Answer: a=.347
Explanation: Acceleration can be calculated by subtracting the initial velocity (2.1 m/s) from the final velocity (7.3) and dividing the difference by the time (15s).
[tex]\frac{7.3-2.1}{15} = .347[/tex]
What would be the acceleration of gravity (in m/s2) at the surface of a world with nine times Earth's mass and three times its radius?
Answer:
Explanation:
Given:
M = 9*M₃
R = 3*R₃
g₃ =9.8 m/s²
_______
g - ?
g₃ = G*M₃ / R₃²
g = G*M / R² = G*9·M₃ / (3*R₃)² = G*9·M₃ / (9*R₃²) = G*M₃ / R₃² = g₃
Accelerations are the same
An airplane at 70 m/s in the direction 133 degrees counterclockwise from east. What are the east and north components of the plane's velocity?
Answer:
See below
Explanation:
East is 70 cos 133 = -47.7 m/s East
North is 70 sin 133 = 51.2 m/s North
A motor car having a mass of 2 tonnes is being accelerated up a gradient of 1 in 25. At an engine speed of 4 000 rimin the b. P. Is 57 kw the effective tyre radius is 330 mm, the rolling res?stance is 180 n/tonne, and the rear-axle ratio is 4. 4 to 1 assuming a transmission efficiency of 90 % and neglecting air resistance, determine the value of the acceleration at the given speed 262 mls1.
The value of the Acceleration at the given speed of 262 m/s will be 0.245 m / s²
Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has acceleration.
Given that:
Mass of car = 2 Tonnes = 2000 kg.
Wheel's power transfer = Efficiency * b.P.
Power = 0.9 * 57000
Therefore, Power = 51300 W
Wheel's angular velocity = (2[tex]\pi[/tex]N / 60) * (1 / rear-axle ratio)
Angular Velocity = (2[tex]\pi[/tex] * 4000) / 60 * (1 / 4.4)
Therefore, Angular Velocity = 95.15 rad / sec
Wheel:
Power = Torque * Angular Velocity
P = F * Tyre Radius * W
⇒ 51300 = F * 0.33 * 95.15
F = 51300 / (0.33 * 95.15)
F = 51300 / 31.4
Therefore, Force = 1633.76 (by the engine)
Resistance:
Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N
F₁ = 360N
Gradient Resistance:
tanθ = 1 / 25
θ = 2.2906°
Fg = mg * sinθ
Fg = 2000 * 9.84 * sin (2.2906)
Fg = 783.37 N
Acceleration (a):
Net force = Mass * Acceleration
F - (Fr + Fg) = 2000 * a
1633.76 - (360 + 783.37) = 2000 * a
a = 490.39 / 2000
Therefore, Acceleration = 0.245 m / s²
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what quantity of heat energy is needed to melt 120g of ice at -20°C to water at 30°c? (SHC of water = 4200J/kg/k, SHC for ice = 2100J/kg/K, Specific latent heat of fusion of ice = 3.36x10^5 J/kg)
Answer:
59, 720 Joules
Explanation:
[tex]q = mc(t2 - t1) + m(lf) + mc(t2 - t1)[/tex]
first term=ice to 0 degrees
second term=water to ice
third term-water to 30 degrees
[tex]q = 0.12 \times 2100 \times 20 + 0.12 \times 3.36 \times {10}^{5} + 0.12 \times 4200 \times 30[/tex]
[tex]q = 59720 \: joules[/tex]
sound waves have entered natalie’s ear and traveled through to her auditory nerve. what process that will now take place in which she identifies what the sound is?
Sound waves have entered Natalie’s ear and traveled through to her auditory nerve. The process of perception took place in which she identifies what the sound is.
Perception is the ability to see, hear and become aware of something through the senses.
The process of interpreting a present stimulus based on past experience is called as perceptionSound waves from the environment enter the outer ear and are directed to the ear drum
The eardrum vibrates when sound waves are received, and the vibrations are sent to the oval window through the ossicles of the ear, .
From the oval window, these vibrations are transmitted to the fluid of the cochlea, where waves are generated in the lymph.
These waves generate vibrations in the basilar membrane that bends the hair cells and push them against the tectorial membrane, and hence are sent to the brain which gives signal to the organ to react.
Hence perception is used by Natalie to react.
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adjacent antinodes of a standing wave on a string are 15.0 cmcm apart. a particle at an antinode oscillates in simple harmonic motion with amplitude 0.850 cmcm and period 0.0750 ss. the string lies along the xx-axis and is fixed at xx
D = 15 cm , b) λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e) v = 80.43 cm / s , v = -80.43 cm / s, f) D₂= 7.5 cm
Standing waves form when two waves of the same frequency traveling in opposite directions,
A) in the waves the distance of the nodes and antinode is the same since the wavelength is constant
D = 15 cm
B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is the lamina of the wavelength.
D = λ / 2
λ= 15 2
λ = 30.0 cm
C) the amplitude of each wave is 0.0850 cm, and the amplitude of the standing wave is double A = 0.17 cm
D) Let's use the speed ratio
v = λ f
f = 1 / T
v = λ / T
v = 30.0 /0.0750
v = 400 cm / s
E) the transverse speeds are the speed of the oscillatory movement
y = A cos (wt)
w = 2π f = 2π / T
w = 2π / 0.0750
w = 83.78 rad / s
y = 0.850 cos (83.78 t)
Speed is
v = dy / dt
v = -A w cost wt
v = - 0.850 83.78 cos (83.78 t)
v = -80.43 cos (83.78 t)
The maximum speed when the cosine values ±1
v = 80.43 cm / s
v = -80.43 cm / s
F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength
D₂ = ¼ λ
D₂ = 30.0/4
D₂= 7.5 cm
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I NEED HELP URGENTLY! FOR 20 POINTS!
The law of definite proportion states that any sample of the compound will always have the same percentage of each element by weight or mass.
There are four elements that made up matter: air, water earth, and fire is not the main idea of dalton's atomic theory.
What is the law of definite proportion?The Law of Definite Proportion defines that the elements that composed a chemical compound are generally arranged in a definite mass ratio regardless of preparation.
The composition of compounds will always be the same by mass using the law of definite proportions. Chemical compounds are made of elements that are present at fixed ratios in terms of their mass.
In the nitrogen dioxide molecule (NO₂), Nitrogen and oxygen atoms are always present in a 1:2 ratio.
According to Dalton's atomic theory, all matter consists of atoms. The atoms of the same element have the same mass and the atoms of different have different masses and compounds are made of atoms of more than one element.
Therefore, for question (1) option (C) and for (2) option (C) is correct.
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A small plane, starting from rest, much reach a speed of 33 m/s for takeoff.
A.) How long of a runway is needed if the plane has a constant acceleration of 3.0 m/s^2 during takeoff?
B.) How much time does it take for the plane to take off?
A.) Runway has to be 181.5 long.
B.) Plane takes 11 second for the plane to take off.
What is acceleration?Change in velocity (Δv) divided by the change in time (Δt), is called acceleration that can be represented by the equation
a = Δv/Δt.
This lets you measure how fast a velocity changes in (m/s^2). Acceleration a vector quantity, that is it has both magnitude and direction
Meter per second squared is the SI unit of acceleration.
Given, a small plane must reach a speed of 33m/s for takeoff, starting from rest and constant acceleration is 3.0m/s^2
Let the time be 't'
hence,
(33-0 )/t = 3
33 = 3t
t = 11 sec
Time taken by the plane to take off is 11sec.
Average velocity = (33 + 0)/t
= 16.5 m/sec
Distance = speed * time
= 16.5 * 11
= 181.5 m
Runway has to be at least 181.15 meters long.
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An object is thrown up from the top of a building of height h with an initial velocity v,. The object reaches its maximum height and then returms down to the ground. The velocity of this object when it reaches the maximum height is equal to:
Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point - and it's falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0)
use triangle,parallelogram and polygon method determine the resultant vector of a) 10km left,20km up b) 150km north,50km west c) 7km east,14km north
The resultant forces in each case is;
a) 22.3 Km
b) 158 Km
c) 15.7 Km
What is the resultant force?Let us note that the resultant force is the force that would have the same effect in magnitude and direction as the the two force that are acting together.
In this case we have been asked to find the resultant of the forces and we would use the triangle method.
a) R = √(10)^2 + (20)^2
R = 22.3 Km
b) R = √(150^2) + (50)^2
R = 158 Km
c) R = √(7)^2 + (14)^2
= 15.7 Km
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if solar radiation is 1190 w/m2 , how many photons strike the leaf every second? assume three significant figures and an average wavelength of 504 nm for solar radiation.
7.15 x 10^17 photons strike the leaf every second if solar radiation is 1190 w/m2 strike .
Solar radiation intensity = 1200 W/m2
= 1200 J/m2 s-1 (1 W = 1 J/s)
Area of leaf = 2.35 cm2
= 2.35 x 10-4 m2 (1 cm2 = 10-4 m2)
Total energy striking leaf per second = intensity x area x time
= 1200 J/m2 s-1 x 2.35 x 10-4 m2 x 1 s
= 0.282 J
Wavelength λ = 504 nm = 504 x 10-9 m (1 nm = 10-9 m)
Energy of 1 photon E = hc/λ
= 6.626 x 10-34 x 2.998 x 108/504 x 10-9
= 3.9414 x 10-19 J
where h is Planck constant and c is speed of light
Number of photons striking leaf per second = total energy/energy of 1 photon
= 0.282/3.9414 x 10-19
= 7.15 x 10^17 photons
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a spring with an mm-kg mass and a damping constant 5 (kg/s) can be held stretched 1 meters beyond its natural length by a force of 2 newtons. if the spring is stretched 2 meters beyond its natural length and then released with zero velocity, find the mass that would produce critical damping.
A spring with a damping constant 5 (kg/s) can be held stretched 1 meters beyond its natural length by a force of 2 newtons. The mass m = 3.12 kg that would produce critical damping
From hooke's law, force required to stretch the spring is
k (1) = 2
Spring Constant, k = 2
For critical damping, c²-4mk =0
m = c² / 4 k
c= damping constant (from question)
m = Mass to produce critical damping
There fore, m = (5²/4*2) = 3.12 kg
According to Hooke's law, the restoring force is equal to -kx, where k is a positive number known as the spring constant. Since c is a positive constant that is also known as the damping constant, we assume that the damping force is -c(dx/dt). Robert Hooke, an English scientist, developed the law of elasticity in 1660. According to Hooke's law, for relatively minor deformations of an item, the displacement or amount of the deformation is directly proportional to the deforming force or load.
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a 14.0-kg bucket is lowered vertically by a rope in which there is 163 n of tension at a given instant. what is the acceleration of the bucket? is it up or down?
A 14.0-kg bucket is vertically dropped by a rope with 163 n of tension at any given time. The acceleration of the bucket is upward-directed and has a value of 2.06 ms^-2.
Let's imagine that two bodies are attached by a rope, causing the system to move with an acceleration an in opposition to the force of gravity acting on one of the bodies. By dividing a body's mass (m) by the net force (F n e t) exerted on it, one can calculate the acceleration (a) of the body.
Please direct the bucket's acceleration in an upward direction.
The tension T supplied to the bucket is resisted by the weight mg acting downward, which causes the bucket to rise with an acceleration.
Applying the force balance we have as a result,
ma = T-mg
14a = 163-14 x 9.8
a = 1.84 m/s²
We can see that the acceleration is 1.84 m/s² times larger than the speed and since a has a positive sign, we can infer that the direction is upward.
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a car is traveling driving at 80 km/h when the driver sees an accident 50 meters ahead and applies the brakes. what constant deceleration is required to stop the car in time to avoid hitting the vehicles ahead? express your answer in m/s2.
The correct answer is -4.937284m/s^2 constant deceleration is required to stop the car in time to avoid colliding with the vehicles ahead.
u= 80km/h= 22.22m/s
s= 50m
a=? , v=0
According to newton's third equation:
2as= v^2-u^2
a= v^2-u^2/2s
a= 0-(22.22)^2/2*50
a= -493.7284/100
a= -4.937284m/s^2 (solution)
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If an element starts off with an activity of 100Bq, and its half life is 10 minutes, what would the activity be after 5 minutes???
The radioactivity of the element after 5 minutes is 75 Bq.
What is radioactivity?Radioactivity is a phenomenon exhibited by radioactive elements or isotopes by emitting energy and subatomic particles spontaneously.
The radioactivity of a radioactive element or isotope in becquerels is denoted by decay per second.
The radioactivity of the isotope in becquerels is calculated as follows;
Bq = decay / time
Half life = 10 min
This implies that after 10 minutes, the activity of the element will be; ¹/₂(100 Bq) = 50 Bq
The given time, 5 minutes is not up to 10 minutes, so the element will not be reduced to 50 Bq.
5 minutes = half of 10 minutes
half of 50 Bq = 25 Bq
So after 5 minutes, the element will decay 25 Bq, and the activity will be 75 Bq.
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A helicopter is ascending vertically with a constant speed of 5.20 m/s. At a height of 125
m above ground, a package is dropped from the helicopter.
a) How much time does it take to reach the ground?
b) How far above ground is the helicopter when the package lands?
According to the given statement:
a)It take time to reach the ground is 3.69 s.
b)The helicopter when the package lands far above the ground is 144.18 m.
What is constant speed and example ?Constant speed refers to a speed that remains constant throughout the duration of the motion. Constant speed is demonstrated in our example of using cruise control while driving a car.
Briefing:Using this formula:
t= √(h/g)
h= 125m
g= 9.2 m/s
t = √(125/9.2)
t = √13.59
t= 3.69 s
The package must touch the ground in 3.69 seconds.
From equation of motion s = u t + 1/2 a t².
Here a= 0, then s= ut
s= 5.2x 3.69 = 19.18 m.
Total height = 19.18 + 125 = 144.18 m.
Helicopter is 144.18m far above from the ground when the package lands.
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two boxes sit side-by-side on a smooth horizontal surface. the lighter box has a mass of 5.56 kg, the heavier box has a mass of 7.51 kg. calculate the contact force between these boxes when a horizontal force of 5.02 n is applied to the light box.
Answer:
18.09
Explanation:
add all the numbers together
A metal rod 800mm long is heated from 10°C to 95°C.If it expands by 1.36mm,the linear expansivity of the metal is?
Answer:
2 x 10^(-5)
Explanation:
The linear expansivity α can be calculated using the following equation:
[tex]\Delta L=\alpha\cdot\Delta T\cdot L[/tex]Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:
[tex]\begin{gathered} 1.36=\alpha(95-10)(800) \\ 1.36=\alpha(85)(800) \end{gathered}[/tex]Then, solving for α, we get:
[tex]\begin{gathered} 1.36=\alpha(68000) \\ \frac{1.36}{68000}=\frac{\alpha(68000)}{68000} \\ 2\times10^{-5}=\alpha \end{gathered}[/tex]Therefore, the linear expansivity of the metal is 2 x 10^(-5)
pingus pingus pingus pingus pingus pingus
Answer: pingus
Explanation: pingus
would adding mass to the top of a slope in the form of houses or buildings make the mass more or less likely to slide?
adding mass to the top of a slope in the form of houses or buildings make the mass more likely to slide because the houses add weight to the slope making it more unstable.
When a slope breaks, there is mass waste. When a slope is excessively steep and unstable given the materials and environmental factors at play, it fails. The slope angle and the underlying material's strength are the two main criteria that eventually influence slope stability.
On the Earth's surface, the force of gravity, which contributes to mass wasting, is mostly constant, however there are minor fluctuations based on the height and density of the underlying rock. In the illustration, the force of gravity is seen pulling a rock block on a slope down toward the center of the Earth.
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When you drop a .44 kg apple earth exerts a force on it that accelerates it at 9.8 m/s^2 towards the earth's surface. newtons third law, the apple must exert an equal but opposite force on earth. if the mass of earth is 5.98 x 10 ^24 what is the magnitude of the earths acceleration towards the apple
If the mass of earth is 5.98 x 10 ^24 Then magnitude of the earths acceleration towards the apple 6.56 * 10^(-25) m/s²
A key concept in science is the concept of magnitude in physics. The general quantity or distance is referred to as magnitude. When it comes to the elements of movement, we can tie magnitude to an object's size and motion speed.
A particular object's magnitude is determined by its size or quantity. For instance, when it comes to speed, if a car is moving at a quicker rate than a nearby motorcycle, the magnitude of the automobile's speed is greater than the speed of the motorcycle. Although they contain directions as well as magnitude, vector quantities. Vector quantities include things like force, acceleration, speed, velocity, and many others. A vector's absolute value is referred to as its magnitude.
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Anya has 115 mangoes lauren has five times the the number of mangoes Anya has they put them together and sold them in the market at $450 to $15 the sold all the mangoes how much money was collected at the end of the sale
$10,350 is the amount of money that has been collected mangoes are sold by Anya and Lauren at $15.
Number of mangoes of Anya's = 115 mangoes
Number of mangoes of Lauren's = 5 × 115 = 575 mangoes
Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has
= 115 + 575
= 690 mangoes
Amount each mango sold = $15
The total amount of money collected = Total number of mangoes × Amount each mango were sold
= 690 × 15
= $10,350
So, therefore, Anya and Lauren sold their total mangoes for $10,350.
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Mr. Mangan is in freefall on Planet Y. His velocity increases from rest to 30 m/s in 1.2 s. If his mass is 86 kg, what is his weight on Planet Y? What is the gravitational field strength on Planet Y?
Explanation:
First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e
a stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 40 cm/s. find the rate (in cm2/s) at which the area within the circle is increasing after each of the following.
Area of circular ripple is increasing after 2sec is 6400π cm²/s,
after 3 sec is 9600π cm²/s and after 6 sec is 19200π cm²/s
An individual who throws a pebble into a body of water will likely see a splash and hear the booming plop of the pebble. He might observe a center point where the stone struck the water, with concentric circles spreading outward from it. Other outcomes of the tossed pebble could include frightening a nearby duck that jumps out of the water, hitting another rock and rebounding, or frightening a school of fish as it sinks into the pond. The individual who throws the rock is linked to the pebble, the water, and the duck and fish through his deeds. Through a single, straightforward action, he has sparked change. The ripple effect is the term used to describe this idea in education.
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What is the mass of an object that has a weight of 61.1 N?
Answer:
6.23kg
Explanation:
61.1/9.8 = 6.23kg
9.8 is the amount of gravity acting on the object so divide the weight by the gravity to get mass.
Pls help with the questions in the photo, any of them will help :)
Answer: The velocity of the bird is 7m/s
Explanation: Since momentum is the total quantity of the motion which is contained in the body.
It is defined as the multiply of mass and velocity of the body
It is given in the question that mass of bird is 2.5 kg and momentum is 17.5 kg/s.
A rocket is fired with an initial velocity of 100m/s at angle of 55degree above the horizontal it expodes on the mountain side 12 second after it's firing what is the x and y coordinates of the rocket relative to it's final point
The coordination of the rocket relative to its firing point is 688.32m and 277.44m.
What is coordination?
The purpose of organizing people or groups so they work together properly.
Sol-
The X and Y coordinates of the rocket relative of firing
As per the given question
Velocity (vi)=100ms-1
Angle=55.0
Time (t)=12
The horizontal range of projectile at X is
X=vxi×t
x=vi×cos×t
Now substituting the required value we get
X=300×cos 55×12
X=100×0.5756×12
X=688.32 m
Now substituting the recauird value
We get
Y= 983.04-705.6
Y=277.44m
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an aluminum wire having a cross-sectional area equal to 5.10 10-6 m2 carries a current of 7.50 a. the density of aluminum is 2.70 g/cm3. assume each aluminum atom supplies one conduction electron per atom. find the drift speed of the electrons in the wire.
1.29×10^-4 m/s is the drift speed of the electrons in the wire.
volume=molar mass/density= 26.98g/2.7g/cm3 = 9.99 cm3
n=(6.02E23 electron/volume)*(1.00E6 cm3/ 1 m3) = 6.024E28 m3
V= I/neA= 7.50 A/(6.024E28 m3)×(1.60E-19 C)×(5.60E-6 m2))
V= 1.29×10^-4 m/s
Electrons and other subatomic particles constantly migrate in arbitrary ways. When exposed to an electric field, electrons do travel randomly, but they do so slowly in the direction of the applied electric field. The drift velocity refers to the overall speed of these electrons.
M/s is the SI unit for drift velocity. It can also be expressed in m2/ (V.s). The relationship between the electrons' current density and their drift velocity is straightforward. Additionally, when the strength of the electric field grows, the drift velocity and current flowing through the conductor do as well.
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Which of the following equations illustrates the law of conservation of
matter?
A. 2H₂ + O₂ → H₂O
OB. 2H₂ + 202 → 2H₂0
OC. H₂ + O2 → H₂O
D. 2H₂ + O₂ → 2H₂O
SUBMO
Answer:
Explanation:
Answer : D that’s the answer
a railroad car collides and couples with a second railroad car that is standing still. if the external forces acting on the two cars are negligible, how will the velocity of the first car change after the collision?
velocity of the first car will decrese after the collision.
Momentum is conserved so when the mass of the moving system is increased by the addition of the second car the velocity will be less than that of the first car before the collision.
Most often, the collision between the objects is described in terms of conservation of momentum. In the event of an isolated system interacting with the objects, the momentum is preserved. The starting and ultimate momentum of an isolated system will be the same since there is no external force operating on the system.
When a collision happens between the two objects in the isolated system, the total momentum before the collision and the total momentum after the collision are identical. Elastic and inelastic collisions are the two forms of collision.
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