Answer:
KE = 19.652 J to the right
Explanation:
KE = J or N*m
KE = (1/2)m*v²
KE = kinetic energy
m = mass(kg)
v = velocity (m/s)
KE = .5*0.068kg*(17m/s)²
KE = 9.826 J to the left
So double it to the right to get 17m/s.
KE = 19.652 J to the right
J = Joules or can be expressed as N*m which is Newton-meters.
a force acting on 25kg mass produces an acceleration of 4m/square what would this the same force produce on a 12kg mass
Answer:8.3m/s
Explanation:
from F=ma, f=25*4=100N. since the force is 100, 100=12a. acceleration= 8.3m/s
A 29000-kg open railroad car, initially coasting at 0.825 m/s with negligible friction, passes under a hopper that dumps 117500 kg of scrap metal into it.
a)What is the final speed, in meters per second, of the loaded freight car?
b)How much kinetic energy is lost, in joules, when the freight car receives this scrap metal? Ignore the free-fall kinetic energy of the scrap metal.
Answer:
a) Answer: 0.16331 m/s
b) Answer: 8522.66 joules
Explanation:
The final speed is 0.1633 m/s.
When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.
What is momentum?A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.
(a) Given parameter:
Mass of the railroad car, M = 2900 Kg.
Mass of the scrap metal, m= 11750 Kg.
Initial speed of the car, u = 0.0825 m/s.
Initial speed of the scrap metal = 0 m/s.
Final speed of the system, v = ?
Then, initial momentum of the system = initial momentum of the car + initial momentum of the scrap metal .
= (29000×0.825 + 117500×0) kg.m/s.
= 23925 kg.m/s.
Final momentum of the system = total mass of the system× final speed
= (29000 + 117500)× v kg.m/s
= 146500v kg.m/s.
Hence, from principle of conservation of momentum,
initial momentum of the system = Final momentum of the system
⇒ 23925 = 146500v
⇒ v = 0.1633 m/s.
The final speed of the loaded freight car is 0.1633 m/s.
(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.
= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.
= 7915.72 Joule.
Hence, 7915.72 Joule kinetic energy is lost in this process.
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A large solar farm has 21 700 solar panels and generates 5.0 MW of power.
1.0 MW = 1.0 × 106 W
Calculate the average power each panel produces.
Answer:
answer is
Explanation:
average power each panel produces = 21700/ 5×10^6
4340 ×10^-6
that's mean 4340 micro Watt
A rock on the moon has 0.5kg. It is brought to Earth where the gravitational field is stronger. On Earth, the rock will have:
a) Less mass and same weight
b) The same mass and more weight
c) Less mass and less weight
d) The same mass and same weight
Answer:
Explanation:
It will be B.
The correct answer is the same mass and less weight.
What happens to the weight of an object when it is brought from the moon to the Earth?
The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.
What happens to the mass of an object when you take it to the moon?
Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.
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a dragster accelerate to a speed of 112m/s over a distance of 398m/s. determine the acceleration (assume uniform) of the dragster
The total power input to the leaf blower is 750 W. The useful power outlet of the leaf blower is 360 W. Calculate the efficiency of the leaf blower.
H = Pu / P x 100% = 360/750 x 100% = 48%
P/s: Pu is the useful power outlet of the leaf blower
P is the total power input to the leaf blower
ok done. Thank to me :>
How do you change an object's motion?
A piece of wood is floating in a tub of water. a second piece of wood rests on top of the first piece; it does not touch the water. if the second piece of wood is removed from on top of the first piece and placed in the water, what happens to the water level in the tub?
Answer:
The water would rise because of displacement in the water
Explanation:
According to the principle of regularity, it is recommended that an individual exercise.
A 3-4 days per week at the beginning and progress to 4 or 5 days a week as your fitness improves.
B 7 days per week at the beginning and progress to 4 or 5 days a week as your fitness improves.
C 3-4 days per week at the beginning and progress to 7 days a week as your fitness improves.
D 1-2 days per week at the beginning and progress to 5 or 6 days a week as your fitness improves.
Answer:
Socratic app
Explanation:
it will help you
A 3.00 kg toy falls from a height of 10.0 m. Just before hitting the ground, what will its kinetic energy be? (Disregard air resistance; g = 9.81 m/s2.)
The kinetic energy of the toy before hitting the ground is 294.3 J
From the question given above, the following data were obtained:
Mass (m) = 3 Kg
Height (h) = 10 m
Acceleration due to gravity (g) = 9.81 m/s²
Kinetic energy (KE) =?Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.
KE = PE = mgh
KE = 3 × 9.81 × 10
KE = 294.3 JTherefore, the kinetic energy of the toy is 294.3 J
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What is the weight, on Earth, of a book with a mass of 1. 5 kg? 1. 5 N 6. 5 N 11. 3 N 14. 7 N.
Answer:
The weight, on Earth, of a book with a mass of 1.5kg is 14.7N.
Explanation:
Hi there!
Weight of an object = mass (kg) × acceleration due to gravity (N/kg)
Plug in the given values using the g constant g = 9.8 N/kg:
W = 1.5 × 9.8 = 14.7 N
how can the motion of an object that is already moving change?
Answer: A force can change the direction in which an object is moving
Explanation: A bigger force of an object will produce a bigger change in motion
A bus speeds up from 5 m/s to 15 m/s in 20 seconds. How far did it go during the 20 seconds? (use KE1 to find a, then use that to find xf)
The distance the bus travelled in 20 seconds is 12.75 m
The first step is to write out parameters given in the question
Final velocity= 15
Initial velocity= 5
Time= 20
Distance= ?
V² + U²= 2as
15² + 5²= 2(9.8)s
225+25= 19.6s
250= 19.6s
s= 250/19.6
= 12.75
Hence the distance the bus travelled in 20 seconds is 12.75 m
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How would the gravity between two objects change if one object got bigger?
The correct answer is the 3rd answer, gravity would increase its pull on the small object
hope this helps! :)
What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 9 m/s and the acceleration of gravity is 9.8 m/s 2 . Neglect air resistance.
Answer:
The time to reach max height is h = 1/2 g t^2
The time to fall is the same as that for an equivalent rise
m g h = 1/2 m v^2 KE vs PE
Here: (Vf - VI) / g = t = -9 / -9.8 = .92 s
4. A force of 50 Newtons is applied to a mass resulting in an acceleration of 8 m/s2. What force would need to be applied to this mass to cause an acceleration of 25 m/s??
Answer:
125N
Explanation:
force =mass×acceleration
50 =mass×8m/s2
mass=6.25kg
When an electron falls from one energy level to a lower energy level, the result is the emission of:
Answer:
fsdfbfsdhfsfiic,dsiwe
Explanation:
As a speaker, I should know my purpose and method of delivery before giving my speech so...
Explanation:
I will prepare my speech first and then I will give a speech on it.
[tex] \huge \mathcal{Question}[/tex]
Can someone Help me with this question ?
(I need proper Explanation if possible)
Thanks for Answering ~
Answer:
c. Force applied is 75 N
EDITED
tan 37 = a/g
a = 3g/4
a in equation
t× 3/5 = 2 × 3g/4
t = 5× 10/2
t = 25n
f = ma
f = ( mt + mb )a
F = 10 × 3× 10/4
F = 75 n
• Correct option is (C).
We know that the angle made by string is θ=
[tex]tan {}^{ - 1} ( \frac{a}{g} )[/tex]
where a is the acceleration of the frame in which the string is hanging in our case it is a trolley.
[tex]putting \: θ=37° \: or \: tan \: 37° = \frac{3}{4} [/tex]
[tex]we \: get \: a \: \frac{3g}{4} = \frac{30}{4} = 7.5 \: m/s^2[/tex]
[tex] \boxed{Force \: F=total \: mass \: of \: the \: system \: on \: which \: force \: is \: acting ×acceleration \: of \: the \: system=(8+2)×7.5=75 }[/tex]
[tex] \boxed{ so \: force \: is \: 75 \:N. }[/tex]
which of the following changes will result in a weaker electromagnet
Answer:
Changing the metal core for a different metal will make the electromagnet stronger or weaker.
Explanation:
Hope this helped, nya~ :3
A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 x 10^6
meters. Find the mass of the moon
equation- F= G m1 m2/ d^2
Answer:
7.36 × 10^22 kg
Explanation:
Answer:
D
Explanation:
I need help making a chart (preferably a line graph) with this data. I'm not sure how to show that it will be a linear line in a graph. If you don't have excel can you explain to me how to do it.
note: these datasets are separate and arent related
Spring Constant (N/m) Displacement (m)
100 0.5m
300 0.167m
500 0.1m
700 0.071m
Applied force (N) Displacement (m)
20 0.2m
30 0.3m
50 0.5m
70 0.7m
Answer:
the graph plotted based on your data, you did not mention what are the variables on the x-axis and y- axis . and the graphs can be three small graphs of different material of one quality i.e. thickness or length
hope it helps
Explanation:
Please Help
A car travels on a straight road with velocity components of 20 m/s west and 70 m/s south. What is the total distance the car travels in 50 s?
What do these two changes have in common
a slice of banana turning brown
bleaching clothes
Answer:
They get air inside
Explanation:
bananas turn brown when air is inside
Lợi ích của lực ma sát và cách làm tăng
PLz help--- What's happening here?
This object is not moving
This object is not changing speeds.
This object is changing speeds; it's getting faster.
This object is changing speeds; it's getting slower.
Answer:
getting faster
Explanation:
the curve gets more steeper, and steeper line shows more distance for less time, meaning faster.
John carries a 5 kg bag horizontally to the checkout line. How much work must he
do to move it 8 m at a constant velocity of 1 m/s to the right?
The work John must do to move the bad horizontally to given distance is 2.5 J.
The given parameters;
mass of the bag, m = 5 kgdistance moved by the bad, d = 8 mvelocity of bag, v = 1 m/sThe acceleration of the bag at the given distance and velocity is calculated as follows;
[tex]v^2 = u^2 + 2as\\\\1^2 = 0 + 2(a)(8)\\\\1 = 16 a\\\\a = \frac{1}{16} \\\\a = 0.0625 \ m/s^2[/tex]
The work done in moving the bag to 8m is calculated as follows;
[tex]W = F \times d\\\\W = ma \times d\\\\W = 5 \times 0.0625 \times 8 \\\\W = 2.5 \ J[/tex]
Thus, the work John must do to move the bad horizontally to given distance is 2.5 J.
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What mass M will cause this system accelerate e 0.75 m/s²?
Answer:
5.54 [kg].
Explanation:
1) if m₁=6; g=9.81; a=0.75 and m₂ - reqired mass, then
2) it is possible to write: m₁*a=m₁*g-m₂*g, and
3) [tex]m_2=\frac{m_1(g-a)}{g}; \ => \ m_2=\frac{6*(9.81-0.75)}{9.81}=5.54[kg].[/tex]
what is the relationship of physics and technology
Answer:
Physics explains and describes natural phenomena. It tells us how different parts of nature work and react to different situations. Technology helps us solve problems and complete tasks by using the world around us.
It is observed that technology gives rise to new physics and at other times physics generates new technology. Physics Generating New Technology: Newton's law of motion helped in the development of rockets.
Explanation:
Hope this helps you! :)
2. Summarize how to use a spring scale to measure a pull and how to use it to apply a push with
a specific force.
If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.
According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.
The force applied;
F = kx
where;
k is the springThe applied force can be in form of push or pull. A push force can result in compression of the spring while a pull force can result in extension of the spring.
If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.
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