A block slides down an inclined plane from rest. Initially the block is at 4.5m above the ground. Find the speed of the block when it is 1.5m above the ground. 1) 7.7m/s 2) 9.4m/s 3) 5.4m/s 4) 3.2m/s

Answer:

[tex]v=d\sqrt{\frac{k}{m}} [/tex]

Explanation:

In order to solve this problem, we can do an analysis of the energies involved in the system. Basically the addition of the initial potential energy of the spring and the kinetic energy of the mass should be the same as the addition of the final potential energy of the spring and the kinetic energy of the block. So we get the following equation:

[tex]U_{0}+K_{0}=U_{f}+K_{f}[/tex]

In this case, since the block is moving from rest, the initial kinetic energy is zero. When the block loses contact with the spring, the final potential energy of the spring will be zero, so the equation simplifies to:

[tex]U_{0}=K_{f}[/tex]

The initial potential energy of the spring is given by the equation:

[tex]U_{0}=\frac{1}{2}kd^{2}[/tex]

the Kinetic energy of the block is then given by the equation:

[tex]K_{f}=\frac{1}{2}mv_{f}^{2} [/tex]

so we can now set them both equal to each other, so we get:

[tex]=\frac{1}{2}kd^{2}=\frac{1}{2}mv_{f}^{2}[/tex]

This new equation can be simplified if we multiplied both sides of the equation by a 2, so we get:

[tex]kd^{2}=mv_{f}^{2}[/tex]

so now we can solve this for the final velocity, so we get:

[tex]v=d\sqrt{\frac{k}{m}} [/tex]

Answer:

becomes wider

Explanation:

From;   asin θ= m λ

It was said in the question that in this particular instance  blue light is replaced by red light. The wavelength of blue light is less than that of red light, it then follows that the central bright maximum in this pattern widens when red light is used.

Therefore the diffraction pattern becomes wider.

Answer:

v = 12.8 m/s

Explanation:

       [tex]p_{ox} = p_{fx} (1)[/tex]

       [tex]p_{oy} = p_{fy} (2)[/tex]

       [tex]p_{oy} = m_{t} * v_{ot} = 3520 kg* v_{ot} (3)[/tex]

       [tex]p_{fy} = m_{f} * v_{fy} = 5000 kg* 9.8 m/s * sin 66.9 = 45080 kg*m/s (4)[/tex]

       [tex]v_{ot} =\frac{45080kg*m/s}{3520kg} = 12.8 m/s (5)[/tex]

Answer:

310 m

Explanation:

120+150+40=310

Answer:

3.8961038961038

Explanation:

6000/1540=3.8961038961038

X= v/t

Answer:

A vibration is a repeated back-and-forth or up-and-down motion.

Explanation:

Waves carry energy through empty space or through a medium without transporting matter.

Answer:

16 m/s

Explanation:

Given that

y momentum = 0.080 *25 = 2

x momentum = 0.075*20 = 1.5

total momentum = √(4 + 2.25)

Total momentum = √6.25

Total momentum = 2.5

total mass = mass of x and y momentum = 0.075 + 0.080 = 0.155

speed of mass center = total momentum / total mass = 2.5/0.155 = 16.

And thus, the speed of the center of mass of this two-particle system at this instant is 16 m/s

Answer:

less than stating velocity due to friction and air resistance.

Explanation:

Answer:

1m/s

Explanation:

Speed of a wave is expressed as;

Speed = frequency × wavelength

Given

Frequency = 2Hz

Wavelength = 0.5m

Required

Speed of the wave

Substitute

Speed = 2×0.5m

Speed = 1.0m/s

Hence the speed is 1.0m/s

Answer:

2:5

Explanation:

We have the initial mass of the fish = 4.5kg

The mass of water intake = 40%of 4.5kg

= 0.40x4.5kg

= 1.8kg

The formula for conserving momentum

M1V1 = M2V2

M1 = mass of the puffer fish = 4.5kg

M2 = mass of the applied water = 1.8kg

V1 = velocity of the puffer fish

V2 = velocity of water

We are then to find v1/v2

V1/V2 = M2/M1

V1/V2 = 1.8/4.5

= 1/2.5

This is also 2/5

Therefore we have the ratio to be 2:5

Answer:

Q = PV(In 4)

Explanation:

We are told that the volume expands from V to a state with volume 4V.

Thus, initial volume is V and Final volume is 4V.

We want to find How much heat is added to the expanding gas.

For an isothermal process, the work done is calculated from;

W = nRT(In(V_f/V_i))

Where;

V_f is final volume

V_i is initial volume

Thus;

W = nRT(In(4V/V))

W = nRT(In 4)

Now, from ideal gas equation, we know that;

PV = nRT

Thus;

W = PV(In 4)

Now from first law of thermodynamics, we know that internal energy is zero and thus; Q = W

Where Q is quantity of heat

Thus;

Q = PV(In 4)

Answer:

D. Height of the ramp.

Explanation:

The solid spherical ball is expected to have more mass than that of the hollow spherical ball. And the speed of both balls would be influenced by the gravitational force as they roll down the ramp. Thus, the masses would move at different speed.

At the bottom of the ramp, the speed of the balls can be varied by varying the height of the ramp. So that the speed of both balls depend on the height of the ramp. As the height of the ramp increases, consequently, the speed of the balls increases. And if the height of the ramp decreases, the speed of the balls decreases consequently.

Answer:

10m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 100m/s

Time taken  = 10s

Unknown:

Acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

  A = [tex]\frac{v - u}{t}[/tex]

v = final velocity

u = initial velocity

t = time taken

 So, insert the parameters and solve;

  A = [tex]\frac{100 - 0}{10}[/tex]   = 10m/s²

Answer:

Hypothesis

Explanation:

Answer:

Jerusalem

Explanation:

because now a days jerusalem is the royal capital of the kingdom of israel so i conclude that the answer is jerusalem

Answer:

5 million miles

Explanation:

Answer:

option 3

Explanation:

can i get brainliest

Answer:

133.333 s

Explanation:

From the question given above, the following data were obtained:

Displacement = 400 m North

Velocity (v) = 3 m/s

Time (t) =?

Thus, we can obtain the time taken for the man to complete his trip as shown below:

Velocity = Displacement /Time

3 = 400/time

Cross multiply

3 × time = 400

Divide both side by 3

Time = 400/3

Time = 133.333 s

Therefore, it will take the man 133.333 s to complete his trip.

Answer:

Explanation:

Given the length and width in inches

Length = 8.5in

Width = 11in

b) Convert to centimeters

1in = 2.54cm

8.5in = x

Cross multiply

x = 8.5 × 2.54

x = 21.59cm

Hence the width in cm is 21.59cm

a) 11in = y

1in = 2.54cm

Cross multiply

x = 11 × 2.54

x = 27.94cm

Hence the length in cm is 27.94cm

Answer:

D

Explanation:

Took the test :)

Answer:

1.066 m/s^2

Explanation:

On the earth and on Mars respectively, the time periods of the pendulums are expressed as:

Tearth = 2pi * sqrt(L/gearth)

Tmars = 2pi * sqrt(L/gMars)

Divide the two equations above:

Tearth/Tmars = sqrt(gMars/gearth)

gMars = gearth(Tearth/Tmars)^2 = (9.80m/s^2)(1.26s/3.82s)^2 = 1.066 m/s^2

Answer:

"2941.96 J" is the appropriate answer.

Explanation:

The given values are:

Mass,

m = 79 kg

Height,

h = 10.5 m

Now,

The total energy at the given height will be,

⇒ Potential energy = mgh

On substituting the values, we get

                                = [tex]79\times 9.8\times 10.5[/tex]

                                [tex]=8129.1 \ J[/tex]

So,

⇒ At height 6.7 m, total energy =  At height 10.5 m, total energy

On substituting the values, we get

⇒ [tex]Potential \ energy+Kinetic \ energy=8129.1[/tex]      

⇒       [tex]79\times 9.8\times 6.7+Kinetic \ energy=8129.1[/tex]

⇒                [tex]5187.14+Kinetic \ energy=8129.1[/tex]

⇒                                   [tex]K.E=8129.1-5187.14[/tex]

⇒                                   [tex]K.E=2941.96 \ J[/tex]

Explanation:

A-It starts to expand. Hence ice and water of same weight has different volumes

Expansion happens to a given mass of water as it is cooled from 4°C to zero. Option A is correct.

Temperature directs to the hotness or coldness of a body. In straightforward terms,

it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

Water loses density when it is cooled from 4°C to 0°C. It turns out that the temperature at which liquid water has the most significant density is 4 degrees Celsius.

It will increase in size when heated or cooled. Since most liquids shrink when they are chilled, it is rare for water to expand when cooled to lower temperatures.

As a mass of water is cooled from 4°C to zero, expansion occurs.

Hence, option A is correct.

To learn more about the temperature refer to the link;

https://brainly.com/question/7510619

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Answer:

The height above the top of the window is 1.44 m

Explanation:

Given;

time of motion, t = 0.32 s

height traveled at the given time, h = 2.2m

determine the initial velocity of the stone;

h = ut + ¹/₂gt²

2.2 = u(0.32) + ¹/₂ x 9.8 x 0.32²

2.2 = 0.32u + 0.502

0.32u = 2.2 - 0.502

0.32u = 1.698

u = 1.698 / 0.32

u = 5.31 m/s

This initial velocity on top of the window becomes the final velocity from the height above the window.

v² = u² + 2gh

where;

u is the initial velocity of the stone from the height above the window;

5.31² = 0 + (2 x 9.8)h

19.6h = 28.196

h = 28.196/19.6

h = 1.44 m

Therefore, the height above the top of the window is 1.44 m

Answer:

Explanation:

Step one:

given data

density of water= 1000kg/m^3

the dimension of the barge

width= 10m

length= 60m

depth of the boat in the water= 1.2m

Hence the volume occupied by the boat is

volume=10*60*1.2

volume= 720m^2

Step two:

Required is the weight of the barge

we can first find the mass using the relation

density = mass/volume

mass= density*volume

mass= 1000*720

mass= 720000kg

Step three:

Weight =mg

g=9.81m/s^2

W=720000*9.81

W=7063200N

divided by 10^6

W=7.06MN

W=7.1MN approx.

Answer:

414.9 m

Explanation:

First, become familiar with the horizontal, and vertical vector components.

Vertical vector: Vy = V × sin (θ).

Horizontal vector: Vx = V × cos(θ).

Distance traveled = Velocity vector × time in the air.

Time in the air given Vy = 2 × Vy / g (in respect to the metric of the vector).

Range of the projectile = Vx² / g

Time in the air given Vx = (Vx + √(Vx)² + 2gh) / g.

Given a 28° angle with an initial velocity of 70m/s, we have enough information to calculate!

Vx = 70 m/s × cos(28°) ≈ 61.806 m/s

Vy = 70 m/s × sin(28°) ≈ 32.863 m/s

t = 2 × Vy / g

t = 2 × ≈32.863 / 9.8

t = ≈65.726 / 9.8

t ≈ 6.7 s

Distance traveled (horizontal) = Vx × t = 61.806 × 6.7 ≈ 414.9 m

Answer:

describe, explain, predict, and change/control behavior.

Explanation:

describe: What are they doing? -Pavlov noticed that dogs were salivating when they would see his lab assistant before food was presented to them. This observation acted as a description of what was happening to them.

explain: Why are they doing that?- Pavlov started to look into why they were doing it. There was a stimulus, the assistant giving them food in the past to where they started to salivate at the sight of the lab assistant

predict: What would happen if I responded in this way?- Pavlov predicted that he could get the same reaction if he used a bell as a stimulus. Using this he was able to condition dogs to salivate at the ring of the bell.

change/control: What can I do to get them to stop doing that? Because of this discovery we can use conditioning today. For example, in the classroom teachers can use conditioning with their students to make it easier, parents to teach their children right from wrong and to have good behavior. (you do this bad thing you get time out, do a good thing and I will praise you, etc) It can be used when training employees and many other places.

Answer:

The net work done by friction on the body of the snake is 333.35J

Explanation:

Work done is given by

W = F × s

Where W is the Work done

F is the force

and s is the distance covered

Since we are to determine the work done by friction, then we will determine the frictional force. The frictional force is given by

f = μN = μw

Where μ is the coefficient of friction

N is the normal reaction

and w is the weight

But, F = f

∴ W = μws

From the question

μ = 0.25

w = 54.0 N

Now, we will determine s

From the question,

We are to determine the work done by friction on the body of a snake slithering in a complete circle of 3.93 m radius.

The distance s here is given by the circumference of the circle. Circumference of a circle is given by 2πr

∴ s = 2πr

s = 2 × π × 3.93

s = 7.86π m

Hence,

W = 0.25 × 54.0 × 7.86π

W = 333.35 J

Hence, the net work done by friction on the body of the snake is 333.35J.

The net work done by friction on the body of the snake is :

-333.35J

Formulas:

Work done (W) = F × s

F = force

s = distance covered

f = μN = μw

μ = coefficient of friction

N = normal reaction

w = weight

Solution:

F = f

Weight is :

W = μws

μ = 0.25

w = 54.0 N

Distance covered:

s = 2πr

s = 2 × π × 3.93

s = 7.86π m

Therefore,

W = 0.25 × 54.0 × 7.86π

W = 333.35 J

The net work done by friction on the body of the snake is 333.35J.

Learn more about "Friction":

https://brainly.com/question/13357196?referrer=searchResults

Answer:

60.185 percent of the original kinetic energy is convertible to internal energy.

Explanation:

Let suppose that collision between both particles is entirely inellastic. If there is no external forces exerted on any of the particles, then we can apply the Principle of Linear Momentum Conservation. That is:

[tex]m_{A}\cdot v_{A,o} + m_{B}\cdot v_{B,o} = (m_{A}+m_{B})\cdot v[/tex]

[tex]v = \frac{m_{A}\cdot v_{A,o}+v_{B}\cdot v_{B,o}}{m_{A}+m_{B}}[/tex] (1)

Where:

[tex]m_{A}[/tex] - Mass of the 4.8-g particle, measured in kilograms.

[tex]m_{B}[/tex] - Mass of the 7.4-g particle, measured in kilograms.

[tex]v_{A,o}[/tex] - Initial speed of the 4.8-g particle, measured in meters per second.

[tex]v_{B,o}[/tex] - Initial speed of the 7.4-g particle, measured in meters per second.

[tex]v[/tex] - Final speed of the collided particles, measured in meters per second.

If we know that [tex]m_{A} = 4.8\times 10^{-3}\,kg[/tex], [tex]m_{B} = 7.4\times 10^{-3}\,kg[/tex], [tex]v_{A,o} = 3\,\frac{m}{s}[/tex] and [tex]v_{B,o} = 0\,\frac{m}{s}[/tex], then the final speed of the system is:

[tex]v = \frac{(4.8\times 10^{-3}\,kg)\cdot \left(3\,\frac{m}{s} \right)+(7.4\times 10^{-3}\,kg)\cdot \left(0\,\frac{m}{s} \right)}{4.8\times 10^{-3}\,kg+7.4\times 10^{-3}\,kg}[/tex]

[tex]v = 1.180\,\frac{m}{s}[/tex]

During the collision part of the initial energy is dissipated in the form of heat, which is related to the internal energy ([tex]\Delta U[/tex]), measured in joules. According to the Principle of Energy Conservation, we have the following model:

[tex]\Delta U = K_{A}+K_{B}-K[/tex] (2)

Where:

[tex]K_{A}[/tex], [tex]K_{B}[/tex] - Initial translational kinetic energies of each particle, measured in joules.

[tex]K[/tex] - Final translational kinetic energy of the collided particles, measured in joules.

By applying the definition of translational kinetic energy, we expand and simplify the equation above:

[tex]\Delta U = \frac{1}{2}\cdot m_{A}\cdot v_{A,o}^{2}+\frac{1}{2}\cdot m_{B}\cdot v_{B,o}^{2} -\frac{1}{2}\cdot (m_{A}+m_{B})\cdot v^{2}[/tex] (3)

If we get that  [tex]m_{A} = 4.8\times 10^{-3}\,kg[/tex], [tex]m_{B} = 7.4\times 10^{-3}\,kg[/tex], [tex]v_{A,o} = 3\,\frac{m}{s}[/tex], [tex]v_{B,o} = 0\,\frac{m}{s}[/tex] and [tex]v = 1.180\,\frac{m}{s}[/tex], the internal energy associated with the system is:

[tex]\Delta U = \frac{1}{2}\cdot (4.8\times 10^{-3}\,kg)\cdot \left(3\,\frac{m}{s} \right)^{2}+ \frac{1}{2}\cdot (7.4\times 10^{-3}\,kg)\cdot \left(0\,\frac{m}{s} \right)^{2}-\frac{1}{2}\cdot (4.8\times 10^{-3}\,kg+7.4\times 10^{-3}\,kg)\cdot \left(1.180\,\frac{m}{s} \right)^{2}[/tex]

[tex]\Delta U = 0.013\,J[/tex]

And the initial energy of both particles is:

[tex]E_{o} = \frac{1}{2}\cdot (4.8\times 10^{-3}\,kg)\cdot \left(3\,\frac{m}{s}\right)^{2}+\frac{1}{2}\cdot (7.4\times 10^{-3}\,kg)\cdot \left(0\,\frac{m}{s} \right)^{2}[/tex]

[tex]E_{o} = 0.0216\,J[/tex]

Lastly, the percentage of the original kinetic energy that is convertible to internal energy is: ([tex]\Delta U = 0.013\,J[/tex], [tex]E_{o} = 0.0216\,J[/tex])

[tex]\%e = \frac{\Delta U}{E_{o}}\times 100\,\%[/tex] (4)

[tex]\%e = \frac{0.013\,J}{0.0216\,J}\times 100\,\%[/tex]

[tex]\%e = 60.185\,\%[/tex]

60.185 percent of the original kinetic energy is convertible to internal energy.

Explanation:

m = 4kg

u = 20m/s

t = 10s

v = 60m/s

initial momentum = mass × initial velocity

= 4 × 20 = 80kgm/s