(a) The time taken for the ball to reach the height of the fence is 4.1 s.
(b) The position of the ball from the batter at the time is 111.33 m.
(c) Henry will have a home run.
Time to reach the height of the fence
The time taken for the ball to reach the height of the fence is calculated as follows;
[tex]h = v_0_y t - \frac{1}{2} gt^2\\\\(3 - 1.2) = (34 \times sin37)t - \frac{1}{2} (9.8)t^2\\\\1.8 = 20.46t- 4.9t^2\\\\4.9t^2 - 20.46t+ 1.8 = 0\\\\a = 4.9, \ b = -20.46, \ c = 1.8\\\\t = \frac{-b\pm \sqrt{b^2 - 4ac} }{2a} \\\\t = 4.1 \ s[/tex]
Position of the ball at the timeThe position of the ball at the time is calculated as follows;
[tex]X = v_x t\\\\X = (34 \times cos37) \times 4.1\\\\X = 111.33 \ m[/tex]
Since, 111.33 m is greater than 106 m, Henry will have a home run.
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1-Light carries energy in the form of ______energy?
helpp
Answer:
electromagnetic radiation
Hope this helps :)
What is the new velocity of an 1140 kg car that was traveling at 13.6 m/s and slams on the brakes losing 50000 of energy?
Answer:
9.86m/s
Explanation:
let's get to the formula
kinetic energy = 1/2*m*v^2= .5*1140*(13.6)^2=105427.2 j
it looses 50k j of energy. so new energy = 105427.2-50000 = 554227.2
again use the formula for k.e
ans = 9.86 m/s
Please help me out with this.
True or False?
You are helping a friend push a couch across their living room floor.
Gravity is a field force acting downward on the couch.
Friction from the carpeted floor is a contact force acting against your push.
We have that Gravity a force acting down ward against any object and frictional force is a force acting a against movement, Hence
TrueTrueGravity and frictional forceGenerally, Gravity a force acting down ward against any object on earth at an acceleration of about 9.8m/s
and frictional force is a force acting a against the movement based on contact with another surface
Therefore
Gravity is a field force acting downward on the couch:
This is True
Friction from the carpeted floor is a contact force acting against your push.
This is True
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Anyone no how to do number 5
Which of the following is an example of a SOLUTION?
Milk
Italian Salad Dressing
Orange Juice with Pulp
Salt Water
Answer:
Salt water
Explanation:
This is the answer
The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is __________.
A. 9,887.5 J
B. 1,537.5 J
C. 58,037.5 J
D. 8,350 J
The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 8350 J.
Amount of heat requiredThe amount of heat required to change 25 g of −30°C ice into 0°C liquid water is calculated as follows;
Q = mLf
where;
m is mass of the iceLf is latent heat of fusionQ = 25 x 334
Q = 8350
Thus, the amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 8350 J.
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Answer:
The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 9,887.5 J.
Frosted glass is an example of which type of material?
Multiple choice question.
A)
transparent
B)
translucent
C)
opaque
D)
radiant
Answer:
B)
translucent
Hope this helps♡♡♡
A ball falling from a great height will reach terminal speed when ____.
Answer:
you can view my profile and go to questions and answer the recent questions i posted
Explanation:
Question 10.
Mass (M), acceleration (a) and force (F) are related by the equation
F=ma
Re-arrange this equation so as to make the acceleration a the subject, i.e.
a= ??
Answer:
[tex]a=\frac{F}{m}[/tex]
Explanation:
Just divide mass from both sides
A 200-W light bulb is connected across a 110-V dc power supply. What current will flow through this bulb
Answer:
it should be 1.8
What would happen if we
decreased the WIDTH of
these wires?
A. The resistance would stay the same.
B. The resistance would increase.
C. The resistance would decrease.
Answer:
i think the correct answer is (a)
The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in height with respect to sea level corresponds to 10 mb pressure, What is the Sea Level Pressure at Leh
We have that the sea level pressure for Leh area is 1150mb mathematically given as
Ps= 1150 mb
Sea level pressureQuestion Parameters:
Ladakh is 800 mb.
assuming that Leh is at an altitude of 3500 m and every 100 m
increase in height with respect to sea level corresponds to 10 mb pressure,
Generally, for 3500m the pressure change will be 350 mb.
Therefore, here for the sea level pressure we need to add,
Ps=800+350
Ps= 1150 mb
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The force between 2 pith balls
Answer:
charged pith ball works well to show the Coulomb force between two charged objects. If a glass rod is rubbed with silk, the silk rubs some electrons off the rod. The rod thus becomes positively charged. ... Since like charges repel, the pith balls repel one another.
Explanation:
What can be said in general about warm colours
Answer:
Warm colours are those with a yellow-ish or black undertone. Imagine how everything looks through your tinted sunglasses or on a beautiful day in autumn when the leaves are falling. The hints of yellow give these colours a sunny warmth, while those with more black mixed in appear darker and can seem more muted.
Calculate the force of gravity between planet X and planet y if both planets are 3.75 X 10^11 m apart, planet X has a mass of 1.55 X 10^22 kg and planet
Y has a mass of 3.95 X 10^28 kg.
(The radius of planet X is 6.0 X 10^6 m, the radius of planet Y is 1.50 X 10^6 m, and G = 6.67 X 10^-11 Nm2/kg2)
So, the force of gravity that the asteroid and the planet have on each other approximately [tex] \boxed{\sf{2.9 \times 10^{17} \: N}} [/tex]
IntroductionHi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :
[tex] \boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}} [/tex]
With the following condition :
F = gravitational force (N)G = gravity constant ≈ [tex] \sf{6.67 \times 10^{-11}} [/tex] N.m²/kg²[tex] \sf{m_1} [/tex] = mass of the first object (kg)[tex] \sf{m_2} [/tex] = mass of the second object (kg)r = distance between two objects (m)Problem SolvingWe know that :
G = gravity constant ≈ [tex] \sf{6.67 \times 10^{-11}} [/tex] N.m²/kg²[tex] \sf{m_X} [/tex] = mass of the planet X = [tex] \sf{1.55 \times 10^{22}} [/tex] kg.[tex] \sf{m_Y} [/tex] = mass of the planet Y = [tex] \sf{3.95 \times 10^{28}} [/tex] kg.r = distance between two objects = [tex] \sf{3.75 \times 10^{11}} [/tex] m.What was asked :
F = gravitational force = ... NStep by step :
[tex] \sf{F = G \times \frac{m_X \times m_Y}{r^2}} [/tex]
[tex] \sf{F = 6.67 \cdot 10^{-11} \times \frac{1.55 \cdot 10^{22} \cdot 3.95 \times 10^{28}}{(3.75 \times 10^{11})^2}} [/tex]
[tex] \sf{F \approx \frac{40.84 \times 10^{-11 + 22 + 28}}{14.0625 \times 10^{22}}} [/tex]
[tex] \sf{F \approx 2.9 \times 10^{39 - 22}} [/tex]
[tex] \sf{F \approx 2.9 \times 10^{17} \: N} [/tex]
ConclusionSo, the force of gravity that the asteroid and the planet have on each other approximately
[tex] \boxed{\sf{2.9 \times 10^{17} \: N}} [/tex]
See MoreGravity is a thing has depends on ... https://brainly.com/question/26485200An elephant has a mass of 5000 kg. What is the elephant's weight?
What’s the power if a student does 2240j of work for 2.8 seconds
Answer:
800 Watts
Explanation:
Power = Work/time
Working in SI units, Power = Watts, Work = Joules, Time = seconds.
Power = 2240J/2.8s = 800 Watts.
what is the average velocity if the initial velocity of an object is 10 m/s and the final velocity ia 28 m/s ?
A system releases 124 kJ of heat while 114 kJ of work is done on the system. Calculate the change in internal energy (in kJ).
Answer:
10kj should be the answer so I think
What is the magnitude of the electric field strength at a position that is 1.2 m from a point charge of 4.2 x10^-6 C
This is the correct answer
The magnitude of the electric field strength at that position is 2.6×10⁴ Newton/Coulomb.
What is electric field?An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field. Electric charges and time-varying electric currents are the building blocks of electric fields.
Given parameters:
Charge of the point charge: Q = 4.2 × 10⁻⁶ Coulomb.
Distance of the position from the position: r = 1.2 meter.
The magnitude of the electric field strength at that position = kQ/r²
= 9 × 10⁹ × 4.2×10⁻⁶/(1.2)² Newton/coulomb.
= 2.6×10⁴ Newton/Coulomb.
Hence, the magnitude of the electric field strength at that position is 2.6×10⁴ Newton/Coulomb.
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Please Help!!!
Imagine two astronauts working in outer space. Suppose they have equal masses and accidentally run into each other. The first astronaut moves 4.0 m/s to the right before the collision and 1.5 m/s to the left afterwards. If the second astronaut moves 4.0 m/s to the right after the perfectly elastic collision, what was the second astronaut's initial velocity? Hint m1 and m2 are equal, so you do not need them to solve for vzi 1. List your Givens. 2. Show your Work. 3. Give your answer
Take "to the right" to be the positive direction. By conservation of momentum,
m₁v₁ + m₂v₂ = m₁(v')₁ + m₂(v')₂
where the v-s denote initial velocities and the v'-s denote final velocities. m₁ and m₂ are of course masses, but we're told that m₁ = m₂, so we can eliminate these factors altogether:
v₁ + v₂ = (v')₁ + (v')₂
We're given that v₁ = +4.0 m/s, (v₁)' = -1.5 m/s, and (v')₂ = +4.0 m/s.
Solve for v₂ :
v₁ + v₂ = (v')₁ + (v')₂
4.0 m/s + v₂ = -1.5 m/s + 4.0 m/s
⇒ v₂ = -1.5 m/s
Calculate the magnitude of force, is the vertica Component of force is 10N and its horizontal apre to 60º.
Vector A points along the + y axis and a magnitude of 100.0 units. Vector B points at an angle of 60.0 degrees above the +x axis and has a magnitude of 200.0 units. Vector C points along the +x axis and has a magnitude of 150.0 units. Which vector has (a ) the largest x component and (b) the largest y component ?
Answer:
vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are
→
a
=
x
1
^
i
+
y
1
^
j
and
→
b
=
x
2
^
i
+
y
2
^
j
, we can find the sum of two vectors as follows.
→
a
+
→
b
=
x
1
^
i
+
y
1
^
j
+
x
2
^
i
+
y
2
^
j
=
(
x
1
+
x
2
)
^
i
+
(
y
1
+
y
2
)
^
j
The direction of the sum of the vectors (with positive x-axis) is,
θ
=
tan
−
1
(
y
1
+
y
2
x
1
+
x
2
)
Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j
What is vector ?Vectors are objects which have both, magnitude and direction. Magnitude defines the size of the vector. It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.
Vector A = direction is in y direction = 100j
Since , this vector is only in y direction and have no component in x direction , so its x component will be = 0i
Vector B = direction is at angle of 60.0 degrees above the +x axis
Resolving into x and y components
x component = Vector B*cos(60) = Vector B * (1/2) = Vector B /2 = 200 /2
= 100i
y component = Vector B * sin(60) = Vector B * [tex]\sqrt{3}[/tex]/2 = 173j
Vector C = direction is along the +x axis
hence , it will not have any y component
x component = 150i
y component = 0j
Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j
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A speed skater just finished a race. After she crossed the finish line, she coasted to a complete stop. If her initial speed was 13.0 m/s and her acceleration was -2.9 m/s2, how long did it take her to stop?
Answer:
5seconds
Explanation:
because she was going through the same time
What is the displacement of a train as it is accelerated uniformly from 11 m/s to 33 m/s in a 20 seconds time interval
The displacement of this train is equal to 2.2 meters.
Given the following data:
Initial velocity = 11 m/s.Final velocity = 33 m/s.Time 20 seconds.To determine the displacement of a train:
How to calculate displacement.Mathematically, the displacement of an object is given by this formula:
[tex]d = \frac{V\;+\;U}{t}[/tex]
Where:
V is the final velocity.U is the initial velocity.t is the time.Substituting the given parameters into the formula, we have;
[tex]d = \frac{33\;+\;11}{20}\\\\d = \frac{44}{20}[/tex]
d = 2.2 meters.
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The galaxy NGC 4414 is moving away from us at 7.16x105 m/s. By how much will the frequency of the 6.91x1014 Hz hydrogen line be shifted in the galaxy's spectrum?
The shift in the frequency of hydrogen line is 1.65 x 10¹² Hz.
Relationship between frequency and speed of waveThe relationship between frequency and speed of wave is given in the following formula;
v = fλ
Ratio of speed of speed of galaxy to speed of light[tex]\frac{c}{c_o} = \frac{71.6 \times 10^5}{3 \times 10^8} = 0.00239[/tex]
Shift in the frequency of hydrogen lineThe shift in the frequency of hydrogen line is calculated as follows;
[tex]0.00239 \times 6.91 \times 10^{14} = 1.65 \times 10^{12} \ Hz[/tex]
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The energy of an electromagnetic wave is related to its amplitude.
True false question.
True
False
help
Answer:
True
Explanation:
If amplitudes are equal, high frequency waves carry more energy than low frequency waves.
Calculate the weight of an object with a mass of 50 kg on a planet with an acceleration due to gravity of 2.0 m/s2.
a. .04 N
b. 25 N
c. 100 N
Answer:
C
Explanation:
Basically force is given by the formula.
F= ma
Where m is mass of the body and 'a' is acceleration.
Here the time is not given, hence it is not possible to calculate acceleration, as acceleration is given by the formula
a= v/t
So most probably the question is wrong.
However if we take acceleration= 2m/s^2
Then F= ma= 50*2= 100N
However if the question was to find energy then it is sufficient to find kinetic energy as moving objects possess kinetic energy.kinetic energy is given by the formula:
KE= 1/2*m* v^2
I.e, KE= 1/2 * 50 * 2* 2
Type the name or address of your current location in the address field and select the location provided. Write the exact latitude and longitude coordinates (degrees, minutes, and seconds) that are provided in the answer space. How do these coordinates compare to your estimate from part C?
The coordinates should be written in the following format:
Lat: N 33°34’ 40”
Lon: W 99°29’ 31”
My location coordinates are Lat: N 38.89'76", Lon: W: -77.03'66"
What are geographic coordinates?Geographic coordinates are a term to refer to the terrestrial reference system that allows a location to be specified by means of a series of numbers, letters or symbols.
The basic and best known geographic coordinate system worldwide specifies the following data:
North or South latitude, degrees, minutes and seconds.East and west longitude, degrees, minutes and seconds.To establish the geographical location of a point, the imaginary Greenwich meridian reference lines (longitude) and the equator line (latitude) must be taken into account.
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If this charged soot particle is now isolated (that is, removed from the electric field described in the previous part), what will be the magnitude E of the electric field due to the particle at distance 1.00 meter from the particle?
The magnitude of the electric field due to the particle at the given distance is [tex]9\times 10^9 q[/tex].
Electric field strengthThe electric field strength of a charged particle is the force per unit charge in the given field.
The electric field strength of a charge is given as;
[tex]E = \frac{F}{q} \\\\E = \frac{kq}{r^2}[/tex]
where;
k is Coulomb's constantq is the charger is the distance[tex]E = \frac{9\times 10^9 \times q}{1^2} \\\\E = 9\times 10^9 q[/tex]
Thus, the magnitude of the electric field due to the particle at the given distance is [tex]9\times 10^9 q[/tex].
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