A 0.04 kg honeybee circles a field looking for a flower upon which to land. The radius of the circle she travels is 2.5 m and it takes her 1.57 s to complete the circle.

Find the following:
a) Tangential Velocity
b) Centripetal Acceleration
c) Centripetal Force.​

Answers

Answer 1

For the honeybee that circles a field looking for a flower upon which to land, we have:

a) The tangential velocity is 10.01 m/s.

b) The centripetal acceleration is 40.1 m/s².

c) The centripetal force is 1.60 N.

a) The tangential velocity can be calculated as follows:

[tex] v = \omega r = \frac{2\pi r}{T} [/tex]  (1)

Where:

r: is the radius of the circle = 2.5 m

ω: is the angular velocity = 2π/T

T: is the period = 1.57 s

By entering the above values into equation (1), we have:

[tex] v = \frac{2\pi r}{T} = \frac{2\pi 2.5 m}{1.57 s} = 10.01 m/s [/tex]  

Hence, the tangential velocity is 10.01 m/s.

b) The centripetal acceleration is related to the tangential velocity as follows:

[tex] a_{c} = \frac{v^{2}}{r} = \frac{(10.01 m/s)^{2}}{2.5 m} = 40.1 m/s^{2} [/tex]

Therefore, the centripetal acceleration is 40.1 m/s².

c) The centripetal force is given by:

[tex] F = ma_{c} [/tex]

Where:

m: is the honeybee's mass = 0.04 kg

[tex] F = ma_{c} = 0.04 kg*40.1 m/s^{2} = 1.60 N [/tex]

Hence, the centripetal force is 1.60 N.

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I hope it helps you!


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what is Secular Music's instrument's?​

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Answers

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Answers

Answer:

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The length of such a pipe would be wavelength / 4

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The pipe would have to be 5.46 / 4 = 1.36 m

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Answer:

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Answers

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Explanation:

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Your question is incomplete, most probably the complete question is:

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Answers

Answer:

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Explanation:

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Answer:

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The terms with their correct definition is matched as follows:

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Answer:

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Name 3 things you have in your home that you could use to make an electromagnet.

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In the equation above, what is the
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Answers

Answer:

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Answers

The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:

 The change in fundamental frequency is: f = 1.08 f₀

The speed of the chord wave is given by the relationship between the tension and the density of the medium.

          [tex]v= \sqrt{\frac{T}{\mu } }[/tex]  

Where v is the velocity of the wave, T the tension of the string and μ the density

In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.

             2L = n λ

Where L is the length of the chord and call the wavelength

Wave speeds are related to wavelength and frequency.

        v = λ f

We substitute.

            [tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]  

For the fundamental frequency n = 1

            f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]  

They indicate that the tension increases 1.70%

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           T = 1.17 T₀

We substitute.

         [tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]

         f = ra1.17 f₀

         f = 1.08 f₀

In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:

 The change in fundamental frequency is: f = 1.08 f₀

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I agree to hire you for 30 days. You can decide between two methods of payment: either (1) $1000 a day, or (2) one penny on the first day, two pennies on the second day and continue to double your daily pay each day up to day 30. Use quick estimation to make your decision, and justify it

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Answer:

The second deal.

Explanation:

I had that before, if u pick the second one you will get twice as much in a year as the first one.

A ball is thrown from ground level at an angle of 0 and the initial velocity components are 7.5m/s and 13m/s. Ignoring air resistance, calculate each of:

1- The initial velocity is vi

2- The value of the angle at which the ball was thrown

3 - The horizontal range of the ball R​

Answers

I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that

1. the initial velocity vector is

[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]

which means the ball is thrown with an initial speed of

√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,

and

2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that

[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]

3. At time t, the ball attains a height y and horizontal range x according to

y = (13 m/s) t - g/2 t²

x = (7.5 m/s) t

where g = 9.8 m/s². When the ball reaches the ground (y = 0) for t > 0, we have

(13 m/s) t - g/2 t² = 0

13 m/s - g/2 t = 0

t = 2 (13 m/s)/g = (26 m/s)/g

Plugging this time into the x equation gives a horizontal range of

x = (7.5 m/s) (26 m/s)/g ≈ 20. m

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A. train
B. bus
C. airplane
D. boat

Answers

Answer:

airplane

Explanation:

Answer:

a plane would go by far the fastest

Explanation:

it would be airplane ,train, boat, bus

How much work is needed to stop a 1,110 kg car that is moving straight down the
highway at 59.0 km/h?

Answers

Answer:

382.74 kJ.

Explanation:

The work that must be done to stop an 1100 kg car travelling at 59  km/h is  - 382.74 kJ.

The work needed to stop an 1100 kilograms car moving with a velocity of  59.0 km/hr would be  147.72 kilojoules.

What is work done?

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force * Displacement

As given in the problem we have to find out how much work is needed to stop a 1,110-kilogram car that is moving straight down the highway at 59.0 kilometers/hour

the mass of the car = 1100 kilograms

the velocity of the car = 59 kilometers/hour

KE = 0.5mv²

     =0.5×1100×(59×1000/3600)²

     = 147.72 kilojoules

Thus, the work needed to stop an 1100 kilograms car would be  147.72 kilojoules

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HEEEEEELLLLLLLLPPPPPPPP!!!!!!!!!!

Answers

Answer:

True

True

False (Temperature measures the average kinetic energy of the particles in a substance. Thermal energy measures the total kinetic energy of the particles in a substance.)

False (is true only if both object have the same mass)

False (it's 100°)

True

True

True

True

False (Substances with a high specific heat require a lot of heat to have their temperature raised by one degree. On the other hand, substances with a low specific heat require a smaller amount of heat, like most metals)

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