The pH of the resulting solution is approximately 4.56.
A formic acid sodium formate solution is made up by dissolving 0.2 mole of formic acid and 0.3 mole of sodium formate in 500 InL of water. The pH of the resulting solution, we need to use the Henderson-Hasselbalch equation:pH = pKa + log([salt]/[acid])Here, the acid is formic acid and the salt is sodium formate. The pKa of formic acid is 3.75. Thus:pH = 3.75 + log([0.3]/[0.2])= 3.75 + log(1.5)= 3.75 + 0.18= 3.93Therefore, the pH of the resulting solution is approximately 3.93.b) If 0.05 mL of 12 M HCl is added to this buffer solution, we can find the new concentration of formic acid and sodium formate and then use the Henderson-Hasselbalch equation again to find the new pH. First, let's calculate how much HCl is added:0.05 mL = 0.05 x 10^-3 LNow, we can calculate the new concentration of formic acid:[H+] = 12 M (from HCl)initial concentration of formic acid = 0.2 mole/0.5 L = 0.4 Mnew concentration of formic acid = 0.4 M + (0.05 x 10^-3 L) x (12 mol/L) / (500 mL) = 0.40024 MNext, we can calculate the new concentration of sodium formate:[OH-] = Kw / [H+] = (10^-14) / (12 M) = 8.33 x 10^-14 Minitial concentration of sodium formate = 0.3 mole/0.5 L = 0.6 Mnew concentration of sodium formate = 0.6 M + (8.33 x 10^-14 M) x (0.05 x 10^-3 L) / (500 mL) = 0.60004 MNow we can use the Henderson-Hasselbalch equation again:pH = pKa + log([salt]/[acid])= 3.75 + log(0.60004/0.40024)= 3.75 + 0.16= 3.91Therefore, the pH of the resulting solution is approximately 3.91.c) If 0.0125 mole of NaOH is added to the original solution in part a), we can use the Henderson-Hasselbalch equation to find the new pH. First, we need to calculate the new concentration of sodium formate:[OH-] = 0.0125 mole / 0.5 L = 0.025 Minitial concentration of sodium formate = 0.3 mole/0.5 L = 0.6 Mnew concentration of sodium formate = 0.6 M - 0.025 M = 0.575 MNow we can use the Henderson-Hasselbalch equation:pH = pKa + log([salt]/[acid])= 3.75 + log(0.575/0.2)= 3.75 + 0.81= 4.56Therefore, the pH of the resulting solution is approximately 4.56.
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Someone plz help me
Answer:
maybe falling
Explanation:
Air is a force so its probably pushing down the object then making it fall
I think all objects? Not entirely sure.
HELP ME ASAPPP plsss
in the following reaction, which element in what species is reduced? zn (s) 2 hcl (aq) → zncl₂ (aq) h₂ (g)
Answer : The element that is reduced in the given reaction is hydrogen (H).
Explanation: In the given reaction, Zn (s) 2 HCl (aq) → ZnCl₂ (aq) H₂ (g), Zinc (Zn) is oxidized to form Zinc chloride (ZnCl2). The reduction occurs in the other half of the reaction, where hydrogen cation (H+) from HCl is reduced to hydrogen (H2) gas. The reduction occurs because hydrogen is gaining electrons, which is the opposite of oxidation.The redox reaction in question can be broken down into two half-reactions:Zn (s) → Zn2+ (aq) + 2 e- (reduction half-reaction)2 H+ (aq) + 2 e- → H2 (g) (oxidation half-reaction)Hence, the element that is reduced in the given reaction is hydrogen (H).
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Cooking an egg is one type of process, while the formation of snow is another. Which answer best explains which is exothermic and which is endothermic? Cooking an egg is endothermic because the egg gains heat from the surrounding Formation of snow is exothermic because water loses heat to the surrounding wh becomes snow. Cooking an egg is exothermic because the egg loses heat to the surroundings. Formation of snow is endothermic because water gains heat when it forms snow
Cooking an egg is endothermic because the egg gains heat from the surrounding. The formation of snow is exothermic because water loses heat to the surroundings when it becomes snow.
The endothermic process refers to the process in which heat is absorbed, while the exothermic process refers to the process in which heat is released.
The egg receives/absorbs heat from a heat source,(e.g. the stove), which raises the temperature of the egg and causes it to cook, making it an endothermic process.
On the other hand, heat is released from the water molecule when the water vapor present in the atmosphere condenses and freezes to form snow. Therefore, the formation of snow is exothermic.
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Cooking an egg is endothermic because the egg gains heat from the surroundings, while the formation of snow is exothermic because water loses heat to the surroundings, resulting in the formation of snow.
In terms of energy transfer, an endothermic process absorbs heat from the surroundings, while an exothermic process releases heat to the surroundings. When cooking an egg, heat is applied to the egg through methods such as boiling, frying, or baking. The egg absorbs heat from the surrounding environment to cook and undergo chemical and physical changes. As a result, cooking an egg is an endothermic process because the egg gains heat from its surroundings.
On the other hand, the formation of snow occurs when water vapor in the atmosphere condenses into ice crystals. This process is exothermic because water vapor loses heat to the surroundings, causing the water molecules to slow down and form a solid structure. The release of heat during this phase transition results in the formation of snow. Therefore, the correct explanation is that cooking an egg is endothermic because the egg gains heat from the surroundings, while the formation of snow is exothermic because water loses heat to the surroundings, leading to the formation of snow.
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what is the ratio between the energy and oxygen based on the equation
The ratio between the energy and oxygen is 21.36 kJ/g of oxygen.
According to the given balanced equation:C_{2}H_{5}OH + 2O_{2} → 2CO_{2} + 3H_{2}O + 1367 kJ. The balanced equation tells us that one molecule of C_{2}H_{5}OH reacts with two molecules of O2 to form two molecules of CO2, three molecules of H_{2}O, and 1367 kJ of energy. Therefore, to determine the ratio between energy and oxygen, we need to first find the energy released per mole of O2 reacted. To do this, we need to use the energy released by the combustion of 1 mole of C_{2}H_{5}OH, which is given as 1367 kJ. So, 1 mole of C_{2}H_{5}OH releases 1367 kJ of energy. To balance the equation, 2 moles of O2 are required for every mole of C_{2}H_{5}OH reacted. So, 2 moles of O2 is equivalent to 1367 kJ of energy. Therefore, the energy released per mole of O2 is 1367/2 = 683.5 kJ/mol. Oxygen has a molar mass of 32 g/mol and therefore the mass of one mole of oxygen is 32 g/mol. Using the molar mass of oxygen and the energy released per mole of O2, we can calculate the energy released per gram of oxygen as follows: Energy released per gram of O2 = Energy released per mole of O2 / Molar mass of O2= 683.5 / 32 = 21.36 kJ/g. Therefore, the ratio between the energy and oxygen is 21.36 kJ/g of oxygen.
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complete question: C_{2}H_{5}OH + 2O_{2} → 2CO_{2} + 3H_{2}O + 1367 kJ
What is the ratio between the energy and oxygen based on the equation?
-[?] kJ
[?]mol O2
write out the mechanism on a separate sheet of paper, and then draw the structures of amide anion 1 and carbinolamine 6.
The conversion of a carboxylic acid to an amide is accomplished by the interaction of the acid with a reagent capable of converting the carboxylate ion into the amide anion1.
Here's the mechanism for this conversion:The mechanism of this reaction is shown below:The first step is the addition of the nucleophile, which is the nitrogen in the amine, to the carbonyl carbon of the carboxylic acid. This addition causes the formation of a tetrahedral intermediate that is then protonated to form an imidic acid. The intermediate loses water to form an amide anion. When a molecule of water is removed, an amide is generated from the reaction between the carboxylic acid and the amine. Here are the structures of amide anion 1 and carbinolamine 6:Structures of amide anion 1 and carbinolamine 6 are given as follows:Image transcriptions:Image 1:Structure of amide anion 1:Image 2:Structure of carbinolamine 6:
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Given the balanced reaction: 2KOH + H2SO4 → 2H20 + K2SO4
What mass of KOH is required to react completely with 2.70 grams of
H2SO4 to produce K2SO4 and water?
Molar mass of H2SO4 is 98 grams.
Molar mass of KOH is 56 grams.
O 2.36 g
O 3.09 g
4.73 g
O 1.54 g
I will give brainliest
Answer: 3.09 g
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} H_2SO_4=\frac{2.70g}{98g/mol}=0.0275moles[/tex]
The balanced chemical equation is
[tex]2KOH+H_2SO_4\rightarrow 6H_2O+K_2SO_4[/tex]
According to stoichiometry :
1 mole of [tex]H_2SO_4[/tex] require 2 moles of [tex]KOH[/tex]
Thus 0.0275 moles of [tex]H_2SO_4[/tex] will require=[tex]\frac{2}{1}\times 0.0275=0.0551moles[/tex] of [tex]KOH[/tex]
Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.0551moles\times 56g/mol=3.09g[/tex]
Thus 3.09 g of KOH is required to react completely with 2.70 grams of
[tex]H_2SO_4[/tex]
ClO3−
Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the formal charges of all atoms in the correct structure.
The molecule ClO₃⁻ consists of one chlorine atom (Cl) and three oxygen atoms (O), with a negative charge (⁻) on the molecule.
The molecule ClO₃⁻ consists of one chlorine atom (Cl) and three oxygen atoms (O), with a negative charge (⁻) on the molecule.
The chlorine atom (Cl) is in the center, bonded to one oxygen atom (O) through a single bond and to the other two oxygen atoms (O) through double bonds. Each oxygen atom (O) has two lone pairs of electrons around it.
When all the electrons of an atom are shared equally, the charge attained by the atom is known as a formal charge.
The formal charge can be calculated as:
Formal charge =
valence electron - non-bonding electron - bonding electron/2
In the molecule, the formal charge of Oxygen = -1.
In the molecule, the formal charge of Chlorine = +2
The oxygen atom has 8 electrons, in which 2 are shared in the bond formation, and 6 electrons are valence electrons.
The chlorine atom has 7 valence electrons in which 6 electron pairs are shared with the oxygen atom, and 1 lone pair has been available with Cl.
The structure of molecule ClO₃⁻ has been given in the image attached. The image shows the available lone pairs and the bonding in the structure.
Thus, the molecule has a formal charge of -1 on all oxygen atoms, and +2 on the Cl atom.
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For which of the following equations would the value of Kp = Kc(RT)? Note Kc is sometimes called K.
A. A (g) + 2B (s) = C(s) + 2 D (g)
B. 2 NO₂ (g) = N₂O. (g)
C. 2 NBr. (g) = N₂ (g) + 3 Br₂ (g)
D. 2 HI (g) H₂(g) + 12 (g)
The equation for which the value of
Kp = Kc(RT) is valid is B.
2 NO₂(g) ⇌ N₂O₄(g).
The equilibrium constant (Kc) for the forward reaction is the ratio of the product of the concentration of the products to the product of the concentrations of the reactants, with each concentration raised to the power corresponding to the number of moles of that substance in the balanced chemical equation.
The expression for Kc is as follows:
Kc = [C]c [D]d/[A]a [B]b
Where [ ] represents the concentration of each substance in moles per liter and a, b, c, and d are the coefficients in the balanced chemical equation, as shown above.
Thermodynamic equilibrium constant is denoted by Kp. If we use the ideal gas law, we can link Kp and Kc as follows:
Kp = Kc(RT)ⁿ
where R is the ideal gas constant, T is the temperature in Kelvin, and n is the number of moles of gaseous product minus the number of moles of gaseous reactant.
For the equation,
2 NO₂(g) ⇌ N₂O₄(g)
we can see that the products and reactants are in gas phase.
Hence, the value of
Kp = Kc(RT)
is valid for this equation.
Answer: B. 2 NO₂(g) ⇌ N₂O₄(g)
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explain why it is important to eat the wet sand before heating the iron wool
Answer:
huh,eat wet sand b4heating iron wool??
Define Neutralisation reaction along with examples.
Answer:
Please find the definition and example of neutralization reaction below
Explanation:
In chemistry, neutralization reaction is a type of reaction involving a base and an acid to form salt and water. In other words, when an acid and a base comes together chemically to form a salt and water, a neutralization reaction is said to occur.
For example; in a reaction between sodium hydroxide (NaOH) and hydrogen chloride (HCl) as follows:
HCl(aq) + NaOH(aq) → NaCl(s) + H2O(l)
In this neutralization reaction, the HCk is the acid while the NaOH is the base (reactants). For the products, the NaCl is the salt while H2O is water.
Boyle's Law shows an inverse relationship between:
Answer:
According to Boyle's Law, an inverse relationship exists between pressure and volume. Boyle's Law holds true only if the number of molecules (n) and the temperature (T) are both constant.
F or pass? I’m okay with pass
Answer:
pass
Explanation:
pass
Drag and drop each trait to the name it describes.
Kim
Understands gardening
Wendell
Gonzalo
Learn English quickly
Is determined and strong
Can be impatient
Tries new things easily
Helps his family survive
Answer:
Kim:
Is determined and strong Tries new things easilyWendell:
Can be impatient Understands gardeningGonzalo:
Learns English quickly Helps his family surviveExplanation:
did it on Edge.
You are given a 1.55 g mixture of calcium nitrate and calcium chloride. You dissolve this mixture in 20 mL of water and add an excess of 0.300 M silver nitrate. You collect and dry the resulting precipitate and determine it has a mass of 0.535 grams. Calculate the percent calcium chloride in the original mixture.
Answer:
13.4 (w/w)% of CaCl₂ in the mixture
Explanation:
All the Cl⁻ that comes from CaCl₂ (Calcium chloride) will be precipitate in presence of AgNO₃ as AgCl.
To solve this problem we must find the moles of AgCl = Moles of Cl⁻. As 2 moles of Cl⁻ are in 1 mole of CaCl₂ we can find the moles of CaCl₂ and its mass in order to find mass percent of calcium chloride in the original mixture.
Moles AgCl - Molar mass: 143.32g/mol -:
0.535g * (1mol / 143.32g) = 3.733x10⁻³ moles AgCl = Moles Cl⁻
Moles CaCl₂:
3.733x10⁻³ moles Cl⁻ * (1mol CaCl₂ / 2mol Cl⁻) = 1.866x10⁻³ moles CaCl₂
Mass CaCl₂ -Molar mass: 110.98g/mol-:
1.866x10⁻³ moles CaCl₂ * (110.98g/mol) = 0.207g of CaCl₂ in the mixture
That means mass percent of CaCl₂ is:
0.207g CaCl₂ / 1.55g * 100 =
13.4 (w/w)% of CaCl₂ in the mixtureCollision theory states that when two molecules collide with each other with sufficient energy and hit in the proper orientation, a
bond is formed. Which action will increase the rate of reaction in a closed container?
A)
adding an inert gas
B)
expand the volume
C)
increase the temperature
D
decrease the concentration
Answer:
c increase the temperature
Explanation:
Can anyone tell me what the answer is?
Answer: c) A. 5.606x10²³atoms is the correct answer.
Explanation:
Calculate the molar mass of a solute in a 1.30 L solution with of 0.50 M
containing 10.5 g of the solute.
Answer: 16 g/mol
Explanation: Molarity is Moles/Liters or Mol/L
(0.50 mol/L)(1.30L) = 0.65mol
(cancels out L)
Molar mass is g/mol so...
10.5g/0.65mol = 16.1 g/mol
Rounded to 2 sig figs is 16 g/mol
which of the following combinations cannot produce a buffer solution? * 1 point hno2 and nano2 hcn and nacn hclo4 and naclo4 nh3 and (nh4)2so4 nh3 and nh4br
The answer is hclo4 and naclo4
Explanation:Buffer solutions are solutions that can resist changes in pH upon addition of acid or base. They are mixtures of weak acids and their corresponding weak bases or mixtures of salts of weak acids and their corresponding strong bases.A buffer solution must have an appreciable amount of both a weak acid and its conjugate base or a weak base and its conjugate acid.
Therefore, the combination of a strong acid and a strong base cannot produce a buffer solution because they do not have the necessary weak acid or base species.hno2 and nano2 can produce a buffer solution because nitrous acid is a weak acid and sodium nitrite is its conjugate base.hcn and nacn can produce a buffer solution because hydrogen cyanide is a weak acid and sodium cyanide is its conjugate base.nh3 and (nh4)2so4 can produce a buffer solution because ammonia is a weak base and ammonium sulfate is a salt of its conjugate acid.nh3 and nh4br can produce a buffer solution because ammonia is a weak base and ammonium bromide is a salt of its conjugate acid.hclo4 and naclo4 cannot produce a buffer solution because both are strong acids and therefore, they don't have any weak acid or base species.
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How would you prepare a 35 ml solution of 95% (volume/volume solution of ethanol?
Explanation:
Solutions. 1. If 47 g of KCl dissolved in enough water to give 375 mL of soloution, what is the molarity ... vo volume of solute . ... v/v ethanol, how much 95% v/v ethanol ... prepare 200. mL ...
What do the quantum numbers of electrons represent?
A. The total number of protons and electrons in the atom
B. The number of valence electrons the atom has
O C. The oxidation states most common to the atom
D. The energy levels and orbitals the electrons are in
Answer:
the energy levels and orbitals the electrons are in
Explanation:
i just took the test :)
The energy levels and orbitals the electrons are in. Hence, option D is correct.
What are atoms?An atom contains a central nucleus surrounded by one or more electrons.
The quantum numbers of electrons represent the probable distance of the electron from the nucleus. It refers to the size of the orbital and the energy level an electron is placed in.
Hence, option D is correct.
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Weight is the measure of gravity on an object measured by a weight in Newtons. Weight changes if gravitational force changes.
Mass is the amount of kilogram in an object measured by a __________ in grams and does not change…it stays the _________.
Mass is an intrinsic property of matter and is measured in kilograms. The mass of a bird is a constant. A 15-gram bird is 15 grams, whether measured on the Earth, the Moon, or Mars. Weight is a measure ofthe force of gravity on a physical object and is measured in newtons.
Which element is in the lanthanide family?
Answer:
The 15 elements, together with their chemical symbols, are lanthanum (La)
Answer:
PM Promethium
Explanation:
What would cause entropy to increase in a reaction?
A. The products becoming more spread out
B. The products forming an ordered pattern
C. The products forming fewer molecules
D. The products forming a more rigid structure
i think A but if I'm wrong sorry
then if increasing then becoming spread out so letter A
in the late 1970s, proponents of rational expectations argued that. the sacrifice ratio was smaller than previously thought.
In the late 1970s, proponents of rational expectations argued that (a.) the Fed should not attempt to aggressively fight inflation.
Proponents of rational expectations in the late 1970s argued that the Fed should not aggressively fight inflation because they believed that people have rational expectations and would adjust their behavior accordingly.
According to their theory, if the central bank attempted to stimulate the economy by expanding the money supply, individuals and firms would anticipate the inflationary effects and adjust their expectations, wages, and prices accordingly.
As a result, the expansionary monetary policy would be ineffective in stimulating real economic activity, but would only lead to higher inflation.
Therefore, they advocated for a more hands-off approach by the central bank and argued that monetary policy should primarily focus on maintaining price stability.
The complete question should be:
In the late 1970s, proponents of rational expectations argued that
a. the Fed should not attempt to aggressively fight inflation.
b. the sacrifice ratio was smaller than previously thought.
c. the short run was relatively long.
d. None of the above is correct
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In a science experiment, Javi concludes that a chemical reaction has occurred. What evidence would support this conclusion?
A
a substance melted
B
a substance's color and odor changed
C
a substance's mass and texture changed
D
new atoms were created
Answer:
B) a substance's color and odor changed Explanation: A signal that a chemical change has occurred is when its odor (its smell) or its appearance has changed.
Sam is about to drop a golf ball from his hand.
Get ready, you should catch it.
Answer:
As an object falls, its gravitational potential energy decreases as its speed—and therefore its kinetic energy—increases.
Explanation:
Study Island
A 1.00 L volume of gas at 35.0 °C exerts a pressure of 85.5 kPa. What will the pressure
be at 127 °C? Assume constant volume.
Answer:
111.03kPa = P₂
Explanation:
Gay Lussac's Law states that the pressure of a gas is directly proportional to the absolute temperature when volume remains constant.
The equation is:
P₁T₂ = P₂T₁
Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.
P₁ = 85.5kPa
T₂ = 127°C + 273.15 = 400.15K
P₂ = ?
T₁ = 35°C + 273.15 = 308.15K
P₁T₂ = P₂T₁
85.5kPa*400.15K = P₂*308.15K
111.03kPa = P₂Which traits do you think are passed down from alien parents to their offspring, and which traits are not? Explain.
Answer:
things like hair color, eye color, skin color, size of lips, curly or straight hair, are things that could be passed down to an offspring. Things like tattoos wont be passed down.
Explanation:
things like hair color, eye color, etc. get passed down because those are inheritable traits and things like tattoo aren't.
What conditions apply to masses mA and ms for the acceleration to be in one direction (nay, ma down the plane), or in the opposite direction? Check all that apply 0 mA > m sin (mA up the plane) Determine a formula for the acceleration of the system in terms of mA, mp. 0, and 9. Ignore the mass of the cord and pulley, Express your answer in terms of the variables mA, mp.0, and g. mB9-mAgsine mBmA Previous Answers ✓ Correct Constants / Periodic Ta What conditions apply to masses mA and mB for the acceleration to be in one direction (say, mA down the plane), or in the opposite direction? Check all that apply. O mA > mosin 0 (mA up the plane) masinº < mb (mA up the plane) MA> msin 0 (ma up the plane) mA< MB (mA down the plane) MA > MB (mA down the plane) mA> mB sine (mA down the plane) Ain 0 > MB (mA up the plane) m > mB (mA up the plane) MA< MB (mA up the plane) masin > mA down the plante) OMA > msin ma down the plane) Asin mar de te plane) Submit
The conditions that apply to masses mA and mB for the acceleration to be in one direction (say, mA down the plane), or in the opposite direction are as follows:
1. mA > mB sine (mA down the plane)
2. mB9-mAg sine mBnA
The conditions that apply to masses mA and mB for the acceleration to be in one direction (say, mA down the plane), or in the opposite direction are as follows:
1. mA > mB sine (mA down the plane)
2. mB9-mA gsine mBnA
When the value of mass mA is greater than mB sine (mA down the plane), the acceleration is in one direction.
When mB9-mAgsine mBmA is greater, the acceleration is in the opposite direction.
Determine a formula for the acceleration of the system in terms of mA, mp.0, and 9.
Ignore the mass of the cord and pulley, Express your answer in terms of the variables mA, mp.0, and g.
The formula for acceleration of the system in terms of mA, mp, 0 and 9 is given below;
a = (mB-mAsinθ)/(mA + mB + m0) * g
Where,
θ = angle of inclination of the plane.
g = acceleration due to gravity.
mA = mass of object A.
mB = mass of object B.
m0 = mass of the pulley and cord.
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