Answer:
[tex]P(Green\ or\ Red) = 0.30[/tex]
Step-by-step explanation:
Given
[tex]White = 40[/tex]
[tex]Green = 24[/tex]
[tex]Red = 12[/tex]
[tex]Yellow = 24[/tex]
[tex]Blue = 20[/tex]
Required
[tex]P(Green\ or\ Red)[/tex]
The total numbe of candy is:
[tex]Total = 40 + 24 + 12 + 24 + 20[/tex]
[tex]Total = 120[/tex]
This probability is calculated as:
[tex]P(Green\ or\ Red) = P(Green) + P(Red)[/tex]
For each, we have:
[tex]P(Green\ or\ Red) = \frac{Green}{Total} + \frac{Red}{Total}[/tex]
Take LCM
[tex]P(Green\ or\ Red) = \frac{Green+Red}{Total}[/tex]
[tex]P(Green\ or\ Red) = \frac{24+12}{120}[/tex]
[tex]P(Green\ or\ Red) = \frac{36}{120}[/tex]
[tex]P(Green\ or\ Red) = 0.30[/tex]
The population of rabbits in a forest follows the law of
exponential
growth.
If 90 rabbits are present initially and
there are 180 after 3 years, how many will here be in 4 yours
Answer:
226.78579
Step-by-step explanation
first, find k in 90(3^kx)
90(e^0) = 90 [when time is 0 years, the population is 90]
180=90(e^k3), 2=e^3k
ln2 = 3k, k=(ln2)/3
90(e^4(ln2)/3) = 90(e^ln(16)/3)
it is about 226.78579
During a school fund-raiser, the Student Government Association tracked the
average donation by student. Which of the following can you conclude about
the fund-raiser?
Average Number of Dollars Donated
to Kennedy High School, by Grade
120
100
80
60
Average donation (S)
20
0
9th
10th
12th
11th
Grade
A. The higher the grade, the larger the average donation.
O B. The school raised a total of $100.
c. 100 12th graders donated to the fund-raiser.
D. The school raised $271.
Answer:
A) The higher the grade, the larger the average donation
Answer:
The Answer is A
Step-by-step explanation:
2.6x + 10.5 = 31.3
I need to find the answer of x whoever gets it correct will get brianliest!
Answer:
2.6x + 10.5 = 31.3
Step-by-step explanation:
4) This shape is made from rectangles.
6 cm
Not drawn
accurately
12 cm
8 cm
11 cm
Use the ALEKS calculator to find 35% of 67. Do not round your answer.
Answer:
23.45
Step-by-step explanation:
35 percent of 67=23.45
35×67=2345
2345/100=23.45
Ryan has constructed a multiple regression model and wants to test some assumptions of his regression model. In particular, he is testing for normality of the residuals. To do this Ryan should:
a. construct a normal quantile plot of the residuals and see if the result is an approximately upward sloping straight line
b. plot the residuals vs the predicted values of the response variable and check if the result is a random pattern
c. plot the residuals vs the observed values of the response variable and check if it forms and upward sloping line
d. plot the residuals vs each explanatory variable to check if they are approximately random and form no clear pattern
e. construct a normal quantile plot of the residuals and see if the result is an approximately horizontal straight line
f. construct a normal quantile plot of the residuals and see if the result is an approximately downward sloping straight line
Answer:
plot the residuals vs the observed values of the response variable and check if it forms and upward sloping line ( C )
Step-by-step explanation:
Ryan should plot the residuals vs the observed values of the response variable and check if it forms and upward sloping line ( C )
The exact right action on what Ryan should do is not listed in the options listed below, hence I have just picked the closest on what Ryan should do if he is testing for normality of the residuals after constructing a multiple regression model
Normality of residuals test is performed to ensure that the residuals are properly/evenly distributed
im sooooooooo bord sooooo you get 100 points for ansering 1+1¥¥¥¥¥¥¥¥
Answer:
1+1=2
Step-by-step explanation:
THANKS YOU YAY HOPE IT HEOPS
Answer:
2 thanks
Step-by-step explanation:
(PLEASE HELP) A teacher surveyed a sample of students from Lake Middle School. He asked the students where they'd like to go for a field trip. He recorded these results:
• 80 chose the aquarium.
• 60 chose the science center.
• 30 chose the planetarium.
• 40 chose the farm.
The teacher wants to figure out the relative frequency of a student choosing the aquarium. He'll then estimate how many students out of all 1000 at the school are likely to choose the aquarium.
(he surveyed 210 students and about 38% of them chose the aquarium)
Write and solve a proportion that the teacher can use to estimate how many students in the whole school would choose the aquarium.
Answer:
relative frequency of choosing aquarium is 80/210
about 400 students out of 2000 will choose aquarium
Step-by-step explanation:
relative frequency of choosing aquarium is 80/210
proportion:
a = students who choose aquarium
80/210 = a/1000
210a = 80000
a = 80000/210 which is close to 80000/200 which equals 800/2 or about 400 students
If g(x) = 1/4X-4 find
g(-4) = [g1]
g(12) = [g2]
Answer:
G1 = -5 G2 = -1
Step-by-step explanation:
plug in the values given into X and solve
g1= 1/4(-4) -4
g1 = -1 -4
g1 = -5
g2= 1/4(12) -4
g2= 3 -4
g2= -1
7)
The diagram below shows the graph of y = |x-3|
Which diagram shows the graph of y= -|x - 3|
Answer:
y= -|x - 3| graph
Step-by-step explanation:
You wonder what is the average number of credits Le Moyne students take per semester. You speak with the Le Moyne registrar, and they tell you that Le Moyne students take an average of 17 credits per semester with a population standard deviation of 2.5 credits. We plan to take a sample of 49 students and ask each student how many credits they plan to take. Assume that the population mean is 17 credits and the populations standard deviation is 2.5 credits. What does the CLT say about the distribution of the sample mean of 49 students
Answer:
The CLT says that the distribution is approximately normal, with mean of 17 credits and standard deviation of 0.3571 credits.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Assume that the population mean is 17 credits and the populations standard deviation is 2.5 credits.
This means that [tex]\mu = 17, \sigma = 2.5[/tex]
What does the CLT say about the distribution of the sample mean of 49 students?
It is approximately normal.
The mean is 17.
Due to the sample of 49, n = 49, and the standard deviation is [tex]s = \frac{2.5}{\sqrt{49}} = 0.3571[/tex]
The CLT says that the distribution is approximately normal, with mean of 17 credits and standard deviation of 0.3571 credits.
Help me with my homework, please
Answer:
150°
Step-by-step explanation:
We know each angle in a equilateral triangle is 60° and that of a rectangle is 90° . So ,
[tex]\implies \angle ABC = \angle DBC + \angle ABD \\\\\implies \angle ABC = 90^o + 60^o \\\\\implies \boxed{\boxed{ \angle ABC = 150^o }}[/tex]
Cos^2x+cos^2x*cot^2x
Answer:
Cos^2x csc^2x
Step-by-step explanation:
Cos^2x (1 + cot^2x)
Solve the simultaneous equations
2x - 5y = 9
3x + 4y = 2
Answer:
x = 2
y = 1
Step-by-step explanation:
Answer:
x= 2
y= -1
Step-by-step explanation:
Find value a, b and c
Answer:
a= 30 degree
b= 120 degree
c= 150 degree
Question One
The length and width of a rectangle is 12 in. And 5 in. The width of a similar rectangle is 8 in. What is the length of the similar rectangle?
Answer:
Step-by-step explanation:
Set up proportions. Make sure length and widths line up!
[tex]\frac{12}{5} =\frac{x}{8}[/tex]
Then do butterfly method.
[tex]12(8) = 5x[/tex]
Solve for x.
[tex]96 = 5x\\\\x= 19.2 in[/tex]
Hope that helped!
Find cos 0
16
20
12
A.
12
16
B.
12
20
C.
16
20
10
D.
Answer:
b cuz its cosine but i flipped the numbers so it can be 20 over 12 and gave me exactly 0
The trigonometric function gives the ratio of different sides of a right-angle triangle. The value of cos(θ) in the given triangle is 0.6.
What are Trigonometric functions?The trigonometric function gives the ratio of different sides of a right-angle triangle.
[tex]\rm \sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\\cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\\tan \theta=\dfrac{Perpendicular}{Base}\\\\\\[/tex]
where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.
In a right angle, the cosine function of trigonometry is the ratio of the base of the triangle and the hypotenuse of the triangle.
For angle θ, the dimension of the triangle will be,
Perpendicular = 16
Base = 12
Hypotenuse = 20
Now, the measure of cos(θ) will be,
Cos(θ) = Base / Hypotenuse
= 12 / 20
= 6 / 10
= 0.6
Hence, the value of cos(θ) in the given triangle is 0.6.
Learn more about Trigonometric functions here:
https://brainly.com/question/6904750
#SPJ5
Please help me!!!!!!!!
PLZZZ HELP!!!!!!!!!1
What is the median and Q1 of the data set represented on the plot?
Median = 30; Q1 = 20
Median = 33; Q1 = 20
Median = 30; Q1 = 25
Median = 33; Q1 = 25
Answer:
i cant put the picture
Step-by-step explanation:
d. Median=33;Q1=25 the median is represented by the line in between the two boxes. Q1 is represented by the line on the far left of the box in the picture Q1 is marked for quadrent 1 and m is for median
Abdul earns 44 dollars per week working part-time at a book store. He makes one dollar more for each book that he sells. The amount, A (in dollars), that Abdul
earns in a week if he sells b books is given by the following function.
A(b) = 44+b
How much does Abdul earn in a week if he sells 31 books?
Answer:
$75
Step-by-step explanation:
he makes $44 and then you add the dollar per 31 books making $75
(MATH) (6) ((PHOTO))
label is m
Multiply the length by the height:
6.5 x 2 = 13
The width is the volume divided by 13
Width = 52/13 = 4 m
Please help. I’ll give brainlest!! No links
Answer:
352
Explanation
Answer:
352 square inches
Equation to find the surface area:
A=2(wl+hl+hw)
Steps:
2·(4·12+8·12+8·4)=352
If you have any questions revolving around this topic,feel free to ask me and i will be happy to help,Good luck!
(NO LINKS)
Please help this assignment is over due and I don't get it
Answer:
B + 8 = 17 (just incase you need it, B = 9)
Step-by-step explanation:
Hope this helps, pls try to turn it in soon! :))
Please help me with this I'm having some trouble
obtuse: B
straight: C
acute: A
right: D
Step-by-step explanation:
Draw a clock and put the hands on the clock and you can see the angel that the clock has.
The experimental probability that Kevin will catch a
fly ball is equal to 3/4. About what percent of the
time will Kevin catch a fly ball?
A. 77%
B.55%
C.88%
D.75%
Answer:
C.
Step-by-step explanation:
Answer:
75%
Step-by-step explanation:
The fraction 3/4 is equivalent to 75%. Therefore, the percent Kevin will catch a fly ball is 75%.
Find the measure of Arc MP.
Answer:
use this formula
x/230×2×pie×radius
PN=180
MPN=MN=31
MP=x
180=31+x
x=180-31
x=149
help me for a brianly
Answer:
35
Step-by-step explanation:
you multiply like it is a rectangle then you cut your answer in half in this case 7x10=70 cut in half is 35
what is the answer
Move the correct number to the first box to show the answer. Then, move numbers to the other boxes to explain the answer.
Answer:
[tex]\frac{1}{4} * 3 = \frac{3}{4}[/tex]
Because:
[tex]\frac{1}{4} * 3 = \frac{1}{4} +\frac{1}{4} + \frac{1}{4}[/tex]
Step-by-step explanation:
Given
[tex]\frac{1}{4} * 3 = [\ ][/tex]
Because
[tex]\frac{1}{4} * 3 = [\ ] + [\ ] + [\ ][/tex]
Required
Fill in the box
[tex]\frac{1}{4} * 3 = [\ ][/tex]
This can be written as:
[tex]\frac{1}{4} * 3 = \frac{1* 3 }{4}[/tex]
Solve the numerator
[tex]\frac{1}{4} * 3 = \frac{3}{4}[/tex]
(b) Because
[tex]\frac{1}{4} * 3 = [\ ] + [\ ] + [\ ][/tex]
The above implies that
[tex]\frac{1}{4}[/tex] be added in 3 places
i.e.
[tex]\frac{1}{4} * 3 = \frac{1}{4} +\frac{1}{4} + \frac{1}{4}[/tex]
The height meters of a mass projected vertically upwards at a time seconds s=ut-0.5gt².
Determine how long the mass will take after being projected to reach a height of 16m on the ascent.
b. on the descent when u=30m/s and g=9.8m/s
9514 1404 393
Answer:
t ≈ 0.590 s (ascent); 5.532 s (descent)
Step-by-step explanation:
We are interested in the values of t when s=16.
s = 30t -4.9t²
4.9t^2 -30t +16 = 0 . . . . . substitute 16 for s; put in standard form
The quadratic formula can be used to find the solutions:
t = (-(-30) ±√((-30)² -4(4.9)(16)))/(2(4.9))
t = (30 ±√586.4)/9.8 ≈ 0.59023, 5.53221 . . . . seconds after launch
a) It will take 0.590 seconds to reach 16 m height initially.
b) It will take 5.532 seconds to return to 16 m height on descent.
Choose the theorem that proves these triangles are congruent.
Answer:
SAS
Step-by-step explanation: