A 65 kg jogger runs with a constant acceleration of 1.2 m/s/s. Determine
the net force responsible for this acceleration. *

Answers

Answer 1

Answer:

78 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 65 × 1.2

We have the final answer as

78 N

Hope this helps you


Related Questions

Try to move the magnet back and forth between the two coils. Explain the motion of the magnet and what might be causing this.

Answers

Answer:

Please find the answer in the explanation.

Explanation:

When you try to move the magnet back and forth between the two coils, the motion of the magnet will be oscillatory and this action will cause current and EMF to induce

According to law of Faraday, current or EMF will be induced when a magnet is moved in the presence of coils

If the magnet continues to move back and forth between the two coils, what might be causing this will be the presence of the induced electromagnetic force between the two coils.

The first excited state of a particular atom in a gas is 5.8 eV above the ground state. A moving electron collides with one of these atoms, and excites the atom to its first excited state. Immediately after the collision the kinetic energy of the electron is 3.7 eV. What was the kinetic energy of the electron just before the collision?
Ki = ____eV

Answers

Answer:

E₀ = 9.5 eV

Explanation:

In the processes of absorption, excitation and shocks the energy must be conserved therefore the energy before the shock is

         E₀ = E_excitation + E_residual

         E₀ = 5.8 + 3.7

         E₀ = 9.5 eV

this is the energy of the electron before the collision

A cannonball is launched diagonally with an initial horizontal speed of 51.0m/s
and an initial vertical speed of 24.0m/s. Label the hypotenuse, opposite side and
adjacent side, and determine all unknowns.
m/s
initial speed:
initial horizontal speed:
initial vertical speed:
m/s
m/s
At what angle () was the cannonball launched?

Answers

• initial horizontal speed: 51.0 m/s

• initial vertical speed: 24.0 m/s

• initial speed: √((51.0 m/s)² + (24.0 m/s)²) ≈ 56.4 m/s

• angle: tan(θ) = (24.0 m/s) / (51.0 m/s)   →   θ ≈ 25.2º

Using Pythagoras, the initial speed and the launch angle of the cannon ball are 56.36 m/s and 25.20° respectively.

The initial speed can be obtained using length of the diagonal :

v² = 51² + 24²

v² = 2025

v = √3177

v = 56.36 m/s

The launch angle, θ :

Tanθ = opposite / Adjacent

θ = tan¯¹(24/51)

θ = tan¯¹(0.4705)

θ = 25.20°

Hence, the angle of launch is 25.20°

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anybody wanna play among us?​

Answers

Answer:

yess

Explanation:

Answer:

yes me

mark me brainliest

A 5 kg block is released from rest at the top of a quarter- circle type curved frictionless surface. The radius of the curvature is 3.8 m. When the block reaches the bottom o the curvature it then slides on a rough horizontal surface until it comes to rest. The coefficient of kinetic friction on the horizontal surface is 0.02.
a. What is the kinetic energy of the block at the bottom of the curved surface?
b. What is the speed of the block at the bottom of the curved surface?
c. Find the stopping distance of the block?
d. Find the elapsed time of the block while it is moving on the horizontal part of the track.
e. How much work is done by the friction force on the block on the horizontal part of the track?

Answers

Answer:

a. 186.2 J b. 8.63 m/s c. 190 m d. 43.2 s e. 186.2 J

Explanation:

a. From conservation of energy, the potential energy loss of block = kinetic energy gain of the block.

So, U + K = U' + K' where U = initial potential energy of block = mgh, K = initial kinetic energy of block = 0, U' = final potential energy of block at bottom of curve = 0 and K' = final kinetic energy of block at bottom of curve.

So, mgh + 0 = 0 + K'

K' = mgh where m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height above the ground of block = radius of curve = 3.8 m

So, K' = 5 kg × 9.8 m/s² × 3.8 m = 186.2 J

b. Since the kinetic energy of the block K = 1/2mv²  where m = mass of block = 5 kg, v = velocity of block at bottom of curve

So, v = √(2K/m)

= √(2 × 186.2 J/5 kg)

= √(372.4 J/5 kg)

= √(74.48 J/kg)

= 8.63 m/s

c. To find the stopping distance, from work-kinetic energy principles,

work done by friction = kinetic energy change of block.

So ΔK = -fd where ΔK = K" - K' where K" = final kinetic energy = 0 J (since the block stops)and K' = initial kinetic energy = 186.2 J, f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance

ΔK = -fd

K" - K' = - μmgd

d = -(K" - K')/μmg

Substituting the values of the variables, we have

d = -(0 J - 186.2 J)/(0.02 × 5 kg × 9.8 m/s²)

d = -(- 186.2 J)/(0.98 kg m/s²)

d = 190 m

d. Using v² = u² + 2ad where u =initial speed of block = 8.63 m/s, v = final speed of block = 0 m/s (since it stops), a = acceleration of block and d = stopping distance = 190 m

So, a = (v² - u²)/2d

substituting the values of the variables, we have

a = (0² - (8.63 m/s)²)/(2 × 190 m)

a = -74.4769 m²/s²/380 m

a = -0.2 m/s²

Using v = u + at, we find the time t that elapsed while the block is moving on the horizontal track.

t = (v - u)/a

t =(0 m/s - 8.63 m/s)/-0.2 m/s²

t = - 8.63 m/s/-0.2 m/s²

t = 43.2 s

e. The work done by friction W = fd where

= μmgd where f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance = 190 m

W = 0.02 × 5 kg × 9.8 m/s² × 190 m

W = 186.2 J

The potential energy of the loss of the block will be equal to the kinetic energy gain. The kinetic energy of the block is 186.2 J at the bottom of the curved surface.


From the conservation of energy:

The potential energy of the loss of the block will be equal to the kinetic energy gain.

So,

[tex]U = mgh[/tex]

Where,

[tex]U[/tex] - potential energy

[tex]m[/tex] - mass of block =  5 kg

[tex]g[/tex] - gravitational  acceleration = 9.8 m/s²

[tex]h[/tex] = height = radius of curve = 3.8 m

Put the values in the formula,

[tex]U = 5 \times 9.8 \times 3.8 \\\\ U = 186.2 \rm \ J[/tex]

Therefore, the kinetic energy of the block is 186.2 J at the bottom of the curved surface.

Learn more about kinetic energy:

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Maria wrote the following steps in the formation of igneous rocks. Step 1: Rocks pushed under Earth due to movement of tectonic plate Step 2: Rocks melt Step 3: Molten rocks are heated Step 4: Rocks solidify Which step contains an error?

Answers

Answer:

Step 1: Rocks pushed under Earth due to movement of tectonic plate

Step 2: Molten rocks are heated

Step 3: Rocks melt

Step 4:  Rocks solidify

Explanation:

Step 1: Rocks pushed under Earth due to movement of tectonic plate

Step 2: Rocks melt

Step 3: Molten rocks are heated

Step 4:  Rocks solidify

In the formation of igneous rocks, rocks are pushed under the earth due to the movement of tectonic plate.

As the rocks are pulled beneath the crust, they are heated and begin to melt to form magma.

Then, with time, the magma solidify to form an igneous rock.

 Step 2 is wrong.

  Step 3 should come first

Step 1: Rocks pushed under Earth due to movement of tectonic plate

Step 2: Molten rocks are heated

Step 3: Rocks melt

Step 4:  Rocks solidify

The difference between a law and a theory is the diffrence between what and why . Explain

Answers

Answer:

A law is defined as a description or a statement given after an observed phenomenon. A theory is a simplification of certain observational data as to how and why it happened.

Explanation:

I hope this helped solve your question.

A 12-volt battery maintains a 4.5A current through a resistor. What is the resistance of the resistor.

Answers

R=v/i
R= 12 ÷ 4.5 = 2.6 Ω

The frequency of an electromagnetic wave is 1.0 x 105 Hz. Calculate the wavelength in meters. Show your work,
and be sure to keep track of the units.

Answers

Answer:

wavelength = 3000 m

Explanation:

We use the formula for the relationship between the speed (c), frequency (v), and wavelength [tex](\lambda)[/tex]:

[tex]c=\lambda\,*\,\nu\\300000000 \,\,m/s = \lambda\,*100000 \,\,1/s\\\lambda \,=\,3000\,\,m[/tex]

1.
How does centripetal force due to gravity keep a satellite in orbit?

It continuously changes the direction of the satellite.

It provides the thrust to launch the satellite into space.

It prevents the satellite from falling toward Earth.

It keeps increasing the speed of the satellite.

Answers

Answer:

1st one,.

It changes the direction,

And satellite falls in earth infinity,

Its total workdone is zero

Answer:

It continuously changes the direction of the satellite.

Explanation:

our Welcome (; (:

During a football workout, two linemen are pushing the coach on the sled. The
combined mass of the sled and the coach is 300 kg. The coefficient of friction between
the sled and the grass is 0.800. The sled accelerates at the rate of 0.580 m/s^2.
Determine the force applied to the sled by the lineman.

Answers

Answer:

F_{players} = 2528.4[N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.

On the sled act two forces, the force of friction and The Force executed by the football players.

The movement of the football players will be taken as positive, while the friction will be taken as negative, since it is opposed to the movement of the sled.

ΣF = m*a

where:

F = force [N]

m = mass [kg]

a = acceleration = 0.580 [m/s²]

[tex]F_{players} - f_{friction} = m*a[/tex]

The friction force is defected as the coefficient of friction by the normal force, the normal force on a horizontal surface can be calculated as the product of mass by gravitational acceleration.

[tex]f_{friction}=0.8*(300*9.81)\\f_{friction}=2354.4[N][/tex]

Now we can calculate the force exerted by the players.

[tex]F_{players}-2354.5=300*0.580\\F_{players}=2528.4[N][/tex]

A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?

Answers

Answer:

Charge, [tex]q=7.68\times 10^{-12}\ C[/tex]

Explanation:

It is given that,

The number of electron in a RBCs, [tex]n=4.8\times 10^7[/tex]

We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :

q = ne

e is the change on electron

[tex]q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C[/tex]

So, the net charge is [tex]7.68\times 10^{-12}\ C[/tex].


the lanthanides are all radioactive true or false

Answers

Answer:

False

Explanation:

All the lanthanides are not radioactive in nature. Just one of the lanthanides are radioactive.

The lanthanides belong to the f-block on the periodic tableOnly Promethium in this group are radioactive in nature. Other elements in the lanthanide series might have radioactive isotopes.

For mechanical waves, such as sound waves or ocean waves, increasing the intensity of the wave increases both the amplitude (height) of the wave and the energy it carries. In that situation, a low-frequency but high-intensity wave should have the same effect as a high-frequency but low-intensity wave. How does light behave differently from this model?

Answers

Answer:

the effect is given by the energy that depends on the frequency, but not on the intensity

Explanation:

There are similarities and differences between mechanical waves and electromagnetic waves. The main difference is that mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magnetoscope fields.

In the case of light (electromagnetic wave) the energy is given by the relation

          E = h f

where h is Planck's constant and f is the frequency.

Then the intensity is given by the number of waves or quasiparticles (photons) that are in the ray.

Consequently the effect is given by the energy that depends on the frequency, but not on the intensity

The energy in the given model depends on the frequency, but not on the intensity.

The given problem is based on the mechanical wave and electromagnetic waves. The mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magneto scope fields.

In the case of light (electromagnetic wave) the energy is given by the relation,  

E = h f

Here,

h is Planck's constant.

And f is the frequency.

Then the intensity is given by the number of waves (photons) that are in the ray.  So, it is evident the effect is given by the energy that depends on the frequency, but not on the intensity.

Thus, we can conclude that the energy in the given model depends on the frequency, but not on the intensity.

Learn more about the intensity of wave here:

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1) An object travels 15 m in 3 s. What is its' speed?​

Answers

Answer:

5m/s

Explanation:

Distance/Time= Speed

D/T=S

15/3=S

5=S

A cannonball is fired straight up at a speed of 25 m/s. What is the maximum altitude that it will reach?

Answers

Answer:

When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.

Explanation:

Hope it helped =)

The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m

According to the question;

The cannonball is fired straight up at a speed of 25 m/s

Additionally, the cannonball is fired against the force of gravity.

Consequently, the motion is in the opposite direction of the acceleration due to gravity.

From the equation of motion;

V² = U² - 2gH

At the maximum altitude, V = 0.

0² = 25² - (2× 9.81) H

19.62H = 625

H = 625/19.62

H = 31.86m

The maximum altitude that it will reach is;

H = 31.86m

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A boy pulls his 9.0 kg sled, applying a horizontal force of 14.0 N (rightward). The coefficient of friction between the snow and the sled is 0.12. Determine the net force and the acceleration of the sled. Draw a free-body diagram for the sled; use appropriate force symbols to label the type of each force acting on the sled.

Answers

Here is the answer, dud

A ferris wheel with radius 12 m makes a revolution every 3 minutes. Find the linear (tangental) speed of a passenger. How far does a person move in a 5 minute ride?

Answers

Answer:

The linear (tangential) speed of a passenger is 0.4188 m/s

The distance traveled by the person in 5 minutes ride is 125.64 m

Explanation:

Given;

radius of the Ferris, r = 12 m

1 revolution per 3 minutes, [tex]\omega = \frac{2\pi (radian)}{3\ (minutes)} *\frac{1\ minute}{60 \ seconds} = 0.0349 \ rad/s[/tex]

The linear (tangential) speed of a passenger is given by;

v = ωr

v = (0.0349)(12)

v = 0.4188 m/s

The distance traveled by the person in 5 minutes ride is given by;

d = vt

d = (0.4188)(5 x 60)

d = 125.64 m

Block A of 15kg of the figure below slides on a surface where the coefficient of kinetic friction is uk=0.3. The block moves at 10m/s when it is s=4m from a second 10kg B block, initially at rest. Considering this situation, determine what will be the maximum compression of the spring, initially decompressed, after the collision if the coefficient of return between the blocks is e=0.6. Tip here, as the blocks are subject to friction forces, use the equation that relates mechanical energy and the work done by non-conservative forces.

Answers

Answer:

0.287 m

Explanation:

The velocity of block A when it reaches block B is:

KE₀ = KE + W

½ mv₀² = ½ mv² + Fd

½ mv₀² = ½ mv² + mg μ d

v₀² = v² + 2g μ d

v² = v₀² − 2g μ d

v² = (10 m/s)² − 2 (9.8 m/s²) (0.3) (4 m)

v = 8.75 m/s

The coefficient of restitution is 0.6, so the relative velocity between A and B after the collision is:

e = |Δv after| / |Δv before|

0.6 = Δv / (8.75 m/s)

Δv = 5.25 m/s

Momentum is conserved, so the speed of block B after the collision is:

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(15 kg) (8.75 m/s) + (10 kg) (0 m/s) = (15 kg) (v) + (10 kg) (v + 5.25 m/s)

131.2 m/s = 25v + 52.5 m/s

25v = 78.7 m/s

v = 3.15 m/s

Energy is conserved, so the compression of the spring is:

KE = EE + W

½ mv² = ½ kd² + Fd

½ mv² = ½ kd² + mg μ d

½ (10 kg) (3.15 m/s)² = ½ (1000 N/m) d² + (10 kg) (9.8 m/s²) (0.3) d

49.6 = 500 d² + 29.4 d

0 = 500 d² + 29.4 d − 49.6

d = [ -29.4 ± √(29.4² − 4(500)(-49.6)) ] / 1000

d = (-29.4 ± 316.2) / 1000

d = 0.287 m

Which physical activity is NOT aerobic exercise?

A) Hip-hop dancing

B) Jump roping

C) Yoga

D) Jogging​

Answers

Answer:

C

Explanation:

Answer:

Hip-hop Dancing

Explanation:

Aerobic exercises are light (somewhat, a more accurate word would be bearable) workouts that you can endure over long periods of time. Anaerobic workouts describe workouts that require sudden burst of energy, like the ones you seen in most forms of dance, such as Hip-hop dance.

Hope this helps!

The towel has better blank
than that towel.
A.duplication
B.formation
C.qualification
D.absorption

Answers

Answer:

D

Explanation:

Towels Absorb

A Carnot engine takes in heat at a temperature of 790 K and releases heat to a reservoir at a temperature of 470 K. What is its efficiency?

Answers

Answer: 1280 kilometers :D

Explanation:

790 K ' 470 K = 1280 KM (KILOMETERS)

Answer:

GIVE DIS GUY BRAINLIST

Explanation:

An ideal transformer has 60 turns in its primary coil and 360 turns in its secondary coil. If the input rms voltage for the 60-turn coil is 120 V, what is the output rms voltage of the secondary coil

a. 240 V
b. 720 V
c. 360 V
d. 480 V
e. 20 V

Answers

Answer:

720 V

Explanation:

Given that,

The number of turns in primary coil, N₁ = 60

The number of turns in secondary coil, N₂ = 360

The input rms voltage, V₁ = 120 V

We need to find the output rms voltage of the secondary coil . The relation between number of turns in primary coil - secondary coil to the input rms voltage to the output rms voltage is given by :

[tex]\dfrac{N_1}{N_2}=\dfrac{V_1}{V_2}\\\\V_2=\dfrac{N_2V_1}{N_2}\\\\V_2=\dfrac{360\times 120}{60}\\\\V_2=720\ V[/tex]

So, the output rms voltage of the secondary coil is 720 V. Hence, the correct option is (b).

An airplane with a mass of 5,000 kg needs to accelerate 5 m/s2 to take off before it reaches the end of the runway. How much force is needed from the engine

Answers

Answer:

25000 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5000 × 5

We have the final answer as

25000 N

Hope this helps you

A squirrel falls from this tree after being shocked by the falling apples. If the
squirrel was 3.5 meters above the ground, how long until the squirrel hits the
ground?

Answers

Answer:

0.85m

Explanation:

Given parameters:

Height of fall  = 3.5m

Unknown:

Duration of fall  = ?

Solution:

To solve this problem, we apply the right motion equation.

Since we know the height, we can use the equation below;

  S = ut + [tex]\frac{1}{2} gt^{2}[/tex]  

  S is the height

  u is the initial velocity  = 0m/s

   t is the time

   g is the acceleration due to gravity

  3.5  = 0 + [tex]\frac{1}{2}[/tex] x 9.8 x t²

  3.5  = 4.9t²

       t² = [tex]\frac{3.5}{4.9}[/tex]

       t² = 0.71

       t  = √0.71  = 0.85m

 

 

6. Which of the following types of energy is not lost when energy is
transferred between one of the Earth's four physical systems?*
heat
light
sound
nuclear
vibration
movement

Answers

Answer:

heat light sound viberation

Explanation:

i'm built different

How would you go about measuring the speed of a vehicle? What measurements would you have to take? What calculations would you have to perform?

Answers

Answer:

For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.

hii i need these answers please!! as soon as possible and if you can’t see anything jus let me know and ill tell you what it says

Answers

Answer:

Explanation:

CANT SEE ITS TOO PIXELATED

If the sound source is moving then the pitch of the sound will ___________________ to the observer.

Answers

Answer:

Increase

Explanation:

The frequency of sound determines the sound. If the frequency is lower the pitch will be lower. If the frequency is higher the pitch will be higher. This is affected by the motion of the sound source because when a sound source is moving faster the frequency will become higher.

what is the difference of dispersed phase and continuous phase?​

Answers

Answer:

The phase existing as small droplets is called the dispersed phase and the surrounding liquid is known as the continuous phase. Emulsions are commonly classified as oil-in-water (O/W) or water-in-oil (W/O) depending on whether the continuous phase is water or oil.

Explanation:

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