[tex]\huge \bf༆ Answer ༄[/tex]
First, find the force exerted by the box.
[tex] \sf \: F = ma [/tex]
The required terms are :
m = mass = 20 kga = Acceleration due to gravity = 10 m/s²Calculate the force : -
[tex] \sf \: F = 20 \times 10 [/tex][tex] \sf \: F = 200 \: N[/tex]_____________________________________
Pressure can be calculated using this formula : -
[tex] \sf \: P = \dfrac {F }{A }[/tex]The stated terms are :
P = pressure F = force = 200 NA = Area = 4 m²Calculate the Pressure now : -
[tex] \sf \: P = \dfrac{200}{4} [/tex][tex] \sf \: P = 50 \: pascals[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
Which country is considered to have one of the best ski teams in the world?
Answer:
France
Explanation:
France is the undisputed champion in the world of skiing.
HELP PLZZZZZZ
A 30 g spoon is lifted above a table and has 0.062 J of potential energy. How high is it?
Hi there!
We know that:
U (Potential energy) = mgh
We are given the potential energy, so we can rearrange to solve for h (height):
U/mg = h
g = 9.81 m/s²
m = 30 g ⇒ 0.03 kg
0.062/(0.03 · 9.81) = 0.211 m
An electric heater is rated 300W 110V. The safety fuse in the circuit can withstand 15 A of current. How many heaters can be safely operated in the circuit
The number of heaters that can safely be operated in the circuit is 5 heaters.
From the question given above, the following data were obtained:
Power of heater = 300 W
Voltage (V) = 110 V
Current (I) = 15 A
Number of heaters = ?Next, we shall determine the power that can be drawn from the circuit. This can be obtained as follow:Voltage (V) = 110 V
Current (I) = 15 A
Power (P)= ?P = IV
P = 15 × 110
P = 1650 WThus, the power that can be drawn from the circuit is 1650 W
Finally, we shall determine the number of heaters that can be operated in the circuit. This can be obtained as follow:Power of heater = 300 W
Power of Circuit = 1650 W
Number of heaters = ?[tex]Number \: of \: heaters \: = \frac{power \: of \: circuit}{power \: of \: heater} \\ \\ = \frac{1650}{300} \\ \\ = 5.5[/tex]
From the calculation made above, the number of heaters that can be operated safely in the circuit is 5 heaters.
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If you had a stain on your shoe, what would you do to cover it?
Answer: depends what kind of stain and color shoe.
Explanation:
Answer:
Wash the shoe
Explanation:
If the stain is unwashable, then I'd either get new shoes or paint over them.
A concave mirror has a centre of curvature of 24.0 cm. An object 2.5 cm tall is placed 40.0 cm in front of the mirror.
a) At what distance from the mirror will the image be formed?
b) What is the height of the image?
Answer:
Object distance should be 48
Explanation:
in pic
_____________________________
(hope this helps can I pls have brainlist (crown)☺️)
If Earth's mass doubled, your weight would..
a. increase
b. decrease
c. stay the same
Answer:
a. increase
Explanation:
Doubling the mass of the Earth would double your weight, since gravitational force is directly proportional to mass, but doubling the radius (which doubles if the diameter doubles) would decrease your weight by a factor of 1/4, since gravitational force is inversely proportional to the square of the radius.
how much heat is needed to warm .052kg of gold from 24 degrees celsius to 120 degreees celsius
Explanation:
i need answers to this problem
a person with a mass of 15 kg is walking downhill at a velocity of 10 ms what is the Walkers momentum
Answer:
[tex]150 kg\cdot m/s[/tex]
Explanation:
Same as if he was walking uphill, or horizontally. Momentum is defined as the product of mass times velocity. [tex]p = mv = 15\cdot 10 = 150 kg\cdot m/s[/tex]
11. A box with a mass of 1.0 kg is resting on a horizontal surface and the coefficient of friction between the block and the surface is 0.20. It is accelerated by attaching a 1.5 kg mass, as shown in the diagram. Assume that the pulley is frictionless and that the cord has negligible mass.
a. What is the acceleration of the box? What is the tension?
Answer:
We know that the force pulling the box in the positive x direction has a magnitude of m g sin 30 . Using Newtons Second Law, F = ma , we just need to solve for a :
ma=mgsin30
a=gsin30
=(10m/s2)(0.500)
=5m/s2
Answer:
A force is applied acting to the right. Assume that friction is negligible. Ikg 0.5N. For each question, one or more features of the system.
Explanation:hope this helps
which acts as a transverse wave with particle motion perpendicular to wave motion?
Answer:
transverse wave, motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.
Two illustrations labeled A and B. In Illustration A a hand is pushing on a mass labeled m that is connected to a spring and the spring is connected to a wall. In illustration B the spring is back to its normal length and the mass is moving away from the end of the spring at a velocity v. The position where the block started from is labeled x = 0. A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes conservation of energy in position A?
Answer:
The answer is (C) E= 1/2 kx^2
Explanation:
Answer:
ITS C JUST FINISH
Explanation:
A black disk rotates with constant speed and a coin that is located on the edge of the disk moves with speed v. If on a white disk that also rotates with constant speed, we place the same coin on the edge, it is moving with speed 4v. Which disk has a larger radius?
The white disk has a larger radius.
We know that the speed of the coin v = rω where r = radius of the disk and ω = angular speed of the disk.
Now, since both disks rotate at constant speed, ω = constant.
So, v ∝ r
For the black disk, its radius is r, the coins speed is v.
For the white disk, let its radius be R, the coins rotates at a speed V = 4v
We know that v ∝ r.
Since the coin on the white disk has a greater speed, so its radius would be greater.
So, the white disk has a larger radius.
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10. Which of the following will happen to the respiratory-associated muscles if you were to blow up a balloon?
A. Diaphragm contracts, Internal intercostal would relax
B. Diaphragm would contract, external intercostal would relax
C. Internal intercostal and abdominal muscles would contract
D. External intercostal would contract and diaphragm would relax
Answer:
C
for sure
go for it
..............
251mL=25100L
True or false and why or why not?
Answer:
False
Explanation:
To find how many liters 251mL is you would need to divide 251 by 100 which is 0.251.
If you took a balloon of gas and then warmed the balloon in a sunny window, what can now be said about the density of the gas in the balloon
Explanation:
The density of the gas in the balloon will explode
Find the gravitational potential energy of a body of mass 25kg,kept at a height of 4m If g=10m/s'.
Answer:
Explanation:E=mgh=25×4×10=1000J
difference between 1 hectoliter and one kiloliter
Answer: 100 and 1000
Explanation:
The weight of a cart with a mass of 150 kg is ___ N. (Use 9.8
m/s2 for the acceleration due to gravity.)
Answer:
1470 N
Explanation:
Weight = m*g
So 150 kg * 9.8 m/s^2 = 1470 N
What role does physical health play into nutrition?
The maximum allowable potential difference across a 250 mH inductor is 360 V . You need to raise the current through the inductor from 1.5 A to 2.5 A . What is the minimum time you should allow for changing the current?
This question involves the concepts of potential difference, inductance, and current.
The minimum time that should be allowed for the current to change is "0.694 ms".
The inductance of an inductor is given by the following formula:
[tex]E=L\frac{\Delta I}{\Delta t}\\[/tex]
where,
E = potential difference across the inductor = 360 volts
L = inductance of the inductor = 250 mH = 0.25 H
ΔI = change in current = 2.5 A - 1.5 A = 1 A
Δt = time required = ?
Therefore,
[tex]\Delta t = \frac{(0.25\ H)(1\ A)}{360\ volts}[/tex]
Δt = 6.94 x 10⁻⁴ s = 0.694 ms
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a ball is thrown with a speed of 100 m/s at a height of 150 m take g equals 9.8 m per second calculate the time of flight,angle of projection,range pls help I don't know how to solve it
Hi there!
Since the ball is thrown with an initial HORIZONTAL velocity, we can treat this as a free-fall situation since the horizontal motion does NOT impact the ball's vertical motion.
We can use the derived kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}}[/tex]
Plug in the given values:
[tex]t = \sqrt{\frac{2(150)}{9.8}} = \large\boxed{5.53 s}}[/tex]
The angle of projection is 0° because there is no vertical component to the velocity as the initial velocity is purely horizontal.
Range:
We can use the equation:
dₓ = vₓt
displacement (x direction) = velocity (x direction) · time
Used the solved-for time and given velocity:
dₓ = 100 · 5.53 = 553 m
Determine the kinetic energy of a 1500 kg roller coaster car that is moving with a speed of 35.0 m/s.
Answer:
kinetic energy equation is 85,714.2857 kg.
Explanation:
What net force would be necessary to cause a block of wood with a mass of 2.5 kg to accelerate at a rate of 3.0 m/s2
Answer:
7.5 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 2.5 kg
acceleration = 3.0 m/s²
We have
force = 2.5 × 3.0 = 7.5
We have the final answer as
7.5 NHope this helps you
what is the average speed of the toy car during the two trials to the nearest tenth of m/s
wait nvm the answer is D
Answer:
what is the average speed of the toy car during the two trials to the nearest tenth of m/s
wait nvm the answer is B
Explanation:
CARRY ON LEARNING
What happens to the volume of a fixed amount of gas if both the pressure and the absolute temperature are doubled
Answer: no change in volume
Explanation:
Use the graph of velocity versus time for an object to answer the question.
Which statement fairly compares segment 2 and segment 3?
(1 point)
O These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
These represent different periods of time, but the force acting on the object is the same during each period of time.
O These represent different periods of time, and the force during segment 2 is different than the force during segment 3.
O These represent equal periods of time, and the force acting on the object is the same during each period of time.
The statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Since segment 2 starts at t = 60 s and ends at t = 150 s, the time interval is Δt = 150 - 60 = 90 s.
Also, segment 3 starts at t = 150 s and ends at t = 240 s, the time interval is Δt = 240 - 150 = 90 s.
So, their time periods are the equal.
We notice that segment 2 is less steep than segment 3 this implies that the acceleration in each segment is different, since the acceleration is the slope of the graph.
Since force is determined by acceleration, this implies that the force on segment 2 is different form the force acting in segment 3.
So, we have equal time periods but different forces.
So, the statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Learn more about velocity-time graph here:
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Answer:
Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3 !! :)
Explanation:
why the max Static frictional force is a Little bit bigger than the sliding frictional force
v=VyV67.2 -8.2 m/s
Part B
Now let's see if your prediction agrees with the experimental results. There isn't any data at y=-3.5 m, so you'll need to interpolate by zooming in
on the relationship between y velocity (W) and y displacement. You'll use Tracker's Data tool to help with this analysis. Follow these steps:
• Change the vy versus t graph to a vy versus y graph. (Click the t label on the horizontal axis and select y. position y-component from the
menu.)
• It's a little hard to see what's going on with this graph at y = -3.5, so zoom in. Double-click on the graph to open it up in the Data tool.
. Put your cursor on the point where the graph line intersects y = -3.5. Click and hold to read the vy at that point shown in a yellow box in the
bottom left comer).
What's the interpolated graph value of v, at y = -3.57 Comment on how well this value agrees with the value of v, that you calculated in part A of
this activity. Make a hypothesis about any notable difference.
Answer:
-3.5
Explanation:
b/c the distance is moving in to two A And B A +B or S1 +S2 that is it
Answer:
The interpolated velocity value from the graph is -8.1 meters/second. The calculated value based on the average acceleration is -8.2 meters/second. This is very good agreement.
Explanation:
Which ONE of the following pairs of physical quantities consists of one scalar and one vector quantity?
A. Distance and speed
B.Speed and acceleration C.Displacement and velocity
D. Velocity and acceleration.
Answer:
speed and acceleration
Explanation:
speed is a scalar quantity
acceleration is a vector quantity
Sachi wants to throw a water balloon to knock over a target and win a prize. The target will only fall over if it is hit with a force of 0. 035 N. The water balloon has a mass of 11. 4 grams. How fast will Sachi have to make the water balloon accelerate to hit the target with enough force and win the prize? Round the answer to the nearest one tenth m/s2. The water balloon must accelerate m/s2.
Hi there!
We can use the following equation (Newton's Second Law):
∑F = ma
m = mass of object (kg)
a = acceleration (m/s²)
We can rearrange to solve for 'a':
F/m = a
Remember to convert grams to kg.
1000g = 1 kg
0.035/(0.0114) = 3.07 m/s²