A 4 kilogram box is at rest on a frictionless floor. A net force of 12 newtons acts on it. What is the acceleration of the box?

Answers

Answer 1

Answer:

3 m/s^2

Explanation:

Step one:

given

Mass m= 4kg

Force F= 12N

Required

Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force

F=ma

a=F/m

a=12/4

a=3 m/s^2


Related Questions

Guys I really need help here
a) Find the energy needed
to to heat a tank holding water of 60 kg to rise the temperature from 10 degree Celsius to 60 degree Celsius (c=4200
J/K°C)
b)find the time for rising this much temperature if the power of heater is 3KW

Answers

Answer:

c

Explanation:

What is a physical combination of two or more substances that are blended together without forming a new substance?

Answers

Answer:

It is called a mixture.

Explanation:

A mixture is a physical combination of 2 or more substances that are blended together without forming a new substance.

You used measurements of distance and time to find velocity. When you calculate the uncertainty on your measurements of time, what units will that uncertainty have?a. counts/time b. time^2 c. time d. time/counts

Answers

Answer:

C

Explanation:

The uncertainty will carry the unit of time because it's the time in itself that has error, and not the distance, nor the velocity.

Had it been the uncertainty was to the velocity, then we would say both the unit of the distance and that of the time would have been affected. But as it stands, only that of time will be affected.

Cars have safety features to protect people during a crash. A bumper is one type of safety feature. Which bumper design do
you think is safer?
a bumper that crumples
a bumper that's rigid

Answers

Answer:

Explanation:

second one ??? pls i hope im right

Answer:

A bumper that crumbles (plato)

Explanation:

Which of the following is an example of Newton’s second law of motion?


A.....Catie’s skateboard hits a curb and she falls forward onto the grass.

B.....a tissue and a rock are dropped from a ladder. The rock exerts a greater force when it hits the ground.

C.....a person stands on a chair and pushes down, and the chair pushes upwards on

the person.

D......Tires from a bike push against the road, and the road pushes back.

Answers

Answer:

B

Explanation:

Newton’s Second Law of Motion

Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.

This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.

The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.

Answer:

b

Explanation:

On a smooth horizontal floor, an object slides into a spring which is attached to another mass that is initially stationary. When the spring is most compressed, both objects are moving at the same speed. Ignoring friction, and considering the two masses and spring as a system, what is conserved during this interaction?A) momentum and potential energyB) kinetic energy onlyC) momentum and kinetic energyD) momentum onlyE) momentum and mechanical energy

Answers

Answer:

E) momentum and mechanical energy

Explanation:

In the context, an object is attached to the another mass with a spring which is initially at a rest position. Now when the spring is compressed, the two masses moves with the same speed. Now since the both the masses combines with the spring to move together they are considered as one system and in this case the momentum and the kinetic energy will be conserved.

The kinetic energy and momentum of the system after collision and the kinetic energy and momentum of the two masses before collision will be constant.

Two flat glass surfaces are separated by a 150-nm gap of air.
A. What wavelength light illuminating the air gap is reflected brightly?
B. What wavelength of radiation is not reflected in the air gap?

Answers

Answer:

a. 600 nm

b. 300 nm

Explanation:

According to the question it is given that there is two flat glass surface that is separated by 150nm air gap

Based on the above information

The computation is shown below

a. The bright thickness is

[tex]t = \frac{\lambda}{2} (m - \frac{1}{2} )\\\\\lambda = \frac{2t}{(m - \frac{1}{2} )} \\\\\frac{2(150)}{(1 - \frac{1}{2} )} \\\\[/tex]

= 600 nm

b. The dark thickness is

[tex]t = \frac{m\lambda }{2} \\\\\lambda = \frac{2t}{m} \\\\\frac{2(150)}{1}[/tex]

= 300 nm

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.380 m/s^2. Suppose it moves with constant acceleration for 3.80 s.

Required:
a. Find the position of the particle after this time.
b. Find its velocity at the end of this time interval.

Answers

Answer:

a

  [tex]x_2 = -2.3356[/tex]

b

 [tex]v = -1.384 \ m/s[/tex]

Explanation:

From the question we are told that

  The initial position of the particle is  [tex]x_1 = 0.180 \ m[/tex]

  The initial  velocity of the particle is  [tex]u = 0.060 \ m/s[/tex]

  The acceleration is   [tex]a = -0.380 \ m/s^2[/tex]

   The time duration is  [tex]t = 3.80 \ s[/tex]

Generally from kinematic equation

    [tex]v = u + at[/tex]

=>  [tex]v = 0.060 + (-0.380 * 3.80)[/tex]

=>  [tex]v = -1.384 \ m/s[/tex]

Generally from kinematic equation

   [tex]v^2 = u^2 + 2as[/tex]

Here s is the distance covered by the particle, so

   [tex](-1.384)^2 = (0.060)^2 + 2(-0.380)* s[/tex]

=>  [tex]s = -2.5156 \ m[/tex]

Generally the final position of the particle is  

    [tex]x_2 = x_1 + s[/tex]

=>   [tex]x_2 = 0.180 + (-2.5156)[/tex]

=>   [tex]x_2 = -2.3356[/tex]

Explain why balancing the forces acting on a body is not enough to establish equalibrium. Give anexample to justify your answer.

Answers

Answer:

Please find the answer in the explanation.

Explanation:

Balancing the forces acting on a body is not enough to establish equlibrium because of the principle of moment say that:

1.) For equilibrium to be attained, the sum of clockwise moment must be equal to the sum of anticlockwise moments.

2.) The sum of upward forces must be equal to the sum of the downward forces

According to the definition of moment, is the product of force and perpendicular distance.

Therefore, the perpendicular distance is needed to be considered.

what tells you the strength of a wave?​

Answers

the first factor is wind speed, the second factor is wind duration, and the last factor is the fetch, the distance over which the wind blows without a change in direction.

all these factors determines the strength of a wave.

hope this helps :)

How is energy that is stored in food released?
A- atoms increase in movement
B- atoms are split
C- heat is released
D-chemical bonds in fats are proteins are broken​

Answers

Answer:

i think its A

Explanation:

Answer:

D

Explanation:

The chemical energy stored in food is released by cells through the process of respiration. (cellular respiration)

This stored energy is released whenever these chemical bonds are broken in metabolic processes such as cellular respiration. Cellular respiration is the process by which the chemical energy of “food” molecules is released and partially captured in the form of ATP.

help please! what is the right answer ​

Answers

i think the answer is D. the opponent process theory
the answer to this question is D

Which of the following is most likely to occur at a convergent boundary?
A: Mountain formation
B: Seafloor spreading
C: Faults
D: Mid-Atlantic rift

Answers

Answer:A: mountain formation

Explanation:

Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja. If Derek pulls horizontally on the dog with a force of 10.0 N and Anudja pulls with a horizontal force of 11.0 N, what is the horizontal acceleration of the dog?

Answers

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

a = 3.33 m/s²

A 72.0-kg person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface of the door. The doorknob is located 0.800 m from axis of the frictionless hinges of the door. The door begins to rotate with an angular acceleration of 2.00 rad/s2, What is the moment of inertia of the door about the hinges? A) 2.74 kg m2 B) 1.88 kg m2 C) 0.684 kg m2 D) 4.28 kg m2 E) 7.52 kg m2

Answers

Answer:

[tex]I=2\ kgm^2[/tex]

Explanation:

Given that,

Mass of a person, m = 72 kg

Force acting on a doorknob, F = 5 N

The doorknob is located 0.800 m from axis of the frictionless hinges of the door.

The angular acceleration of the dor, a = 2 rad/s²

We need to find the moment of inertia of the door about the hinges.

The person applies a torque to the door and it is given by :

[tex]\tau=Fr[/tex] ...(1)

Also, the torque is equal to :

[tex]\tau=I\alpha[/tex] ...(2)

From equation (1) and (2) we get :

[tex]Fr=I\alpha[/tex]

I is the moment of inertia

[tex]I=\dfrac{Fr}{\alpha }\\\\I=\dfrac{5\times 0.8}{2}\\\\=2\ kgm^2[/tex]

So, the moment of inertia of the door about the hinges is [tex]2\ kgm^2[/tex].

Degree day calculations are based on a temperature of?

Answers

Answer:

65F

Explanation:

Find the Acceleration of a car with the mass of 1200kg and a force of 11x10^3 N

Answers

Answer:

9.17 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{11 \times {10}^{3} }{1200} \\ = 9.16666...[/tex]

We have the final answer as

9.17 m/s²

Hope this helps you

A metallic laboratory spring is typically 5.50cm long and 0.140 cm in diameter and has 50.0 coils. If you connect such a spring in an electric circuit, how much self-inductance must you include for it if you model it as an ideal solenoid?

L = ________?

Answers

Answer:

um hm err

Explanation:

how was the theory of plate tectonics developed?

Answers

Answer: A conflict between established theory, and empirical evidence, resulting in compromise.



Explanation;

Plate tectonic theory had its beginnings in 1915 when Alfred Wegener proposed his theory of "continental drift." Wegener proposed that the continents plowed through crust of ocean basins, which would explain why the outlines of many coastlines look like they fit together like a puzzle.

Answer:

Plate tectonic theory began in 1915, when Alfred Wegener developed his "continental drift" idea. Wegener believed that continents plowed through ocean basin crust, explaining why many coasts (such as those in South America and Africa) appear to fit together like a puzzle.

Find the mass of a water balloon that was thrown at Bookie with a force of 42 N and an acceleration of 3.99 m/s2.

Answers

Answer:

10.52 kg

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{3.99} \\ = 10.5263...[/tex]

We have the final answer as

10.52 kg

Hope this helps you

A vector B , with a magnitude of 8.0 m, is added to a vector A , which lies along an x axis. The sum of these two vectors is a third vector that lies along the y axis and has a magnitude that is twice the magnitude of A . What is the magnitude of A?

Answers

Answer:

the magnitude of A is 3.577

Explanation:

According to the question it is given that there is a magnitude of 8.0 m that added to the vector A that lies on x axis also the sum of two vectors would be third vector by considering the y axis and the magnitude is the twice of the magnitude B

The computation of the magnitude of A is shown below:

[tex]A \hat{i} + B = 2A \hat{j}\\\\A \hat{i} + 8 = 2A \hat{j}\\\\8 = 2A \hat{j} - A \hat{i}\\\\\mid8\mid = \sqrt{(2A \hat{j})^2 + (- A \hat{i})^2} \\\\8 = \sqrt{5A} \\\\A = \frac{8}{\sqrt{5} }[/tex]

A = 3.577

Hence, the magnitude of A is 3.577

An 4.0-kg fish pulled upward by a fisherman rises 1.9 m in 2.4 s, starting
from rest. Assuming the acceleration is constant, find the magnitude
and direction of the net force acting on the fish during this interval.

Answers

Answer:

2.64N  

Explanation:

Force = mass * acceleration

Given

mass = 4kg

distance = 1.9m

Time t = 2.4s

Get the acceleration using the equation of motion

S = ut + 1/2at²

1.9 = 0 + 1/2a(2.4)²

1.9 = 5.76a/2

1.9 = 2.88a

a = 1.9/2.88

a = 0.66m/s²

Get the magnitude of the force

Force = 4 * 0.66

Force = 2.64N

Hence the net force acting on the fish is 2.64N  

A child swings a sling with a rock of mass 1.3 kg, in a radius of 0.6. From rest to an angular velocity of 6 rad/s. What is the rotational kinetic energy of the rock?

Answers

Answer:

8.42Joules

Explanation:

The rotational kinetic energy, denoted by E(rotational), can be calculated using the formula:

E(rotational) = 1/2 × I × ω²

Where;

I = moment of inertia (kgm²)

ω = angular velocity (rad/s)

However, we need to calculate the moment of inertia in this question by using the formula:

I = m × r²

Where;

m = mass (1.3kg)

r = radius (0.6m)

I = 1.3 × 0.6²

I = 1.3 × 0.36

I = 0.468 kgm²

Since I = 0.468 kgm², ω = 6 rad/s, we can calculate rational kinetic energy using:

K.E(rotational) = 1/2 × I × ω²

K.E(rotational) = 1/2 × 0.468 × 6²

K.E(rotational) =1/2 × 0.468 × 36

K.E(rotational) = 18 × 0.468

K.E(rotational) = 8.424

K.E(rotational) = 8.42Joules

White light (380nm-750 nm) strikes a diffraction grating (900 lines/mm) at normal incidence. What is the highest-order visible maximum that is formed?

Answers

Answer:

Highest order: m = 1

Explanation:

Formula for solving this is;

dsin θ_m = mλ

We want to find m, thus;

m = (dsin θ_m)/λ

We are told that White light spans from 380nm - 750 nm. Thus, at maximum, λ = 750 nm.

θ_m = 90°

d = (900 lines/mm) = 9000 × 10^(-7) lines/nm

Since we want to find m, the units nm has to cancel out in the equation.

Thus, we will write d in nm/lines as (10^(7))/9000 nm/lines

Thus;

m = ((10^(7))/9000 × sin 90)/750

m = 1.48

Approximately 1

a. An object weighs 7.84 N when it is in air and 6.86 N when it is immersed in water. What is the specific gravity of the object?
b. How much pressure does it take for a pump to supply a drinking fountainwith 300 kPa, if the fountain is 30.0 m above the pump?

Answers

Answer:

a

 [tex]W_s = 8[/tex]

b

[tex]P = 594 000 \ Pa[/tex]

Explanation:

Considering question a

 From the question we are told that

   The weight of the object in  air is  [tex]W_1 = 7.84 \ N[/tex]

    The weight of the object in water  is [tex]W_2 = 6.86\ N[/tex]

Generally the specific gravity of the object is mathematically represented as

       [tex]W_s = \frac{W_1 }{W_1 - W_2 }[/tex]

=>    [tex]W_s = \frac{7.84}{7.84 -6.86 }[/tex]

=>    [tex]W_s = 8[/tex]

Considering question b

From the question we are told that        

   The pressure required is  [tex]P_r = 300 \ kPa = 300 *10^{3} \ Pa[/tex]

    The height is  [tex]h = 30.0 \ m[/tex]

Generally the pressure require to get the water to  the given height is mathematically represented as

      [tex]P_h = \rho * g * h[/tex]

Here  [tex]\rho[/tex] is the density of  water with value  [tex]\rho = 1000 \ kg / m^3[/tex]

So  

     [tex]P_h = 1000 * 9.8 * 30[/tex]

=>  [tex]P_h = 294000 \ Pa[/tex]

Generally the pressure require to pump the water to  the given height at the require pressure is mathematically represented as

      [tex]P = P_h + P_r[/tex]

=>  [tex]P = 294000 + 300*10^{3}[/tex]

=>  [tex]P = 594 000 \ Pa[/tex]

What is inertia?
An object's tendency to move quicker
An object's tendency to change direction
An object's tendency to resist changes in motion
An unbalanced force on an object

Answers

Answer:

I think the answer should be an object's tendency to resist changes in motion.

Explanation:

Inertia is resistance of any physical object to any changes in its velocity.

Answer:

an object's tendency to resist changes in motion.

Explanation:

What is the final speed of a free electron accelerated from rest through a potential difference of -120 V? The mass of the electron is 9.11x10-31kg. You need to express the speed in km/s.
You should round your answer to an integer, indicate only the number, do not include the unit.

Answers

Answer:

The final speed of the electron is 6,497 km/s

Explanation:

Given;

mass of the electron, m = 9.11 x 10⁻³¹ kg

electron potential, V = -120 V

Apply work energy theorem;

¹/₂mv² = eV

Where;

v is the final speed of the electron

e is the charge of the electron, = 1.602 x 10⁻¹⁹ C

[tex]v = \sqrt{\frac{2eV}{m} }\\\\v = \sqrt{\frac{2(1.602*10^{-19})(120)}{9.11*10^{-31}} }\\\\v = 6496473.75 \ m/s\\\\v = 6,497 \ km/s[/tex]

Therefore, the final speed of the electron is 6,497 km/s

Kenny eats a snickers bar. Her body uses the candy as energy to move her muscles. What type of energy conversion is this an example of?
A- Thermal to chemical
B- Chemical to mechanical
C-Chemical to thermal
D- Potential to mechanical​

Answers

Answer:

c- chemical  to thermal

Explanation:

At standard temperature and pressure, carbon dioxide has a density of 1.98 kg/m3. What volume does 1.70 kg of carbon dioxide occupy at standard temperature and pressure?

Answers

Answer:

volume= 0.85m^3

Explanation:

The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho

Step one:

given data

we are told that the density  of Co2=  1.98 kg/m3

and the mass of Co2 is= 1.70 kg

we know the relation between mass, volume and density is

[tex]density=mass/volume[/tex]

make volume subject of formula we have

[tex]volume=mass/density[/tex]

substitute we have

[tex]volume=1.7/1.98\\\\volume= 0.85m^3[/tex]

When a student shines a 540 nm laser through this grating, how many bright spots could be seen on a screen behind the grating?

Answers

Complete Question

A commercial diffraction grating has 600 lines per mm.  

When a student shines a 540 nm laser through this grating, how many bright spots could be seen on a screen behind the grating?

Answer:

The number of  bright spots is  [tex]m = 7[/tex]    

Explanation:

From the question we are told that

  The wavelength is  [tex]\lambda = 540 nm = 540 *10^{-9} \ m[/tex]

   The number of lines per length the commercial diffraction grating has is [tex]L = 600 \ lines / mm = 600 * 1000 \ lines / m = 600 *10^{3} \ lines / m[/tex]

Generally the condition for constructive interference is mathematically represented as

       [tex]dsin(\theta) = n\lambda[/tex]

Here d  is the separation between the gratings which is mathematically represented as

       [tex]d=\frac{1}{L}[/tex]

=>    [tex]d=\frac{1}{600 *10^{3}}[/tex]

=>    [tex]d= 1.67 *10^{-6 } \ m[/tex]

and  n is the order of bright fringe, the maximum number is seen when [tex]\theta = 90^o[/tex]

So

   [tex]1.67 *10^{-6}sin(90) = n * 540 *10^{-9 }[/tex]

=>  [tex]n = 3[/tex]

Generally the number of bright spot (considering central bright fringe and the same order of bright fringe on each side of the central  bright fringe) is mathematically represented as

      [tex]m = n * 2 + 1[/tex]

=>   [tex]m = 3 * 2 + 1[/tex]

=>   [tex]m = 7[/tex]    

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