55 V, what is the maximum current in the circuit, in amperes? I max
=
Therefore, we cannot determine the values for parts (a) and (b) of the question. Unfortunately, we cannot determine the values for parts (a) and (b) of the question.
For a parallel-plate capacitor, the capacitance, C is given byC=ϵ0A/dwhere ϵ0 is the permittivity of free space, A is the area of each plate, and d is the distance between the plates. The period of oscillation is given byT=2π√LCwhere L is the inductance of the inductor in the circuit. Since the circuit oscillates at 50% of its maximum value, the peak current, I_max can be determined usingOhm's law, I=V/R. The current, I at any given moment in time can be found usingI=I_maxsin(ωt), where ω is the angular frequency, which is given byω=2π/T. Part (a)The oscillation frequency of the circuit, in hertz, is given byf=1/T=1/2π√LC. Since we are not given any values for the inductance or capacitance, we cannot determine the frequency of oscillation. Part (b)The maximum current, I_max, is given byI_max=V/R, where V is the maximum potential difference between the plates of the capacitor and R is the resistance of the circuit. We are not given any information about the resistance of the circuit, so we cannot determine the maximum current in amperes. Therefore, we cannot determine the values for parts (a) and (b) of the question. Answer: Unfortunately, we cannot determine the values for parts (a) and (b) of the question.
To know more about oscillating visit:
https://brainly.com/question/32232136
#SPJ11
A 0.250 kg mass is attached to a horizontal spring of spring constant 140 N/m, supported by a frictionless table. A physics student pulls the mass 0.12 m from equilibrium, and the mass is then let go. Assume no air resistance and that it undergoes simple harmonic motion.
a) Calculate the work done by the student on the mass in pulling it a distance of 0.12 m.
b) Using conservation of energy principles, calculate the maximum speed of the mass.
a) The work done by the student on the mass in pulling it a distance of 0.12 m is 0.10 J.b) The maximum speed of the mass is 0.79 m/s.
a) Work done by the student on the mass in pulling it a distance of 0.12 m.The amount of work done by the student is equal to the amount of potential energy stored in the spring.Potential energy stored in the spring = 1/2 kx²where, k is the spring constant and x is the displacement from the equilibrium position.Now, the displacement of the mass is given as 0.12 m.Substituting the given values,1/2 × 140 N/m × (0.12 m)² = 0.10 JTherefore, the work done by the student on the mass in pulling it a distance of 0.12 m is 0.10 J.
b) Maximum speed of the massUsing the law of conservation of energy, the potential energy stored in the spring is equal to the kinetic energy of the mass at the maximum speed.Potential energy stored in the spring = Kinetic energy of the mass at maximum speed1/2 kA² = 1/2 mv²where, A is the amplitude, m is the mass, and v is the maximum velocity of the mass.Substituting the given values,1/2 × 140 N/m × (0.12 m)² = 1/2 × 0.250 kg × v²Solving for v, v = 0.79 m/sTherefore, the maximum speed of the mass is 0.79 m/s.
Learn more about Potential energy here,
https://brainly.com/question/21175118
#SPJ11
In cases of Refraction, when the refracted beam approaches the Normal when passing the medium, it is due to:
A) the refractive index is lower because the material is less dense
B) The wavelength changes but the frequency remains constant.
C) The refractive index increases because it is denser.
D) The medium where light refracts absorbs energy.
Correct option is C. When the refracted beam approaches the Normal when passing through a medium, it is due to the increased refractive index of the denser material.
Refraction is the bending of light as it passes from one medium to another with a different refractive index. The refractive index is a measure of how much a medium can bend light. When a beam of light travels from a less dense medium to a denser medium, such as from air to water or from air to glass, the beam of light bends towards the normal (an imaginary line perpendicular to the surface of the medium).
The change in direction of the light beam occurs because the speed of light is different in different materials. The refractive index is defined as the ratio of the speed of light in a vacuum to the speed of light in the medium. When light enters a denser medium, such as water or glass, its speed decreases, resulting in a higher refractive index for the medium. As a result, the beam of light bends towards the normal.
Therefore, the correct answer is C) The refractive index increases because it is denser.
Learn more about refractive index here:
https://brainly.com/question/30761100
#SPJ11
A parallel plate capacitor, in which the space between the plates is filled with a dielectric material with dielectric constant κ=16. 9
, has a capacitor of V=19. 9μF
and it is connected to a battery whose voltage is C=65. 8V
and fully charged. Once it is fully charged, while still connected to the battery, dielectric material is removed from the capacitor. How much change occurs in the energy of the capacitor (final energy minus initial energy)? Express your answer in units of mJ (mili joules) using two decimal places.
To determine the change in energy of the capacitor when the dielectric material is removed, we need to calculate the initial and final energies and then find the difference between them.
The energy stored in a capacitor is given by the formula:
E = 0.5 * C * V^2
Given:
Capacitance (C) = 19.9 μF = 19.9 × 10^(-6) F
Voltage (V) = 65.8 V
Dielectric constant (κ) = 16.9
Let's first calculate the initial energy when the dielectric material is present:
Initial Energy (E_initial) = 0.5 * C * V^2
Next, we need to calculate the final energy after the dielectric material is removed. Since the dielectric constant is removed, the effective capacitance of the capacitor will change.
The new capacitance without the dielectric can be calculated using the equation:
C_new = C / κ
Now we can calculate the final energy:
Final Energy (E_final) = 0.5 * C_new * V^2
To find the change in energy:
ΔE = E_final - E_initial
Let's perform the calculations:
E_initial = 0.5 * (19.9 × 10^(-6)) * (65.8)^2
C_new = (19.9 × 10^(-6)) / 16.9
E_final = 0.5 * C_new * (65.8)^2
ΔE = E_final - E_initial
Calculating ΔE will give us the change in energy of the capacitor.
Please note that the result will be provided in units of mJ (mili joules) with two decimal places.
To know more about "Capacitance" refer here:
brainly.com/question/29591088#
#SPJ11
There is a DFB-LD composed of InGaAsP with a central wavelength of 1550 nm and an effective refractive index of 3.6 (a) The change in oscillation wavelength according to the temperature of DFB-LD is +0.1 nm/°C. Assuming that wavelength tuning is performed due to the temperature change of TEC, what is the wavelength tuning range A if it is operated between -20 °C and 80 °C ? (b) We intend to produce a tunable laser array that can use the entire C-band (1525 nm to 1565 nm) using multiple channels of DFB-LD with different center wavelengths. If the temperature range of the TEC is operated between -20 °C and 80 °C, what is the minimum number of channels of DFB-LD required?
A) the wavelength tuning range A if it is operated between -20 °C and 80 °C is 10 nm
B) the minimum number of channels of DFB-LD required to span the entire C-band would be 4 channels.
(a) The change in oscillation wavelength according to the temperature of DFB-LD is +0.1 nm/°C.
Assuming that wavelength tuning is performed due to the temperature change of TEC, what is the wavelength tuning range A if it is operated between -20 °C and 80 °C?
The wavelength tuning range is determined by the minimum temperature of -20°C and the maximum temperature of 80°C, with a range of 100°C. For every degree of temperature increase, the oscillation wavelength increases by 0.1 nm.
The oscillation wavelength range can be found using the following equation:
A = Δλ/ΔT x ΔT
Where,
Δλ/ΔT = Temperature Coefficient of the device
ΔT = Change in temperature
A = Wavelength tuning range, we have,
Δλ/ΔT = +0.1 nm/°C
ΔT = (80 - (-20))°C = 100°C
So,
A = Δλ/ΔT x ΔT = +0.1 nm/°C x 100°C= 10 nm
(b) We intend to produce a tunable laser array that can use the entire C-band (1525 nm to 1565 nm) using multiple channels of DFB-LD with different center wavelengths. If the temperature range of the TEC is operated between -20 °C and 80 °C, what is the minimum number of channels of DFB-LD required?
To span the entire C-band (1525 nm to 1565 nm), we need to find the range of center wavelengths that is required. We can find this by finding the difference between the maximum wavelength of the C-band and the minimum wavelength of the C-band, which is,
1565 nm - 1525 nm = 40 nm
We know that for every degree of temperature increase, the oscillation wavelength increases by 0.1 nm. So, to span a wavelength range of 40 nm, we need to change the temperature by:
40 nm / 0.1 nm/°C = 400°C
To cover this range, we have a temperature range of 80 - (-20) = 100°C available to us.
Therefore, the minimum number of channels required to cover the full C-band would be:
400°C / 100°C = 4 channels
Hence, the minimum number of channels of DFB-LD required to span the entire C-band would be 4 channels.
learn more about tunable laser array here:
https://brainly.com/question/17011884
#SPJ11
One long wire lies along an x axis and carries a current of 46 Ain the positive x direction A second long wire is perpendicular to the xy plane, passes through the point (0,6.4 m, 0), and carries a current of 45 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0.11 m.)? Number ___________ Units ______________
The magnitude of the resulting magnetic field at the point (0.11 m) is 6.92 × 10⁻⁶ T.
The problem involves calculating the magnitude of the resulting magnetic field at a point (0.11 m). To do this, find the magnetic field caused by each wire and then add them together.
The formula for calculating the magnetic field caused by a wire is:
B = (µ₀ / 4π) * (2I / d)
Where:
B is the magnetic field,
I is the current,
d is the distance between the wire and the point where we want to calculate the magnetic field,
µ₀ is the permeability of free space, which is equal to 4π × 10⁻⁷ Tm/A.
Let's calculate the magnetic field caused by each wire:
For the first wire:
B₁ = (µ₀ / 4π) * (2 * 46 A / 0.11 m)
B₁ = 6.41 × 10⁻⁶ T
For the second wire:
B₂ = (µ₀ / 4π) * (2 * 45 A / 6.4 m)
B₂ = 2.63 × 10⁻⁶ T
The direction of B₂ is along the positive y-axis.
Now, calculate the total magnetic field by using the Pythagorean theorem:
B = √(B₁² + B₂²)
B = √((6.41 × 10⁻⁶)² + (2.63 × 10⁻⁶)²)
B = 6.92 × 10⁻⁶ T
Therefore, the magnitude of the resulting magnetic field at the point (0.11 m) is 6.92 × 10⁻⁶ T.
Learn more about magnetic field: https://brainly.com/question/7802337
#SPJ11
A beam of light strikes the surface of glass (n = 1.46) at an angle of 70° with respect to the normal. Find the angle of refraction inside the glass. Take the inder of refraction of air n₁ = 1.
The given case is not possible. The given parameters must be incorrect.Conclusion:The given parameters must be incorrect because the value of sin cannot be greater than 1. Hence the angle of refraction inside the glass cannot be calculated.
Given parameters are,n = refractive index of glassn₁ = refractive index of airAngle of incidence (i) = 70°We are required to calculate the angle of refraction (r) inside the glass.To calculate the angle of refraction inside the glass, we can use Snell’s law.Snells law states that the ratio of the sines of the angle of incidence (i) and the angle of refraction (r) is equal to the ratio of the refractive indices of two media. i.e.,sin i / sin r = n1 / n2
Where,n₁ = Refractive index of air = 1n₂ = Refractive index of glass = 1.46sin i / sin r = 1 / 1.46 sin r = (sin i) x (n2 / n1)sin r = sin 70° × (1.46 / 1) = 1.2351The value of sin cannot be greater than 1. Hence, the given case is not possible. The given parameters must be incorrect.Conclusion:The given parameters must be incorrect because the value of sin cannot be greater than 1. Hence the angle of refraction inside the glass cannot be calculated.
Learn more about Refractive here,
https://brainly.com/question/83184
#SPJ11
You are given a vector in the xy plane that has a magnitude of 81.0 units and a y component of −69.0 units. Part B Assuming the x component is known to be positive, specify the magnitude of the vector which, if you add it to the original one, would give a resultant vector that is 80.0 units long and points entirely in the −x direction. Part C Specify the direction of the vector. Express your answer using three significant figures
Part A: we have the following:|a| = √(ax² + ay²) = √(81² + (-69)²) = 105 units.Part B: The magnitude of the second vector is 44.1 units.
Part C: The direction of the vector is 57.1 degrees below the negative x-axis.
Part A:To find the magnitude of a vector, the Pythagorean theorem is used. Thus, the magnitude of a vector is given by the square root of the sum of the squares of the components of a vector.|a| = √(ax² + ay²)Where ax is the x-component and ay is the y-component of vector a.Using this formula, we have the following:|a| = √(ax² + ay²) = √(81² + (-69)²) = 105 units.
Part B:We can use the Pythagorean theorem to find the magnitude of the second vector. If v is the second vector, then:v = -sqrt((80)^2 - (105)^2) = -44.1 units.The magnitude of the second vector is 44.1 units.
Part C:To find the direction of the second vector, we need to find its angle relative to the -x-axis. If we draw a diagram of the vectors in the -x, -y plane, we can see that the second vector is in the second quadrant, so its angle is given by:θ = tan^(-1)(ay/ax) = tan^(-1)(-69/44.1) = -57.1°.Thus, the direction of the vector is 57.1 degrees below the negative x-axis.The direction of the vector is 57.1 degrees below the negative x-axis.
Learn more about magnitude here,
https://brainly.com/question/30337362
#SPJ11
A physicist illuminates a 0.57 mm-wide slit with light characterized by i = 516 nm, and this results in a diffraction pattern forming upon a screen located 128 cm from the slit assembly. Compute the width of the first and second maxima (or bright fringes) on one side of the central peak. (Enter your answer in mm.) W1 = ____
w2 = ____
The width of the first maximum (bright fringe) on one side of the central peak is 0.126 mm, and the width of the second maximum is 0.252 mm.
1- The width of the bright fringes in a diffraction pattern can be determined using the formula for single-slit diffraction: W = λL / w,
where W is the width of the bright fringe, λ is the wavelength of light, L is the distance from the slit to the screen, and w is the width of the slit.
The width of the slit is 0.57 mm, the wavelength of light is 516 nm (or 516 × 10⁻⁹ m), and the distance from the slit to the screen is 128 cm (or 1.28 m):
W₁ = (516 × 10⁻⁹ m × 1.28 m) / (0.57 × 10⁻³ m) ≈ 0.126 mm
similarly we can calculate the W2 :
2-W₂ = 2 × 0.126 mm ≈ 0.252 mm
learn more about single-slit diffraction here:
https://brainly.com/question/26384235
#SPJ4