7. A drag car takes off at the green light heading in a straight line. The car goes
from a complete stop to 45m/s in 9 seconds. What is its acceleration?

Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.

Explanation:do you want me to explain it more??

We have: [tex]I=\frac{U}{R}=\frac{120}{20}=6A[/tex]

ok done. Thank to me :>

Answer:

The Current is 6 Ampere.

Step-by-step explanation:

Given :

To Find :

Using Formula :

[tex] \star{\small{\underline{\boxed{\sf{ I = \dfrac{V}{R}}}}}}[/tex]

Solution :

Substituting all the given values in the formula to find Current :

[tex]{\dashrightarrow{\pmb{\sf{ I = \dfrac{V}{R}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = \dfrac{Voltage}{Resistance}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = \dfrac{120}{20}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = \cancel{\dfrac{120}{20}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = 6A}}}[/tex]

[tex]{\star{\underline{\boxed{\sf{\red{ Current = 6A}}}}}}[/tex]

Hence, the Current is 6 Ampere.

[tex]\rule{300}{1.5}[/tex]

Answer:Yes

Explanation:Because the virus is so dangerous

Answer:

d. action force and the reaction force act on two different objects.

Hope you could understand.

If you have any query, feel free to ask.

In an action-reaction pair, action force and the reaction force act on two different objects.

Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."

It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.

When considering the options,

So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.

Learn more about Newton's third law,

https://brainly.com/question/974124

#SPJ2

Answer:

Magnets have two poles, called north and south. The like poles are attracted to unlike poles, but like poles repel each other. For example, the north pole of one magnet is attracted to the south pole of another. ... To make objects move with a magnet attach a piece of metal, or another magnet, to it.

Answer:

Sulfur

Selenium

Nitrogen

Oxygen

Explanation:

Sulfur is the most reactive out of the four and Oxygen is the least reactive out of the four.

Answer:

translucent

Explanation:

Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.

Answer:

F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2

F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons

F = 3.53E22 N

Answer:

I think A

Explanation:

The two chemical compounds having a molar ratio of 1 : 1 is CO₂ and K₂CO₃

                4KO₂ + 2CO₂ —> 2K₂CO₃ + 3O₂

                4       :    2         :   2       :       3

From the balanced equation above, the coefficients are 4, 2, 2, 3

A careful observation of the equation shows that CO₂ and K₂CO₃ exist in ratio 2 : 2 which can be simplified as 1 : 1

Therefore, we can conclude that CO₂ and K₂CO₃ has molar ratio of 1 : 1

Learn more about stiochoimetry: https://brainly.com/question/25830314

Answer:

a planet

Explanation:

If planetesimals, objects that combined to form protoplanets, were to collide head on in the early solar nebula, they would shatter to the point where they would be unable to grow into a larger size, a protoplanet. A protoplanet is a massive object that will eventually become a planet.

Microwave Radiation????????????

Resistance = volts / amps

Resistance = 12 volts / 3 amps

Resistance = 4 Ohms

Answer: 4 Ohms

The two forces involved in this collision are the colliding force and the reaction force which are equal in magnitude but opposite in direction.

According to Newton's third law, action and reaction are equal and opposite. This law is very important in describing head - on collisions between objects and is particularly apt in describing the collision between the two boats.

In this collision, two forces are important these are the action and the reaction. The action is the colliding force which the boat that was hit experiences. The reaction force is the force that this boat experiences as a result of hitting the boat in front of it. The both forces are equal in magnitude but opposite in direction.

Learn more: https://brainly.com/question/904448

The length of the room is 96 ft.

Let L be the length of the room and W be the width of the room.

Since the length is twice its width, L = 2W.

Its area A = LW

= 2W × W

= 2W²

If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)

= (2W + 1)(W + 1)

= 2W² + 3W + 1

Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1

2W² + 145 = 2W² + 3W + 1

145 = 3W + 1

3W = 145 - 1

3W = 144

W = 144/3

W = 48 ft.

Since its length L = 2W, substituting W = 48 into the equation, we have

L = 2(48)

L = 96 ft

So, the length of the room is 96 ft.

Learn more about length of a room here:

https://brainly.com/question/24375989

fh= 6.4×23

fh=147.2

fv=2.2×1.4

fv=3.08

f=147.2+3.08

f=150.28

The force of friction on the block is 20.798 N.

Acceleration is the rate at which speed and direction of velocity vary over time. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the  block: m = 6.4 kg.

Angle of inclination = 23°

Hence, Magnitude force acting along the motion = mg sin23°

= 6.4 × 9.8 × sin23° N

= 24.51 N.

The block travels 1.4 meters in 2.2 seconds. Acceleration = (2×1.4)/2.2² m/s²

= 0.58 m/s²

Hence,  the force of friction on the block is = F - ma

= 24.51 N - 6.4×0.58 N

= 20.798 N

Learn more about acceleration here:

brainly.com/question/12550364

#SPJ2

Answer:

3.5 hours

Explanation:

Answer:

The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.

At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.

According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.

From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;

Increasing the force acting on the mouse

Decreasing the mass of the mouse

Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.

Explanation:

Hi there!

Recall Newton's Second Law:

[tex]\large\boxed{\Sigma F = ma}[/tex]

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

We must begin by solving for the acceleration using the following:

a = Δv/t

In this instance:

Δv = 3 m/s

t = 2.5 sec

a = 3/2.5 = 1.2 m/s²

Now, plug this value along with the mass into the equation for net force:

[tex]\Sigma F = 5(1.2) = \boxed{6 N}}[/tex]

Answer:

[tex]\boxed {\boxed {\sf 6 \ Newtons}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration. The mass of the object is 5 kilograms, but the acceleration is unknown.

We can find acceleration using the following formula:

[tex]a= \frac{ \Delta v}{t}[/tex]

The velocity of the object increases by 3 meters per second. It accelerates in 2.5 seconds.

Substitute the values into the formula.

[tex]a= \frac{3 \ m/s}{2.5 \ s}[/tex]

[tex]a= 1.2 \ m/s/s = 1.2 \ m/s^2[/tex]

Now we know the mass and acceleration.

Substitute the values into the force formula.

[tex]F=ma[/tex]

[tex]F= (5 \ kg)(1.2 \ m/s^2)[/tex]

[tex]F= 6 \ kg*m/s^2[/tex]

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 6 kilogram meters per second squared is equal to 6 Newtons.

[tex]F= 6 \ N[/tex]

Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

The given parameters:

The normal reaction on the rough surface due to weight of the block is calculated as follows;

[tex]F_n = 40 \ N[/tex]

The static friction between the block and the plane is calculated as follows;

[tex]F_s = \mu_s F_n[/tex]

where;

Thus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

Learn more about static friction here: https://brainly.com/question/13680415

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

The change in the energy applied to the car is calculated as;

[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]

The final speed of the car is calculated as follows;

[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]

Thus, the final speed of the car at the given conditions is 30.1 m/s.

Learn more about change in kinetic energy here: https://brainly.com/question/6480366

Answer:

Yes.

Explanation:

Displacement is a vector quantity, meaning it has to be a straight graph jointing from starting point to final point and has a direction as well as magnitude and it can also be negative as well as positive and zero.

Displacement is also changes in position (points) of distance. A distance is scalar quantity meaning it only has magnitude and does not have direction. Since distance is scalar quantity, it cannot be negative. Also graph of distance can be a curve graph or any graph.

So when does displacement equal to distance? If an object is moving in straight path or line in one/fixed direction, both displacement and distance are same.

Because if a distance is a straight path and the displacement is simply a straight line (or ray) jointing from starting point to end point, both distance and displacement are both straight path or rays. Since distance and displacement have same graph, we can conclude that both are same in values.

If we go by calculus, given x = 2t as example of straight graph where x stands for position and t stands for time. We can find the displacement from b to a by using the following formulas:

Displacement

[tex]\displaystyle \large{s=\int\limits^b_a {v} \, dt}[/tex]

Distance

[tex]\displaystyle \large{l=\int\limits^b_a {|v|} \, dt}[/tex]

v stands for velocity which we can find from:

Velocity

[tex]\displaystyle \large{v=\frac{dx}{dt}}[/tex]

If you have learnt calculus, first, differentiate x = 2t with respect to t.

[tex]\displaystyle \large{v=2}[/tex]

Then substitute v = 2 in s and l to find find if both displacement and distance are equal in straight path.

Displacement

[tex]\displaystyle \large{s=\int\limits^b_a {2} \, dt}\\\displaystyle \large{s=[2t]\limits^b_a}\\\displaystyle \large{s=2b-2a = 2(b-a)}[/tex]

Distance

[tex]\displaystyle \large{l=\int\limits^b_a {|2|} \, dt}\\\displaystyle \large{l=\int\limits^b_a {2} \, dt}\\\displaystyle \large{l=[2t]\limits^b_a}\\\displaystyle \large{l=2b-2a=2(b-a)}[/tex]

Since both displacement and distance are equal when integrating on straight graph, we can conclude that an object moving in straight fixed point has same distance and displacement.

Answer:

[tex]1\; \rm V[/tex].

Explanation:

Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:

[tex]V = I \, R[/tex].

It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].

Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)

Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:

[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].

Answer:

2:3

Explanation:

mathqway

Answer:

the answer is 32sin(45°)m/s

Answer:

it’s the third option: 4,600,000 km

Explanation:

just took the test and that was correct