9ma electric current is flowing through a conducting wire , then the number of electron passing through it in 3 min is

Answer:

These atomos are called isotopes.

Explanation:

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number (Z).

The number of neutrons in the nucleus can vary. There are almost always as many or more neutrons than protons. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element. That is, isotopes are atoms whose atomic nuclei have the same number of protons but different numbers of neutrons.

So, these atomos are called isotopes.

Answer:

The answer is A

Explanation: i took k12

Answer:

1st

Explanation:

20 meters per second

Explanation:

look at the chart

Answer:

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

'f'

Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

Answer:

Higher than A, Lower than F

Explanation:

Answer:

300N

Explanation:

Given parameters:

Mass of car  = 1500kg

Initial velocity  = 0m/s

Distance covered  = 45m

Time  = 15s

Unknown:

Net force applied  = ?

Solution:

From Newton's second law:

  Force  = mass x acceleration

  Force  = mass x [tex]\frac{v - u}{t}[/tex]  

v is the final velocity

u is the initial velocity

t is the time taken

    Final velocity  = [tex]\frac{45}{15}[/tex]   =3m/s

 Force  = 1500 x [tex]\frac{3 - 0}{15}[/tex]   = 300N

Explanation:

= 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

When displacement is y, then acceleration, a=−ω2y

Velocity, V=ωr2−y2

Case (a)    When y=5cm=0.05m

a=−(10π)2×0.05=−5π2m/s2

V=10π×(0.05)2−(0.05)2=0

Case (b)    When y=3cm=0.03m

a=−(10π)2×0.03=−3π2m/s2

V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s

Case (c)    When y=0

a=−(10π)2×0=0

V=10π×(0.05)2−02=

hope it helps. pls follow and mark as brainliest

Answer:

moment's equilibrium required

moment = force x perpendicular distance from force's line of action (from pivot)

counter clockwise = clockwise moments

=> 15g(1.5) = F(0.3)

=> F = 15*9.81*5 = 735.75 ~= 736 N

Explanation:

Answer:

I don't know the multiple choices or if you have any but my best answer is castle.

I hope this helps!

Answer:

the work function of the metal is 4.167 x 10⁻¹⁹ J .

Explanation:

Given;

wavelength of the incident light, λ = 450 nm = 450 x 10⁻⁹ m

kinetic energy, K.E = 2.5 x 10⁻²⁰ J

The energy of the incident light is calculated as;

[tex]E = hf = \frac{h c}{\lambda} \\\\where;\\\\c \ is \ speed \ of \ light = 3 \times 10^8 \ m/s\\\\ h \ is \ Planck's constant = 6.626 \times 10^{-34} Js \\\\E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{450 \times 10^{-9}} \\\\E = 4.417 \times 10^{-19} \ J[/tex]

Apply Einstein photoelectric equation to determine the work function of the metal;

E = W + K.E

where;

W is the work function of the metal

W = E - K.E

W = 4.417 x 10⁻¹⁹ J - 2.5 x 10⁻²⁰ J

W = 44.17 x 10⁻²⁰ J -  2.5 x 10⁻²⁰ J

W = 41.67 x 10⁻²⁰ J

W = 4.167 x 10⁻¹⁹ J

Therefore, the work function of the metal is 4.167 x 10⁻¹⁹ J .

The work function of the photon is 4.167*10^19J

The energy of this photon can be calculated as

E = hc/λ

Data given;

substituting the values into the equation;

[tex]E = hc / y\\E = \frac{6.626*10^-^3^4*3.0*10^8}{450*10^-^9} \\E = 4.42*10^-^1^9J[/tex]

The work function of the photon can be calculated as;

E = K.E + Ф

4.42*10^-19 = 2.5*10^-20 + Ф

Ф = [tex]4.42*10^-^1^9 - 2.5*10^-^2^0=4.167*10^-^1^9J[/tex]

The work function of the photon is 4.167*10^-19 J

Learn more on work function  of a photon here;

https://brainly.com/question/11683155

Answer:

Average speed will be 50km/hr

Explanation:

Distance/Time

100/2

50kmph

plz mark as brainliest

Answer:

50km/hr

Explanation:

avgspeed=Δdistance/Δtime

Δd=100km

Δt=2hr

=100km/2hr

=50km/hr

Answer: A) Current

Current is the flow of electrons. The more electrons that flow, then the higher the amperage which measures this flow. If the current is high enough, then the electrical shock may cause damage of some kind.

"Amperage" is abbreviated as "Amp". You may see something like "milliamp" when it comes to measuring this amperage.

Answer:

[tex]55\ \text{minut}[/tex]

[tex]82.5\ \text{km}[/tex]

Explanation:

Timpul când mașina părăsește Alexandria este [tex]23:25[/tex]

Ora sosirii mașinii la București este [tex]00:20[/tex]

Deci, timpul necesar pentru călătorie este [tex]60-25+20=55\ \text{minut}=\dfrac{55}{60}\ \text{ore}[/tex]

Viteza mașinii este de 90 km/h

Distanța este dată de produsul vitezei și al timpului

[tex]90\times \dfrac{55}{60}=82.5\ \text{km}[/tex]

Distanța dintre localități este [tex]82.5\ \text{km}[/tex].

Answer:

kinetic energy is when an object is moving

Answer:

[tex]40\:\mathrm{m}[/tex]

Explanation:

We can use kinematics equation [tex]\Delta y={v_i}^2+\frac{1}{2}at^2[/tex] to solve this problem. Because the metal ball's initial velocity was 0, [tex]{v_i}^2=0[/tex].

Therefore, our equation becomes:

[tex]\Delta y=\frac{1}{2}at^2[/tex] (freefall equation).

[tex]t[/tex] is given as 3 seconds and [tex]a[/tex] is acceleration due to gravity ([tex]9.81\:\mathrm{m/s}[/tex]).

Therefore, our answer is:

[tex]\Delta y = \frac{1}{2}\cdot9.81\cdot3^2=44.145=\fbox{$40\:\mathrm{m}$}[/tex] (one significant figure).

 [tex]\huge\text{Graphs:}[/tex]

The graph of  

• The I-V for Ohmic Metal wire conductor at constant temperature  always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1

• The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2

[tex]\Large\textbf{Diode:}[/tex]  

A diode is a device that allows current to flow in only one direction.

[tex]\Large\textbf{Forward and Reverse Biasing:}[/tex]  

Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)

Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.

 [tex]\Large\textbf{Answer to the Question "Resistance"}[/tex]

The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.

Answer:

ezrfdjhsetnhtjhsksdjghbksfneunaifghejbcifkikjayhr

Explanation:

TOTAL FLIGHT TIME

Rising Projectile

vi = initial velocity = 58.8 m/s

vf = final velocity = 0

g = gravity acceleration = -9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (0 - 58.8)/-9.81

t = -58.0/-9.81

t = 5.99 s ≈ 6.00 s

Falling Projectile

vi = initial velocity = 0

vf = final velocity = 58.8 m/s

g = gravity acceleration = 9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (58.8 - 0)/9.81

t = 58.0/9.81

t = 5.99 s ≈ 6.00 s

t(total) = t(up) + t(down) = 6.00 s + 6.00 s = 12.0 s Total Flight Time

HORIZONTAL DISTANCE TRAVELED

v = velocity, horizontal = 20.0 m/s

d = to be determined

t = elapsed time = 12.0 s

v = d/t

vt = d

d = vt

d = (20.0 m/s)(12.0 s)

d = 240 m Horizontal Distance Traveled

00

Answer:

Attraction.

Explanation:

Charging by friction involves rubbing of objects against one another so that one loses electron(s), while the other gains the electron(s). Thus, the objects would have opposite charges after the process.

The glass test tube rubbed with silk loses electron, thus becomes positively charged. While the acrylic rob rubbed with paper towel becomes negatively charged. Since the two rods have opposite charges, then the interaction between them would be attraction. A force of attraction between the rods would be experienced while the rods are brought to a required close range.

Answer:

If an atom gains a neutron, the atom becomes an isotope, which means that it has the same atomic number (#of protons) but a different atomic mass because it has gained the mass of 1 neutron

Explanation:

Let us first calculate  long does it take to go 12m at 30m/s( assumed speed)

12/30 = 0.4 seconds

horizontal distance the ball drop in that time

H= (0)(0.4)+1/2(-9.8)(0.4)2

H= -0.78m

negative sign shows that the height of the ball at the net from the top.

Height of the ball at the net and from the ground= H1-H=2.4-0.78=1.62m

As 1.62m>0.9m so the ball will clear the net.

H_1= V0y t’ + ½ g t’^2

-2.4= (0)t’ + ½ (-9.8) t’^2

t’= 0.69s

X’=V0x t’

X’=(30)(0.96)

X’= 20.7m

Answer:

30m³

Explanation:

Calculation for the volume the balloon would have

First step is to calculate the Constant

Constant=30pka*5m³

Constant=150m³

Now let calculate the Volume using this formula

Balloon Volume=Constant/ Pressure

Let plug in the formula

Balloon Volume=150m³/5kpa

Balloon Volume=30m³

Therefore the volume that the balloon would have when the pressure inside the ballon has fallen to 5kpa is 30m³

Answer:

9508.1kg

Explanation:

Given parameters:

Gravitational force  = 6.7 x 10⁻⁴N

Distance of separation  = 3m

Unknown:

Mass of one of the truck  = ?

Solution:

Let the mass of one of the truck be  = m

According to the Newton's law of universal gravitation:

   Fg  = [tex]\frac{G m1 m2}{d^{2} }[/tex]  

 G is the universal gravitation constant  = 6.67 x 10⁻¹¹

  m1 and m2 are the masses of the two bodies, here m1  = m2  = m

  d is the distance of separation between them

 6.7 x 10⁻⁴   = [tex]\frac{6.67 x 10^{-11} x m^{2} }{3^{2} }[/tex]  

          6.67 x 10⁻¹¹m²   = 9 x   6.7 x 10⁻⁴  

                          m   = 9508.1kg

The mass of one of the trucks is 9510 kg.

The problem above can be solved using the mathematical expression of newton's law of universal gravitation

Using Newton's law of universal gravitation,

F = Gm²/r²................... Equation 1

Where F = Gravitational force on the truck, m = mass of each truck, r = distance between the trucks, G = universal constant

make m the subject of the equation

m = √(Fr²/G)................ Equation 2

From the question,

Given: F = 6.7×10⁻⁴ N, r = 3.0 m.

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 2

m = √[(6.7×10⁻⁴×3²)/(6.67×10⁻¹¹)]

m = √(9.04×10⁷)

m = 9.51×10³ kg.

m = 9510 kg

Hence, The mass of one of the trucks is 9510 kg

Learn more about Newtons law of universal gravitation here: https://brainly.com/question/9373839

Answer:

Respiration and excretion

Explanation:

Respiration. When animals breathe, their lungs release water vapour to the atmosphere.

Animals excrete water by respiration and by passing urine.

Answer: work

Explanation:

When Jerome swings on a rope and hence this leads to the transfer of energy from the gravitational potential energy to a kinetic energy, this implies that work is being done.

For work to be done, it simply means that one has to transfer energy from one particular form to another form. In this case, the energy was transferred from the gravitational potential energy to a kinetic energy.

Answer:

work

Explanation:

Answer:

(a) The length of the stretched string is approximately 42.53846 cm

(b) The elastic potential energy stored in the string is approximately 0.073877 Joules

Explanation:

(a) The given parameter are;

The force constant of the vertical spring, k = 26 N/m

The relaxed length of the spring, L = 35 cm = 0.35 m

The mass attached to the end of the spring, m = 200 g = 0.2 kg

By Hooke's law, we have;

F = k·x

Where;

F = The applied force on the sting = The weight of the attached mass, W

∴ F = W

The weight of the attached mass, W = m × g

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

Therefore, F = W = 0.2 kg × 9.8 m/s² = 1.96 N

From Hooke's law, we have;

x = F/k = 1.96 N/(26 N/m) ≈ 0.0753846 m

The extension of the stretched spring, x ≈ 0.0753846 m

The length of the stretched string, L[tex]_{stretched}[/tex] = L + x

∴ L[tex]_{stretched}[/tex] ≈ 0.35 m + 0.0753846 m ≈ 0.4253846 m

0.4253846 m = 42.53846 cm

The length of the stretched string ≈ 42.53846 cm

(b) The elastic potential energy stored in the string, U = 1/2·k·x²

By substituting the known values, we get;

U = 1/2 × 26 N/m × (0.0753849 m)² ≈ 0.073877 Joules

Answer:

9J

Explanation:

Given parameters:

Mass of cell phone  = 80g

          1000g  = 1kg

            80g is therefore 0.08kg

Velocity of the cellphone  = 15m/s

Unknown:

Kinetic energy of the cellphone  = ?

Solution:

The kinetic energy of a body is the energy due to its motion.    

 It is expressed as:

    K.E  = [tex]\frac{1}{2}[/tex] mv²   =  [tex]\frac{1}{2}[/tex]  x 0.08 x 15²   = 9J

Answer:

The adiabatic process can be derived from the first law of thermodynamics relating to the change in internal energy dU to the work dW done by the system and the heat dQ added to it. The word done dW for the change in volume V by dV is given as PdV. Hence, the equation is true for an adiabatic process in an ideal gas.

Explanation:

Hope it helps......bro

Complete question:

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.

Answer:

2.0N

Explanation:

Given that,

Mass, m of the frog = 0.5 kg

The acceleration of the frog = 4.0 m/s².

We have been asked To find,

The magnitude of the net force exerted on the frog as it leaps.

So

We calculate this using the formula below :

F = ma

When we insert the values into the formula, we have:

F = 0.5 kg × 4 m/s²

F = 2.0 N

Therefore, the magnitude of net force is 2.0 N.