A 2.5 kg block starts with a speed of 3 m/s, goes down a 4 m hill, and then slides up a new hill but stops when it is only 1.5 m high.
a) How much work was done by friction?
b) If there was no friction, how high could the block have slidden without stopping?

Answers

Answer 1

Answer:

See the answers below

Explanation:

This problem can be solved by means of the law of conservation of energy, which tells us that the energy between two points is conserved, that is, remains the same.

That is to say, we have two points, the point A where it starts to move and reaches the point B that is 1.5 [m] high, where it stops.

The key to solving this problem is to identify the types of energies at each point. At point A we have kinetic energy and potential energy where the block moves at speed 3 [m/s] at a height of 4 [m]. Whereas at Point B we only have potential energy, since the body is at a height of 1.5 [m], relative to the ground.

a)

Since between the displacement between points A and B there is a friction force, this friction force decreases the final energy in B, in this way the energy or work of the friction will have a negative sign.

[tex]E_{A}-W_{A-B}=E_{B}[/tex]

Now replacing in the above equation.

[tex](\frac{1}{2}*m*v^{2}+m*g*h_{1})-W_{1-2}=m*g*h\\(\frac{1}{2}*2.5*(3)^{2}+2.5*9.81*4)-W_{1-2}=2.5*9.81*1.5\\\\W_{1-2}=72.56[J][/tex]

b)

We must use the same equation, but this time eliminating the Working term due to friction.

[tex]E_{A}=E_{B}\\\frac{1}{2}*m*v^{2}+m*g*h_{A}=\ m*g*h_{B}[/tex]

[tex](\frac{1}{2}*2.5*(3)^{2}+2.5*9.81*4) =\ 2.5*9.81*h_{B}\\h_{B}=4.45 [m][/tex]

As we can see without friction the block can reach a higher height


Related Questions

Why does a concave lense always form a virtual image?

Answers

Answer:

Concave lens spreads out light rays that are then refracted through it.: A concave mirror or a converging lens will only produce a virtual image at a point if the image is located beyond the focal point. By the focal point, we define the point that is more than one focal length away.

From the poem Black woman what does it mean by Savannah stretching to clear horizons, Savannah shuddering beneath the East wind's eager caresses.​

Answers

Answer:

From the poem Black woman what does it mean by Savannah stretching to clear horizons, Savannah shuddering beneath the East wind's eager caresses.​

Explanation:

If a 1000 kg car is traveling at 3
meters per second, what is its
kinetic energy?

Answers

Kinetic energy:
KE= .5 mv^2
KE = .5 * 1000 kg * 3 m’s^2
KE = 4500 kg m^2/s^2
KE = 4500 Joules

Electromagnetic waves are classified as longitudinal waves.


Please select the best answer from the choices provided

T
F

Answers

Answer:

False

Explanation:

Electromagnetic waves are transverse waves. That means that the electric and magnetic fields oscillate in a plane that is perpendicular to the direction of wave propagation.

Answer:

false electromagnetic waves are not classified as longitudinal waves

Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth's surface. This would place the student a distance of 6.39 x 106 m from earth's center.

Answers

Answer:

[tex]F=683.790939[/tex]N

Explanation:

From the Question we are told that

Earth mass [tex]m_1= 5.98 * 10^2^4 kg[/tex]

Students mass [tex]m_2=70kg[/tex]

Distance of student from earth center Radius [tex]r=6.39 * 10^6 m[/tex]

Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by

 [tex]F=\frac{Gm_1m_2}{r^2}[/tex]

 [tex]F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}[/tex]

Therefore the force of attraction b/w the student and the earth is

 [tex]F=683.790939N[/tex]

 [tex]F\approx 684N[/tex]

Please answer the following question (in image).

Answers

We are given:

Mass of object 1(m₁) = 3000 kg

Mass of object 2(m₂) = 4500 kg

Distance between their centers(r) = 1.5 m

Gravitational Attraction between the objects:

We know the formula:

g = G(m₁)(m₂) / r² ,where G is the universal Gravitational Constant and g is the force of attraction

g = (6.67 * 10⁻¹¹ * 3 * 10³ * 4.5 * 10³) / (1.5)²

g = [(6.67 * 3 * 4.5) * (10³⁺³⁻¹¹)] / 2.25

g = (90 * 10⁻⁵) / 2.25

g = 40 * 10⁻⁵ N

An airplane is traveling at a speed of 200 m/s relative to the Earth. A person walks toward the front of the plane at a speed of 1 m/s. How fast is that person traveling in reference to the other people on the plane?

Answers

Answer:

1 m/s

Explanation:

This is because, everybody in the plane including the person walking is moving at the speed of the plane which is 200 m/s. Now, when the person starts to walk with a speed of 1 m/s, his relative velocity to the other passengers is 1 m/s since he is already moving at the speed of the plane before starting to walk.

His velocity relative to the ground V' = velocity of plane relative to ground, V + velocity of person relative to plane, v

V = 200 m/s and v = 1 m/s

So, V' = 200 m/s + 1 m/s = 201 m/s

Since the velocity of the other passengers is the velocity of the plane, V = 200 m/s. The velocity of the person traveling in reference to the other people on the plane is V" = V' - V = 201 m/s - 200 m/s = 1 m/s

What is a consequence that makes the behavior happen more frequently?
Punishment
Reinforcement
Reflex
Extinction

Answers

punishment is a consequence that makes the behavior happen more frequently.

please mark as brainleiest and follow me

Answer:

The correct answer on Grad Point is —Reinforcement

Explanation: I just got it WRONG from the above answer

Please help I’ll give you brain

Answers

Answer:

Explanation:

distance (km)

a) As near as I can tell from the graph, the distance travelled was 4km

b) I would answer 40 minutes, but don't be surprised if your instructor says 30 minutes.

c) The average speed is 4 km/40 minutes = 0.1 km/minute

Please help i will give brainliest

Answers

Answer:

Answers below--

Explanation:

1. F/Force

2.H/Contact force

3.A/Non-contact force

4.C/electric force

5.D/gravity

6.I(i)/magnetic force

7.J/kilogram

8.G/newton

9.B/friction

10.E/lubricant

What are the properties of photon

Answers

Answer:

I know they are stable, have no electrical charge, have interactions with electrons.

Explanation:

Identify the state of matter.

A)The molecules are a great distance apart, moving
very rapidly, with negligible interaction. The
substance occupies all the space available.
B)The molecules are only able to vibrate rapidly about
fixed positions. The substance does not need a
container to maintain its shape.
C)The molecules move about amongst each other,
with attractive forces between them. The substance
does not necessarily fill its container

Answers

Answer:

Gases

Solids

Liquids

Explanation:

A)The molecules are a great distance apart, moving  very rapidly, with negligible interaction. The  substance occupies all the space available.

Gases

The state of matter described above is for gases. The distances between gases are far apart and they have very weak intermolecular attraction. They have no fixed volume as they occupy any volume of space they are introduced into.

B)The molecules are only able to vibrate rapidly about  fixed positions. The substance does not need a  container to maintain its shape.

Solids

Solids have fixed shape and volume. They are held together in their fixed lattice and are only able to rapidly vibrate about their fixed positions.

C)The molecules move about amongst each other,  with attractive forces between them. The substance  does not necessarily fill its container.

Liquids

The state of matter described here are the liquids. Liquids flow amongst each other. The attractive force between them is greater than that of gases but lesser than those of solids.

A dependent variable is associated mainly with:
O A. the result of an experiment.
O B. the treatment group.
O C. the treatment in an experiment.
O D. the experimental group.

Answers

Answer: A. the result of an experiment.

The experimental group and treatment group are the same group. It's just two different names for the same thing. If you apply a treatment to a group, then that's where you're performing the experiment.

For instance, if you are testing a fertilizer, then the independent variable would be "use of fertilizer or not using fertilizer". So that means the control group doesn't get any fertilizer. The dependent variable would be the heights of the plants between the two groups, so we can see if the fertilizer has an effect or not. This is the result of the experiment. So in other words, the input is the fertilizer (or no fertilizer), and the output is measuring the heights of the plants. The output is the result we analyze.

Keep in mind that the heights of the plants are likely to be randomly distributed. So this is where statistics comes into play. If the plants grow due to some random chance, and not necessarily the fertilizer, then you can use the control group to determine if that's the case or not. The control group helps you do this comparison.

As the name implies, "dependent" means it relies on something else. The height of the plant relies on if you used fertilizer or not. The independent variable is able to change without relying on any other variable.

A cart falls from a track with an acceleration of 10 m/s2 (which is always the acceleration due to gravity). If it falls for 9 seconds before hitting the ground, what is it’s velocity at impact? (show work plz)

Answers

Answer:

90m/s

Explanation:

Given parameters:

Acceleration  = 10m/s²

Time of fall  = 9s

Unknown:

Final velocity  = ?

Solution:

We can assume that the cart falls from rest.

   Initial velocity  = 0m/s

Using

        v  = u + gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

       v  = 0 + 10 x 9  = 90m/s

Answer:

90m/s

Explanation:

2200 kg semi truck driving down the highway has lost control. The truck rolls across the median and into oncoming traffic. The truck collides with a 2000 kg car that is traveling north at 45 m/s. The two vehicles stick together creating a single wreck that travels south at 15 m/s. what was the initial speed and direction of the semi truck?

Answers

Answer:

The semi truck travels at an initial speed of 69.545 meters per second downwards.

Explanation:

In this exercise we see a case of an entirely inellastic collision between the semi truck and the car, which can be described by the following equation derived from Principle of Linear Momentum Conservation: (We assume that velocity oriented northwards is positive)

[tex]m_{S}\cdot v_{S}+m_{C}\cdot v_{C} = (m_{S}+m_{C})\cdot v[/tex] (1)

Where:

[tex]m_{S}[/tex], [tex]m_{C}[/tex] - Masses of the semi truck and the car, measured in kilograms.

[tex]v_{S}[/tex], [tex]v_{C}[/tex] - Initial velocities of the semi truck and the car, measured in meters per second.

[tex]v[/tex] - Final speed of the system after collision, measured in meters per second.

If we know that [tex]m_{S} = 2200\,kg[/tex], [tex]m_{C} = 2000\,kg[/tex], [tex]v_{C} = 45\,\frac{m}{s}[/tex] and [tex]v = -15\,\frac{m}{s}[/tex], then the initial velocity of the semi truck is:

[tex]m_{S}\cdot v_{S} = (m_{S}+m_{C})\cdot v -m_{C}\cdot v_{C}[/tex]

[tex]v_{S} = \frac{(m_{S}+m_{C})\cdot v - m_{C}\cdot v_{C}}{m_{S}}[/tex]

[tex]v_{S} = \left(1+\frac{m_{C}}{m_{S}} \right)\cdot v - \frac{m_{C}}{m_{S}} \cdot v_{C}[/tex]

[tex]v_{S} = v +\frac{m_{C}}{m_{S}}\cdot (v-v_{C})[/tex]

[tex]v_{S} = -15\,\frac{m}{s}+\left(\frac{2000\,kg}{2200\,kg} \right) \cdot \left(-15\,\frac{m}{s}-45\,\frac{m}{s} \right)[/tex]

[tex]v_{S} = -69.545\,\frac{m}{s}[/tex]  

The semi truck travels at an initial speed of 69.545 meters per second downwards.

1. A kangaroo hops 84 m to the east in 7 seconds.
o What is the kangaroo's speed? 12 m/s
o What is the kangaroo's velocity?

Answers

Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = [tex]\frac{distance}{time }[/tex]   = [tex]\frac{84}{7}[/tex]  = 12m/s

  Velocity  = [tex]\frac{displacement}{time}[/tex]   = [tex]\frac{84}{7}[/tex]   = 12m/s due east

I need help please I will give points

Answers

Answer:

-5 N of force

Explanation:

Hope it helps!

Planet Beta has two times a gravitational field strength and two times the mass of the Earth. How does the radius of planet beta compared with the radius of Earth

Answers

Answer:

rbeta=rearth

Explanation:

khan

Planet Beta has 2 times the gravitational field strength and 2 times the mass of the Earth.

How does the radius of planet Beta compare with the radius of Earth?

Answer: CORRECT (SELECTED

rBeta = rEarth

Which of these pairs of atoms are isotpoes? (Physical Science) Pair A Pair B Pair C # protons 6 8 5 2 12 12 # neutrons 8 8 5 3 13 14

Answers

Answer:

I guess that the atoms are:

Protons:     6     8    5    2    12    12

Neutrons:  8     8     5   3     13    14

Now, two atoms are isotopes if they share the same number of protons (so both atoms are the same element) but they have a different number of neutrons.

From the given options, the only two that have the same number of protons but a different number of neutrons are:

Protons 12, neutrons 13

and

Protons 12, neutrons 14.

These two are isiotopes.


Questions
1 A stone falls from rest from the top of a high tower. Ignore
air resistance and take g = 10 m/s2
a What is its velocity after
() 15
(ii) 25,
(iii) 35,
(iv) 5s?
b How far has it fallen after
(i) 15,
(ii) 2s,
(iii) 35,
(iv) 5s?
2 An object falls from a hovering helicopter and hits the
ground at a speed of 30 m/s. How long does it take the
object to reach the ground and how far does it fall? Sketch
a velocity-time graph for the object (ignore air resistance).

Answers

Answer:

I am sorry i don't do physics

A solar panel gives our 250 Watts
of power in 2 seconds. How much
work did the solar panel do?

Answers

2 seconds worth of work

[04.04] Which best describes the current atomic theory? ​

Answers

Atoms are composed of electrons in different clouds around a positive nucleus.

What is common between transverse waves and longitudinal waves?

Both include an amplitude, crest, and rarefactions
Both move faster at higher temperatures
Both move slower through densely packed molecules
Both include a wavelength from compression to compression

Answers

Answer:

b

Explanation:

i took the quiz

Both the transverse and longitudinal waves move faster at higher temperatures.

What is meant by transverse wave?

A wave in which the motion of the particles is perpendicular to the direction of the wave propagation is referred to as a transverse wave.

Here,

As a result of the shear stress that is produced, transverse waves are frequently observed in elastic materials.

In this situation, the oscillations are caused by the displacement of the solid particles from their relaxed state in directions perpendicular to the wave's propagation.

The wave in which the particles of the medium oscillate parallel to the direction of propagation of the wave is called a longitudinal wave.

Sound waves similarly oscillate parallel to the direction of propagation, forming the compressions and rarefactions. Hence sound waves are called longitudinal waves.

Hence,

Both the transverse and longitudinal waves move faster at higher temperatures.

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A solution is...

A. a mixture of two or more substances of the same state
B. a mixture of two or more substances. It is heterogeneous at the molecular level
C. a mixture of two or more substances. It is homogeneous at the molecular level
D. a mixture of two or more substances, one of which is water.

Answers

Answer:

C. a mixture of two or more substances. It is homogeneous at the molecular level

Q2. An initially stationary 18-kg curling rock has a force applied to it over 2.0s. Its released with a velocity of 8.3 m/s [forward]. Determine the magnitude and direction of the applied force. Try solving this problem two different ways.​

Answers

Answer: 74.7 N

Explanation:

Both approaches yield the same result: the magnitude of the applied force is approximately 74.7 N, and its direction is forward.

To solve this problem, we'll use two different approaches: Newton's second law and the work-energy principle.

Approach 1: Newton's Second Law

Newton's second law states that the force applied to an object is equal to the change in momentum of the object over time.

Step 1: Calculate the initial momentum (pinitial) of the curling rock.

pinitial = m * vinitial

pinitial = 18 kg * 0 m/s (since it's initially stationary)

pinitial = 0 kg m/s

Step 2: Calculate the final momentum (pfinal) of the curling rock.

pfinal = m * vfinal

pfinal = 18 kg * 8.3 m/s

pfinal = 149.4 kg m/s

Step 3: Calculate the change in momentum (Δp).

Δp = pfinal - pinitial

Δp = 149.4 kg m/s - 0 kg m/s

Δp = 149.4 kg m/s

Step 4: Calculate the magnitude of the applied force (Fapplied).

Fapplied = Δp / Δt

Fapplied = 149.4 kg m/s / 2.0 s

Fapplied = 74.7 N

Step 5: Determine the direction of the applied force.

The direction of the applied force is forward since the curling rock is released with a velocity of 8.3 m/s forward.

So, according to Newton's second law, the magnitude of the applied force is 74.7 N, and its direction is forward.

Approach 2: Work-Energy Principle

The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.

Step 1: Calculate the initial kinetic energy (KEinitial) of the curling rock.

KEinitial = 0.5 * m * [tex]vinitial^2[/tex]

KEinitial = 0.5 * 18 kg * (0 [tex]m/s)^2[/tex]

KEinitial = 0 J

Step 2: Calculate the final kinetic energy (KEfinal) of the curling rock.

KEfinal = 0.5 * m * [tex]vfinal^2[/tex]

KEfinal = 0.5 * 18 kg * (8.3 [tex]m/s)^2[/tex]

KEfinal = 0.5 * 18 kg * 69.0 [tex]m^2/s^2[/tex]

KEfinal = 621.0 J

Step 3: Calculate the work done on the curling rock (W).

W = KEfinal - KEinitial

W = 621.0 J - 0 J

W = 621.0 J

Step 4: Calculate the magnitude of the applied force (Fapplied) using the work done.

Fapplied = W / d

Fapplied = 621.0 J / 2.0 s

Fapplied = 310.5 N

Step 5: Determine the direction of the applied force.

The direction of the applied force is forward since the curling rock is released with a velocity of 8.3 m/s forward.

So, according to the work-energy principle, the magnitude of the applied force is 310.5 N, and its direction is forward.

Both approaches yield the same result: the magnitude of the applied force is approximately 74.7 N, and its direction is forward.

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Can someone help pls

Answers

qs 1: m = 1/2*KE*V^2

qs 2: 6,223.39 kg

Which type of matter is likely to absorb the most sound waves? A. Metal door B. Loudspeaker C. Hot air O D. Foam wall​

Answers

Answer:

its either A or D

Explanation:

They use foam walls in like asylums but in the movies all the bad guys say "They can't hear you the metal is too thick" so its either one of those, hope it helped

Sound absorbing foams are typically softer and more lightweight than their sound blocking counterparts. This open and flexible cell structure acts as a natural soundwave absorber and prevents noises from reverberating off hard surfaces like walls, floors and ceilings.

What are sound waves ?

"A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords."

What is sound ?

"Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain."

What is noise ?

Sound is defined as vibrations that travel through air or another medium that can be heard when they reach a person's or animal's ears. Noise is defined as unwanted sound. In engineering, noise has the additional connotation of signals varying over time without meaning, whereas sound connotes meaningful signals.

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A patient arrives at an emergency room complaining of pain in her ankle. The nurse examines the patient’s ankle, looking for skin discoloration or swelling. The nurse is relying mostly on his knowledge of

Answers

Answer:

Superficial anatomy.

Explanation:

Superficial anatomy can be defined as the physical examination of the external parts of a living organism such as ankle, nose, skin, knee, toes, fingers, cornea etc.

Hence, superficial anatomy is also popularly referred to as surface anatomy.

In this scenario, a patient arrives at an emergency room complaining of pain in her ankle. The nurse examines the patient’s ankle, looking for skin discoloration or swelling. The nurse is relying mostly on his knowledge of superficial anatomy by studying or examining the patient's ankle for any sign of decoration or swelling on the skin.

A car traveled 1,215 km West from El Paso to Dallas in 13.5 hours. What was its velocity? A: 90 m/s west B. 90km/h C. .09km/h West D. 90km/h West

Answers

Answer:

B. 90km/hr

Explanation:

The formula for finding velocity =

Displacement/time

The displacement of the car has been given to be = 1215 km West

Time it took to go from Dallas to Paso = 13.5 hours

Then velocity = 1215/13.5

= 90

Therefore velocity = 90km/hour

Option B is the correct answer to this question.

Thank you!

if an object is projected upwards with an angle 30 to the horizontal and its initial velocity is 20 m/s, its maximum height= ? ( consider g= 10m/s^2 )

Answers

Answer:

[tex]h_m=5 \ m[/tex]

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.

The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:

[tex]\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}[/tex]

Where:

vo = initial speed of the object

θ   = initial launch angle

g   = acceleration of gravity ([tex]10\ m/s^2[/tex])

The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:

[tex]\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}[/tex]

[tex]\displaystyle h_m=\frac{400\cdot 0.5^2}{20}[/tex]

[tex]\boxed{h_m=5 \ m}[/tex]

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