Complete Question
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Answer:
The distance covered horizontally is [tex]d = 43 \ m[/tex]
Explanation:
From the question we are told that
The initial horizontal velocity is [tex]u = 10 \ m/s[/tex]
The time taken by the ball in the air is [tex]t = 4.3 \ s[/tex]
Generally the distance traveled by the ball is
[tex]d = u * t[/tex]
=> [tex]d = 10 * 4.3[/tex]
=> [tex]d = 43 \ m[/tex]
What happens when an electrically charged balloon is placed close to an uncharged soda can?
The balloon attracts the can.
The balloon is negatively charged.
The can attracts the balloon.
The can becomes positively charged.
Answer:
The surface closest to the balloon becomes positively charged, while the far side of the can becomes negatively charged. This results in an attractive force that draws the can to the balloon.
Explanation:
Answer:
The balloon is negatively charged.
Explanation:
hope it helps
How can you increase the pressure on an object?
why are annowwhisker used to repel stains on fabrics
Answer:Because it makes the stains like go away which makes the fabrics get not stained so yeah
Why is it important to lean forward and listen
An object with a mass of 43 kg measured on Earth is taken to the Moon. What is the mass of the object on the Moon's surface if the acceleration due to gravity on the Moon is one-sixth of that on Earth? O a. 16 kg O b. 43 kg O c. 7.9 kg O d. 26 kg
Answer:
b 43 kg
Explanation:
mass doesn't differ from place to place.
but the weight may
The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this impressive position is traveling with an initial velocity of 8.0 m/s before accelerating. Then the rider travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider's velocity after the acceleration?
Answer:
14.97m/sExplanation:
Given
Initial velocity of the car u = 8m/s
Distance travelled by the rider S = 40m
Acceleration a = 2m/s²
Required
rider's velocity after the acceleration v
Using the equation of motion
v² = u²+2as
v² = 8²+2(2)(40)
v² = 64+160
v² = 224
v = √224
v = 14.97m/s
Hence the rider's velocity after the acceleration is 14.97m/s
Under what conditions can an object have forces acting on it, but its motion does not change ?
Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.
Explanation: I hoped that helped!!
A 2 kg mass moving along a horizontal surface at 10 m/s is acted upon by a 5 N force of
friction. Calculate the net force?
Answer:
F = 20.61 N
Explanation:
Given that,
Mass of the object, m = 2 kg
It is moving with a speed of 10 m/s
It is acted upon by a 5 N of friction.
The force of gravity acts in downward direction which is given by :
W = mg
W = 2 × 10 = 20 N
5 N of force is acting in horizonal surface.
The net force is given by the resultant of two vectors as follows :
[tex]F=\sqrt{20^2+5^2} \\\\=20.61\ N[/tex]
So, the net force acting on the object is 20.61 N.
The net force acting on the mass is equal to 13.6 Newton.
Given the following data:
Mass = 2 kgSpeed = 10 m/sForce of friction = 5 NWe know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex].
To calculate the net force:
First of all, we would determine the normal force acting on the mass.
Mathematically, the normal force is given by the formula:
[tex]F_N = mg[/tex]
Where:
m is the mass of an object. g is the acceleration due to gravity.Substituting the given parameters into the formula, we have;
[tex]F_N = 2 \times 9.8[/tex]
Normal force = 19.6 Newton
To find net force:
[tex]Net\;force = 19.6 - 5[/tex]
Net force = 13.6 Newton.
Note: We subtracted because friction opposes the motion of an object and as such acts in opposite direction.
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The attachment is here. It is physics/chem.
Answer:
Can some body plz explain me plzzz
a relationship between two or more variables that is shown is an observational study is a: a. correlation. b. social norm. c. coupling. d. causal relationship.
Answer:
Correlation
Explanation: Answer for Ap3x
GIVING THE REST OF MY POINTS!
Energy can be:
A. destroyed or converted to another form.
B. destroyed.
C. created, but never destroyed.
D. converted to another form.
what can i do to recycle?
Answer:
You could throw away the following items:
Mixed paper: Newspaper, magazine, junk mail, cardboard, frozen food packaging, wrapping paper, paper bags, etc.
Cans: aluminum, foil, tin, steal, aerosol (empty without pressure) and metal food trays. ...
Unbroken glass: Wine bottles, bottles and jars.
Plastic: Rigid containers like milk jugs, shampoo or water bottles.
Hope this helped
If no work is done, the total energy is not changed. In that situation, if the kinetic energy changes, what must happen to the potential energy?
Answer:
the potential energy will also change
Explanation:
kinetic energy and potential energy are inversely proportional to each other, so if kinetic energy changes, potential energy will also change..
two monkeys were swinging on vines together. One monkey got stuck hanging from a branch unable to move. the other monkey, who was very smart,knew that to move he needed to have a net force in the direction he wanted to go
Answer:
Hi, what is the question here?
Explanation:
Happy to help if I'm able to
what is the peacocks displacement from 2 to 3 seconds
Miguel's parents drove him to a track meet that was 305 km away from the school. It took them 3 hours, which included a 30 minute break for breakfast. What was their average speed?
A.101.7 km/h
B.915 km/
C.122 km/h
D.275 km/h
would someone just answer this now?
A 58-kg boy swings a baseball bat, which causes a 0.140-kg baseball to move toward 3rd base with a velocity of 38.0 m/s.
Calculate the kinetic energy of the baseball (rounding your answer to the integer).
Answer:
101 J
Explanation:
Answer:
[tex]\boxed {\boxed {\sf 101 \ Joules}}[/tex]
Explanation:
Kinetic energy can be found using the following formula:
[tex]KE=\frac{1}{2}mv^2[/tex]
The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.
[tex]m= 0.140 \ kg \\v= 38.0 \ m/s[/tex]
Substitute the values into the formula.
[tex]KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2][/tex]
First, evaluate the exponent.
(38.0 m/s)²= 38.0 m/s * 38.0 m/s = 1444 m²/s²[tex]KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)[/tex]
Multiply the two numbers in parentheses together.
[tex]KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)[/tex]
Multiply the fraction by the number, or divide the number by 2.
[tex]KE=101.08 \ kg*m^2/s^2[/tex]
Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.
[tex]KE\approx 101 \ kg*m^2/s^2[/tex]
1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).
[tex]KE\approx 101 \ J[/tex]
The kinetic energy of the baseball is about 101 Joules.
If the net force acting on a moving object is zero, the object will: *
slow down and, eventually, stop.
continue at the same speed but change direction.
O
continue in the same direction but change speed.
O
continue in the same direction with no change of speed.
Answer: D) continue in the same direction with no change of speed.
In other words, the velocity of the object won't change.
A net force of 0 means that all forces acting on the object are in balance. If the object is in motion, then it stays in motion. If the object is at rest, then it stays at rest. This is newton's first law of motion describing inertia.
a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy? calculate it
Answer:
It has potential energy
PE = 15450.75 J
Explanation:
we know its potential energy because the carriage is not moving, although it can
PE = mgh
in this case, m is 75, h is 21, and g is always 9.81
plug these in: PE = (75) (21) (9.81)
your answer: PE = 15450.75 J
Bird man is flying horizontally at a speed of 33m/s and a height of 86m. Bird man releases a turd directly above the start of the field. How far from the start of the field should the robot hold the bucket to catch the turd.
Answer:
2838
Explanation:
How might heating the molecules inside the bottle change the motion of the molecules?
A Boy has a ball and throws it straight up into the air with an initial velocity of 6 m/s. Calculate the maximum height of the ball and the time the ball is in the air.
Answer:
i. 1.84 m
ii. The ball's time in the air is 1.23s.
Explanation:
The ball moves upward (against the gravitational pull) with an initial velocity of 6 m/s.
I. Applying the third equation of free fall, the maximum height is;
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] - 2gs
where the variables have there usual meaning.
[tex]V^{2}[/tex] = 0 m/s, [tex]U^{2}[/tex] = 6 m/s, g = 9.8 m/[tex]s^{2}[/tex].
0 = [tex]6^{2}[/tex] - 2 x 9.8 x s
0 = 36 - 19.6s
⇒ 19.6s = 36
s = [tex]\frac{36}{19.6}[/tex]
= 1.8367
= 1.84 m
The maximum height of the ball is 1.84 m.
II. The time the ball was in air can be determined by,
time of flight, T = [tex]\frac{2USin A}{g}[/tex]
where U is the initial velocity of the ball, A is the angle of projection and g is the acceleration due to gravity.
U = 6 m/s, A = [tex]90^{o}[/tex] (since the ball is thrown vertically upward), and g = 9.8 m/[tex]s^{2}[/tex].
T = [tex]\frac{2 *6 Sin90^{o} }{9.8}[/tex]
= [tex]\frac{12}{9.8}[/tex]
= 1.2245
T = 1.23s
The ball's time in the air is 1.23s.
Someone in a car going past you at the speed of 32 m/s drops a small rock from a height of 2 m. How far from the point of the drop will the rock hit the ground? the acceleration due to gravity is 9.8m/s^2. answer in units of m.
Answer:
The rock will hit the ground at 20.44 m from the point of the drop
Explanation:
Horizontal Motion
It occurs when an object is thrown horizontally from a height h at an initial speed v.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
When the small rock is dropped from a car at speed v=32 m/s, it starts a curved path that ends up when the rock hits the ground. The height is h=2 m, thus the range is:
[tex]\displaystyle d=32\cdot\sqrt{\frac {2\cdot 2}{9.8}}[/tex]
[tex]\displaystyle d=32\cdot\sqrt{0.4082}[/tex]
[tex]d=20.44\ m[/tex]
The rock will hit the ground at 20.44 m from the point of the drop
Which of the following is the best example of positive peer pressure?
Answer:
1.Your friend says "no thanks" to the dinner your dad cooked and prefers to just hang out with friends instead.
2. Your teammates keep making fun of you for spending so much time studying for Friday's math test.
3. Your coworkers spend every weekend watching movies at Tim's house and invite you to join them.
4. Your friends all sign up for a free class at the gym and suggest you sign up for it, too.
A jogger takes five minutes to run a distance of three kilometres. His speed, in metres per second, is approximately A) 5.5 M/S B) 10 M/S C) 36 M/S D) 4.5 M/S
Answer:
His speed, in metres per second, is approximately 10m/s. The correct option is B.
Explanation:
Speed is defined as the rate in which an object cover a distance in a given time. It is measured in meters per second ( m/s). From the question, the jogger covered a distance of 3Km which when converted to meter is 3000meters in a given time 5 minutes which is 300seconds. The calculation of his speed in meter per second is shown below:
Distance= 3Km to meters ( as 1000meters = 1Km). Therefore 3× 1000 = 3000m
Time= 5 minutes to seconds ( as 1 minute = 60 Seconds). Therefore 5× 60= 300.
Speed= distance/ time
= 3000/300
= 10m/s
Therefore his speed, in metres per second, is approximately 10.
Where are alkaline earth metals found on the periodic table? Group 1 Group 2 Groups 3–12 Group 17'
Answer:
B- Group 2... It says my answer is too short so how ya'll doing today?
A copper rod of crosssectional area 0.500 cm2 and length 1.00 m is elongated by 2.00 * 10-2 mm and a steel rod of the same cross-sectional area but 0.100 m in length is elongated by 2.00 * 10-3 mm. Which rod is under greater tensile strain?
Answer:
They have the same tensile strainExplanation:
Strain of a material is the ratio of its extension to its original length.
strain = e/lo
e is the extension
lo is the original length
For a copper rod;
e = 2.00 * 10^-2mm
lo = 1.00m
convert 1.00m to mm
1.00m = 1*10^-3mm
get the strain
Strain = 2.00 * 10^-2mm/1*10^-3mm
Strain = 2 * 10^{-2+3}
Strain = 2*10^1 = 20
For the steel
e = 2.00 * 10^-3mm
lo = 0.100m
convert 0.100m to mm
0.1m = 0.1*10^-3mm
0.1m = 10^-4mm
get the strain
Strain = 2.00 * 10^-3mm/10^-4mm
Strain = 2 * 10^{-3+4}
Strain = 2*10^1 = 20
Since the value of their strain are the same, this means that they a re under the SAME tensile strain. No one is greater that the other.
The rod under greater tensile strain is ; Neither of them i.e. They both have the same tensile strain
Given data :
Cross sectional area of copper rod = 0.5 cm²
Length of copper rod = 1.0 m = 1 * 10³ mm
Elongation of copper rod ( Ec ) = 2.0 * 10⁻² mm
For Steel
Cross sectional area of steel = 0.5 cm²
Length of steel rod = 0.1 m = 1 * 10² mm
Elongation of steel rod ( Es )= 2.0 * 10⁻³ mm
Determine the Tensile strain of each rod
i) For copper rod
Tensile strain = Ec / Length of copper rod
= ( 2.0 * 10⁻² ) / ( 1 * 10³ )
= 2.0 * 10⁻⁵
ii) For the steel rod
Tensile strain = Es / Length of steel rod
= ( 2.0 * 10⁻³ ) / ( 1 * 10² )
= 2.0 * 10⁻⁵
The Tensile strain for the copper rod and the steel rod is the same ( 2.0 * 10⁻⁵ ) This means that both rods are under the same tensile strain
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The diagram shows the forces acting on an object at an instant of time. Which of the following statements about the forces is true?
Answer:
If you want help, try showing that diagram and the following statements.
How does the force of gravity change between two planets when the masses ofBOTH planets are doubled?
Fg=G m1m2
d2
O A
2 times the gravity
B.
4 times the gravity
O
C
no change in gravity
Oo
1/2 the gravity
Answer:
B. 4 times
Explanation:
Fg'=G(2m1)(2m2)/d²
Fg'=4Gm1m2/r²