A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g, what is the radius of a single jawbreaker

Answers

Answer 1

The radius of each jawbreaker is approximately 0.68 cm.

Volume of a sphere;v = 4 /3 πr³

where

r = radius

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

Therefore,

volume of each jawbreaker = 4 /3 πr³

1.32 = 4 / 3 × 3.14 × r³

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

r = 0.680651651 = 0.68

Therefore, the radius of each jawbreaker is approximately 0.68 cm.

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Related Questions

Can you please help me with this one

Answers

oh ok where is it bring it

according to Newton's second law of motion. what is force product​

Answers

Newton's second law equates the net force on an object to the rate of change of its momentum, the latter being the product of the mass of a body and its velocity.

Hope this helps :)

Answer:

Force can be defined as the product of mass and acceleration.

Explanation:

~Cornasha_Weeb

The period of a .75 m pendulum is _s

Answers

Hi there!

We can use the following equation for the period of a pendulum:

[tex]\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}[/tex]

T = Period (s)
L = length of simple pendulum (.75 m)

g = acceleration due to gravity (9.8 m/s²)

Plug in the values:

[tex]T = 2\pi \sqrt{\frac{.75}{9.8}} = \boxed{1.738 s}[/tex]

On the periodic table, the elements known as noble gases are found in

Answers

Answer:

The noble gases are located in the 18th group of the periodic table.

If you increase your speed from 10 mph to 30 mph, how much will your stopping distance increase?

Answers

When you double the speed of your car, your braking distance quadruples. every time you double your speed, you multiply your braking distance by four.

The stopping distance of a vehicle is the sum of breaking distance and thinking distance. The stopping distance of a vehicle when we increase the velocity from 10mph to 30 mph, increases from30 feet to 90 feet.

What is stopping distance?

Stopping distance is the distance covered by a vehicle when we stops. Distance is the product of time and velocity. As the velocity increases then, the time taken to cover the distance will be lower.

Stopping distance mathematically is the sum of breaking distance and thinking distance .Thinking distance is simply the speed and it is in fact means how long it takes on average to think for a break.

Breaking distance is means how long the driver takes to break or stop in actual. In general, the breaking distance is speed multiplied by 2.

Thus, for 10 mph, the thinking distance is 10 feet and breaking distance is 10 × 2 = 20 feet and therefore, the stopping distance is 10 + 20 =30 feet.

Similarly for 30 mph, breaking distance is 60 feet and thinking distance is 30 feet thus, having 60 + 30 = 90 feet of stopping distance.

Therefore, when the speed increased from 10 mph to 30 mph, stopping distance increases from 30 feet to 90 feet.

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what is the relationship between distance, average speed and time​

Answers

Answer:

average speed= total distance/total time

Explanation:

Related to the distance traveled by the object which means, it is only represented by the magnitude and direction of travel is not important. so average speed= total distance/total time

A car engine burns gas at 495 K and exhausts to the air at 293 K if it ran at the highest possible efficiency and use 10,000 J of input heat how much he would it be rejected into the air? WILL GIVE BRAINLIEST​

Answers

Answer:

5,920 J

Explanation:

Lowest temperature T₂ = 293 K

Highest temperature T₁ = 495 K

Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408

Input heat Q₁ = 10,000 J

Find output heat Q₂

e = 1 - Q₂/Q₁

0.408 = 1 - Q₂/10,000

Q₂/10,000 = 1 - 0.408 = 0.592

so

Q₂  = 10,000 x 0.592 = 5,920 J

How much work is done on a small car if 4250 N force is exerted to move it 83.5 m to the side of the road?

Answers

Answer:

354875 J

Explanation:

The equation for Work is:

[tex]Work=Force*Distance[/tex]

We can plug in the given values into the equation:

[tex]Work=4250N*83.5m=354875J[/tex]

Light passes through a single slit of width 8.77 x 10-6 m. The second (m = 2 diffraction minimum occurs at an angle of 5.62º. What is the wavelength of the light IN NANOMETERS?​

Answers

Answer:

429.424

Explanation:

Trust :)

The wavelength of the light passing through the single slit is approximately 429 nanometers.

To calculate the wavelength of the light passing through a single slit, we can use the formula for the diffraction of light:

w × sin(θ) = m ×λ

Where:

w is the width of the slit

θ is the angle of the diffraction minimum

m is the order of the diffraction minimum

λ is the wavelength of the light

Given:

Width of the slit (w) = 8.77 × 10^(-6) m

Angle of the diffraction minimum (θ) = 5.62º = 5.62° = 5.62 × π/180 radians

Order of the diffraction minimum (m) = 2

To solve for the wavelength (λ),  rearrange the formula:

λ = (w × sin(θ)) / m

Substituting the given values:

λ = (8.77 × 10^(-6) m × sin(5.62° × π/180)) / 2

Calculating this expression:

λ ≈ (8.77 × [tex]10^{(-6)[/tex] m × sin(0.098)) / 2

λ ≈ (8.77 ×[tex]10^{(-6)[/tex] m × 0.098) / 2

λ ≈ 4.29 ×[tex]10^{(-7)[/tex] m

To convert the wavelength to nanometers, we multiply by[tex]10^9[/tex]:

λ = 4.29 × [tex]10^{(-7)[/tex] m × 10^9 nm/m

λ ≈ 429 nm

Therefore, the wavelength of the light passing through the single slit is approximately 429 nanometers.

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A football is kicked at ground level with a speed of 18.0 m/s at an angle of 31.0 to the horizontal. How much longer does it hit the ground?

Answers

The football hit the ground 2.11 seconds later.

Hope this helps

3. An airplane travels at a speed of 600 km/h. How much time will it take to fly a distance of 3180 km to California

Answers

Answer:

5.3 hours

Explanation:

(3180 km) / (600 km/h) = 5.3 hours

If each pull-up requires 300 J and Ben does a pull-up in 2 seconds, what is his power? 150 watts 300 watts 600 watts 750 watts

Answers

Answer:

150 watts

Explanation:

300/2 = 150 watts

Answer:

150 watts

Explanation:

The explanation is in the picture

PLEASE MARK BRAINLIEST

If a green ball is rolled from an initial position of 2m and travels to a final
position of 10m - what distance does it travel? (just type the number, no
need for units).

Answers

Answer:

10m-2m = 8m

8

Hope this helps!

Two dwarf galaxies revolve in circles around a normal large galaxy. Dwarf Galaxy A is 70,000 light years away from the large galaxy, and Dwarf Galaxy B is 500,000 ly away from the large galaxy. Which of the two galaxies, A or B, takes the longest time to orbit the large galaxy and what law tell us so

Answers

Answer:

B

Explanation:

From Kepler's Third Law, T^2 is proportional to r^3.

Now r of B is larger than r of A,

so T of B is larger than T of A.

Then B takes the longest time.

Dwarf Galaxy B takes the longest time to orbit the large galaxy. This can be explained using Kepler's Third Law of Planetary Motion, also known as the Law of Periods.

Kepler's Third Law states that the square of the orbital period (T) of a celestial body is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit. Mathematically, it can be expressed as:

[tex]\[ T^2 \propto a^3 \][/tex]

Where:

T is the orbital period (time taken for one complete orbit), and

a is the semi-major axis of the elliptical orbit.

In the case of dwarf galaxies A and B revolving around the large galaxy, we can use the distances from the large galaxy to each of the dwarf galaxies as the semi-major axes (a) of their orbits.

Let's compare the values of [tex]\( a^3 \)[/tex] for the two dwarf galaxies:

For Dwarf Galaxy A:

[tex]\( a_{\text{A}} = 70,000 \)[/tex] light years

For Dwarf Galaxy B:

[tex]\( a_{\text{B}} = 500,000 \)[/tex] light years

Now, let's calculate [tex]\( a^3 \)[/tex] for each galaxy:

For Dwarf Galaxy A:

[tex]\( a_{\text{A}}^3 = (70,000)^3 = 343,000,000,000 \)[/tex] cubic light years

For Dwarf Galaxy B:

[tex]\( a_{\text{B}}^3 = (500,000)^3 = 125,000,000,000,000,000 \)[/tex] cubic light years

Since [tex]\( a_{\text{B}}^3 \)[/tex] is significantly larger than [tex]\( a_{\text{A}}^3 \)[/tex], it means that Dwarf Galaxy B has a larger a value and therefore a longer orbital period according to Kepler's Third Law. In other words, Dwarf Galaxy B takes the longest time to orbit the large galaxy.

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Alkali Metals • Most ___________________ metals

Answers

Answer: They’re the most reactive metals

Explanation: They have larger ionic radii and low ionization energies

A 200g ball is accelerated from 5m/s to 25m/s in 0.3sec. What force was applied?​

Answers

Answer:

30N

Explanation:

30N of force was applied

quizlet

what is the kinetic energy of a sky diver with a mass of 60.0 kg falling at a terminal velocity of 40.0 ms?

Answers

Answer:

48,000 J

Explanation:

m = 60.0 kg

v = 40.0 m/s

kinetic energy = mv^2/2 = 60*40^2/2 = 48,000 J

3. A wooden block is at rest on a wooden inclined
plane. As the angle the plane makes with the
horizontal is increased, the magnitude of the
force of static friction between the block and
the plane
(1) decreases
(2) increases
(3) remains the same

Answers

As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

Static frictional force

Since the static frictional force between the block and the plane is given by F = μN where

μ = coefficient of static friction and N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where W = weight of block and θ = angle of inclined plane

Now, F = μN

F = μWcosθ

Since μ and W are constant, we see that

F ∝ cosθ and cosθ ∝ θ

So, F ∝ θ

Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.

So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

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3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the plane of the coil is parallel to the magnetic field as shown in figure below.

a) Calculate the force on each side of the coil.
b) What is the resultant effect of the force on the coil?
c) What happen to the coil?

Answers

It’s B I took the assignment and passed

Explain why friction becomes desirable and undesirable

Answers

Answer:

A friction is very much desirable to stop the body from its moving condition. ... If the friction is more between the block and inclined surface then a large force is required to push the block on the plane.

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

[tex]kai6417[/tex]

Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
meters/second?

Answers

To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.

Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: [tex]\frac{∆v}{t}[/tex]

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 [tex]\frac{feet}{second}[/tex] then sped up to 5 [tex]\frac{feet}{second}[/tex], then the change in my speed would be 2 [tex]\frac{feet}{second}[/tex], because I started walking 2 [tex]\frac{feet}{second}[/tex] faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 [tex]\frac{meters}{second}[/tex] to 16 [tex]\frac{meters}{second}[/tex]  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = [tex]\frac{∆v}{t}[/tex]

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 [tex]\frac{meters}{second}[/tex] by 4 [tex]\frac{meters}{second}[/tex]. That makes sense, right? Back to the equation.

a = [tex]\frac{∆v}{t}[/tex]
a = [tex]\frac{16-4}{4}[/tex]

(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = [tex]\frac{12}{4}[/tex]

a = 3 ([tex]\frac{meters}{second^{2}}[/tex])

We have our answer! The car's acceleration is 3 meters per second^{2}.

(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit [tex]\frac{\frac{meters}{second}}{second}[/tex], which can be simplified down to [tex]\frac{meters}{second^{2} }[/tex])

Let me know if you need clarification on anything I explained here!
- breezyツ

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by
−0.50t, in m/s2 for t in seconds. It stops at t =
A. 64 s
B. 32 s
C. 16 s
D. 8.0s
E. 4.0s​

Answers

A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.

What is velocity?

The change of displacement with respect to time is defined as the velocity.  velocity is a vector quantity.

Given data;

t = 0 ,u=16 m/s

acceleration = −0.50t m/s²

v=0,t=?

The acceleration is found as;

[tex]\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt[/tex]

Intregating both sides we get;

[tex]\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec[/tex]

Hence, the car stops at t=8sec. Option D is correct.

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The lightbulb of a flashlight creates light and heat, both of which are forms of
energy. What is the source of the energy?
A. Elastic potential energy stored in the molecules of the flashlight
B. Chemical potential energy stored in the ions of the battery
C. Kinetic energy of the electrons flowing through the lightbulb
O D. Gravitational potential energy stored in Earth's gravitational field

Answers

Answer:

B

Explanation:

What is the speed of the plane wave defined by sin(ωt−kx) with ω=3376.7 Thz and k=11.79μm−1?

Answers

The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s

Speed of a wave

the speed of the plane wave defined by sin(ωt−kx) is v = ω/k where

ω = angular frequency of wave and k = wave number of wave

Now ω = 3376.7 Thz = 3376.7 × 10¹² Hz and k = 11.79μm⁻¹ = 11.79 × 10⁶ m⁻¹

So, substituting the values of the variables into v, we have

v = ω/k

v = 3376.7 × 10¹² Hz/11.79 × 10⁶ m⁻¹

v = 286.4 × 10⁶ m/s

v = 2.864 × 10⁸ m/s

The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s

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What do you mean by escape speed at a place?​

Answers

In celestial mechanics, escape velocity or escape speed is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a primary body, thus reaching an infinite distance from it.

PLEASE MARK AS BRAINLIEST

how can i plot a graph?​

Answers

Answer:

so you have your boxes go by tens on the x-axis okay which is the one going straight up then the second number goes by 5's is your y-axis. 30,6 so 30 is your x and 6 is your y. start at 0,0 which is the little corner piece. find 30 on x and then go over 6 and that's it!

Explanation:

What is the acceleration of the object?

Answers

30 because v1 - v2 is 30 v1 is 40 v2 is 10

Peak expiratory flow readings are Higher in the morning; lower in the evening Lower when patients are well; higher when patient's airway is constricted Lower in the morning; higher in the evening Higher when patients are well; lower when patient's airway is constricted

Answers

Peak expiratory flow readings are higher when patients are well, but lower when a  patient's airway is constricted.

What is the peak expiratory flow?

This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.

This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.

What does the peak expiratory flow indicate?

This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.

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Why do charged particles interact with each other?(1 point)

because they are small
because they are small

because they are in the same molecule
because they are in the same molecule

because of their electric and magnetic fields
because of their electric and magnetic fields

because they have opposite charges

Answers

Answer:

because they have opposite charges

Explanation:

If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.

Charged particles interact with each other because they have opposite charges.

How charged particles interact with each other?

When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.

So we can conclude that Charged particles interact with each other because they have opposite charges.

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compare your previous result to the present hrf result are there any changes if yes explain your answer​

Answers

Answer:

I don't know what are you saying but I don't have any results

Explanation:

[tex]kai6417[/tex]

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