Answer:
The correct answer is "0.66 kg.m²".
Explanation:
The given values are:
K.E = 500 J
w₁ = 65 rad/s
w₂ = 52 rad/s
As we know,
⇒ [tex]K.E=\frac{1}{2}I[w_1^2-w_2^2][/tex]
then,
⇒ [tex]I=\frac{2(K.E)}{w_1^2-w_2^2}[/tex]
On putting the given values, we get
⇒ [tex]=\frac{2\times 500}{(65)^2-(52)^2}[/tex]
⇒ [tex]=\frac{1000}{4225-2704}[/tex]
⇒ [tex]=\frac{1000}{1521}[/tex]
⇒ [tex]=0.66 \ kg.m^2[/tex]
Increasing the telescope diameter beyond the value found in part (a) will increase the light-gathering power of the telescope, allowing more distant and dimmer astronomical objects to be studied, but it will not improve the resolution. In what ways are the Keck telescopes (each of 10-m diameter) atop Mauna Kea in Hawaii superior to the Hale Telescope (5-m diameter) on Palomar Mountain in California
Answer:
Ability of the Keck telescope to capture more distant object despite been atop Mauna kea that Hale Telescope may not capture even if it is atop Palomar mountain in California
Explanation:
If increasing the Diameter of a Telescope beyond a given value will increase the ability of the telescope to capture more light and also capture astronomical objects located in a very distant position without improving resolution.
Hence the superiority of Keck telescope atop Mauna Kea over Hale Telescope atop Palomar mountain in California is the ability of the Keck telescope to capture more distant object despite been atop Mauna kea that Hale Telescope may not capture even if it is atop Palomar mountain in California
PLZ help 10 points!!! space question!
Answer:
B. They are smaller and made of rocky material
Explanation:
i think it's right??
Consider the model of the energy transformation of this system. What can you say about N and M in the model?
A) M < N
B) N = M
C) N < M
D) N + M =
Model of the energy transformation of this system we can say about N and M in the model is M < N.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
The model shows the energy transformation in electrical appliance Fan the is lass of energy in form of heat so M < N.
Model of the energy transformation of this system we can say about N and M in the model is M < N.
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Student Exploration: Energy Conversion in a SystemNCVPS Chemistry Fall 2014Vocabulary: energy, gravitational potential energy, heat energy, kinetic energy, law of conservation of energy, specific heat capacityPrior Knowledge Questions (Do these BEFORE using the Gizmo.)A battery contains stored energy in the form of chemical energy.1. What are some examples of devices that are powered by batteries? ____________________________________________________________________________________________2. What different forms of energy are dmonstrated by these devices? ___________________ _________________________________________________________________________Gizmo Warm-upEnergy constantly changes from one form to another, but in a closed system, the total amount of energy always remains the same. This concept is known formally as the law of conservation of energy.The Energy Conversion in a System Gizmo™ allows you to observe the law of conservation of energy in action. In the Gizmo, a suspended cylinder has gravitational potential energy. When the cylinder is released, the
Answer:
a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights
b) ed lights and flashlights transform into light energy and thermal energy
c) Em₀ = U = m gh, Em_f = K = ½ m v²
Explanation:
In this exercise ask to complete the sentences
a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights
b) These devices transform the chemical energy stored in the batteries into other forms of energy.
Led lights and flashlights transform into light energy and thermal energy
Keyboards transform into electromagnetic energy that is emitted
clocks transform to mechanical energy from the movement of the needles
Electronic weights transforms the chemical energy of the baria into gravitational potential energy that prevents the movement of the plate and this translates into the reading of the body weight
c) The total energy of the cylinder mechanical energy when sustained is
Em₀ = U = m gh
it is transformed as it descends into kinetic energy, at any point
Emₙ = K + U = 1/2 m v² + m g y
at the lowest point of the trajectory all energy is transformed
Em_f = K = ½ m v²
In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 4.07 kg. They then hang the object on a pivot located 0.155 m from the object's center of mass and set it swinging at a small amplitude. As two of the team members carefully count 113 cycles of oscillation, the third member measures a duration of 247 s. What is the moment of inertia of the object with respect to its center of mass about an axis parallel to the pivot axis
Answer:
I = 0.65 kgm²
Explanation:
Since the mass is an inertial pendulum, we use the formula for the period, T of an inertial pendulum.
T = 2π√(I/mgh) where I = moment of inertia of object about pivot point, m = mass of object5 = 4.07 kg, g = acceleration due to gravity = 9.8 m/s² and h = distance of center of mass of object from pivot point = 0.155 m.
Given that the team measures 113 cycles of oscillation in 247 s, the period, T = time of oscillations/total number of oscillations = 247 s/113 oscillations = 2.186 s/oscillation
So, T = 2.186 s
We now find I by making it subject of the formula in the equation for T.
So,
T = 2π√(I/mgh)
dividing both sides by 2π, we have
T/2π = √(I/mgh)
squaring both sides, we have
(T/2π)² = [√(I/mgh)]²
T²/4π² = I/mgh
multiplying both sides by mgh, we have
T²mgh/4π² = I
I = T²mgh/4π²
substituting the values of the variables into the equation, we have
I = T²mgh/4π²
I = (2.186 s)² × 4.07 kg × 9.8 m/s² × 0.155 m/4π²
I = 4.778 s² × 4.07 kg × 9.8 m/s² × 0.155 m/4π²
I = 29.539 kgm²/4π²
I = 0.748 kgm²
Now I = I' + mh² (parallel axis theorem) where I' = moment of inertia of object about its center of mass, m = mass of object = 4.07 kg and h = distance of center of mass object from pivot point.
So, I' = I - mh²
Substituting the values of the variables into the equation, we have
I' = I - mh²
I' = 0.748 kgm² - 4.07 kg × (0.155 m)²
I' = 0.748 kgm² - 4.07 kg × 0.02403 m²
I' = 0.748 kgm² - 0.098 kgm²
I = 0.65 kgm²
All the questions are in the photos above. Thanks guys!
Answer:
right
Explanation:
What is surface tension
Answer:
Surface tension is, the surface where the water meets the air, water molecules cling even more tightly to each other.
Consider a block of mass m at rest on an inclined plane of angle theta. An acrobat of mass m_A is standing on the top corner of the block so that their weight presses vertically (perpendicular to the flat ground under the incline) downward. If the coefficient of static friction between the block and the incline is mu_s find an expression relating m_A, m, theta, and mu_s just before the block begins slipping. If the condition for slipping does not involve some of these parameters, leave them out.
Enter your expression as best you can and I will check it. Do not forget to upload your work as well.
Answer:
μ = tan θ
Explanation:
For this exercise let's use the translational equilibrium condition.
Let's set a datum with the x axis parallel to the plane and the y axis perpendicular to the plane.
Let's break down the weight of the block
sin θ = Wₓ / W
cos θ = W_y / W
Wₓ = W sin θ
W_y = W cos θ
The acrobat is vertically so his weight decomposition is
sin θ = = wₐₓ / wₐ
cos θ = wₐ_y / wₐ
wₐₓ = wₐ sin θ
wₐ_y = wₐ cos θ
let's write the equilibrium equations
Y axis
N- W_y - wₐ_y = 0
N = W cos θ + wₐ cos θ
X axis
Wₓ + wₐ_x - fr = 0
fr = W sin θ + wₐ sin θ
the friction force has the formula
fr = μ N
fr = μ (W cos θ + wₐ cos θ)
we substitute
μ (Mg cos θ + mg cos θ) = Mgsin θ + mg sin θ
μ = [tex]\frac{(M +m) \ sin \ \theta }{(M +m) \ cos \ \theta }[/tex]
μ = tan θ
this is the minimum value of the coefficient of static friction for which the system is in equilibrium.
has a man he has married many women but has never been married before who is he
Answer:
Explanation:
The answer is a priest or a moulana
which of the following best defines spring constant ?
a. the amount of force needed to extend or compression of a spring for every 1 kilogram of the spring.
b. the amount of force needed every 1 meter of stretch or compression of the spring.
c. the amount of energy needed to extend or compress a spring for every 1 kilogram of mass of the spring.
d. the amount of energy needed for every 1 meter of stretch or compression of the spring.
Answer:
your answer gonna be The letter C is the correct answer
1. Describe the following energy transformations for the following scenario:
A student plays piano in music class.
Answer:
Explanation:
iphotosynthesis 2coal burning 3electric motor 4 electricity generator 5 waterturbines 6 solar bulb
⦁ An electron is moving through a 10 T magnetic field at a speed of 3.5 x107m/s perpendicular to the direction of the field. What is the force that applied on the charge?
Answer:
F = 5.6 10⁻¹¹ N
Explanation:
The magnetic force is given by
F = q v x B
The bold indicate vectors, the scalar form of this expression is
F = q v B sin θ
in this case they indicate that the speed and the magnetic field are perpendicular, so the angle is 90º and the sin 90 = 1
F = q v B
the magnitude of the force is
F = 1.6 10⁻¹⁹ 3.5 10⁷ 10
F = 5.6 10⁻¹¹ N
ILL GIVE BRAINLIST PLS In which circuit does charge reverse direction many times per second?
A. A DC circuit
B. A combined circuit
C. A parallel circuit D. An AC circuit
Answer: D. An AC circuit
Explanation:
I took it on a test and it was correct ; )
A skater spins with an angular speed of 5.9 rad/s with her arms outstretched. She lowers her arms, decreasing her moment of inertia by a factor of 1.7. Ignoring friction on the skates, determine the ratio of her final kinetic energy to her initial kinetic energy.
Answer:
the ratio of her final kinetic energy to her initial kinetic energy is 1.7.
Explanation:
Given;
initial angular speed, ω₁ = 5.9 rad/s
let her initial moment of inertia = I₁
her final moment of inertia [tex]I_2 = \frac{I_1}{1.7}[/tex]
Apply the principle of conservation of angular momentum to determine the final angular speed of the girl;
[tex]\omega_1I_1 = \omega_f I_2\\\\\omega_f = \frac{\omega _1 I_1}{I_2} \\\\\omega_f = \frac{5.9 \times I_1}{I_1/1.7} \\\\\omega = 5.9 \times 1.7 \\\\\omega_f = 10.03 \ rad/s[/tex]
The initial rotational kinetic energy is given as;
[tex]K.E_I = \frac{1}{2}I_1 \omega_I ^2[/tex]
The final rotational kinetic energy is given as;
[tex]K.E_f = \frac{1}{2}I_2 \omega_f ^2[/tex]
The ratio of her final kinetic energy to her initial kinetic energy is given as;
[tex]\frac{K.E_f}{K.E_I}= \frac{\frac{1}{2}I_2 \omega_f^2 }{\frac{1}{2} I_1\omega _1^2} \\\\\frac{K.E_f}{K.E_I}= \frac{I_2 \omega_f^2}{ I_1\omega _1^2} \\\\\frac{K.E_f}{K.E_I}= \frac{I_1/1.7 \times \omega_f^2}{ I_1 \times \omega _1^2} \\\\\frac{K.E_f}{K.E_I}= \frac{ \omega_f^2}{ 1.7 \omega _1^2} \\\\\frac{K.E_f}{K.E_I}= \frac{ (10.03)^2}{ 1.7(5.9)^2} = \frac{17}{10} = 1.7[/tex]
Therefore, the ratio of her final kinetic energy to her initial kinetic energy is 1.7.
Planet X has a moon similar to Earth’s moon.
Which path would this moon’s orbit take?
What is a negative effect of increased carbon dioxide within the carbon cycle?
Answer:
Carbon dioxide controls the amount of water vapor in the atmosphere and thus the size of the greenhouse effect. Rising carbon dioxide concentrations are already causing the planet to heat up
Explanation:
Hope it helps! Correct me if I am wrong
Im sure about my answer
A geologist notices that a river is eroding its valley at a constant rate. Knowing the height of the valley walls, how could the geologist figure out when the river started carving the valley?
A.
Count growth rings of trees growing on the valley floor.
B.
Divide the height of the valley walls by the rate of erosion.
C.
Fill up the river valley with rocks, and time how long it takes the rocks to wash out.
D.
Sit and observe the river for a few hours until the valley walls double in height.
Answer:
B.
Divide the height of the valley walls by the rate of erosion.
Explanation:
There is a relationship between the rate of erosion and the hieght at which it is eroded according to Newton's law of motion. In the case of the scenario above, the best way to determine the time the river started carving the valley would be the division of the height of the valley walls by the rate of erosion.
Can someone take there time and answer this :)
Answer: I think B.)
Explanation:
Imagine you are on a space mission and you are 6 AU's from the Sun and you use a light sensor to measure the brightness of the Sun. The amount of sunlight received per square centimeter would be different by what factor compared to the same measurement on Earth at AU
Answer:
36 times less.
Explanation:
The distance from you to the sun is 6AU's, and from the sun to the earth is 1 AU.
Therefore,
At Earth sunlight received per unit cm² is:
[tex]I_{earth} = \dfrac{I_o}{4 \pi \times (1)^2}[/tex]
[tex]I_{earth} = \dfrac{I_o}{4 \pi}[/tex]
[tex]I_{me} =\dfrac{I}{4 \pi (6)^2}[/tex]
[tex]I_{me} = \dfrac{I_o}{36(4 \pi)}[/tex]
Thus, [tex]I_{earth} = 36 \times I_{me}[/tex]
Thus, the right answer is 36 times less.
You want to find out how many atoms of the isotope 65Cu are in a small sample of material. You bombard the sample with neutrons to ensure that on the order of 1% of these copper nuclei absorb a neutron. After activation, you turn off the neutron flux and then use a highly efficient detector to monitor the gamma radiation that comes out of the sample. Assume half of the 66Cu nuclei emit a 1.04-MeV gamma ray in their decay. (The other half of the activated nuclei decay directly to the ground state of 66Ni.) (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e 2 for 120.)
Required:
a. If after 10 min (two half-lives) you have detected 10000 MeV of photon energy at 1.04 MeV, approximately how many 65Cu atoms are in the sample?
b. Assume the sample contains natural copper. Refer to the isotopic abundances listed in your text (Chemical and Nuclear Information for Selected Isotopes) and estimate the total mass of copper in the sample.
Answer:
a) number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶ atoms
b) m_total Cu = 1.585 10⁹ u = 2.632 10⁻¹⁸ kg
Explanation:
a) For this exercise let's start by using the radioactive decay ratio
N = N₀ [tex]e^{- \lambda t}[/tex]o e - lambda t
The half-life time is defined as the time it takes for half of the radioactive (activated) atoms to decay, therefore after two half-lives there are
N = ½ (½ N₀) = ¼ N₀
N₀ = 4 N
in each decay a photon is emitted so we can use a direct rule of proportions. If an atom emits a photon it has Eo = 1,04 Mev, how many photons it has energy E = 10,000 MeV
# _atoms = 1 atom (photon) (E / Eo)
# _atoms = 1 10000 / 1.04
# _atoms = 9615,4 atoms
N₀ = 4 #_atoms
N₀ = 4 9615,4
N₀= 38461.6 atoms
in the exercise indicates that half of the atoms decay in this way and the other half decays directly to the base state of Zinc, so the total number of activated atoms
N_activated = 2 # _atoms
N_activated = 2 38461.6
N_activated = 76923.2
also indicates that 1% = 0.01 of the nuclei is activated by neutron bombardment
N_activated = 0.01 N_total
N_total = N_activated / 0.01
N_total = 76923.2 / 100
N_total = 7.692 10⁶ atoms
so the number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶
b) the natural abundance of copper is
⁶³Cu 69.17%
⁶⁵Cu 30.83%
Let's use a direct proportion rule. If there are 7.692 10⁶ ⁶⁵Cu that represents 30.83, how much ⁶³Cu is there that represents 69.17%
# _63Cu = 69.17% (7.692 10⁶ / 30.83%)
# _63Cu = 17.258 10⁶ atom ⁶³Cu
the total amount of comatose is
#_total Cu = #_ 65Cu + # _63Cu
#_total Cu = (7.692 + 17.258) 10⁶
#_total Cu = 24.95 10⁶
the atomic mass of copper is m_Cu = 63.546 u
m_total = #_totalCu m_Cu
m_total = 24.95 10⁶ 63,546 u
m_total = 1.585 10⁹ u
let's reduce to kg
m_total Cu = 1.585 10⁹ u (1,66054 10⁻²⁷ kg / 1 u)
m_total Cu = 2.632 10⁻¹⁸ kg
Which macronutrient is made up of carbon and hydrogen elements joined together in long groups called hydrocarbons?
Proteins Magnesium Potassium Fats
Answer:
FATS
Explanation:
Fats are made up of carbon and hydrogen elements joined together in long groups called hydrocarbons. The simplest unit of fat is the fatty acid, of which there are two types: saturated and unsaturated.
The macronutrient which is made up of carbon and hydrogen elements joined together in long groups called hydrocarbons is: D. Fats.
A macronutrient refers to a very large molecule (structure) that comprises covalently bonded organic atoms (hydrocarbons) and smaller molecular structures (monomers).
In Science, macronutrients are grouped into four (4) main categories and these are;
Nucleic acid.Carbohydrates.Proteins.Fats (Lipids).Fats (Lipids) are macronutrients that are typically made up of both carbon and hydrogen elements, which are joined together in long groups referred to as hydrocarbons.
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A rock falls from a cliff and hits the ground at a velocity of 31m/s. How long did it take to fall?
Answer:
i dont know man
Explanation:
i dont know man
A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 starts from rest at t = 0. The wheel has a diameter of 20 cm. What is the magnitude of the total linear acceleration of a point on the outer edge of the wheel at t = 0.60 s? Hint: To find total linear acceleration (in m/s2)you need to have tangential and radial acceleration . Tangential acceleration can be calculated using angular acceleration at=rα To find redial acceleration you need to calculate final linear speed of that point and use ar=vf2r . And vf=rωf.
Answer:
The total linear acceleration is approximately 0.246 meters per square second.
Explanation:
The total linear acceleration ([tex]a[/tex]) consist in two components, radial ([tex]a_{r}[/tex]) and tangential ([tex]a_{t}[/tex]), in meters per square second:
[tex]a_{r} = \omega^{2}\cdot r[/tex] (1)
[tex]a_{t} = \alpha \cdot r[/tex] (2)
Since both components are orthogonal to each other, the total linear acceleration is determined by Pythagorean Theorem:
[tex]a = \sqrt{a_{r}^{2}+a_{t}^{2}}[/tex] (3)
Where:
[tex]r[/tex] - Radius of the wheel, in meters.
[tex]\omega[/tex] - Angular speed, in radians per second.
[tex]\alpha[/tex] - Angular acceleration, in radians per square second.
Given that wheel accelerates uniformly, we use the following kinematic equation:
[tex]\omega = \omega_{o}+ \alpha\cdot t[/tex] (4)
Where:
[tex]\omega_{o}[/tex] - Initial angular speed, in radians per second.
[tex]t[/tex] - Time, in seconds.
If we know that [tex]r = 0.1\,m[/tex], [tex]\alpha = 2\,\frac{rad}{s^{2}}[/tex], [tex]\omega_{o} = 0\,\frac{rad}{s}[/tex] and [tex]t = 0.60\,s[/tex], then the total linear acceleration is:
[tex]\omega = \omega_{o}+ \alpha\cdot t[/tex]
[tex]\omega = 1.2\,\frac{rad}{s}[/tex]
[tex]a_{r} = \omega^{2}\cdot r[/tex]
[tex]a_{r} = 0.144\,\frac{m}{s^{2}}[/tex]
[tex]a_{t} = \alpha \cdot r[/tex]
[tex]a_{t} = 0.2\,\frac{m}{s^{2}}[/tex]
[tex]a = \sqrt{a_{r}^{2}+a_{t}^{2}}[/tex]
[tex]a \approx 0.246\,\frac{m}{s^{2}}[/tex]
The total linear acceleration is approximately 0.246 meters per square second.
A sound wave travels with a velocity of 1.5 m/s and has a frequency of 500 Hz. What is its wavelength?
Student 1 and student 2 talk about the speed of the truck
Answer:
Explanation:
any more explanation?
Some thermometers contain alcohol. Alcohol is used in thermometers because
A. is soluble in water
B. is a clear gas when it evaporates
C. expands and contracts easily
D. has a high density
Answer:
Explanation:
Option C is the correct answer
Some thermometers contain alcohol. Alcohol is used in thermometers because expands and contracts easily. The correct option is C.
What is thermometer?Thermometer is the temperature measuring device which consists of a liquid in the bulb which expands as the temperature is increased.
The liquid metal used in the thermometer must have the property to respond on the hotness and coldness rapidly.
In place of mercury, some thermometers use alcohol because an alcohol has a very low freezing point as compared to the Mercury.
Thus, the correct option is C.
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Some thermometers contain alcohol. Alcohol is used in thermometers because expands and contracts easily.
Chemotherapy is used to treat
cervical cancer.
endometriosis.
undescended testicles.
benign prostatic hypertrophy.
Answer:
Cervical cancer
Explanation:
Chemotherapy is a common treatment or most cancers
Answer:
A
Explanation:
Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a current of 4.33 A. (a) Find the force per meter exerted on the 2.75-A wire. (b) Is the force per meter exerted on the 4.33-A wire greater than, less than, or the same as the force per meter exerted on the 2.75-A wire
Answer:
a)[tex]\frac{F_1}{L}=1.95*10^-^5N[/tex]
b)[tex]\frac{F_2}{L}=1.95*10^-^5N[/tex]
Explanation:
From the question we are told that:
Distance between wires [tex]d=32.2[/tex]
Wire 1 current [tex]I_1=2.75[/tex]
Wire 2 current [tex]I_2=4.33[/tex]
a)
Generally the equation for Force on [tex]l_1[/tex] due to [tex]I_2[/tex] is mathematically given by
[tex]F_1=I_1B_2L[/tex]
Where
B_2=Magnetic field current by [tex]I_2[/tex]
[tex]B_2=\frac{\mu *i_2}{2\pi d}[/tex]
Therefore
[tex]F_1=I_1B_2L[/tex]
[tex]F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L[/tex]
[tex]\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }[/tex]
[tex]\frac{F_1}{L}=1.95*10^-^5N[/tex]
b)
Generally the equation for Force on [tex]I_2[/tex] due to [tex]I_1[/tex] is mathematically given by
[tex]F_2=I_2B_1L[/tex]
Where
B_1=Magnetic field current by [tex]I_2[/tex]
[tex]B_1=\frac{\mu *I_1}{2\pi d}[/tex]
Therefore
[tex]\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})[/tex]
[tex]\frac{F_2}{L}=1.95*10^-^5N[/tex]
10 POINTS!! SPACE QUESTION!!
Answer: A (first option)
Explanation: In general, the surface temperatures decreases with increasing distance from the sun. Any warm object in space loses heat via infrared radiation; also visible radiation if it is hot enough. The hotter is the object, the faster it loses heat. Consequently any object warmed by the Sun stays at equilibrium temperature - it warms up until the radiative heat loss equals to the heat received, and cannot get any warmer beyond that.
Which of the following is not a unit of speed *
a) m/s
b) km/s
c) mph [miles per hour]
d) light year
Answer:
I think it's light year but there shouldn't be also km/s but km/h