Answers
Answer:
A. 1.02 moles .
Explanation:
Hello!
In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:
[tex]n=\frac{PV}{RT}[/tex]
Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:
[tex]n=\frac{1.00atm*22.9L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.02mol[/tex]
Therefore, the correct answer is A. 1.02 moles
Best regards!
Related Questions
Draw a Lewis structure of the molecule that matches the description below. All non- H atoms should have full octets, and all formal charges should be zero. Unless you're told otherwise, assume there are no rings in the molecule.
Description: The molecule is composed of
2 C 's, 5 H 's, and 1 N and it contains a C - C double bond.
Answers
Answer:
See attached picture.
Explanation:
Hello!
In this case, according to the given instructions, on the attached picture you will find the required Lewis structure, whereas there is a double bond between the two carbon atoms, and one of those is bonded to the nitrogen; moreover the terminal carbon has two out of five hydrogen atoms, the middle carbon, one out of five and the nitrogen atom has two out of five hydrogen atoms; therefore the molecule would be ethenamine.
Best regards!
How many sulfur atoms are in 5 SF6 ?
Answers
Answer:
The molecular formula for sulfur hexafluoride is SF6 S F 6 , in which there is 1 sulfur atom and 6 fluorine atoms.
Explanation:
hope this helps
Using the phase diagram for CO2, what phase is carbon dioxide in at -20°C
and 1 atm pressure?
A. It is in the gas phase.
B. It is in the solid phase.
C. It is at its boiling point.
D. It is in the liquid phase.
Answers
A. It is in the gas phase. The carbon dioxide in at -20°C and 1 atm pressure is in the gas phase.
What does carbon dioxide look like at 20 C?Carbon dioxide is an odorless, colorless, barely acidic, and non-flammable gas at room temperature (20–25 C). A molecule having the chemical formula CO2 is carbon dioxide.
What can we infer about water and carbon dioxide from their phase diagrams?The general Y-shape of the phase diagrams for water and carbon dioxide is the same, although they are offset from one another. This change happens because the liquid phase in ice can occur at lower temperatures and pressures than it can in dry ice, which can only happen at greater temperatures and pressures.
Is there a liquid phase of CO2?A gas, solid, or liquid form of carbon dioxide is possible. Beer and soft drinks are generally carbonated using gaseous carbon dioxide. It also functions as a chemical in the purification of water.
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Suppose your metal sample is hammered into the shape of a thin coin with a diameter of 8.62 cm. Determine the thickness (in mm) of this metal sheet. Use the measured metal mass and true denisty of your metal for this calculation.
measured metal mass: 83.956 g
true density: 8.90 g/cm3
Answers
Answer:
The thickness of the metal sheet is 0.162 centimeters.
Explanation:
If mass within the coin is uniformly distributed, then the density ([tex]\rho[/tex]), measured in grams per cubic centimeter, can be represented by the following formula:
[tex]\rho = \frac{m}{\frac{\pi}{4}\cdot D^{2}\cdot z }[/tex] (1)
Where:
[tex]m[/tex] - Mass, measured in grams.
[tex]D[/tex] - Diameter, measured in centimeters.
[tex]z[/tex] - Thickness, measured in centimeters.
If we know that [tex]m = 83.956\,g[/tex], [tex]D = 8.62\,cm[/tex] and [tex]\rho = 8.90\,\frac{g}{cm^{3}}[/tex], then the thickness of the coin is:
[tex]z = \frac{m}{\frac{\pi}{4}\cdot D^{2}\cdot \rho }[/tex]
[tex]z = \frac{83.956\,g}{\frac{\pi}{4}\cdot (8.62\,cm)^{2}\cdot \left(8.90\,\frac{g}{cm^{3}} \right) }[/tex]
[tex]z = 0.162\,cm[/tex]
The thickness of the metal sheet is 0.162 centimeters.
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.8635 g of CO2 and 0.1767 g of H2O. What is the empirical formula of the compound?
Answers
Answer: The empirical formula is [tex]C_3H_3O_2[/tex].
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of [tex]CO_2[/tex] = 0.8635
Mass of [tex]H_2O[/tex]= 0.1767 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 0.8635 g of carbon dioxide, =[tex]\frac{12}{44}\times 0.8635=0.2355g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 0.1767 g of water, =[tex]\frac{2}{18}\times 0.1767=0.0196g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (0.4647) - (0.2355+0.0196) = 0.2096 g
Mass of C = 0.2355 g
Mass of H = 0.0196 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{0.2355g}{12g/mole}=0.0196moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.0196g}{1g/mole}=0.0196moles[/tex]
Moles of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.2096g}{16g/mole}=0.0131moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.0196}{0.0131}=1.5[/tex]
For H =[tex]\frac{0.0196}{0.0131}=1.5[/tex]
For O = [tex]\frac{0.0131}{0.0131}=1[/tex]
The ratio of C : H: O = 1.5 : 1 .5 : 1
Converting to simple whole number ratio:
The ratio of C : H: O = 3 : 3: 2
Hence the empirical formula is [tex]C_3H_3O_2[/tex].
Why does the light coming from a flashlight appear brighter when it is closer to an object than when it is farther
away?
a. It is because the air is absorbing less of the light.
b. It is because the air is absorbing more of the light.
c.It is because the light waves are being refracted.
d. It is because the light waves are appearing at their normal line.
Answers
The answer is c and possibly a I don't know why im here i dont know what this is so bye...
Explanation:
C I hope this is right for your question.
Diana has just completed a reaction that had a chemical change. Which two changes could be evidence of this change?
color and odor
color and shape
odor and density
shape and density
Answers
Answer:
I think its A im sorry if im wrong
Explanation:
Answer:
color and odor
Explanation:
A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the temperature of the water starts off at . When the temperature of the water stops changing it's . The pressure remains constant at . Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits.
Answers
Answer:
Therefore, the specific heat capacity of the iron is 0.567J/g.°C.
Note: The question is incomplete. The complete question is given as follows:
A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.
Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits
Explanation:
Using the formula of heat, Q = mc∆T
where Q = heat energy (Joules, J), m = mass of a substance (g)
c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)
When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water
mass of iron = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C
∆T = 85.0 °C - 27.6 °C = 57.4 °C
mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C
∆T = 27.6°C - 23.0°C = 4.6 °C
Substituting the values above in the equation; Heat lost by Iron = Heat gained by water
59.1 g * c * 57.4 °C = 100.0 g * 4.184 J/g.°C * 4.6 °C
c = 0.567 J/g.°C
Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 20.m . Calculate the frequency of these radio waves. Be sure your answer has the correct number of significant digits.
Answers
Answer:
1.5×10⁷ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength of radio wave (λ) = 20 m
Frequency (f) =?
Frequency and wavelength of a wave are related by the following equation:
v = λf
Where:
'v' is the velocity of electromagnetic wave.
'λ' is the wavelength
'f' is the frequency.
With the above formula, we can obtain the frequency of the radio wave as illustrated below:
Wavelength of radio wave (λ) = 20 m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 20 × f
Divide both side by 20
f = 3×10⁸ / 20
f = 1.5×10⁷ Hz
Thus the frequency of the radio wave is 1.5×10⁷ Hz
1. The following equation represents the reaction between sodium and water.
2Na(s) + 2H20(1) - 2NaOH(aq) + H2(g)
During this reaction, water is acting as ...
A)an acid and an oxidant
B)an acid and a reduc tant
C)an oxidant only
D)an acid only
Answers
Anyone Can help me this question ♂️ please ?
Answers
Answer:
54.66 liters
Explanation:
First of all, remember this. 1 mole equals 22.4 liters.
Second of all, to show your work use dimensional analysis.
Write 2.44 moles and then put moles on the bottom and liters on top.
2.44 moles of O * 22.4 liters / 1 mol of O
Moles will cancel out.
2.44 x 22.4 = 54.656
Usually I would have used sig figs. But the question said to round your answer to two digits after the decimal point.
54.656 rounds to the hundreths place.
So 54.656 = 54.66
All in all, the final answer is 54.66 liters(don't forget the units).
Hope it helped!
Describe briefly how you will determine the relative density of kerosene
Answers
Explanation:
First determine the weight of the density bottle(A1) when it's empty.
Then fill it with the liquid you want to determine the density.
Then determine the weight of the bottle with the liquid(A2).
Then the weight of the liquid is equal to (A2 - A1)
You already know the volume of the bottle.
Apply them to density = weight/volume
Make sure to mention the temperature you measured it because density varies from one temperature to another.
Which of the following elements is most reactive?
A.LI
B.Ne
C.K
D.Au
E.Cs
Answers
Answer:
E
Explanation:
Anything going down Column 1 is going to be more reactive than anything else.
So the only contenders that are in column 1 are Li and Cs. The most reactive ones are the ones going down.
Cs is at the bottom of column 1. The answer is E
carbon dioxide is in a steel tank at 20 degrees celsius and 10 liters. what is the volume on the gas when the tank is heated to 100 degrees celsius?
Answers
Answer:
12.73 L
Explanation:
Given that,
Initial temperature, [tex]T_i=20^{\circ}=20+273=293\ K[/tex]
Initial volume, [tex]V_i=10\ L[/tex]
We need to find the volume on the gas when the tank is heated to 100 degrees celsius or 373 K.
We know that volume is directly proportional to the temperature of the gas. Using above relation,
[tex]\dfrac{V_i}{T_i}=\dfrac{V_f}{T_f}\\\\V_f=\dfrac{V_iT_f}{T_i}[/tex]
Putting all the values,
[tex]V_f=\dfrac{10\times 373}{293}\\\\V_f=12.73\ L[/tex]
So, the final volume of the gas is 12.73 L.
What is the empirical formula of a compound whose percentage composition is found to be 62.60% lead, 8.40% nitrogen, and 29.0% oxygen?
Answers
Answer:
PbN₂O₆
Explanation:
Empirical formula is the simplest formula of a compound.
To find the empirical formula, we use the system below:
Lead Nitrogen Oxygen
Percentage
Composition 62.6 8.4 29
Molar mass 207.2 14 16
Number of
Moles 62.6/207.2 8.4/14 29/16
0.302 0.6 1.813
Divide by the
smallest 0.30/0.302 0.6/0.302 1.813/0.302
1 2 6
Empirical formula is PbN₂O₆
The empirical formula of the compound containing 62.60% lead, 8.40% nitrogen, and 29.0% oxygen is PbN₂O₆ or Pb(NO₃)₂
From the question given above, the following data were obtained:
Lead (Pb) = 62.60%
Nitrogen (N) = 8.40%
Oxygen (O) = 29.0%
Empirical formula =?The empirical formula of the compound can be obtained as illustrated below:
Divide by their molar mass
Pb = 62.60 / 207 = 0.302
Nitrogen (N) = 8.40 / 14 = 0.6
Oxygen (O) = 29.0 / 16 = 1.8125
Divide by the smallest
Pb = 0.302 / 0.302 = 1
Nitrogen (N) = 0.6 / 0.302 = 2
Oxygen (O) = 1.8125 / 0.302 = 6
Thus, the empirical formula of the compound is PbN₂O₆ or Pb(NO₃)₂
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How do you know when to put a positive or negative exponent?
Answers
Answer:
If a negative number is raised to an even power, the result will be positive. If a negative number is raised to an odd power, the result will be negative. The negative number must be enclosed by parentheses to have the exponent apply to the negative term.
Explanation:
Select the correct balanced equation for the single displacement reaction of bromine and potassium iodine.
Br + Kl -> KBr +1
Answers
Answer:
D
D...............DDDDDDD
Answer: D
Explanation:
The answer is D as it is the only correctly balanced equation.
A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium
carbonate, CaCO3, according to the reaction CaCO3 → CaO + CO2. Calculate the theoretical yield and
the percent yield for the reaction. Show and/or explain your work.
Answers
Answer:
A. Theoretical yield of CaO is 11.59 g
B. Percentage yield of CaO = 58.76%
Explanation:
The following data were obtained from the question:
Mass of CaCO₃ = 20.7 g
Actual yield of CaO = 6.81 g
Theoretical yield of CaO =?
Percentage yield of CaO =?
The equation for the reaction is given below:
CaCO₃ —> CaO + CO₂
Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:
Molar mass of CaCO₃ = 40 + 12 + (3×16)
= 40 + 12 + 48
= 100 g/mol
Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g
Molar mass of CaO = 40 + 16 = 56 g/mol
Mass of CaO from the balanced equation = 1 × 56 = 56 g
SUMMARY:
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
A. Determination of the theoretical yield of CaO.
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
Therefore, 20.7 g of CaCO₃ will decompose to produce =
(20.7 × 56)/100 = 11.59 g of CaO.
Thus, the theoretical yield of CaO is 11.59 g
B. Determination of the percentage yield.
Actual yield of CaO = 6.81 g
Theoretical yield of CaO = 11.59 g
Percentage yield of CaO =?
Percentage yield = Actual yield /Theoretical yield × 100
Percentage yield = 6.81/11.59 × 100
Percentage yield of CaO = 58.76%
someone help me pls ada
Answers
The currently accepted model of the atom includes an electron cloud.
A. True
B. False
Answers
Answer:
True
Explanation:
Answer: True
Explanation:
Identify which element is the least malleable: potassium, calcium, scandium, or titanium
Answers
94.9 grams of Br is equivalent to how many moles of Br?
Answers
Answer:
The answer is 79.904.
Explanation:
We assume you are converting between grams Br and mole.
You can view more details on each measurement unit:
molecular weight of Br or mol
The SI base unit for amount of substance is the mole.
1 grams Br is equal to 0.012515018021626 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Br and mole.
Type in your own numbers in the form to convert the units!
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2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)
How many grams of water can be produced with 1.85 moles of NaOH
Answers
16.7 g H₂O
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Stoichiometry
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)
[Given] 1.85 mol NaOH
Step 2: Identify Conversions
[RxN] 2 mol NaOH → 1 mol H₂O
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Step 3: Stoichiometry
Set up: [tex]\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})[/tex]Multiply/Divide: [tex]\displaystyle 16.6685 \ g \ H_2O[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
16.6685 g H₂O ≈ 16.7 g H₂O
6. Three of these terms belong together. Which one doesn't belong?
A) nucleus
B) cytoplasm
C) cell wall
D) cell membrane
Explain why the one you chose doesn't belong with the other three?
Answers
Answer:
i am 50/50 at the memoent but i have a feeling it is the cytoplasm as it isnt a cell like the others. Hope this helps :(
Explanation:
The element in Period 4 and Group 14 of the Periodic Table would be classified as a
Answers
Answer:
Chalcogen
Explanation:
Given the molecular formula, C2H8N, write the empirical formula.
Answers
Answer:
C2H8N
Explanation:
it wont change since there is no common factor between the 2:8:1 which will give us a whole number so it stays the same
In table below, there are descriptions of an experiment on samples of three different chemical compounds. Decide whether the compound is ionic or molecular, if you can. If there is not enough information to decide, choose can't decide in the third column.
compound description ionic or molecular
1 Compound 1 is a light gray solid made of
overlapping hexagonal crystals. When heated gently it
starts to soften and develop an unpleasant smell about
50 °C. above room temperature.
2 Compound 2 is a dull white smooth solid which does not
conduct electricity. Applying an ordinary laboratory burner
to the material only makes the substance hot, it does not
otherwise change. In fact, the substance can't be melted
or even softed by any ordinary laboratory equipment.
3 Compound 3 is a clear liquid with a strong pleasantly
fruity smell. If cooled it freezes at about -10 °C. In the
solid state it does not conduct electricity.
Answers
Answer:
Compound 1 is molecular
Compound 2 is ionic
Compound 3 can't really be decided
Explanation:
A molecular substance does not conduct electricity, has very low melting and boiling points and is held together by very weak intermolecular forces.
An ionic substance conducts electricity in solution or in molten state but never in the pure solid state, has a high melting and boiling point and has a dull appearance most times.
Compounds 1 shows the properties of molecular substances hence it are designated as such.
On the other hand, compound 2 shows the properties of an ionic substance and is also designated as such.
We can't really decide on compound 3 because it shows some properties of ionic substances and some properties of molecular substances.
differentiate between normal publication window and the story editor window in desktop publishing
Answers
The main differentiation between given windows is that in normal publication window we can edit the document after generation also and the story editor window in desktop publishing we can not able to edit after generation.
What is windows?Windows in the computer world is a part of the graphical user interface (GUI), which is a separate viewing area on the display of monitor where they allow multiple viewing area.
In the normal publication window, word processing software like Microsoft Word, Pages, Writer and WordPerfect comes which is used to create any text document like resume, report, thesis, etc. which can be manipulate after the generation also.The story editor window in desktop publishing is used to create page layouts of any documents for publication in print or online.Hence, in the above paragraph differentiation is given.
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The wormwood plant is known for having leaves that taste bitter and have a strong odor. What advantage would these qualities give the
wormwood plant?
A. It would be more likely to repel other plants.
B. It would be less likely to be grown for use by humans.
C. It would be less likely to be eaten by insects.
D. It would be more likely to attract birds.
Answers
Answer:
C. It would be less likely to be eaten by insects.
Explanation:
The bitter taste and strong odor of the wormwood plant would repel the insects from eating the plant.
This is an adaptation by the tree to prevent is from being destroyed by the insect that would feed on its leaves. The bitter taste would not be edible for the insect to feed on. Also, the strong odor will not be attractive for the insects. So, the tree is well adapted to survive any insect invasion.A gas mixture in a rigid container has a total pressure of 2.5 atm. One gas, lets call it X, has 0.85 moles and accounts for 1.2 atm of pressure. What is the mole fraction of the other gases (all gases that are not X) in the container?
Answers
The mole fraction of the other gases : 0.52
Further explanationGiven
P tot = 2.5 atm
P x = 1.2 atm, n = 0.85 moles
Required
mole fraction
Solution
P tot = P gas X + P other gases
mol fraction = mol x : mol total
P gas X = mol fraction gas X x P total
1.2 atm = mol fraction gas X x 2.5 atm
mol fraction gas X = 0.48
mol fractionof the other gases = 1 - 0.48 = 0.52
Or we can use
P other gases = 2.5 - 1.2 = 1.3 atm
mol fraction the other gases = 1.3 : 2.5 = 0.52