A block with a mass of 55 kg is pulled with a force of 220 N. Assuming a frictionless surface, what will be the acceleration of the block?
OA
0.25 m/s2
о
B
4.0 m/s2
O.
9.8 m/s2
Oo. 22 m/s2
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Answer:

– 2.5 m/s²

Explanation:

We have,

• Initial velocity, u = 180 km/h = 50 m/s

• Final velocity, v = 0 m/s (it stops)

• Time taken, t = 20 seconds

We have to find acceleration, a.

[tex]\longrightarrow[/tex] a = (v ― u)/t

[tex]\longrightarrow[/tex] a = (0 – 50)/20 m/s²

[tex]\longrightarrow[/tex] a = –50/20 m/s²

[tex]\longrightarrow[/tex] a = – 5/2 m/s²

[tex]\longrightarrow[/tex] a = – 2.5 m/s² (Velocity is decreasing) [Answer]

Answer:Korotkoff Sounds. -tapping sounds created by turbulent blood flow in arm. -pressure is slowly being released from cuff, so systolic pressure is above that of the cuff, but diastolic is still below, so the artery opens in systole and collapses in diastole.

Explanation:

Answer:

They are provided with keen senses of sight, smell and hearing.

Answer:

Terrestrial animals

Answer:

200 (m) for 20 seconds

10 times 20 is 200

Answer:

200

Explanation:

Jill is running at 10 meters per second

20 * 10 = 200

Answer:

Explanation: all of them have made sentence structure (grammar point view) and from the physical aspect.

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is [tex]1.50 \times 10^{11}\;\rm m[/tex].

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

[tex]T^2 \propto R^3[/tex]

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

[tex]T^2 \propto R^3[/tex]

[tex]T^2 = kR^3[/tex]

Substituting the values, we get the value of constant k for mars.

[tex]687^2 = k\times (2.279 \times 10^{11})^3[/tex]

[tex]k = 3.92 \times 10^{-29}[/tex]

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

[tex]365^3 = 3.92\times 10^{-29} R^3[/tex]

[tex]R^3 = 3.39 \times 10^{33}[/tex]

[tex]R= 1.50 \times 10^{11}\;\rm m[/tex]

Hence we can conclude that the distance of the earth from the sun is [tex]1.50 \times 10^{11}\;\rm m[/tex].

To know more about Kepler's third law, follow the link given below.

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Apply Newton's second law

[tex]\\ \tt\hookrightarrow F=ma[/tex]

[tex]\\ \tt\hookrightarrow F=1167(4)=4668N[/tex]

Now

[tex]\\ \tt\hookrightarrow W=Fd[/tex]

[tex]\\ \tt\hookrightarrow d=\dfrac{W}{F}[/tex]

[tex]\\ \tt\hookrightarrow d=\dfrac{105}{4668}[/tex]

[tex]\\ \tt\hookrightarrow d=0.022m[/tex]

Now

According to third equation of kinematics

[tex]\\ \tt\hookrightarrow v^2=u^2+2as[/tex]

[tex]\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)[/tex]

[tex]\\ \tt\hookrightarrow v^2=100+8(0.022)[/tex]

[tex]\\ \tt\hookrightarrow v^2=100+0.176[/tex]

[tex]\\ \tt\hookrightarrow v^2=100.176[/tex]

[tex]\\ \tt\hookrightarrow v=10.001m/s[/tex]

During a lightning storm, the bottom of a cloud gains a strong negative electric charge. If you were to measure the charge at the top of a tall metal pole directly under the cloud, what would you expect to observe? The top of the pole would have no charge. The top of the pole would have a positive charge.

In the given scenario, the positive charges within the pole concentrate at the top of the pole to be near the negatively charged cloud bottom.

A thunderstorm, also widely recognized as an electrical storm or even a lightning storm, is a type of storm that is distinguished by the presence of lightning and its acoustic effect on the Earth's atmosphere, which is known as thunder.

Thundershowers are thunderstorms that are relatively weak. Warm air rises and cools, condensing into small droplets of water.

If the air is sufficiently unstable, the updraft of warm air is rapid, and the water vapor forms a cumulonimbus cloud quickly. These cumulonimbus clouds typically form in less than an hour.

In the given scenario, the positive charges within the pole concentrate near the negatively charged cloud bottom at the pole's top.

Thus, this is the observation that can be expected.

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Distance is the measure of the length of ground covered by an object during its motion. Distance is a scalar quantity. The car will travel 69 m while accelerating.

Distance is the measure of the length of ground covered by an object during its motion. While the displacement is defined as the shortest distance between the two paths.

Distance is a scalar quantity. While displacement is a vector quantity. Mathematically it is given as the product of speed and time.

The following data are given in the problem as

u is the initial  speed=5.0 m/sec

v is the final speed=21 m/sec

s is the distance covered by the car =?

a= Acceleration of car =3.0 m/sec²

According to Newton's third equation of motion, the formula derived will be

[tex]\rm{v^2=u^2+2as \\\\[/tex]

[tex]\rm s = \frac{v^2-u^2}{2a} \\\\\rm s = \frac{(21)^2-(5)^2}{2\times3.0} \\\\ \rm s=69 m[/tex]

Hence the car will travel 69 m while accelerating.

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Answer:

its position relative to some zero position

Explanation:

your welcome

Velocity is simply defined as the rate of change of displacement per unit time. Mathematically, it can be expressed as

Velocity = displacement / time

For example: A car travels 400 m due north in 40 s. What is the velocity of the car.

From the question given above, we can obtain the velocity as follow:

Velocity = displacement / time

Velocity = 400 / 40

Velocity = 10 m/s

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Answer: 15 kg*m/s

Explanation:

Momentum = mass*velocity

Momentum = 3kg*5 m/s

Momentum = 15 kg*m/s

Answer:

15 kg m/s

Explanation:

Momentum = mass xvelocity

Momentum = 3kgx 5 m/s

Momentum = 15 kg m/s

Answer:

I think its 25.51 m!!

Explanation:

WHAT? I DON'T UNDERSTAND WHAT ARE YOU SAYING

The force required to keep the beam in equilibrium is 90 N.

It states that for a system at equilibrium, the sum of the clock-wise moment is equal to the sum of anti clock wise moment.

To calculate the magnitude of the force required to keep the beam at equilibrium, we use the Formula below.

Formula:

Where

Make f the subject of the equation

From the question,

Given:

Substitute the given values into equation 2

Hence, The force required to keep the beam in equilibrium is 90 N.

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Answer:

12.5 hz

Explanation:

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge= 7.5 ×10⁻²

v = velocity of charge=2.5 ×10⁴

q = charge=?

B= 8.1 ×10⁻²

F=qvBsinα

[tex]\rm{q= \frac{F}{vBsina}}[/tex]

[tex]\rm{q= \frac{7.5\times 10^-2}{2.4\times 10^-2 \times 8.1\times 10^-2 sin25^0}}[/tex]

q = [tex]8.8 \times 10^ {-5}\rm C[/tex]

Hence the value of the charge will be [tex]8.8 \times 10^ {-5}\rm C[/tex].

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Movement occurs on the compass when there is magnetic field in the surrounding environment.

The movement of the needle appears which represents the presence of magnetic field. The moving compass around confirm that there magnetic field present in that region because the magnetic field is detected by the compass.

A magnetic field is invisible force which can be detected by a compass. A compass contains a small bar magnet which can rotate when it experience magnetic field around it so we can conclude that movement occurs on the compass when there is magnetic field in the surrounding environment.

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Answer:

Simple as 50 km/h

Explanation:

Since the average being measured is of the hours and not distance, it is simply (60+40)/(2+2)

Explanation:

he fell down with telling any one,

Air resistance is negligible

Apply third equation of kinematics

[tex]\\ \tt\longmapsto v^2=u^2+2gs[/tex]

[tex]\\ \tt\longmapsto v^2=2(10)381[/tex]

[tex]\\ \tt\longmapsto v^2=7620[/tex]

[tex]\\ \tt\longmapsto v=87.29ms^{-1}[/tex]

Answer:

According to the Given Statement

Penny is dropped from rest of the 102nd floor which is 381 metres above from the ground.

we 'll take here the acceleration due to gravity (g ) is 9.8m/s²

Its initial velocity u be 0 m/s ( as it is at rest)

Using Kinematic Equation

here h is the height of 102nd floor

➥ v² = 0² + 2 × 9.8 × 381

➥ v² = 0 + 19.6 × 381

➥ v² = 7467.6

➥ v = √7467.6

➥ v = 86.41 m/s

So, 86.41 m/s penny would be fall.

Answer:

Explanation:

Power = work / time

P = 400 J / 5 s

P = 80 watts

Answer:

yes it do rises and then fall down due to gravitational

Answer:

that is the answer

Explanation:

look at it

Answer:

any two difference between negative and positive charge

➢The matter is positively charged if it contains more protons than electrons, and it is negatively charged if it contains more electrons than protons.

Explanation:

I hope it will help you.....

[tex]kai6417[/tex]

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The kinetic energy of the circular disc in initial state is,

[tex]K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]

The initial kinetic energy of the other disc dropped on the first disc is,

[tex]K^{2r} = \frac{1}{2}I^{b}(0)^{2}[/tex]

[tex] = > K^{2r} = 0J[/tex]

As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,

[tex]E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }[/tex]

The net kinetic energy in the initial state is,

[tex]E^{i} = K^{1r} + K^{2r}[/tex]

[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0[/tex]

[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }[/tex]

Thus, the change in the kinetic energy during the change of state is,

[tex]dE = E^{f} - E^{i}[/tex]

[tex] = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]

[tex] = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]

This change in value of energy is the energy lost initially rotating the disk to friction.

Hence, the energy lost in the given case is [tex]dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]

The energy lost initially by the rotating disk to friction is equal to [tex]\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]

Given the following data:

At the initial state, the kinetic energy of the circular disc is given by this formula:

[tex]K.E = \frac{1}{2} I_t\omega_i^2[/tex]

For the second disc, the initial kinetic energy is given by this formula:

[tex]K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0[/tex]

At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:

[tex]E_f = \frac{1}{2} (I_t + I_b)\omega_f^2[/tex]

For the energy lost:

Also, the change in the kinetic energy is given by this formula:

[tex]\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]

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Answer:

The answer is probably A

Answer:

Because Rod protect house from burning down and people from electrocution.