The pressure exerted on the floor by each leg is 427832.0079 Pa.
F = mg
F = (4.5 + 65) × 9.8
F= 681.1 N
This force is evenly distributed on the three leg
radius, r = d/2
= 2.6 / 2
= 1.3 cm = 0.013 m
Total cross sectional area of the three legs, A = 3×π×[tex]r^{2}[/tex]
A = 3 × 3.14 × [tex]0.013^{2}[/tex]
A = 0.00159 [tex]m^{2}[/tex]
Pressure due to weight,
P = Weight/A
P = 681.1/ 0.00159
P = 427832.0079 Pa
Hence, the pressure exerted on the floor by each leg is 427832.0079 Pa.
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Name four planets which never get above freezing at the equators
Answer:
Mercury, Venus, Earth, Mars
Pls help me rapidly is of physical science:
Nitrogen belong to the group 15/5a period 3. It is also Known as pnictogen family .
The pnictogen family—what is it?Any chemical element in group 15 of the periodic table is a pnictogen. Group 15 is often referred to as the nitrogen family or group. Nitrogen, phosphorus, arsenic, antimony, bismuth, and moscovium make up group 15.
What is Periods ?A row of chemical elements makes up a period in the periodic table.
What is groups?In the periodic chart of chemical elements, a group is a column of elements.
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assume that a rod-drawing operation can be carried out either in one pass or in two passes in tandem. if all die angles are the same and the total reduction is the same, will the drawing forces be different?
The drawing forces will be the same because the drawing process can be thought of as a series of incremental reductions taking place in a single die.
What is the draw force of a rod?The pull on the exit section and the friction forces acting along the tube-mandrel interface transmit draw force to the metal. The drawing forces will be the same unless the surface of the rod changes due to external effects such as the environment or additional lubrication while it is between the two dies. There is also increased reduction on a single die.
Ideally, a die can cut into several segments and make it a tandem process. Also, in a tandem operation, the front tension of one segment becomes the back tension of another.
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3
1 point
Which term is equal to velocity change per second?
gravity
O velocity
O speed
Oacceleration
Answer:
acceleration
hope this helps ;>
A train travels with a constant speed of 20.0m/s for 8.00s. Determine all unknowns and answer the following question(s).
Answer: Since the train travels with a constant speed, it does not experience any acceleration. The magnitude of the train's acceleration is 0 m/s^2.
The distance the train travels during this time can be calculated using the formula d = vt, where d is the distance, v is the velocity, and t is the time. Plugging in the values given, we have:
d = 20.0 m/s * 8.00 s = <<20*8=160>>160 m
Therefore, the train traveled a distance of 160 meters during this time.
can somebody help me i want to do my homework please
The difference between the two plot is shown clearly by the distance between the two waves.
What is wave?Wave is defined as a disruption in an energy-conducting medium without a net movement of particles. Wind is the most frequent cause of waves. Wind-driven waves, sometimes referred to as surface waves, are created by friction between the wind and the water's surface.
The two difference between the two plot are the first is the difference between the distance of two crust and trough between the wave in the plot. The second difference is that the first plot is between displacement and distance from the source and the second graph is plot between displacement and time.
Thus, the difference between the two plot is shown clearly by the distance between the two waves.
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in an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression,
The piston's position is given as x = 4.33 cm, piston's velocity is given as v = -5 cm/s and piston's acceleration a = -17.3 m/s².
Given that, piston oscillates with simple harmonic motion so that its position varies according to the expression x = 5 cos( 2t + π/6 ), where x is in centimetres and t is in seconds.
The equation for piston's position is given as
x = 5 cm cos( 2t + π/6 )
At t = 0, x = 5 cos( π/6 ) = 4.33 cm
To find out piston's velocity, we have to differentiate the equation for position with respect to time.
v = dx/dt = -(10 cm/s) sin(2t + π/6)
At t = 0, v = -5 cm/s
To find out piston's acceleration, we have to differentiate the equation for velocity with respect to time.
a = dv/dt = -(20 cm/s²) cos (2t + π/6)
At t = 0, a = -17.3 cm/s²
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LAb motion What do the key results indicate?
Answer:The key results explains how you achieve a certain goal. They have to be quantitative, but always measurable in terms of their progress.
Explanation:
A cello string 0.75 m long plays a fundamental frequency of 220hz . The wavelength and speed of a wave on the string is
the wavelength was found to be1.5m and the speed was found to be 330m/s
define wavelength ?
The distance over which a periodic wave's form repeats is known as the wavelength in physics. It is a property of both travelling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings. The spatial frequency is the reciprocal of wavelength. The Greek letter lambda is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.
A string's length must be half its wavelength for the fundamental frequency to be present. This is,
L is the string's length, and y is its wavelength, therefore 1/2y = L.
y = 2L = 2x0.75 = 1.5 m as a result.
and y=v/f
v=y*f
=15x220
=330 m/s
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On which planet would a measuring instrument placed at the planets equator record the longest time from sunrise to sunset? (1)Mercury (2)Venus (3) Earth (4) Mars
Venus has the longest time from sunrise to sunset, if a measuring instrument is placed at the planet's equator, so option 2 is correct.
What are planets?A planet is a celestial body that revolves around the Sun, has enough mass to overcome rigid body forces and take on a hydrostatic stability shape (nearly round), and has cleared the area in and around its orbit.
The diurnal cycle on Mars is remarkably similar to that on Earth. 24 hours, 37 minutes, and 22 seconds comprise its sidereal day, whereas 24 hours, 39 minutes, and 35 seconds add up to its solar day. Thus, a Martian day (known as "sol") is about 40 minutes longer than an Earthly day.
Venus rotates once every 243 days on Earth. The day on Venus is longer than its orbit.
The smallest and nearest planet to the Sun in the Solar System is Mercury. It is the Sun's planet with the shortest orbital period, taking 87.97 Earth days.
Therefore, Venus has the longest time from sunrise to sunset, if a measuring instrument is placed at the planet's equator.
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the total energy of the twosphere system with earth still external changes as the systemm goes from the confirguration
The supplied statement implies that the system is not being torqued externally.
What kind of energy exist?The six primary forms of energy are biological, galvanic, radiative, muscular, thermal, the nuclear fuel. Other research may focus on other kinds of electrolytic, acoustic, electromagnetic, and others.
Why is energy such a big deal?Despite being a basic human requirement, energy plays a significant role in our daily lives. Energy not only heats but also cools the structures that humans have built. You require energy in order to lift your finger, get out of mattress, or even just walk along the main walkway.
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What kind of machines do astronautical engineers work with?
The astronautical engineers work with machine that fly outside the Earth's atmosphere.
What is aerospace engineering?
The design, development, testing, and production of aircraft, spacecraft, and associated systems and equipment fall within the purview of aerospace engineering. The two main and overlapping sections of the field—aeronautical engineering and astronautical engineering—have historically concentrated on issues relating to air and space flight.
The theory, technique, and application of flight within the earth's atmosphere are the main topics of aeronautical engineering.The science and technology of spacecraft and launch vehicles are the main areas of interest in astronautical engineering.Learn more about aerospace and aeronautical engineering here:
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access flooring systems typically consists of modular floor panels that rest on stringers or pedestals. panel sizes typically range from ____ to 24 inches square.
Modular floor panels that rest on pedestals or stringers make up most access flooring systems. Typically, panel dimensions start at 24 by 24 inches square with same distance.
Their dimensions are constant; a raised floor panel is typically 600 mm by 600 mm. A standard access flooring panel in the USA is slightly larger, measuring 24" x 24". (around 610mm). A brand-new and cutting-edge patented solution that comprises of a polished concrete floor panel system that is intended to be put on to a new or retrofit building project is available. The imperfections and traits of a normal polished concrete floor are evident in this appealing, authentic concrete surface. The longest dimension of an object in geometric terms is its distance. International System of Quantities.
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An astronaut is traveling in a spacecraft in outer space in a straight line at a constant speed of 0.850c. Which of the following effects would she experience?
(Select all that apply.)
A She would feel heavier.
B She would find it harder to breathe.
C Her heart rate would change.
D Some of the dimensions of her spacecraft would be shorter.
E None of those answers is correct
Due to traveling in a spacecraft in outer space in a straight line at a constant speed of 0.850c, an astronaut experiences: she would feel heavier, her heart rate would change, some of the dimensions of her spacecraft would be shorter.
What is special relativity?The theory of special relativity explains how speed affects space, time, and mass. Small amounts of mass (m) can be interchangeable with large amounts of energy (E), as defined by the classic equation E = mc^2, according to the theory, which offers a means for the speed of light to define the link between energy and matter.
When talking about extremely high energy, incredibly fast speeds, and astronomical distances without the difficulties of gravity, special relativity is typically employed.
The mass of an object and the energy needed to move it both grow unlimited as it gets closer to the speed of light. This implies that no substance can move more quickly than light does.
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you take a running leap, leaving the ground with a speed 6.00 m/s at an anglle 40.0 degrees above horizontal.
The maximum height reached while running is calculated to be 0.75m.
The formula for the maximum height of the projectile motion is given by
H = u² (sin θ)²/2g
where, θ is the angle made with the horizontal
H is the maximum height reached
g is the acceleration due to gravity
u is the initial velocity
Given that, u = 6 m/s
g = 10 m/s²
θ = 40°
Substituting the above values, we have,
H = u² (sin θ)²/2g = 6² * (sin 40°)² / 2 * 10 = 36* 0.414/20 = 0.75 m
Thus, the maximum height reached while running is 0.75m.
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if a magnitude of frequency of simple pendulum on Earth surface was(0.263Hz) What is the period for this pendulum at the same place on Earth surface?
Answer:
The period of a simple pendulum is the time it takes for the pendulum to complete one full swing. This is equal to the reciprocal of the frequency, which means that if the frequency of a simple pendulum is 0.263 Hz, its period would be 1/0.263 = 3.80 seconds. This is the time it would take for the pendulum to swing back and forth once at the same location on the Earth's surface.
Explanation:
At a distance r from a charge e on a particle of mass m the electric field value is
At a distance r from a charge e on a particle of mass m the electric field value is 8.9876 × 10⁹ N·m²/C². Divide the magnitude of the charge by the square of the distance of the charge from the point. Multiply the value from step 1 with Coulomb's constant.
what is magnitude ?Magnitude can be defined as the maximum extent of size and the direction of an object.
It is used as a common factor in vector and scalar quantities, as we know scalar quantities are those quantities that have magnitude only and vector quantities are those quantities have both magnitude and direction.
There are different ways where magnitude is used Magnitude of earthquake, charge on an electron, force, displacement, Magnitude of gravitational force
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The statement by Newton that for every action there is an equal but opposite reaction is which of his laws of motion?
Answer: The third law.
Explanation:
If a roadway is banked at the proper angle, a car can round a corner without any assistance from friction between the tires and the road. Find the appropriate banking angle for a 900-kg car traveling at 20.5 m/s in a turn of radius 85.0 m.
Answer:
N cos θ = m g where N is the normal force
N sin θ = m v^2 / R
tan θ = v^2 / (R g) dividing equations
tan θ = 20.5^2 / (85 * 9.80) = .505
θ = 26.8 deg banking angle required
If you know anything about physics please help me i am extremely confused thank you
Each point is at 1-sec time interval, So velocity will be 20 m/s downward at point F.
What is 1st kinematic equation?Kinematics is a branch of classical mechanics that studies the motion of points, objects, and groups of things without addressing the causes of motion. Kinematics is derived from the Greek word "kinesis," which means "motion."
Kinematic equations are a collection of equations that explain an object's motion with constant acceleration. Integrals, rates of change, and derivatives must be understood in order to solve kinematics problems.
Given that Initial speed of ball = V₁= 30 m/s at point A
Now V₂ = -20 m/s [(-)ve sign since final velocity is downward]
a = acceleration due to gravity = - 10 m/s², So
Using 1st kinematic equation:
V₂ = V₁ + a × t
t = (V₂ - V₁)/a
t = [(-20) -30] / (-10) = 5 sec
So velocity of ball will be 20 m/s in downward direction after 5 sec.
Since each point is at 1-sec time interval, So velocity will be 20 m/s downward at point F.
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In the figure, a frictionless roller coaster car of mass m = 826 kg tops the first hill with speed vo = 16.0 m/s at height h = 41.0m. What is the speed of the car (a) point A. (b) point b, and (c) point C? (d) How high will the car go on the last hill, which is too high for it to cross? Use g=9.81 m/s2
The speed of the car at point A is 16 m / s, and the velocity at point B is 24.83 m / s.
What is speed?Speed is the measure of how quickly a moving object changes its distance traveled. It follows that since speed is a scalar, it is a measurement with a magnitude but no direction.
Something that moves quickly and at a high speed, covering a lot of distance quickly. An object moving slowly at a low speed, on the other hand, travels a comparatively short distance in the same amount of time. A thing moving at zero speed doesn't move at all.
Given:
The mass of the car, [tex]m = 826\ kg[/tex],
The initial speed, [tex]u = 16\ m/s[/tex]
(a) The Potential energy [tex](P)[/tex] at point A is the same as the initial because the height of the car is the same.
So, the velocity at point A = 16.0 m/s
(b) Calculate the total energy at the point [tex]E_A = mgh + (1/2)m\times v_A^2 = 833\times 9.81\times 43 + 0.5\times 833\times 16^2[/tex]
[tex]E_A = 432408.39 J[/tex]
And total energy at point [tex]E_B = mgh/2 + (1/2)m\times v(B)^2 = 833\times 9.81\times 43/2 + 0.5\times 833\times v_B^2[/tex] = [tex]E_B =175692.20 + 416.5\times v_B^2[/tex]
Solve the equations,
[tex]432408.39 = 175692.20 + 416.5\times v_B^2[/tex]
[tex]v_B = 24.83 m/s.[/tex]
Therefore, the speed of the car at point A is 16 m / s, and the velocity at point B is 24.83 m / s.
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A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 231 kg. A small boy of mass m = 48 kg runs tangentially to the merry-go-round at a speed of v = 2.5 m/s and jumps on.
Required the moment of inertia of the merry go round.
a. I = 12 MR2 is the formula for the merry-go-moment round's of inertia.
I = ½ * 231 * (1.3 * 1.3)
I = 195.195 kgm2
b. The boy's angular speed is specified as = v/R = 2.5/1.3 = 1.92 rad/s.
c. I' = I + mR2 is the formula for the merry-go-moment round's of inertia following the boy's jump on it.
I’ = 195.195 + 48 * (1.3 * 1.3)
I’ = 276.315 kg/m2
The conservation of angular momentum principle determines the merry-go-angular round's speed. As a result, I (0) + m R = 'I' and = (48 * 1.92* 1.3) / 276.315 = 0.433 rad/s
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A ball is projected upward with an initial speed of approximately 30m/s. The diagram at the right represents its position at 1-second intervals of time. At what location will the ball be moving upward with a speed of approximately 10m/s ?
The ball will be moving at a speed of 10m/s when it's at position C.
Using first equation of motion
v=u-at
where
v is final speed
u is initial speed
a is acceleration (here a will be replaced with g as the motion is vertical)
t is time
u = 30m/s
v = 10 m/s
g = -10m/s
By substituting the values ,
10=30 - gr ( taking g as 10)
10t=20
t= 2s
It was given at each position is at the interval of one second each, so the body will be at position C when going upwards at a speed of 10m/s.
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5. Which of the following correctly describes the above situation?
6. The final velocity of the two cars after they hit and stick together is:
In this case, the magnitude of the momentum of vehicle 2 is greater than the vehicle 1.
What is momentum?
In Newtonian mechanics, an object's mass and velocity are combined to form momentum, more precisely linear momentum or translational momentum. It has both a magnitude and a direction, making it a vector quantity.
The kilogramme metre per second (kg m/s), or newton-second in the International System of Units (SI), is the unit used to measure momentum.
The rate of change of a body's momentum is equal to the net force exerted on it, according to Newton's second law of motion. Although momentum varies depending on the frame of reference, it is a conserved quantity in any inertial frame, which means that if a closed system is not impacted by outside forces.
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A crate is pulled to the right with a force of 71.6 N, to the left with a force of 228.2 N, upward with a force of 457.7 N, and downward with a force of 232 N.
Pt 1: What is the net external force in the x direction? Answer in units of N.
Pt 2: What is the net external force in the y direction? Answer in units of N.
Pt 3: What is the magnitude of the net external force on the crate?
Pt 4: What is the direction of the net external force on the crate (as an angle between −180◦ and 180◦, measured from the positive x-axis with counterclockwise positive)?
Answer: (see answers below)
Explanation:
Fnet x = 71.6 - 228.2 = -156.6 N (left)
Fnet y = 457.7 - 232 = 225.7 N (up)
R = [tex]\sqrt{-156.6^{2} + 225.7^{2} }[/tex] = [tex]\sqrt{75464}[/tex] = 274.7 N
Angle of R = 180 - (tan-1)[tex]\frac{225.7}{156.6}[/tex] = 180 - 55.2 = 124.8°
What is true about the foci of a planet in elliptical orbit?
A:The sun is located at one focus.
B: Earth is located at one focus.
C: Earth is located in the center of the orbit.
D: The sun is located in the center of the orbit
Statement A. The sun is located at one focus is true about the foci of a planet in an elliptical orbit (option A).
What is an elliptical orbit?An elliptical orbit can be defined as any movement of a celestial body in which the attained object (for example a planet around its star) moves in an eccentric manner or oval-shaped way, which is a feature of the planets in the solar systems including the Earth planet.
The movement of a planet in an elliptical orbit is called an ellipse, while two points that are selected chosen at the start site are known as foci in such orbits.
Therefore, with this data, we can see that an elliptical orbit is an excentric movement of a celestial body such as the earth's planet around the sun, and foci are called to fixed points located inside this orbit.
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Problem-1 A gelatin block with mass 1.00kg is sitting at rest on top of a horizontal surface. The
coefficient of kinetic friction between the block and the surface is 0.70.
A small steel ball with mass 10.9g is moving horizontally directly at the center of the block with a speed
of 853m/s. The ball then collides with the block and gets stuck inside of it.
(a) Assuming that the block stays in one piece, how much of the initial kinetic energy of the ball was
converted into overall (heat + light + sound + material distortions) energy during the collision?
KE = 1/2
KE=
- lov
ми
2
10-9x 853
bo
= 3.9655X 10
The loss of energy in the form of heat, light, sound and material distortions 4014 joule.
What is law of conservation of energy?
Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.
The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that all energy is conserved in closed systems, or systems that are isolated from their surroundings.
The kinetic energy of the ball = 1/2×0.0109×863² joule = 4058 joule.
The kinetic energy of the block after the inelastic collision
= 1/2(1 + 0.0109)(0.0109×863/1.0109)² joule.
= 43.77 joule.
Hence, loss of energy in the form of heat, light, sound and material distortions = 4058 joule - 43.77 joule = 4014 joule.
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A light ray strikes the surface of crown glass (n = 1.520), at a 25° angle with respect to the normal from air (n = 1.000293), and leaves the glass, returning to the air. Determine the angle at which the light refracts when it enters the glass.
16.14° is the angle of refraction of the light when it leaves the glass.
What is angle of refraction?Snell's law states that the angle of refraction, θr, is proportional to the angle of incidence, θi and the ratio of the refractive indices of the two media that comprise the interface. The angle θr=θi and no refraction occur when the mediums have equal refractive indices.
Given that,
The glass has an index of refraction (n₁) = 1.52
Air has an index of refraction (n₂) = 1.000293.
According to Snell's law:
n₂/n₁ = sin θ₁ / sin θ₂
or, 1.000293 / 1.52 = sin θ₁ / sin (25°)
or, 0.6581 = sin θ₁ / 0.42262
or, 0.2781 = sin θ₁
or, θ₁ = sin⁻¹ (0.2781)
or, θ₁ = 16.15°
So, 16.15° is the angle of refraction of the light when it leaves the glass.
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a system consists of three particles, each of mass 7.50 g, located at the corners of an equilateral triangle with sides of 35.0 cm.
The magnitude of net force exerted on each one of the three masses is 0.53 * 10⁻¹³ N.
Given, m₁ = m₂ = m₃ = 7.5 g = 7.5 * 10⁻³ kg
Sides of the triangle = 35 cm = 35 * 10⁻² m
As the masses are the same and are at the corners of an equilateral triangle, two equal forces will act on each of the masses.
The forces on mass 1 due to mass 2 and due to mass 3 will be
| F₁₂| = Gm²/r²
⇒ 6.67* 10⁻¹¹* (7.5 * 10⁻³)²/(35 * 10⁻²)² = 375.19* 10⁻¹⁷/(35²* 10⁻⁴)
⇒ 0.306 * 10⁻¹³ N
| F₁₂| = | F₁₃| = 0.306 * 10⁻¹³ N
The magnitude of the net force on mass 1 can be found by the parallelogram law formula giving the magnitude of the resultant of two forces, given their magnitudes and the angle in between:
F₁ = | F₁₂ + F₁₃|
F₁ = √(| F₁₂| ² + | F₁₃|² + 2* | F₁₂|* | F₁₃| cos 60°) = √3 (F)
⇒ √3 * 0.306 * 10⁻¹³ = 0.53 * 10⁻¹³ N
The magnitude of force on each of the mass will be same.
Thus, the magnitude of force on each mass on the corners of the triangle will be 0.53 * 10⁻¹³ N.
The question is incomplete. The continuation to the above question is 'Find the magnitude of net force exerted on each of the three masses.'
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charging a capacitor involves a voltage source redistributing some electrons from one side of the capacitor to the other. T/F
True. When a voltage source is connected to a capacitor, it causes a redistribution of electrons within the capacitor. The voltage source drives the flow of electrons from one plate of the capacitor to the other, causing a separation of charge between the plates. This separation of charge is what gives rise to the electrical potential energy stored in the capacitor.
When charging a capacitor, the voltage source drives the flow of electrons from the negative terminal to the positive terminal. This flow of electrons is opposed by the capacitor, which acts like a resistor to the flow of current. As a result, the capacitor begins to charge up and the voltage across the capacitor increases until it reaches the voltage of the voltage source. At this point, the capacitor is fully charged and the flow of current stops. The charge on the capacitor can then be used to power an electrical circuit or to store electrical energy for later use.
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