A ball is rolling down a hill with an acceleration of 7 m/s^2. The ball has a mass of 10 kg. How much force will the ball apply to a car if it hits a parked car at the bottom of the hill?

Two objects can have the same speed but different velocities. The detailed description is given below.

We can take two escalators to explain the concept. The two escalators are moving up at a speed of 10 m/s. In this case, the two escalators have the same speed and they are moving in the same direction. So, they have the same velocity also.

Now one escalator is moving up at a speed of 10 m/s and the other escalator moving down at a speed of 10 m/s. In this case, both escalators move at 10 m/s, so their speed is the same. But they are not moving in the same direction. Hence their velocity is not the same. One has 10 m/s downwards and the other one has 10 m/s upwards velocity.

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Answer:

Hope the pictures will help you

The orange was at a height of 3.26 m above the ground.

The third equation of motion is

v² - u² = 2aS

Given is an orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground.

We can write -

[v] = 8 m/s

[a] = 9.8 m/s²

[u] = 0 m/s

Using third equation of motion, we get -

v² - u² = 2aS

64 - 0 = 2 x 9.8 x S

64 = 19.6 x S

S = 3.26 m

Therefore, the orange was at a height of 3.26 m above the ground.

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The trumpet would have to be moving at a speed of approximately 345.8 m/s to raise the pitch to C sharp.

What is speed?
In everyday language and kinematics, an object's speed (typically abbreviated as "v") is defined as the size of the change in position that occurs over time or the amount of change that occurs per period of time; it therefore a vector quantity. The instantaneous speed is the upper limit of the average speed as the time interval's duration gets closer to zero; it is calculated by dividing the distance travelled by the time interval's duration. Speed and velocity are distinct concepts.

Speed is measured as distance divided by time.

To raise the pitch of a note by one semitone, the speed of sound must be increased by approximately 6%. In this case, the trumpet would have to be moving at approximately 364 m/s to raise the pitch to C sharp.

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The temperature at which the resistance will be 22.8 Ω is 100 °C

The following data were obtained from the question:

The new temperature can be obtained as illustrated below:

α = R₂ – R₁ / R₁(T₂ – T₁)

0.0065 = 22.8 – 15 / 15(T₂ – 20)

0.0065 = 7.8 / 15(T₂ – 20)

Cross multiply

0.0065 × 15 (T₂ – 20) = 7.8

0.0975 (T₂ – 20) = 7.8

Divide both side by 0.0975

T₂ – 20 = 7.8 / 0.0975

T₂ – 20 = 80

Collect like terms

T₂ = 80 + 20

T₂ = 100 °C

Thus, the temperature is 100 °C

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The Fundamental Theorem of Calculus is used to evaluate the definite integral. A important tool for simulating the dynamics of moving objects and other physical phenomena is the parametric form.

For a parameter t, the dynamics or trajectory of a moving object is given in parametric form. We determine the speed of the object over the range of its parameter using derivatives and a definite integral. The Fundamental Theorem of Calculus is used to evaluate the definite integral. A important tool for simulating the dynamics of moving objects and other physical phenomena is the parametric form.

The velocity function or vector's absolute value or norm can be used to calculate an object's speed.

We obtain the velocity v(t) as the first derivative of the position trajectory given as follows since the velocity is the rate of change of the distance traveled:

v ( t ) = r ′ ( t ) = ⟨ ( 2 t 3 ) ′ , ( − t 3 ) ′ , ( 3 t 3 ) ′ ⟩ = ⟨ 6 t 2 , − 3 t 2 , 9 t 2 ⟩

The speed is given as either its norm or absolute value in the velocity function above as follows:

Speed(t)=∥v(t)∥=∥⟨6t2,−3t2,9t2⟩∥

=√(6t2)2+(−3t2)2(9t2)2=√36t4+9t4+81t4=√126t2(2)

The speed at t = 7 will be (2) from (2).

Speed(7)=√126×72=49√126.

Using (2) and the Calculus Fundamental Theorem, the trajectory's length L can be determined as follows:

L = ∫ 7 0 ∥ r ′ ( t )∥ d t = ∫ 7 0 ∥ v ( t ) ∥ d t = ∫ 7 0 √ 126 t 2 d t = √ 126 [ t 3 3 ] 7 0 = √ 126 [ 7 3 3 − 0 3 3 ] = 7 3 √ 126 3. \s.

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Answer: x(t2)−x(t1) over the time interval [t1,t2]

Explanation: hope this helps

If the stationary female hears a tone of 1240 hertz, then the speed of the sound in the atmosphere of arrakis will be 775 meter per second.

The term "Ducler shift" refers to the apparent change in frequency caused by the source moving closer to the observer or by the relative motion between the source and the object. The formula: true frequency over 1 minus v s over v gives the observed frequency. Let's call this equation 1, shall we? The real frequency in our case is stated as 1200 hertz, but the perceived frequency is reported as 1240 hertz. It is stated that the source's velocity, vs, is 25.0 meters per second. Rearranging equation 1 yields the result that the real frequency over the absorbed is equal to 1 minus b s over v.

As a result, we can be represented as v s over 1 minus f, actual over f absorbed now 1 substituting the values we get 25.0 meter per and over 1 minus 1200 hertz over 1240 hertz. Frequency fur, the rearranging we get 1 minus f real over f absorbed, is equal to v s over v. The sound travels at a speed of 775 meters per second after further calculation.

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By assuming no frictional forces on the cart,  Same work for all five ramps would require you to do the least work.

The force produced by two surfaces coming into contact and sliding against one another is referred to as frictional force. The following variables impact the frictional force, Surface roughness and the amount of force pressing them together have the biggest an impact on these forces.

According to the work energy theorem, the net change in a body's energy is equal to the work that is done on it. K.E. or P.E. Proof: Consider a mass'm' object travelling at a 'u' starting velocity. Allow a body to vary its velocity to v in response to a constant force, F.

Let h be the height of the ramps. Since there is no friction, we can use the

work-energy theorem.

Wtot = Wperson + Wgravity = ∆K

Hence for all the ramps,

Wperson = −Wgravity + ∆K = mgh + ∆K

In particular, if ∆K = 0 (the cart starts from rest and ends at rest),

Wperson = mgh, for all the ramps.

So, the Same work for all five ramps.

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Answer:

Assume that the air resistance on the supplies is negligible, and that [tex]g = 9.8 \; {\rm m\cdot s^{-2}}[/tex].

The plane need to drop the supplies when it is horizontally approximately [tex]700\; {\rm m}[/tex] away from the hill.

The supplies will hit the tree.

Explanation:

Let [tex]u_{y}[/tex] and [tex]v_{y}[/tex] denote the initial and final vertical velocity of the supply; [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] since the plane was flying horizontally.

Let [tex]x_{y}[/tex] denote the vertical displacement of the supply; [tex]x_{y} = 350\; {\rm m} - 810\; {\rm m} = (-460)\; {\rm m}[/tex].

Let [tex]a_{y}[/tex] denote the vertical acceleration of the supply; [tex]a = (-g) = (-9.8)\; {\rm m\cdot s^{-2}}[/tex].

Make use of the SUVAT equation [tex]{v_{y}}^{2} - {u_{y}}^{2} = 2\, a_{y}\, x_{y}[/tex] to find [tex]v_{y}[/tex], the final vertical velocity of the supply:

[tex]\begin{aligned} {v_{y}}^{2} &= {u_{y}}^{2} + 2\, a_{y}\, x_{y} \end{aligned}[/tex].

[tex]\begin{aligned} v_{y} &= -\sqrt{{u_{y}}^{2} + 2\, a_{y}\, x_{y}} \\ &= -\sqrt{0^{2} + 2\, (-9.8)\, (-460)}\; {\rm m\cdot s^{-1}} \\ &\approx (-94.953)\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

(Negative since the supply would be travelling downwards.)

Let [tex]t[/tex] denote time it takes for the supply to land on the hill after being dropped from the plane. Make use of the SUVAT equation [tex]t = (v_{y} - u_{y}) / (a)[/tex] to find the value of [tex]t\![/tex]:

[tex]\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-94.953) - 0}{(-9.8)} \; {\rm s}\\ &\approx 9.6890 \; {\rm s} \end{aligned}[/tex].

Apply unit conversion and ensure that [tex]v_{x}[/tex], the horizontal speed of the plane is in the standard unit [tex]{\rm m\cdot s^{-1}}[/tex]:

[tex]\begin{aligned} v_{x} &= \frac{260\; {\rm km}}{1\; {\rm h}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 72.222\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Under the assumptions, the horizontal speed of the supply will be the same as that of the plane- [tex]v_{x} \approx 72.222\; {\rm m\cdot s^{-1}}[/tex]- until it lands.

While in the air, the supply will travel a horizontal distance of:

[tex]\begin{aligned}x_{x} &= v_{x}\, t \\ &\approx 72.222\; {\rm m\cdot s^{-1}} \times 9.6890\; {\rm s} \\ &\approx 699.76\; {\rm m}\end{aligned}[/tex].

Hence, for the supply to land exactly at the top of the hill, the plane need to drop the supply while at a horizontal distance of approximately [tex]700\; {\rm m}[/tex] away from the hill.

The horizontal distance between the trees and the location where the plane dropped the supply would be approximately [tex](700\; {\rm m} - 30\; {\rm m}) = 670\; {\rm m}[/tex]. The time required for the the supply to reach that horizontal position would be:

[tex]\begin{aligned} t &= \frac{x_{x}}{v_{x}} \approx \frac{669.76\; {\rm m}}{72.222\; {\rm m\cdot s^{-1}}} \approx 9.2736\; {\rm s}\end{aligned}[/tex].

Let [tex]h_{0}[/tex] denote the initial height of the supply (relative to the sea level.) In this question, [tex]h_{0} = 810\; {\rm m}[/tex].

Let [tex]h(t)[/tex] denote the height of the supply (relative to the sea level) after being dropped from the plane for time [tex]t[/tex].

The SUVAT equation [tex]h(t) = (1/2)\, a\, t^{2} + u_{y}\, t + h_{0}[/tex] gives an expression for [tex]h(t)[/tex]. Make use of this equation to find the height of the supply (relative to the sea level) when the supply reach the horizontal position of the trees at [tex]t \approx 9.2736\; {\rm s}[/tex]:

[tex]\begin{aligned} h(t) &= \frac{1}{2}\, a\, t^{2} + u_{y}\, t + h_{0} \\ &= \frac{1}{2}\times (-9.8)\, (9.2736)^{2} + 0\times 9.2736 + 810 \\ &\approx 388.60\; {\rm m} \end{aligned}[/tex].

Note that the altitude of the top of the trees is [tex]350\; {\rm m} + 40\; {\rm m} = 390\; {\rm m}[/tex] relative to the sea level. Since [tex]388.90\; {\rm m} < 390\; {\rm m}[/tex], the supplies will run into the trees.

Equation Q/A = E Electric Field within a parallel plate capacitor

∴ Q = E*Aε

E = 10^6 N/C

A = 4*4 = 16cm^2 = 16 * 10^-4 m^2

ε = 8.852 * 10^-12 F/m

Q = +/- 10^6 * 16 * 10^-4 * 8.852 * 10^-12

= +/- 141.6 * 10^-10 C

= +/- 14.2 nC

You can think of an electric field as a physical field that surrounds all charged particles and pulls on them all.

Before the dielectric breaks down, a parallel plate capacitor can only hold a certain amount of energy. It can be stated as follows: The parallel plate capacitor is a device that uses two parallel plates connected across a battery to create an electric field between them.

A nonmetallic component of a circuit is made in touch with using an electrode, an electrical conductor. Depending on the type of battery, electrodes are a crucial component that can be made of a range of materials.

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Answer:

Explanation:

V = Vb - Va = 30 - 25 = 5 km/h

Answer:

See below

Explanation:

P1V1/T1 = P2V2/T2      IF  T1 = T2

Then

P1V1 = P2V2       P2 = 1/2 P1

P1V1 = 1/2 P1 V2        DIVIDE BOTH SIDES BY P1

V1 = 1/2 V2        MULTIPLY BOTH SIDES BY 2

2V1 = V2           OR     V2 = 2 V1     THE NEW VOLUME IS TWICE ORIGINAL

Answer:

its upto your mind and magic

Explanation:

The distance that separates the charges is 0.7 m.

The distance between the charges is determined by applying Coulomb's law of electrostatic force as shown below.

F = kq₁q₂/r²

where;

r² = kq₁q₂/F

r² = (9 x 10⁹ x 8 x 10⁻⁴ x 3 x 10⁻⁴) / (4.4 x 10³)

r² = 0.49

r = √0.49

r = 0.7 m

Thus, the distance that separates the charges is 0.7 m.

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If there are n wires per unit length, magnitude of B measure at A or C is B = Ωo*n*I/2

A key concept in science is the concept of magnitude in physics. The general quantity or distance is referred to as magnitude. When it comes to the elements of movement, we can tie magnitude to an object's size and motion speed.

A particular object's magnitude is determined by its size or quantity. For instance, when it comes to speed, if a car is moving at a quicker rate than a nearby motorcycle, the magnitude of the automobile's speed is greater than the speed of the motorcycle. Although they contain directions as well as magnitude, vector quantities. Vector quantities include things like force, acceleration, speed, velocity, and many others. A vector's absolute value is referred to as its magnitude.

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The power given to A is 7 times more powerful than the power delivered to B. So, the ratio of the power delivered to a to the power delivered to b is 7:1.

A wire's cross sectional area is computed as follows:

A= πd²/4

A wire's resistance is calculated as;

R= pL/A

R= 4pL/πd²

opposition in wire A;

R= 4pALA/πd²A

opposition in wire B;

P = V²/R

wired power delivery;

P= V²A/RA

energy provided through cable A;

P= V²b/Rb

energy transferred through wire B;

Replace R's value in the power delivered through wire A;

PA= V²A/RA = V²Aπd²/4pALA

PA/PB = d²A/LA x LB/V²B/d²B

The diameter and length of wire A are both seven times greater than those of wire B;

PA : PB = 7 : 1

Consequently, the power given to A divided by the power transferred to B equals 7 : 1

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Answer:

The Answer is D. 300 s because in 5 minutes there are 300 seconds

In the psychology experiment in which Hakeem participates, UCS is click, UCR is blink and tear up, CS is blowing a puff of air, CR is thought of the puff of air and NS is the click before puff of air was introduced.

In psychology the abbreviations of the given terms are as follows:

Here the Unconditioned Response is the blinking and tearing up because he does that even though there is no puff of air. Since clicking provokes the Unconditioned Response, clicking is the Unconditioned Stimulus. The clicking is paired with puff of air for multiple times, that is why Unconditioned Response is stimulated. So the puff of air is the Conditioned Stimulus.

Therefore,

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The magnitude of the force exerted by the heart muscle is 0.02N

since

F = m dv/dt

  = 0.02(0.35-0.25)/0.10

F =0.02N.

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.

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Given:

Speed of light = 3 x 10⁸ m/s

Let's solve for the following:

• (a). How many miles does a pulse of light travel in a time interval of 0.1 s, which is about the blink of an eye?

Apply the formula:

Where:

v is the speed of light

t is the time.

Thus, we have:

Now let's convert the answer from meters to miles.

Where:

1 mile = 1609.34 meters

Δx = 18641.14 mi

• (b). Compare this distance to the diameter of Earth.

Apply the formula:

Where:

r = 6.38 x 10⁶ m.

Thus, we have:

ANSWER:

• (a). 18641.14 mi

• (b). 2.35

Answer:

About 150 million kilometers

Explanation:

have good day♡

The total tangential speed = 3.56 m/s

, r =2 m ,

t =44sw

=17rpm = 17*2*3.14/60

= 1.7793 rad/swo =

01) from rotational kinematic equation

w =wo+t1.7793 =0 + *44 =0.0404 rad/s^2

(2) from rotationla kinematic equation

w^2 -wo^2 = 21.7793*1.7793

= (2*0.0404*)=39.18 rad

3) v =rw =2*1.7793

tangential speed = 3.56 m/s

What is average angular acceleration?

A spinning object's change in angular velocity per unit of time is expressed quantitatively as angular acceleration, also known as rotational acceleration. It is a vector quantity with either one of two predetermined directions or senses and a magnitude component.

The formula for average angular acceleration is: a = change in velocity divided by change in time. a=(w2−w1)/(t2−t1) a = ( w 2 − w 1 ) / ( t 2 − t 1 ) . w2 represents the final velocity measured in radians per second. w1 represents the initial velocity measured in radians per second.

Therefore, tangential speed = 3.56 m/s

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A ball's gravitational potential energy will rise as it is launched vertically upward.

An object's gravitational potential energy is the power it has as a result of being in a gravitational field. The gravitational potential energy is most frequently used for an object close to the Earth's surface, when the gravitational acceleration is believed to remain constant at around 9.8 m/s2. Since any point can be chosen as the gravitational potential energy zero (just like any coordinate system zero), the potential energy at a height h above that point is equal to the work that would be needed to lift the item to that height with no net change in kinetic energy. Its weight must be lifted with the same amount of force, so the gravitational potential energy must also be equal. The gravitational potential energy is most frequently used for an object close to the Earth's surface, when the gravitational acceleration is believed to remain constant at around 9.8 m/s2. Multiple factors affect the gravitational potential energy of an object: its mass, the gravitational acceleration it experiences from the earth, and its distance from the ground.

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Answer:

0.5seconds

Explanation:

where

initial velocity u=5m/s

gravity g=9.8m/s²

final velocity v=0m/s (since velocity at maximum height is 0)

time t=?

using

v=u-gt

0=5-9.8(t)

0=5-9.8t

9.8t=5

t=5/9.8

t=0.5102040816

t=0.5sec

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These 2 statements are 2 steps of solar planet formation 1st statement is 3rd step 2nd statement is 4th step.

In the cosmos, there are a lot of planetary systems with solar planets around a host star, similar to our own. Because we refer to things that are connected to our star as "solar," our planetary system is sometimes known as "the solar system," after the Latin word for the Sun, "solis." The Sun, our star, and everything gravitationally connected to it, including the moons, planets, and dwarf planets like Pluto, Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, make up our solar system. Thousands of planetary systems orbiting other stars in the Milky Way have been found, in addition to our solar system. The Milky Way galaxy's outer spiral arm is where our solar system is situated. In our solar system, there is only the Sun.

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Answer:

c. equal equal to the magnitude of f

An example of demonstrative evidence is the digital rendering of the crime scene that shows where the gun was fired from. That is option B.

A demonstrative evidence is the type of evidence that is being represented using visuals to help enhance the facts of a claim made against an opponent in the law court.

The components of demonstrative evidence include the following:

Based on the various evidence presented concerning the sudden death of Mr. Red Herring who was short dead in his backyard, the demonstrative evidence is when the forensics team also created a digital rendering of the crime showing where the gun was shot.

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Options of question:

In this story, which is an example of demonstrative evidence?

The fingerprint that showed that Mrs. Scarlet handled the gun

The digital rendering of the crime scene that shows where the gun was fired from

The report about bullet striations that prove the shot came from the discarded weapon

The DNA evidence gathered from the blood splatters