A 6.23 g nugget of pure gold absorbed 282 J of heat. The initial temperature was 30.4 degrees Celsius. What was the correct final temperature of the gold nugget if the specific heat of gold is 0.129 J/gC

Answers

Answer 1

Answer:

Final temperature, T2 = 381.28°C

Explanation:

Given the following data;

Mass = 6.23 g

Initial temperature = 30.4°C

Heat capacity = 282 J

Specific heat capacity = 0.129 J/g°C

To find the final temperature;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

[tex] dt = \frac {Q}{mc} [/tex]

Substituting into the equation, we have;

[tex] dt = \frac {282}{6.23*0.129} [/tex]

[tex] dt = \frac {282}{0.8037} [/tex]

dt = 350.88°C

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 350.88 + 30.4

Final temperature, T2 = 381.28°C


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Answer:

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Explanation:

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Which of the following statements is FALSE? *

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Using a Punnett square, what genotypes would you expect in the F2 offspring?
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a
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Answers

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Answers

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Answers

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Answer:

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Answer:

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Let's consider the following balanced thermochemical equation.

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According to the balanced thermochemical equation, 130.4 kJ of heat is released when 2 moles of gallium chlorate react. The number of moles of gallium chlorate that must react to produce 674 kJ of energy is:

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Answers

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Answers

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