Answer:
v= 4.8 m/s
Explanation:
m= 2.0
KE= 1/2 mv^2
v= ?
v= 1/2 (2.0)^2
v= 4.8 m/s
smooth surface is also called ......... surface
Answer:
Plane (or) regular surface
Explanation:
A smooth surface is also called as plane surface. (It is like a mirror)
A block with a mass of 55 kg is pulled with a force of 220 N. Assuming a frictionless surface, what will be the acceleration of the block?
OA
0.25 m/s2
о
B
4.0 m/s2
O.
9.8 m/s2
Oo. 22 m/s2
2022 huminate Education
PLS HELP HELO ME!!!
Answer:
B) 4 m/s²
Explanation:
Since the surface it's kept on is frictionless, the net external force acting on the block will be 220 N.Mass of the block = 55 kg[tex] \boxed{ \sf{ F= m \times a}}[/tex]
Here,
F is the net external force applied to an object,m is the mass of that object, anda is the acceleration it acquires.Substituting the respective values for F and m:
==> 220 = 55 × a
==> 220 = 55 × a
dividing the equation by 55:
==> 4 = a
Therefore, an object of 55 kg when pulled across a frictionless surface by a force of 220 N accelerates at 4 (m/s)/s
A block of aluminum measures 4.0 cm x 5.0 cm x 2.0 cm is completely immersed in a tank of water.
Calculate the buoyant force and the mass of the displaced water (Remember the density of water is 1 g/mL) (g=10m/s2)
Answer:
upthrust or BUOYANT FORCE =Vdg
volume=LWH
upthrust=(4cm×5cm×2cm)×1g/cm²×g
upthrust=40cm³×1g/cm³×g
upthrust=40gf or 0.04kg×10m/s²=0.4N
weight of the displaced liquid is upthrust.
so mass=40g or 0.04kg
upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg
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The energy of random atomic and molecular motion is called.
ill give brainliest
What would happen if the weather became very calm and the wind was not blowing for a few days around the wave hub?
Answer:
the world will become different
The image above shows two opposite forces acting on a rope, what can we say is true about the affect
of the forces on the rope? (SBP3.b)
A It cannot be determined without knowing which man is stronger.
B) It cannot be determined because one man is standing taller than the other.
C) The forces are unbalanced, and net force on the rope moves it to the left.
D) The forces are unbalanced, and net force on the rope moves it to the right.
I have done before and the answer is c
[tex]\bold{\huge{\underline{ Hola \: Brainlians!!! }}}[/tex]
Three particles A, B and C are situated at the vertices of an equilateral triangle ABC of side d at time t = 0. Each of the particles moves with constant speed v. A always has its velocity along AB, B along BC and C along CA. At what time will the particles meet each other ?
- Don't want spam or copied answers
- Don't be greedy for points
- Best answer will be awarded with brainliest.
Given :-
Three particles A, B and C are situated at the vertices of an equilateral triangle ABC.The side of the triangle is d .A always has its velocity along AB, B along BC and C along CA.To Find :-
Time at which the particles will meet .Solution :-
See attachment .
Firstly break the velocity of A , into it's vertical components . That will be ,
[tex] v_A = v_A cos60^o + v_A sin60^o [/tex]
Now the component , [tex]v_A cos60^o [/tex] coincides on side AC and is directed from A to C . Along CA, the velocity of particle C is directed . So both are in opposite directions.
So , the relative velocity of C with respect to A will be ,
[tex] v_{CA}= v_C - v_A [/tex]
Substitute ,
[tex] v_{CA}= v - ( - v cos 60^o) [/tex]
Value of cos 60° is 1/2 ,
[tex] v_{CA}= v + v\bigg(\dfrac{1}{2}\bigg)=v +\dfrac{v}{2}[/tex]
Add the terms,
[tex] v_{CA}= \dfrac{2v + v}{2}=\dfrac{3v}{2}[/tex]
Hence , now we can find the time taken by A and C ,to meet each other will be ,
Since the speed is constant , we can use distance = speed*time , as ;[tex]s = v t [/tex]
Substitute ,
[tex]d = \dfrac{3v}{2} t [/tex]
Multiplying both sides by 2 ,
[tex] 2d = 3vt [/tex]
Dividing both sides by 3v ,
[tex] t = \dfrac{2d}{3v} [/tex]
Similarly , taking any two particles you will get the same time .
Hence the particles meet after 2d/3v time .
I hope this helps .
Answer:
never
Explanation:
Particles moving on paths that don't meet at a point will be particles that never meet. Even if the paths meet at a point, which these don't, the particles may not meet if they arrive at different times.
__
Consider the diagrams in the attachments. In order, they show the positions of the particles shortly after takeoff, midway along the line, and after they have gone farther than the length of the line. The point of closest approach is shown in the second attachment, when the particles are halfway along the line.
Consider particles A and C. Their north/south direction is 'north' for each of them. They both have the same velocity in the 'north' direction, but have started at different points, so can never meet. Those two particles have opposite velocities in the east/west direction, so can pass each other (which they do in the second attachment), but cannot meet.
If an object has an initial velocity of 2.0 m/s and its rate of change in velocity is 3.0 m/s2
calculate its final velocity after 4.0 seconds.
Answer:
14m/s2
Explanation:
initial velocity=2m/s
final velocity =?
time=4s
acceleration=3.0m/s
v=u+at
v=(2)+(3*4)
v=14m/s
by substituting the values in the equation we get the value 14m/s.
Aball is thrown horizontaly from the top of a building with an initial velocity of 15 meters per second. At the same instant, a second ball is dropped from the top of the building. Which of the following is the
same for the two balls?
Answer:
Both balls have the same downward acceleration (and speed)
Worth 25 points on my exam
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A squirrel runs out in front of a car moving at +20m/s. The driver slams on the brakes and begins decreasing at -8m/s^2. Determine the fate of the squirrel if it was initially 26 meters from the car when braking began.
We need to verify the thrid equation of kinematics here
[tex]\\ \tt\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \tt\longmapsto 20^2=2(-8)s[/tex]
[tex]\\ \tt\longmapsto 400=-16s[/tex]
[tex]\\ \tt\longmapsto s=|400/-16|[/tex]
[tex]\\ \tt\longmapsto s=25m[/tex]
The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .
Explanation:
According to the Question
A squirrel runs out in front of a car moving at +20m/s ( initial speed u) . The driver slams on the brakes and begins decreasing at -8m/s² ( here the acceleration is acting in opposite directions of motion a )
When Squirrel was 26 metres ( Distance from the car initially )
Using Kinematic Equation
v² = u² + 2asOn substituting the value we obtain
➥ 0² = 20² + 2 × -8 × s
➥ 0 = 400 - 16 × s
➥ -400 = -16 × s
➥ 400/16 = s
➥ 25 = s
So, the squirrel is 25 metres from the car .
•You have a graduated cylinder which is filled with water up to 150 ml mark. You add a hunk of iron, and the water level rises to 425 ml. What is the mass of the iron?
Answer:
275
Explanation:425- 150 =275mlml=gm
Suppose an asteroid orbiting the sun had an orbital period of 7. 5 years. What would its orbital radius be?.
By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m
What is the orbital period?
This would be the time that a given body does a complete revolution in its orbit.
It can be written as:
[tex]T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }[/tex]
Where:
π = 3.14G is the gravitational constant = 6.67*10^(-11) m^3/(kg*s^2)M is the mass of the sun = 1.989*10^30 kgr is the radius, which we want to find.Rewriting the equation for the radius we get:
[tex]T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }[/tex]
Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s
Replacing the values in the equation we get:
[tex]r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m[/tex]
So the orbital radius is 4.29*10^11 m
If you want to learn more about orbits, you can read:
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A mass on a spring is first placed on a table and set in SHM and then held vertically and set in SHM. What variable/s would change between the two scenarios?
The variable that changes is the period of the motion.
What is simple harmonic motion?The term simple harmonic motion refers to a regular repeating motion. The acceleration of the SHM is always directed towards the center. The spring is an example of a system undergoing simple harmonic motion.
From the description in the question, the variable that changes is the period of the motion.
Learn more about simple harmonic motion: https://brainly.com/question/17315536
I only need 25. What is the skiers kinetic energy at point B? Hint mechanical energy equals potential energy plus kinetic energy
Difference in height = 10 - 5 = 5 meters
Kinetic energy = Energy ( 500 N) x height (5 m) = 2,500 N/m = 2,500 joules
Answer: 2,500 joules
A kid jumping on a trampoline reaches a height of 0.925 m. What was his speed when he left the trampoline?
Answer:
4.26 m/s
Explanation:
h = 0.925
v = 0
u = ?
v = u^2 - 2gh
0 = u^2 - 2gh
u = sqrt 2gh
= sqrt 2*9.8*0.925
= 4.258
= 4.26
How long (in seconds) would it take a machine to do 13,771 joules of work if the power rating of the machine is 0.38 horsepower? (Give the answer without units and round it to the nearest whole number.)
Why do two electrons repel when they interact? (1 point)
O because they both have similar negative electric charge
O because they both have similar mass
o because they both form part of different atoms
o because they both are subatomic particles
Answer:
In order to minimize the potential energy, they repel each other (in the case of a positive and negative charge, potential energy is minimized by bringing them together, so they attract).
Explanation:
Hope it helps
Two electrons repel when they interact, because they both have similar negative electric charge.
What is the property of interacting charges?When the two charges or the charged bodies interact each other, the force of attraction or repulsion acts between them. This force of attraction or repulsion can be find out using the coulombs law.
According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them. It can be given as,
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
Here, (k) is the coulombs constant, (q1 and q2) is the charges of two bodies and (r) is the distance between the two charges.
This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-
Like charges-For the like charges, when two charges interact to each other, then the charges attract each other.Unlike charges-For the unlike charges, when two charges interact to each other, then the charges repel each other.As the electrons are negatively charges. Therefore, two electrons repel when they interact, because they both have similar negative electric charge.
earn more about the property of interacting charges here;
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Social cognitive theory centers around learning cognition and spirituality psychoanalysis economic status
Social cognitive theory centers around: A. learning.
What is cognitive development?Cognitive development can be defined as the development of thought processes, learning skills, knowledge and problem-solving abilities in living organisms such as humans, especially from infancy through adulthood.
What is social cognitive theory?Social cognitive theory refers to a theoretical perspective which states that human behavior is typically learned and developed based on interactions with other people and the natural world.
In conclusion, social cognitive theory centers around learning.
Read more on social cognitive theory here: https://brainly.com/question/8893006
Define 1 unit of electricity?
Answer:
1 Unit Electricity is the amount of electrical energy consumed by a load of 1 kW power rating in 1 hour..
Explanation:
There are 100 steps to get from the ground-floor of a building to its rooftop. Person A walks up to the roof in 100 steps, while person B climbs up, skipping every other step. It takes person A two minutes to reach the top, while person B does it in half the time. From the information provided one can deduce that: __________
a. Both A and B perform the same amount of work, but A delivers more power output than B.
b. Both A and B perform the same amount of work, but delivers more power output than A.
c. A perform more work because he has to walk twice as many steps.
d. B performed less work because it takes him a shorter time to make the climb.
e. B performed less work becuase he only has to work half time
Answer:
C is the correct answer of this question.
Name the two factors that will determine the state of a substance at room temperature
Which of the following statements is NOT true about good communication? A. Good communication makes it difficult to express wants and needs. B. Good communication helps prevent misunderstandings. C. Good communication allows for expression. D. Good communication builds healthy relationships. Please select the best answer from the choices provided. A B C D.
Communication is the act of conveying information from one person to another. .'Good communication makes it difficult to express wants and needs.'These statement is not true about good communication.
What is communication?Communication is the act of conveying information from one location, person, or organization to another. There is a sender, a message, and a recipient for every message.
Communication, while it may appear to be a simple notion, is actually a very complex topic. The message's path from sender to the destination might be influenced by a multitude of circumstances.
Hence the option 'A' is right. 'Good communication makes it difficult to express wants and needs this statement is not true about good communication.
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the answer is A
Explanation : took the quiz on edge 2020
On one stretch of road, any vehicle travelling faster than 25 m/s is breaking the speed limit. The detectors are placed 1.2 m apart. Calculate the speed of a car that takes 0.050 s to travel this distance. Is it breaking the speed limit?
Answer:
Speed = 24 m/s.
No! It doesn't break the speed limit.
Explanation:
The formula we'll be using to find the car's speed:
[tex] \boxed{ \mathsf{speed = \frac{distance}{time} }}[/tex]
The detectors are placed 1.2 m apart.
==> Distance the car travels = 1.2 m
The car, it says, takes 0.050 s to travel that distance.
==> Time taken by the car to travel 1.2 m = 0.050 s
Using the formula mentioned above, let's calculate the speed of the car:
[tex] \sf{speed = \frac{distance}{time} }[/tex]
[tex] \implies \sf{speed = \frac{1.2}{0.050} }[/tex]
On dividing 12 by 0.050 we obtain 24.
[tex] \implies \sf{speed = 24 \: m/s }[/tex]
Any car traveling with a speed that is greater than or equal to 25 m/s is breaking the speed limit.
And since the car in our focus is traveling at 24 m/s that is less than 25 m/s, it doesn't break the speed limit.
the two forces shown acting on square . determine the magnitude of F, which will cause zero moment at point 0
Answer: u excited for the super bowl?
Explanation:
A fishing boat uses a sonar device which sends sound waves to the water that travel at 1000 m/s. The fishing boat detects a signal from a school of fish 1 second after the sonar signal leaves the boat. How far is the school of fish below the boat?
A.1000 m
B.500 m
C.250 m
D.10,000 m
I think its D answer
sorry I dont have explanation but I think its D
Help please :((((
Four movers pushed different boxes across a floor for the same distance. The table shows how much force each mover used, the time it took to move the box, and the mass of the
box.
Force Time. Mass of box
Akira: 155 5 15
Maddie: 120 10 15
Jayden: 90 3 18
Hamid: 160 10 22
Please help!!! I really need to pass this class!
Answer:
Hamid
Explanation:
I got it right on my test
I have a physics mid year exam tomorrow and I'm already so late with my studies AND it's 10:30pm should I study each chapter or just start answering questions and correcting?
Answer:
Depends
Explanation:
If you understand the content rush through questions. If you dont understand learn the key concepts of all the chapters then on the commute tomorrow test your self on the concepts. Good luck!
A star such as the Sun starts out as a protostar with a diameter a hundred times larger than its diameter during its main-sequence lifetime. Accordingly, the protostar's temperature is much less than its main-sequence temperature. Assume that while the Sun was a protostar it had a diameter 95.00 times that of the present-day Sun. How many times greater was the protostar's surface area
The protostar's surface area was 1.1 times greater.
Surface area of the star
The surface of the star can be assumed be circular and the surface area can determined as follows;
initial diameter = 100dfinal diameter = 95dArea = πr²
[tex]Area = \frac{\pi d^2}{4} \\\\Area = \frac{(100d)^2}{(95d)^2} \\\\[/tex]
Surface area = 1.1 times greater
Thus, the protostar's surface area was 1.1 times greater.
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PLS HELP HELP I DONT WANT TO FAIL
An airplane accelerates down a 1000-m stretch of runway at +5m/s^2. How fast is it moving at the end of this stretch of runway?
Apply thrid equation of kinematics
[tex]\\ \tt\longmapsto v^2=u^2+2as[/tex]
[tex]\\ \tt\longmapsto v^2=2(5)(1000)[/tex]
[tex]\\ \tt\longmapsto v^2=10000[/tex]
[tex]\\ \tt\longmapsto v=100m/s[/tex]
What term is used to describe a specific metric that often determines the success or failure of a task?.