Answer:
The value is [tex]f = 0.05 \ Hz[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 615 \ kg[/tex]
The period of the circular motion is [tex]T = 20 \ s[/tex]
The radius is [tex]r = 80 \ m/s[/tex]
Generally the frequency of the circular motion is
[tex]f = \frac{1}{T }[/tex]
=> [tex]f = \frac{1}{ 20 }[/tex]
=> [tex]f = 0.05 \ Hz[/tex]
A car of mass 1500 kg starting from rest can reach a speed of 20
m/s within 10 seconds. Calculate the accelerating force of the car
engine.
Explanation:
F=MA
F=1500 * 2
F=3000N
What causes electric current to flow in the loop of wire that turns between an
electric generator's two permanent magnets?
A. Electric charges in the wire loop flow when the magnetic fields of
the magnets frequently switch direction.
B. The magnetic field of the magnets causes a mechanical force to
act on the electric charges within the moving loop of wire.
C. Electrons that flow from the magnets into the loop of wire carry
mechanical energy to the electric charges within the wire.
D. The magnetic fields of the magnets attract the magnetic field of
each of the atoms that make up the loop of wire.
Answer:
B. The magnetic field of the magnets causes a mechanical force to
act on the electric charges within the moving loop of wire.
The magnetic field of the magnets causes a mechanical force to
act on the electric charges within the moving loop of the wire causes an electric current to flow in the loop of wire that turns between an electric generator's two permanent magnets, therefore the correct option is B.
What is a magnetic field?
A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted. The SI unit of the magnetic field is tesla.
the magnetic field can also be generated as the magnetic effect of electric current for example when current is flown through an electrical wire there is the generation of the magnetic field around the conducting wire
For a simple bar magnet, N-pole and S-pole are the points on a magnet that have the strongest magnetic field. The magnetic field originates from the north pole and terminates in the south pole of a magnet.
The magnetic field of the magnets causes a mechanical force to act on the electric charges within the moving loop of the wire responsible for the electric current to flow in the loop of wire that turns between an
electric generator's two permanent magnets.
Learn more about the magnetic fields from here
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A block wełghing 300 N is moved at a constant speed over a horizontal
surface by a force of 50 N. What is the coefficient of friction? *
1 point
A. 0.25
OB. 0.50
C. 0.10
D. 0.17
Answer:
D) miu = 0.17
Explanation:
To be able to solve this problem we must perform a sum of forces in the direction of the movement. This sum of forces must be equal to zero, since the block moves at a constant speed, therefore there is no acceleration.
The friction force is defined as the product of the normal force by the coefficient of friction.
[tex]f=miu*N[/tex]
where:
f = friction force = 50 [N]
miu = friction coefficient
N = normal force [N]
Now the normal force is defined as the force with equal magnitude to the weight of the block but acting in the opposite direction.
[tex]N=300[N][/tex]
Now replacing:
[tex]miu=f/N\\miu=50/300\\miu = 0.166\\ or 0.17[/tex]
The largest acceleration that a human has ever endured occurred when a race car accidentally crashed into a wall. The car was traveling at a speed of 172.8 km/h when it hit the wall. The car came to a complete stop 2.72 ´ 10–2 s later.
a. Calculate the acceleration of the car using the acceleration formula. Express your answer in both m/s2 and in “g’s.” One g is equal to the free-fall acceleration of 9.8 m/s2.
b. Suppose the driver of the car had a mass of 70.0 kg. What was the unbalanced force on his body as the car underwent negative acceleration?
Answer:
(a) The acceleration oF the car is [tex]-1764.7 m/s^2[/tex] or -180.1 g’s.
(b) The magnitude of the force on the driver's body is 123529 Newtons
Explanation:
Given that:
The initial velocity of the car before the impact, u=172.8 km/h
Or, [tex]u =172.8 \times \frac {1000}{3600} m/s= 48m/s[/tex]
As the car came to a complete stop after the collision, so the final velocity of the car, v=0.
The time required to stop the car completely, [tex]t=2.72\times 10^{-2} s[/tex]
(a) Assuming the acceleration is constant, so
Acceleration, [tex]a= (v-u)/t[/tex]
So, [tex]a=\frac {0-48}{2.72\times 10^{-2}}=-1764.7 m/s^2[/tex]
Now, expressing the acceleration in the unit od "g's",
[tex]a=-1764.7\times \frac{g}{g} \\\\\Rightarrow a=-1764.7 \;m/s^2\times \frac{g}{9.8\; m/s^2} \\\\\Rightarrow a=-180.1 g[/tex]
Hence, the acceleration od the car is -1764.7 [tex]m/s^2[/tex] or -180.1 g’s.
(b) Mass of the driver of the car, m=70.0 kg
The acceleration of the body of the driver is the same as the acceleration of the car.
So, the acceleration faced by the driver, [tex]a= -1764.7 m/s^2[/tex]
As forec = mass x acceleration, so
The force on the driver's body = 70 x (-1764.7)= -123529 Newtons.
The negative sign means the force is in the opposite direction of the direction of motion of the car.
Hence, the magnitude of the force on the driver's body is 123529 Newtons
why does diamond sparkles stars twinkles?
Answer:
Because they want attention
Select the correct answer.
Which equation correctly relates kinetic energy, mass, and velocity?
Answer:
B
Explanation:
I just took the test and got 100%
NEN
How many electrons are being shared in the molecule above?
Spreading my love to everyone, <3
we now the Earth is round .but .the earth is moving .but also some time we go to the under when the earth is moving .but why we cant fall?
Answer:
lol bruhh wat a question
We donot feel any of this motion because these speed are constant. The spining and orbital speed of earth stay the same so we don't feel any acceleration or deceleration. You can only feel motin if your speed change.
Hope it's Help!
Matt is driving his car around a curve that has a radius of 40 m. If his speed is 25 m/s as he negotiates the curve, find the centripetal acceleration for the curve.
A- 13.9 m/s2
B- 24.6 m/s2
C- 15.6 m/s2
D- 7.25 m/s2
Answer:
[tex]\huge\boxed{\sf a_{c} = 15.6\ m/s^2}[/tex]
Explanation:
Given Data:
Radius = r = 40 m
Speed = v = 25 m/s
Required:
Centripetal Acceleration = [tex]\sf a_{c}[/tex] = ?
Formula:
[tex]\sf a_{c} = \frac{v^2 }{r}[/tex]
Solution:
[tex]\sf a_{c} = \frac{v^2}{r} \\\\a_{c} = \frac{(25)^2}{40} \\\\a_{c} = \frac{625}{40} \\\\a_{c} = 15.6 m/s^2\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH18076th grade science I mark as brainliest.
Answer:
[tex]\huge\boxed{\sf Speed = 2 \ m/s}[/tex]
Explanation:
Given:
Time = t = 45 seconds
Distance = S = 90 meters
Required:
Speed = v = ?
Formula:
v = S / t
Solution:
v = 90 / 45
Speed = 2 m/s
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807What is the matter made of
Answer:
Matter is made of atoms which are in turn made up of protons, nuetrons and electrons. Atoms come together to form molecules which is the building block for all matter.
Explanation:
I feel like this question is like What is the meaning of life. Matter is made up of Matter. i don't know man
Which source of energy causes most of the water evaporation on Earth’s surface?
A.
wind
B.
solar
C.
gravity
D.
electrical
Answer:
I think it will be b. solar
Hope I can help.
Answer:
Explanation:
its b
Starting from rest, a spinning disk accelerates constantly to a final rotational speed, ω , in a period of time, Δ Δ t. What expression best represents the revolutions the disk has turned through? A) ω Δ Δ t /2 π B) Δ4 ω Δ t 4 π C)Δ22 ω Δ t 2 2 D) Δ ω Δ t E) 2Δ 2 π ω Δ t
Answer:
the correct one is B, θ = [tex]\frac{1}{4\pi }[/tex] w t [rev]
Explanation:
This is a rotational kinematics exercise
w = w₀ + α t
w² = w₀² + 2 α θ
indicate that part of rest whereby the initial angular velocity is zero
w = α t -> α = w/t
w² = 2 α θ
we substitute
w² = 2 (w / t) θ
w = 2 θ / t
θ = w t / 2
This angle is given in radians, let's reduce to revolutions = 2π rad = 1 rev
θ = w t / 2 rad (1 rev / 2π rad)
θ = [tex]\frac{1}{4\pi }[/tex] w t [rev]
when checking the answers, the correct one is B, even though he has some mistakes in his writing
can someone pls help me answer both of these (its ok if u only do one). ILL GIVE A BRANIEST TO WHOEVER CAN GET IT RIGHT. thank you! :)
Answer:
for number 1 i got 100
Explanation:
What training principle states that you must continue to exercise to mantain fitness a. Balance
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10s. If the airplane is putting out an average force of 5.8810x10^4 N during this time, what is the average friction force exerted on the airplane by the air?
Given :
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.
If the airplane is putting out an average force of [tex]5.8810\times 10^4 \ N[/tex].
To Find :
The average friction force exerted on the airplane by the air.
Solution :
Acceleration is given by :
[tex]a = \dfrac{162-120}{2.10}\ m/s^2\\\\a = 20 \ m/s^2[/tex]
Now, force equation is given by :
[tex]F - F_{friction} = ma\\\\F_{friction} = F-ma\\\\F_{friction} = 58810 - (2450\times 20 )\\\\F_{friction} = 9810\ N[/tex]
Therefore, frictional force exerted in the airplane by the air is 9810 N.
How are magnetic and electric fields similar?
Answer:
Similarities between magnetic fields and electric fields: ... Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges (but moving charges). Like poles repel; unlike poles attract. Electric field points in the direction of the force experienced by a positive charge ...
Explanation:
copied and pasted from google. I copied and pasted your question into google and got this exact answer
Here is another thing from the same website just not shortened:
Similarities between magnetic fields and electric fields:
- Electric fields are produced by two kinds of charges, positive and negative. Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges (but moving charges).
- Like poles repel; unlike poles attract
- Electric field points in the direction of the force experienced by a positive charge. Magnetic field points in the direction of the force experienced by a north pole.
Differences between magnetic fields and electric fields:
- Positive and negative charges can exist separately. North and south poles always come together. Single magnetic poles, known as magnetic monopoles, have been proposed theoretically, but a magnetic monopole has never been observed.
- Electric field lines have definite starting and ending points. Magnetic field lines are continuous loops. Outside a magnet the field is directed from the north pole to the south pole. Inside a magnet the field runs from south to north.
Similarities between magnetic fields and electric fields Magnetic fields are associated with two magnetic poles, north and south, Electric field points in the direction of the force experienced by a positive charge.
Similarities between magnetic fields and electric fields:
Electric fields are produced by two kinds of charges, positive and negative. Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges.
Electric field points in the direction of the force experienced by a positive charge. Magnetic field points in the direction of the force experienced by a north pole.
Differences between magnetic fields and electric fields:
Positive and negative charges can exist separately. North and south poles always come together. Single magnetic poles are known as magnetic monopoles.
Electric field lines have definite starting and ending points. Magnetic field lines are continuous loops. Outside a magnet, the field is directed from the north pole to the south pole. Inside a magnet, the field runs from south to north.
Therefore, Similarities between magnetic fields and electric fields Magnetic fields are associated with two magnetic poles, north and south, Electric field points in the direction of the force experienced by a positive charge.
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I WOULD GIVE BRAINLIEST TO ANYONE THAT ANSWERS :) ✌
How would you build a device to convert the blowing of the wind into a form a car could use to drive down the street on regular tires and wheels?
Answer:
I would add a higher center of gravity, and make the car shaped in a way where wind could hit it, and the wind won't affect the car's movement whatsoever.
Explanation:
A higher center of gravity ensures that your car will take less effects from the wind, and the shape would make it barely noticeable.
It is simpler to maintain your balance the lower your center of gravity is. You can lean over more if you're sitting down than if you're standing. You can lean further to one side or the other when your center of gravity is low.
What device to convert the blowing wind to a form of a car?From a handling perspective, lower is better since it lessens weight transfer during cornering and braking and lessens the tendency to roll over.
For safe handling, the height of the vehicle's center of gravity is crucial. You are more likely to go over if your center of gravity is high, like in the case of having large or stacked-high cargo on top.
It is especially hazardous when driving around curves or when swerving to avoid hazards.
Increase the center of gravity of the vehicle and shape it so that it can be hit by wind without the wind having any impact on how the vehicle moves.
Therefore, Your car will be less affected by the wind if it has a higher center of gravity, and the shape would barely be evident.
Learn more about blow here:
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Arrange Kepler's laws in order: a. The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun. b. The path of each planet around the sun is an ellipse with the sun at one focus. c. As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times. a. 3, 2, 1 b. 2, 3, 1 c. 3, 1, 2 d. 1, 2, 3
Answer:
2,3,1
Explanation:
There are 3 laws of Kepler.
First law = The path of each planet around the sun is an ellipse with the sun at one focus.
Second law = As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.
Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.
Hence, the correct order for Kepler's law is: 2,3,1
I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......
A eureka can of mass 100g and cross-section area 100cm2 is filled with water of density 1g/cm3. A piece of metal of mass 20g and density 8g/cm3 is lowered into the can. ( height of can 10cm ) calculate:
a) the total mass of can before the metal was lowered.
b) the volume of water that overflowed
c) the final mass of can and its content
Answer:
Explanation:
a)
Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.
100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]
Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....
[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg
Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....
1000g + 100g = 1100g or 1.1kg
b)
The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....
20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]
c)
Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.
[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g
So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.
100g + 997.5g + 20g = 1117.5g or 1.1175kg
A 0.25-kilogram ball is observed to accelerate at 4,000 m/sec2 as it is hit with a bat.
How much force is exerted on the bat by the ball?
Answer:
1000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 0.25 × 4000
We have the final answer as
1000 NHope this helps you
A rollercoaster car has 2500 J of potential energy and 160 J of
kinetic energy at the top of the first hill.
How much energy and what kind of energy will there be at the
bottom of the first hill?
Answer:
xaubUajnaai ajn AJ au aun a
Explanation:
ahayba uabah an aj
When momentum is conserved it is called _____. (multiple choice)
A.) Conservation of Momentum
B.) The Law of Momentum
C.) The Physics of Momentum
D.) The Rules of Momentum
Answer:
Based off the word "conserved" I would say
A. Conservation of Momentum.
Explanation:
Answer:
A.) Conservation of Momentum
How does rocks and fossils determine Earth's age?
Answer:
There are two main ways to determine the age of a rock, these are Relative dating and Absolute dating. Relative dating is used to determine the relative order of past events by comparing the age of one object to another.
Explanation:
Explanation:
rock and fossils are made by layers of dirt, sand,organic matter that has beem compressed over thousands,if not millions of years.
some scientists use this layering to determine how old the earth is.
its kind of like looking at the rings of a tree to see how old it is.
the scientists look at each layer of the rock or fossil and use what they already know about when this type of soil or organic matter existed and try to piece together the past
A lava lamp is a decorative item found in some homes. The lamp portion contains a waxy substance in a liquid medium. When the lamp is plugged in, a bulb at the base of the lamp slowly heats the waxy substance sitting at the bottom of the liquid. Eventually, the waxy substance will separate into globs that quickly rise to the top of the lamp where the surrounding liquid cools them and causes them to fall back to the bottom. Based on the information provided, a lava lamp could be used to provide an example of which process of thermal energy transfer?
Answer:
Conduction, convection, and radiation
Explanation:
Conduction is the process in which energy is transferred from a hot body to a cooler body. Convection is a process by which heat is transferred as a result of the movement of heated fluid in the form of air or water. Radiation refers to the transmission of energy through a material medium.
Based on the information provided, a lava lamp could be used to provide an example of conduction, convection, and radiation.
the actuon of a lever is affected by the?
A ferry approaches shore moving north waith a speed of 6.1 m/s relative to the dock. A person on the feery walks from one side of the ferry to the other moving east with a speed of 1.0 m/s relative to the feery
Answer:
6.18 m/s
Explanation:
Given that a ferry approaches shore, moving north with a speed of 6.1 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.0 m/s relative to the ferry Part. What is the speed of the person relative to the dock?
The speed of the person can be calculated by using pythagorean theorem.
Let the speed of the person = S
S^2 = 6.1^2 + 1^2
S^2 = 38.21
S = sqrt ( 38.21)
S = 6.18 m/s
Therefore, the speed of the person relative to the dock is 6.18 m/s
6th grade science I mark as brainliest.
Answer:
divide 10 by 50.
Explanation:
Because its time over speed 10/50
5 meter/ second
I think it's helpful
follow me and don't forget to Mark me as brainlist please
A car accelerates from rest at a constant acceleration of 25.0 m/s^2. At some point, it then turns off its engine, letting the car decelerate slowly from the force of friction at a constant deceleration of 3 m/s^2 until it is at rest again. The total speed the car moves in this time is 200 meters. What is the minimum time needed for the car to move 200 meters given that it both starts and ends at rest?
Answer:
t = 9.14 s
Explanation:
We first analyze the accelerating motion by applying first equation of motion:
Vf₁ = Vi₁ + a₁t₁
where,
Vf₁ = Final Speed of Car before turning off engine
Vi₁ = Initial Speed of Car = 0 m/s
a₁ = acceleration of car = 25 m/s²
t₁ = time taken in accelerating motion
Therefore,
Vf₁ = 25t₁ ---------- equation (1)
Now, we apply second equation of motion:
s₁ = Vi₁ t₁ + (1/2)a₁t₁²
where,
s₁ = distance covered during accelerating motion
Therefore,
s₁ = (0)t₁ + (1/2)(25)t₁²
s₁ = 12.5 t₁² ----------- equation (2)
Now, we analyze the decelerating motion by applying first equation of motion:
Vf₂ = Vi₂ + a₂t₂
where,
Vf₂ = Final Speed of Car = 0 m/s
Vi₂ = Initial Speed of Car after turning off engine
a₂ = deceleration of car = - 3 m/s²
t₂ = time taken in decelerating motion
Therefore,
Vi₂ = 3t₂ ---------- equation (3)
Now, we apply second equation of motion:
s₂ = Vi₂ t₂ + (1/2)a₂t₂²
where,
s₂ = distance covered during decelerating motion
Therefore,
s₂ = (Vi₂)t₂ + (1/2)(-3)t₂²
s₂ = Vi₂ t₂ - 1.5 t₂²
using equation (3):
s₂ = 3 t₂² - 1.5 t₂²
s₂ = 1.5 t₂² ------------ equation (4)
Now, we know that the Final Velocity of accelerating motion (Vf₁) is equal to the initial velocity of decelerating motion (Vi₂):
Vf₁ = Vi₂
using equation (1) and equation (3):
25 t₁ = 3 t₂
t₁ = 0.12 t₂ ------------ equation (5)
Also, we know that sum of the distances is 200 m:
s₁ + s₂ = 200
using equation (2) and equation (4):
12.5 t₁² + 1.5 t₂² = 200
using equation (5):
12.5 (0.12 t₂²) + 1.5 t₂² = 200
3 t₂² = 200
t₂² = 200/3
t₂ = 8.16 s
substitute this in equation (5):
t₁ = 0.12(8.16 s)
t₁ = 0.97 s
Hence, the minimum time required for this motion is:
t = t₁ + t₂ = 0.97 s + 8.16 s
t = 9.14 s
a claim is a set of interacting parts forming a complex whole true or fasle.
Answer:
false
Explanation i have none