5. WHICH OF THE FOLLOWING IS NOT A COVALENT COMPOUND? *
A. CCl4
B. H2O
C. Al3O2
D. CO2

Answer:

Mass = 8.46 g

Explanation:

Given data Mass of water produced = ? Mass of glucose = 20 g Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

              C₆H₁₂O₆           :            H₂O

                  1                   :              6

                0.11                :           6/1×0.11 = 0.66

                  O₂               :            H₂O

                  6                   :              6

                0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

Explanation:

Intermolecular forces such as dipole-dipole forces, London dispersion forces exist between molecules. The state of matter of a substance at a given temperature is determined by the relationship between molecules.

Intermolecular forces of attraction is force of attraction that make two molecule come closer. Intermolecular forces of attraction is directly proportional to the electronegativity of the molecule.

At a given temperature, the state of any matter can be defined on the basis of presence of forces of attraction between the molecules of the matter.

Thus, the state of matter of a substance at a given temperature is determined by the relationship between molecules.

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From the chemical equation showing the reaction, sodium chloride (NaCl) is a solid.

A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and chemical formulas.

From the reaction above, the reaction of a solid sodium and a chlorine gas gives a result of Sodium chloride solid.

There are some steps to be considered when balancing a chemical equation:

In conclusion, we have the fact that Sodium chloride which is also known commonly known as salt, is an ionic compound with the chemical formula NaCl, representing a 1:1 ratio of sodium and chloride ions.

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Answer:

4 moles of glucose = 4 x 6.022 x 10^23 = 2.4088 x 10^24 molecules of glucose.

There are 2.4088 x 10²⁴ atoms in 4 moles of glucose C₆H₁₂O₆

1 mole of any gas is defined as the number of  atoms, molecules or ions present in the gas. 1 mole of any gas equals to 6.022 x 10²³ atoms , ions or molecules . 6.022 x 10²³ is known as avogadro's number.

We need a conversion factor that will converts from moles of glucose, C₆H₁₂O₆ to molecules of glucose.

That is, one mole of any substance contains 6.022 x 10²³ molecule of that substance.

4moles of glucose = 4 x 6.022 x 10²³ = 2.4088 x 10²⁴ molecules of glucose.

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The temperature of a vessel  is 296.43 Kelvin when pressure reads 1.250 atm.

Temperature is a physical quantity that expresses quantitatively the perceptions of hotness and coldness.

At standard temperature and pressure, when pressure is 1.000 atm the value of temperature is 273,15 K.

If the pressure at temperature T changes to 1.250 atm

p1 = 1. 000 atm

T1 = 298.15 k

P2 = 1.250

T2 = ?

We apply Gay-Lussacs law

Using P1/ T1 = P2 /T2 all at constant volume

T2 =  296.43 K.

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The standard form for a linear equation is Ax + By = C with two variables.

Linear equations can be described as the equations of degree 1 and is a mathematical statement, which contains an equal sign (=) between the algebraic expression.

A linear equation is an equation for a straight line and their solutions will produce values, which when substituted for the unknown values and make the equation true.

Linear equations can be described as a combination of constants and variables. The standard form of a linear equation with one variable is expressed as ax + b = 0, where, a ≠ 0 and x is the variable.

A linear equation in two variables is expressed as ax + by  + c = 0, where, a ≠ 0, b ≠ 0, x, and y are the variables.

The linear equation in three variables is expressed as ax + by + cz + d = 0, where a ≠ 0, b ≠ 0, c ≠ 0, x, y, z are the variables.

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Nature contains questions that can be answered by science.

The correct option is B).

What is nature?

The word nature refers to the things we can see with our eyes generally they include: plants, animals, the landscape, and other features and products of the earth, as opposed to humans or human creations.

The science of nature helps us to understand how the world and the universe around us work.

There are five major branches of the Science of Nature:

.Chemistry

.Astronomy

.Earth science

.Physics

.Biology.

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Answer

A. Astrology

Explanation:

The rest isnt science its just like puedoscience so its A.

1. The branched alkane contain 4 carbon in the parent chain and 1 substituent group

2. The branched alkane 10 carbon parent chain and 1 substituent group

A branched chain alkane or branched alkane is an alkane which has alkyl group bonded to its central carbon chain and branched alkane contain only carbon and hydrogen atom and with carbon connected to other carbon by single bond and the longest continuous chain of carbon atom is the parent chain and if there is no longest chain because two or more chain are the same longest length then the parent chain defined as the one with most branches and the substituent atom or group of atom substituent in place of hydrogen atom on the parent chain of hydrocarbon that's why here in the first picture the the branched alkane contain 4 carbon in the parent chain and 1 substituent group and in the second picture the branched alkane 10 carbon parent chain and 1 substituent group

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The element which contains 5 protons and 6 neutrons is Boron (B). The element which contains 8 protons and 10 neutrons is Oxygen (O). The element which contains 15 protons and 16 neutrons is Phosphorous (P).

Boron is the fifth element with a total of 5 electrons. Writing the electron configuration of boron, the first her two electrons enter the 1s orbital. Since 1s can only hold two electrons, the next two electrons of B move to the 2s orbitals. The remaining electrons go to the 2p orbitals.

The Bohr model of oxygen shows eight protons and neutrons in the nucleus, and eight electrons orbiting the nucleus at two energy levels. We know that oxygen has 8 subatomic particles because its atomic number is 8. The first energy level that electrons orbit can hold up to two electrons.

According to the Bohr atomic model, the phosphorus atom consists of 15 protons and 16 neutrons in the nucleus, and 15 electrons orbiting the nucleus in its three shells. K, L, M shells.

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The balanced equation of the reaction: [tex]BaCl_2 (aq) + Na_2SO_4 (aq) --- > BaSO_4 (s) + 2NaCl (aq)[/tex]

The percent yield of the experiment: 81.75%

From the balanced equation of the reaction: [tex]BaCl_2 (aq) + Na_2SO_4 (aq) --- > BaSO_4 (s) + 2NaCl (aq)[/tex]

The mole ratio of the barium chloride and sodium sulfate is 1:1.

Recall that: mole = mass/molar mass

Molar mass of barium chloride = 208.23 g/mol

Molar mass of sodium sulfate = 142.04 g/mol

Mole of 4.50 g barium chloride = 4.50/208.23

                                                   = 0.023 mol

Mole of 3,80 g sodium sulfate = 3.80/142.04

                                                   = 0.027 g/mol

From the moles calculated, sodium sulfate is in excess while barium chloride is the limiting reactant.

The mole ratio of barium chloride and barium sulfate is 1:1. Thus, the equivalent mole of barium sulfate will also be 0.023 mol.

Molar mass of barium sulfate = 233.43 g/mol

Mass of 0.023 mol barium sulfate = 0.023 x 233.43

                                                         = 5.37 g

Percent yield of barium sulfate = 4.39/5.37 x 100

                                                    = 81.75%

Thus, the percent yield of the reaction is 81.75%.

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Answer: An acidic substance

Explanation: An acidic substance will neutralize the potassium hydroxide solution because Potassium hydroxide is a strong base.

Answer:

An acidic substance

Explanation:

maaf kalo salah

Answer:

The ethmoid, sphenoid, occipital, paired frontal, and paired temporal bones are the 5 bones that make up the base of the skull. Three areas of the skull base—the anterior, middle, and posterior cranial fossae—can be distinguished.

If 280 grams of CO₂ is at 13 °C and 445 kilopascal, the volume for the given data in the mL is 34,000 mL.

First we need to convert the given pressure in atm, temperature in Kelvin.

T=13+273=286K

P=445 kpa×(1000 pa/1 kpa)×(760 mmHg/101325 pa)×(1 atm/760 mmHg)

=445×1000×1 atm/101325

=445000 atm/101325

=4.3918 atm

The molar mass of CO₂ is 44g/mol and the number of moles of 280g of CO₂ is

moles(n)=280 g×(1 mol/44 g)

=6.3636 mol

According to the ideal gas law

PV=nRT

Where R=0.08206 Latm/molK

Rearrange the formula for V and plug all the values to solve for V

V=(nRT/P)

=(6.3636 mol×0.08206 Latm×286K)/4.3918atm×molK

=149.38435 L/4.3918

=34.0143 L≈34 L

Convert the above volume in L

34 L×(1000 mL/1 L)

=34000 mL

Therefore, the volume of the given data in mL is 34000 mL.

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1. The empirical formula of the compound, given that it contains 86% C and 14% H is CH₂

2. The mass of C and H present in 100 g of the compound are: 86 g C and 14 g H (Option A)

1. How do I determine the empirical formula?

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

C = 86/ 12 = 7.167

H = 14 / 1 = 14

Divide by the smallest

C = 7.176 / 7.167 = 1

H = 14 / 7.167 = 2

Thus, from the above calculation, we can conclude that the empirical formula of the compound is CH₂

2. How do I determine the mass of C and H?

The mass of C and H in 100 grams of the compound can be obtained as illustrated below

Mass of C = Percentage of C × mass of compound

Mass of C = 86% × 100

Mass of C = 0.86 × 100

Mass of C = 86 g

Mass of H = Percentage of H × mass of compound

Mass of H = 14% × 100

Mass of H = 0.14 × 100

Mass of H = 14 g

Thus, the mass of C and H are: 86 g C and 14 g H (Option A)

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Answer:

Explanation:

gravity plays the role of the force that keeps the moon "attached" to the body.   Gravity is pulling the moon into the planet, as long as the moon has a velocity that keeps it from falling directly into the planet it will orbit

Answer:

2.0 L

Explanation:

P1= first pressure 

P2= second pressure 

V1= first volume 

V2= second volume 

P1V1 = P2V2=
(5.7 atm)(350 mL) = (1.0atm)V2

V2= (5.7 atm)(350 mL) / (1.0 atm)=

V2= 1.99500 L = 2.0 L

Answer:

Energy

Explanation:

Energy is the ability to do work. I always remember this because that definition has never made any sense to me.

You can do work because of energy.

Hope this helps!

The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:

[tex]m_1v_1 = m_2v_2[/tex]

Where [tex]m_1[/tex] is the molarity before dilution, [tex]v_1[/tex] is the volume before dilution, [tex]m_2[/tex] is the molarity after dilution, and [tex]v_2[/tex] is the volume after dilution.

In this case, [tex]m_1[/tex] = 0.774 M, [tex]v_1[/tex] = 10.0 mL, [tex]v_2[/tex] = 100 mL.

[tex]m_2[/tex] = [tex]m_1v_1/v_2[/tex]

     = 0.774 x 10/100

      = 0.0774 M

Thus, the new concentration of the sodium sulfide solution would be 0.0774 M.

Mole of the final solution: 0.0774 x 0.1 = 0.00774 mol

Sodium sulfide formula = [tex]Na_2S[/tex] ---> [tex]2Na^+ + S^{2-[/tex]

Equivalent mole of sodium ion = 0.00774 x 2

                                                    = 0.01548 mol

The concentration of sodium ions = mol/volume

                                                  = 0.01548/0.1

                                                  = 0.1548 M

In other words, the concentration of the sodium ions in the diluted solution would be 0.1548 M.

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If the structure of the crystal contains an identical component at the center of the cube then it is said to be BCC whereas if there are parts in the center of each face along with those at the corners of the cube, then it is FCC.

Crystal structures may be narrated in several ways. The most usual manner is to refer to the size and shape of the cube and the locations of the atoms (or ions) within the cell. The crystal structure is set on by X-ray diffraction. A beam of X-rays strikes the crystal and the diffraction design is then used to study the structure, Matter can broadly be restricted into two categories based on its internal structure i.e. amorphous and crystalline. The morphology of crystals can be studied with the unaided eye in large well-evolve crystals and has been historically examined.

So we can conclude that the size of the unit cell and the positioning of atoms in a crystal may be set on from measurements of the diffraction of X-rays by the crystal, termed X-ray crystallography.

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The molecular formula of the compound, given that it contains only hydrogen and sulfur is H₄S₂

We'll begin by obtaining the mass of sulfur and hydrogen. This is illustrated below:

Mass of S = (32 / 64) × 10

Mass of S = 5 g

Mass of H = (mass of compound) – (mass of S)

Mass of H = 5.31 – 5

Mass of H = 0.31 g

Next, we shall determine the empirical formula

Divide by their molar mass

H = 0.31 / 1 = 0.31

S = 5 / 32 = 0.156

Divide by the smallest

H = 0.31 / 0.156 = 2

S = 0.156 / 0.156 = 1

Thus, the empirical formula is H₂S

Finally, we shall determine the molecular formula. Details below

Molecular formula = empirical × n = mass number

[H₂S]n = 68

[(2×1) + 32]n = 68

34n = 68

Divide both sides by 34

n = 68 / 34

n = 2

Molecular formula = [H₂S]n

Molecular formula = [H₂S]₂

Molecular formula = H₄S₂

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During a chemical reaction: bonds in the reactants are broken new bonds are made in the products Energy is absorbed to break bonds. Bond-breaking is an endothermic process. Energy is released when new bonds form. Bond-making is an exothermic process.

Energy is absorbed when bonds are broken, and it is evolved when bonds are established.

Chemical bonds is defined as the creation of a chemical compound through the creation of a chemical link between two or more atoms, molecules, or ions. To form bonds, atoms exchange or swap their valence electrons. To reach a complete outer energy level, which is the most stable configuration of electrons, atoms must form chemical bonds.

Because more energy is required to break bonds than is produced when new bonds are formed, energy is absorbed in some reactions. As a result, during a reaction, many kinds of bonds may form. Energy is released as a result of the creation of bonds. Energy is absorbed when bonds are broken.

Thus, when bonds are broken, energy is absorbed, and when bonds are formed, energy is evolved.

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Answer: It is conduction.

Explanation: Heat travels through solid substance by the process of conduction. By conduction heat from the fire heats up the pot and reaches the rice grains at bottom.

Acetic acid upon dissociation in water gives acetate ion and hydrogen ion as written in the chemical equation:

[tex]\rm CH_{3}COOH \rightarrow CH_{3}COO^{-} + H^{+}[/tex].

Acetic acid is weak carboxylic acid. It is the simplest organic acid other than formic acid HCOOH. Acetic acid contains one methyl unit and the carboxyl group COOH.

Diluted acetic acid is used as vinegar to preserve food items such as pickle, salads etc. It gives a sore taste to the food also. Acetic acid is soluble in water and will dissociates into carboxylate ion and hydrogen ion.

Even though acetic acid easily loses a proton the carboxylate ion CH3COO- is not stable and it is a weak base the reverse of the reaction dominates in equilibrium.However in the presence of strong acids it can acts as a weak base also.

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The standard electrode potential of the voltaic cell is 1.25 V.

We know that a cell is composed of the anode and the cathode. Current would always enter in via the abode and then leave via the cathode. In any case, there is a metallic conductor that would always acts as a conduit for the electrons to pass through.

In this case, we can see the the cathode and the anode. The cathode is the part of the cell that gains electrons and is reduced while the anode is the part of the cell that is oxidized and there is a loss of electron there.

Now the cell potential can be obtained from;

standard potential = electrode potential of the cathode- Electrode potential of the anode

The standard potential = (-0.50) - (−1.75)

= 1.25 V

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The time that it would take is 1843 years.

The age of the sample is obtained by the use of the formula;

0.693/[tex]t_{\frac{1}{2} }[/tex] = 2.303/t log (No/N)

Given that;

[tex]t_{\frac{1}{2} }[/tex] = Half life of the C - 14

t = The age of the sample

No = The amount of the sample originally present

N = The amount of the sample present at time t

Given that we are told that 20%  of the sample has decayed thus we have only 80% left

0.693/5730 = 2.303/t log(No/0.8No)

1.21 * 10^-4 =  2.303/t log(1.25)

1.21 * 10^-4 =  0.223/t

t = 0.223/1.21 * 10^-4

t = 1843 years

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The molecular formula is obtained from the empirical formula by multiplying with an integer which is get by dividing the molecular mass by the formula mass. Thus if the integer is 2, then the molecular formula of the compound is C₁₄H₁₀O₄.

The molecular formula of a compound is used to represent the atom present in the compound with their correct number of moles. The empirical formula is derived from the mass percents of the elements in the whole compound.

The integer we get from dividing the molar mass by the formula mass is multiplied with the numbers in the empirical formula to get the molecular formula. Here, the empirical formula is C₇H₅O₂. Thus by multiplying it by 2 we get C₁₄H₁₀O₄.

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It is the simplest whole number ratio of elements in a compound. Molecular formula is n times the empirical formula, where n is integers 1,2,... The molecular formula is C[tex]_{14}[/tex]H[tex]_{10}[/tex]O[tex]_{4}[/tex].

Empirical formula gives the proportion of the element that is present in a compound. It does not give information about the actual number or the arrangements of the atoms.

n= molecular formula÷ empirical formula

Empirical formula =C[tex]_7[/tex]H[tex]_5[/tex]0[tex]_2[/tex]

n=2

Substituting the given values

2= molecular formula÷ C[tex]_7[/tex]H[tex]_5[/tex]0[tex]_2[/tex]

molecular formula=  C[tex]_7[/tex]H[tex]_5[/tex]0[tex]_2[/tex]×2

molecular formula=C[tex]_{14}[/tex]H[tex]_{10}[/tex]O[tex]_{4}[/tex]

Therefore, the molecular formula of the compound C[tex]_7[/tex]H[tex]_5[/tex]0[tex]_2[/tex] is C[tex]_{14}[/tex]H[tex]_{10}[/tex]O[tex]_{4}[/tex].

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We can observe that if a gas has a higher relative molecular mass, it does not cover a large distance hence; "More massive gases do not move a large distance". This can be shown by Graham's law.

Thee term diffusion has to do with the movement of the molecules of the gas from one point to another. We know that the gas in this case was allowed to travel through  a horizontal glass tube at room temperature and pressure.

a) We can see from the data of the gas and the relative distance that the gas travelled that the gases that has the largest relative molecular mass tend to travel  the least distance through the glass tube.

b) The hypothesis that would support the statement is the; "More massive gases do not move a large distance".

c) An experiment that can be used to test this hypothesis i the experiment of Graham's law.

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The new state of equilibrium result from shift to the right with net increases in [H₂]

Here given reaction is

2HI ⇄ H₂ + I₂

Equilibrium is the state in which opposing forces or action are balanced so that one is not stronger or greater than the other and when a new equilibrium is reached there will be more product than before and when concentration of reactant is increased the equilibrium shift to the right and there will be more product than before so here in this reaction the equilibrium result from shift to the right with net increases in [H₂]

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