Answer:
The minimum horizontal force that must be applied to keep the bag moving at constant velocity once it has started to move is 16 newtons.
Step-by-step explanation:
According to the First and Second Newton's Laws, an object has net force of zero when it is at rest or moves at constant velocity. Given that bag rests on a horizontal surface, the equation of equilibrium is:
[tex]\Sigma F = P - f = 0[/tex] (Eq. 1)
Where:
[tex]P[/tex] - Horizontal force exerted on the bag, measured in newtons.
[tex]f[/tex] - Kinetic friction force, mesured in newtons.
From (Eq. 1), we get that horizontal force is:
[tex]P = f[/tex]
On the case of a horizontal surface, normal force exerted from ground on the bag and kinetic friction force is:
[tex]f = \mu_{k}\cdot W[/tex] (Eq. 2)
Where:
[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.
[tex]W[/tex] - Weight of the bag, measured in newtons.
Then we eliminate kinetic friction force by equalizing (Eqs. 1, 2):
[tex]P = \mu_{k}\cdot W[/tex]
If we know that [tex]\mu_{k} = 0.2[/tex] and [tex]W = 80\,N[/tex], then the horizontal force that must be applied to is:
[tex]P =0.2\cdot (80\,N)[/tex]
[tex]P = 16\,N[/tex]
The minimum horizontal force that must be applied to keep the bag moving at constant velocity once it has started to move is 16 newtons.
Which of the following statements correctly compares the two numbers?
1.025 5.072
6.403 > 6.43
8.962 < 8.692
Answer:
do you still need help ??
(-7) • (-5) what does it equal to
Answer:
35
Step-by-step explanation:
Negative × negative = Positive-7 × -5 = 35I hope this helps!
Answer:
35
Step-by-step explanation:
Simplify
(-7) X (-5)
Negatives cancel out so its going to be positive
That's how you get 35.
How far can a cheetah run in 2 hours at a speed of 40 miles/hour?
What does that equal??
Answer:
I beileve its 1 and 7/15
Step-by-step explanation:
It was for a test and I beileve I got a 100
Answer:
1 whole, 7/15
Step-by-step explanation:
Step 1_ (23×55)+(45×33)=?
Step 2_ 1015+1215=?
Step 3_ 10+1215=2215
Step 4_ 2215
Step 5_ 22÷15
Step 6_ 2215=1715
Step 7_ 23+45=1715
BTW THE NUMBERS ARE FRACTIONS NOT WHOLE NUMBERS
HOPE THIS HELPS!!
Please help answering these questions 10 points help please (look at the picture)
Answer:
46. -22
47. -22
48. 8
Answer:
46) -22
47) -22
48) 8
49) -8
50) -4
51) 4
Step-by-step explanation:
Which expression is equal to 527.471?*
(5x100)+(2x10)+(7x1)+(4x10) + (7x100)+ (1x1,000)
(5x100,000)+(2x10,000)+(7x1,000)+(4x100) + (7x10)+ (1x1)
(5x100)+(2x10)+(7x1)+(4x1/1) + (7x1/10)+ (1x1/100)
(5x100)+(2x10)+(7x1)+(4x1/10) + (7x1/100)+ (1x1/1,000)
Answer:
Step-by-step explanation:
527.471 =(5 ×100.000) +(2 ×10.000) +(7 ×1.000) +(4 ×100) +(7 ×10) +(1×1)
Answer:
500029301.171
Step-by-step explanation:
Heeeeeeeeelp pls I need help
Answer:
I am pretty sure that is is 64
Step-by-step explanation:
but i used a calculator soooo
what is the equation in slope intercept form 6x-4y=12 ?
Answer:
y=6/4x-3
Step-by-step explanation:
First, you isolate the y, by subtracting 6x from each side. Then, you divide by -4 on both sides to isolate it to an individual y.
Answer:
Slope = 6/4 or 1 1/2
Step-by-step explanation:
Step 1:
6x - 4y = 12 Equation
Step 2:
y = mx + b Slope Intercept Form
Step 3:
- 4y = - 6x + 12 Subtract 6x on both sides
Step 4:
y = 6/4x + 12 Divide 4 on both sides
Answer:
Slope = 6/4 or 1 1/2
Hope This Helps :)
help!!!!!!!!!!!!!!!!
Answer:
2600%
Step-by-step explanation:
The probability that a truck will be going over the speed limit on I-77 South between Dobson and Elkin is about 75%. Suppose a random sample of five trucks are observed on this stretch of I-77. a. Find the mean of this probability distribution. Show the formula and your work. b. Interpret the mean in the context of the problem. c. Find the standard deviation of this probability distribution. Round your answer to 2 decimal places. d. Find the probability that exactly 3 of the observed trucks are speeding. e. Find the probability that less than 3 of the observed trucks are speeding.
Answer:
Explained below.
Step-by-step explanation:
Let X = number of trucks that will be going over the speed limit on I-77 South between Dobson and Elkin.
The probability of X is, p = 0.75.
A random sample of n = 5 trucks are observed on this stretch of I-77.
The random variable X follows a binomial distribution with parameters n = 5 and p = 0.75.
(a)
Compute the mean as follows:
[tex]\mu=n\times p=5\times 0.75=3.75[/tex]
The mean of this probability distribution is 3.75.
(b)
The mean of 3.75 implies that on average 3.75 trucks that will be going over the speed limit on I-77 South between Dobson and Elkin.
(c)
Compute the standard deviation as follows:
[tex]\sigma=\sqrt{np(1-p)}=\sqrt{5\times 0.75\times (1-0.75)}=0.968[/tex]
Thus, the standard deviation of this probability distribution is 0.97.
(d)
Compute the probability that exactly 3 of the observed trucks are speeding as follows:
[tex]P(X=3)={5\choose 3}(0.75)^{3}(1-0.75)^{5-3}\\\\=10\times 0.421875\times 0.0625\\\\=0.263671875\\\\\approx 0.2637[/tex]
Thus, the probability that exactly 3 of the observed trucks are speeding is 0.2637.
(e)
Compute the probability that less than 3 of the observed trucks are speeding as follows:
[tex]P(X<3)=P(X=0)+P(X=1)+P(X=2)\\\\=\sum\limits^{2}_{x=0}{{5\choose x}(0.75)^{x}(1-0.75)^{5-x}}\\\\=0.0009765625+0.0146484375+0.087890625\\\\=0.103515625\\\\\approx 0.1035[/tex]
Thus, the probability that less than 3 of the observed trucks are speeding is 0.1035.
Give the missing reasons for this proof (with picture)
2. alternate angles I think
3. vertically opposite angles
4. Interior angles
Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!
Answer: (for the sentence) an endpoint; one direction
Step-by-step explanation:
Drag the point that does not have an arrow after it to point A and the other one to point B.
Answer:
you move it to align with a and the starting point is B.
Step-by-step explanation:
it is a ray because it has a starting point but goes forever in one direction.
can you give me brainliest?
please help with my guided practice
it's 88 I've been getting so mix up forgive me So the area of the square is 64. When you find the area of the triangle you multiply the base by its height, which is 6 by 8 and then you divide by two. 64+24=88
Help me or I’ll kith you
Answer:
The answer is (-2,10)
Fahrenheit 451
Write a paragraph on the imagery' from this text with evidence, as well as a second paragraph for the mood.
Answer:
mark above answer BRILLIANT
A truck used 6.3 gallons of gasoline to travel 105 miles. How many gallons of gasoline would it need to travel 250 miles? A 15 gallons B 4,166.7 gallons С 150 gallons D 16.7 gallons
Answer:
a
Step-by-step explanation:
got it right in my test
Math helppppppppppp
-0.05/ -5/8
6 1/4/ -5/16
-3/5 / 2 1/4
-9/10/ 1 3/5
Answer:
1) 0.08
2) -20
3) -4/15 or -0.26 repeating
4) -9/16 or -0.5625
At the beginning of a baking session, there were 2.26 kilograms of flour in the bag. By the end of the baking session, there was 0.98 kilogram
of flour in the bag. What is the percent of decrease in the amount of flour? Round the percent to the nearest tenth if necessary?
The answer is not 32 or 43.4.
Answer:
56.6%
Step-by-step explanation:
To calculate percent decrease, you first subtract the original number with the final number.
2.26 - 0.98 = 1.28
Then, you divide your answer by the original number.
1.28/2.26 = 0.56637168141
Finally, you multiply your answer by 100 and round as necessary.
0.56637168141 x 100 = 56.637168141
The stemplot shows the number of magazines sold by students in a band. One data value was inadvertently omitted from the stemplot. A stemplot titled magazines sold has values 8, 9, 12, 12, 13, 15, 16, 16, 16, 18, 21, 22, 23, 27, 28, 32, 34, 40. Which statement is true? If the missing data value was 55, the range of the data would change significantly. If the missing data value was 55, the interquartile range of the data would change significantly. If the missing data value was 22, the range of the data would change significantly. If the missing data value was 22, the interquartile range of the data would change significantly.
Answer:
If the missing data value was 55, the range of the data would change significantly
If the missing data value was 22, the interquartile range of the data would change significantly
Step-by-step explanation:
Given the data
8, 9, 12, 12, 13, 15, 16, 16, 16, 18, 21, 22, 23, 27, 28, 32, 34,40
The range of the data is the difference between the highest value and the lowest value of the data.
Highest value = 40
Lowest value = 8
Range = 40-8
Range = 32
If 55 was missing, we need yo find the range of the data if 55 was included.
Highest value will be 55
Lowest value = 8
Range in this case = 55-8
Range = 47
Difference in range = 47-32= 15
This means that if 55 was missing, it will significantly affect the value of the range.
- Interquartile range = Q3-Q1
Q3 is the median value of the other half of the data.
Q1 is the median value of the first half of the data.
If 55 wasn't included, the first part of the data:
8, 9, 12, 12), 13, (15, 16, 16, 16
Q1 = 13 (median value of the extracted data)
The second part of the data if 55 wasn't included:
18, 21, 22, 23), 27, (28, 32, 34, 40
Q3 = 27 (median value of the second part of the data)
IQR = Q3-Q1
IQR = 27-13
IQR = 14
If 55 was included, the data will be;
8, 9, 12, 12, 13, 15, 16, 16, 16, 18, 21, 22, 23, 27, 28, 32, 34, 40,55
Q1 = N+1/4 the value
N is the sample size = 19
Q1 = 19+1/4
Q1 = 20/4
Q1 = 5th value
The 5th value in the data is 13, hence Q1 is 13
Q3 = 3(N+1)/4th value
Q3 = 3(19+1)/4
Q3 = 60/4
Q3 is the 15th value in the dataset. Since the 15th value is 28, Q3 is 28
IQR = 28-13
IQR = 15 (if 55 was included)
Difference in IQR = 15-14 = 1
This means that if 55 was the missing data, the IQR will not change significantly.
Note that the range of the data will not change if the missing value is 22 because, the 22 is a value lower than the highest value of the dataset, hence the range will remain the same (40-8 = 32) irrespective of 22 missing or not.
For the Interquartile range
If 22 was in
Q3 = 3(N+1)/4th value
Q3 = 3(19+1)/4
Q3 = 60/4
Q3 is the 15th value in the dataset. Since the 15th value is 28, Q3 is 28
IQR = 28-13
IQR = 15 (if 55 was included)
Difference in IQR = 15-14 = 1
This means that if 55 was the missing data, the IQR will not change significantly.
Based on the calculation, the correct options are:
- If the missing data value was 55, the range of the data would change significantly
- If the missing data value was 22, the interquartile range of the data would change significantly
Answer:
a
Step-by-step explanation:
edge 2021
A hot air balloon went from an elevation of 5,340 ft to an elevation of 3,436 ft in 32 minutes what was its rate of descent?
The rate of descent was ____ feet per minute.
Please help ASAP my assignment is due in less then an hour.
Answer
The rate of descent was 59.5 feet per minute
Step-by-step explanation:
Fully Simplify (multiplying imaginary numbers)
(-3_/-63) (9_/7)
See attachment for math work and answer.
How do you write -4.50 as a mixed number
Answer:
-9/2
Step-by-step explanation:
can yall help me plz
Answer:
lol girl i have this one too and im trying to do cuz no one cam to help me so im going to try and then i will see if i help you
Step-by-step explanation:
Answer:
just add thos and then put then to geter and you get 3x+1^2
Step-by-step explanation:
find the surface area
Answer:
The surface area of the box is 496² m.
(11*8)+(11*8)+(11*8)+(11*8)+(8*9)+(8*9)=496
Which of the following is a solution to the Equation 2x^2+4y=3=3x^2
A)-1
B)0
C)3
D)6
Answer:
3
Step-by-step explanation:
I think 3 is the answer
Select the correct answer.
The table represents a proportional relationship.
ху
112
BE
224
336
There are 20,000 animals in a zoo. There are 650 mammals and 225 reptiles that live in the zoo. what fraction of all the animals are a)reptiles b)mammals
Answer:
You have to simplify to the lowest common denominator
Step-by-step explanation:
650/20000=13/400 mammals
225/20000=9/800 reptiles
875/20000=7/160 mammals or reptiles
Hope this helped
Problem ID: PRA3VP4 The veterinarian weighed Oliver's new puppy, Boaz, on a defective scale. He weighed 36 pounds. However, Boaz weighs exactly 34.5 pounds. What is the percent of error in measurement of the defective scale to the nearest tenth? Do not include units, %, in your answer. Modified
Answer: 4.1%
Step-by-step explanation:
Given data:
Measure value ( actual) = 36 pounds
Expected value = 34.5 pounds
Solution:
Percentage error = Actual value - expected value / expected value * 100
= 36 - 34.6 / 34.6 * 100
= 1.4/34.6 * 100
= 0.041 * 100
= 4.1
The percentage error is 4.1%
1/2a + 1/3a =5 please help :)
Answer:
a=6
Step-by-step explanation:
1/2a+1/3a=5
5/6a=5
a=6
hope this helps
brainliest?
Answer:
a=6
Step-by-step explanation:
1/2a + 1/3a =5
Multiply each side by 6 to clear the fractions
6(1/2a + 1/3a) =5*6
3a +2a = 30
Combine like terms
5a = 30
Divide by 5
5a/5 = 30/5
a = 6
what is 2 to the second power
Answer:
4.
Step-by-step explanation:
Hope this helps! <3