(4c+3)+(5b+8) simplify this answer

Answer:

A

Step-by-step explanation:

Because That's The Main Idea

To find the dimensions of the rectangle with the greatest possible area inscribed in the parabola y = 2 - x^2, we need to maximize the area function by determining the x-coordinate where the derivative of the area function is zero.

Let's consider a rectangle with its base on the x-axis, which means its height will be given by the y-coordinate of the parabola. The width of the rectangle will be twice the x-coordinate. Therefore, the area of the rectangle is given by A = 2x(2 - x^2).
To maximize the area, we take the derivative of A with respect to x and set it equal to zero to find critical points. Differentiating A, we get dA/dx = 4 - 6x^2.
Setting 4 - 6x^2 = 0 and solving for x, we find x = ±√(2/3).
Since the rectangle is inscribed, we consider the positive value of x. Therefore, the x-coordinate of the upper corner of the rectangle is √(2/3). Plugging this value back into the equation of the parabola, we get y = 2 - (√(2/3))^2 = 2 - 2/3 = 4/3.
Hence, the dimensions of the rectangle with the greatest possible area are a base of length 2√(2/3) on the x-axis and a height of 4/3.

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Kohl's rectangular gold garden has an area of 54 square feet. To determine the dimensions of the garden, we need to find two numbers whose product is 54.

To find the dimensions of the garden, we can factorize the area of 54 square feet. The factors of 54 are 1, 2, 3, 6, 9, 18, 27, and 54. Since the garden is rectangular, we are looking for two numbers whose product is 54.

By examining the factors, we can see that the dimensions of the garden could be 6 feet by 9 feet, as their product is indeed 54. Alternatively, the garden could have dimensions of 3 feet by 18 feet, as their product is also 54. Both sets of dimensions result in an area of 54 square feet.

Therefore, the possible dimensions of Kohl's rectangular gold garden could be either 6 feet by 9 feet or 3 feet by 18 feet.

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Answer:

(f*g)(x) = 3x^2 + 25x - 18

Step-by-step explanation:

(f*g)(x) represents the product of the two functions f and g:

(f*g)(x) = 27x - 18 + 3x^2 - 2x, or, after simplification,

(f*g)(x) = 25x - 18 + 3x^2, or

(f*g)(x) = 3x^2 + 25x - 18

Answer: 10/3 units

Step-by-step explanation: sqrt 100/9= 10/3

Answer:

If two secant segments intersect outside a circle, then the product of the secant segment with its external portion equals the product of the other secant segment with its external portion.

45(45) = (2x + 75)(27)

2,025 = (2x + 75)(27)

2x + 75 = 75, so x = 0 and GH = 48

Answer:

C) 1/2

Step-by-step explanation:

3 of the 6 numbers on a cube are even. 3/6 = 1/2

There is exactly one solution if v3 lies on this line, and no solution otherwise.

Given: vectors v1, v2, v3 in R2

We know that the vectors v1 and v2 are parallel, and we are asked to find the number of solutions of the system xv1 + yv2 = v3. We will argue geometrically.

Let us say that v1 and v2 are not equal to zero and are parallel to the x-axis. We can then write:

v1 = (a, 0)
v2 = (b, 0)

where a and b are nonzero constants. Since v1 and v2 are parallel, their cross-product is zero:

v1 × v2 = a*0 - 0*b = 0

This means that v1 and v2 are linearly dependent. Thus, we can express v2 as a scalar multiple of v1:

v2 = k*v1

where k is a nonzero constant. We can then substitute these expressions into the system and solve for x and y:

xv1 + yv2 = v3
xv1 + y(k*v1) = v3
(x + ky)v1 = v3

Since v1 is nonzero, the equation has a unique solution if and only if (x + ky) is nonzero. But (x + ky) is zero if and only if x = -ky, which is the equation of a line passing through the origin and perpendicular to v1 and v2. Thus, there is exactly one solution if v3 lies on this line, and no solution otherwise.

To see this geometrically, we can sketch the vectors v1, v2, and v3, and the line passing through the origin and perpendicular to v1 and v2. If v3 lies on this line, then there is exactly one solution, which corresponds to the intersection of the line and the vector v3. If v3 does not lie on this line, then there is no solution, since the line does not pass through v3.

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First use the distributive property by multiplying the 3 with each term inside the parentheses:

-8 + 3c + 3 + c

Now combine like terms:

-8 + 3 = -5

3c + c = 4c

Combine for final answer:

-5 + 4c which can also be written as 4c-5

Answer:

first let's multiply 3 by the bracket

-8+3*c+3*1+c=-8+3c+3+c

then add the numbers that have the same variables -8+3+3c+c

=-8+3+4c then add the numbers

=-5+4c is the answer

you can also write it like this

4c-5

Answer:

450m

Step-by-step explanation:

Answer:

i don't know what goes up with three leg and goes down with 4

Answer:

u

Step-by-step explanation:

Answer:

b(-1,-8)

Step-by-step explanation:

assuming x2 and y2 are the coordinates of b.

and x1 and y1 are the coordinates of A

midpoint are (xm, ym)

formula xm= (x1+x2)/2

ym=(y1+y2)/2

The approximate value of y(1) using Euler's method with a step size of h = 0.1 is 1.

Using Euler's method and a step size of h = 0.1, we can use the given initial value problem (IVP) and iterate through the interval [0, 1] in steps of size h to approximate the value of y(1). Let's begin by determining the number of steps required: n = (1-0) / 0.1 = 10.

Utilizing the accompanying recipe, we can repeat through the span beginning with the underlying condition y(0) = 1.

y(i+1) is equivalent to y(i) + h * (t(i) * y(i) + t(i)2), where I is among 0 and n-1, t(i) is equivalent to I * h, and y(i) is the surmised worth of y at t(i).

At each step, we can inexact the upsides of y utilizing the recipe gave:

The approximate value of y(1) is 1, assuming Euler's method and a step size of h = 0.1. y(0) = 1 y(1)  y(0) + 0.1 * (0 * y(0) + 02) = 1 + 0.1 * (0 + 0) = 1.

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Answer:

a

Step-by-step explanation:

Answer:

1. and 2. I belive are true sorry if wrong

Step-by-step explanation:

Answer:

i. <DCB = [tex]53.13^{o}[/tex]

ii. Sin of <DCB = 0.8

Step-by-step explanation:

Let <DCB be represented by θ, so that;

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Thus from the given diagram, we have;

Sin θ = [tex]\frac{4}{5}[/tex]

        = 0.8

This implies that,

θ = [tex]Sin^{-1}[/tex] 0.8

   = 53.1301

θ = [tex]53.13^{o}[/tex]

Therefore, <DCB = [tex]53.13^{o}[/tex].

So that,

Sin of <DCB = Sin [tex]53.13^{o}[/tex]

                    = 0.8

Sin of <DCB = 0.8

Answer:

A. 5+x-12=2x-7

-7+x+2x-7

x=2x

x-2x=0

-x=0-> x=0

B.

when X=-0.5

5+(-0.5)-12=2 (-0.5)-7

-7.5=-8 (answer does not work)

when X=0

5+0-12=2(0)-7

-7=-7 (answer works)

when x=1

5+1-12=2(1)-7

18=-5 (answer does not work)

Step-by-step explanation:

Answer:

[tex]x=0[/tex]

Step-by-step explanation:

A) From this case you would need to narrow down the whole equation...

Like this: [tex]5+x-12=2x-7[/tex]  →  [tex]x-7=2x-7[/tex]  →  [tex]x=0[/tex]

B) To prove that one of these numbers solve the equation, we would have to check it ourselves.

Like this: [tex]5+(-0.5)-12=2(-0.5)-7[/tex]  →  [tex]-7.5=-8[/tex] (SO THIS WON'T WORK)

[tex]5+0-12=2*0-7[/tex]  →  [tex]0=0[/tex] (THIS WORKS!)

[tex]5+1-12=2(1)-7[/tex]  →  [tex]-6=-5[/tex] (NOR DOES THIS WORK)

Therefore: [tex]x=0[/tex] will work to solve the equation correctly

Answer:

Yes it will be appropriate to model the distribution of a sample mean with a normal model

Step-by-step explanation:

Given that the population is not normal, and the sample is sufficiently large, according to the Central Limit theorem, the distribution of the mean pf the sampling distribution will be approximately normal not withstanding the population from which the sample is obtained. Therefore, the mean, [tex]\overline x[/tex], and the standard deviation, [tex]\dfrac{\sigma}{\sqrt{n} }[/tex], of the sample will be equal to the mean, μ, and standard deviation, σ, of the of the population

Therefore, it will be appropriate to model the distribution of a sample mean with a normal model

Answer:

yes

Step-by-step explanation:

i got it right on plato

Given:

The expressions are:

[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}[/tex]

[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}[/tex]

To find:

The simplified form of the given expressions.

Solution:

We have,

[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}[/tex]

It can be written as:

[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{12a^{2+1}bc^3}{40b^4c^2}[/tex]

[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{3a^{3}c^{3-2}}{10b^{4-1}}[/tex]

[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{3a^{3}c^{1}}{10b^3}[/tex]

Therefore, the value of the given expression is [tex]\dfrac{3a^{3}c}{10b^3}[/tex].

We have,

[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}[/tex]

It can be written as:

[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}=\dfrac{(x+y)(x-y)}{4(x+y)}\cdot \dfrac{x+y}{x-y}[/tex]

[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}=\dfrac{x+y}{4}[/tex]

Therefore, the value of the given expression is [tex]\dfrac{x+y}{4}[/tex].

The exponent on the (x - 1) term include the following: A. 3.

In Mathematics, an exponent is a mathematical operation that is commonly used in conjunction with an algebraic equation or expression, in order to raise a given quantity to the power of another.

Mathematically, an exponent can be represented or modeled by this mathematical expression;

bⁿ

Where:

By critically observing the graph of this polynomial function, we can logically deduce that it has a zero of multiplicity 3 at x = 1, a zero of multiplicity 1 at x = 3, and zero of multiplicity 2 at x = 4;

x = 1 ⇒ x - 1 = 0.

(x - 1)³

x = 3 ⇒ x - 3 = 0.

(x - 3)

x = 4 ⇒ x - 4 = 0.

(x - 4)²

Therefore, the required polynomial function is given by;

P(x) = (x - 1)³(x - 3)(x - 4)²

Exponent of (x - 1)³ = 3.

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5. Assuming that t0 = 200 find the value of the marginal tax rate that will yield the same level of equilibrium GDP as the one obtained

(1). Solution: Given, T = t0 + t1Y and T = 300

Substituting the given values, we get300 = 200 + t1YGDP, Y = C + I + G + X - M

where, Y = GDP; C = consumption; I = private investment; G = government spending; X = exports; M = imports

We know, C = c0 + c1 (Y − T) Disposable income, YD = Y − T

So, C = c0 + c1 (Y − T) = c0 + c1YD

From the question, S = 0.5Y − 500

We know that, private saving, S = Y − C − T

So, Y − C − T = 0.5Y − 500 ⇒ 0.5Y = C + T + 500

Putting the values,

0.5Y = (c0 + c1YD) + T + 500 ⇒ 0.5Y = (c0 + c1(Y - T)) + T + 500 ⇒ 0.5Y = c0 + c1Y - c1T + T + 500

Solving the above expression, we get

0.5Y - c1Y = c0 - 0.5T + 500 ⇒ 0.5(1-c1)Y = c0 - 0.5T + 500

Hence, Y = (c0 - 0.5T + 500) / (0.5 - c1)

Again, from the question, Y = C + I + G + X - M

Substituting the values we get,

(c0 + c1(Y − T)) + 400 = I + 400 + Y - 500 + X - X0.5Y − 500 + 400 = I + 300 + X − G ⇒ 0.5Y + I = 1200 + G + X

Assuming equilibrium GDP Y = Y*, private investment I = I*, government spending G = G* and net exports X = X*, so0.5Y* + I* = 1200 + G* + X*

Now, from the given information of S, we have S = Y* − C* − T.

Substituting for C* from the equation above, we get S = Y* − (c0 + c1(Y* − T)) − T ⇒ S = Y* − c0 − c1Y* + c1T − T

Substituting for Y* from above, we have S = ((c0 - 0.5T + 500) / (0.5 - c1)) - c0 - c1[((c0 - 0.5T + 500) / (0.5 - c1))] + c1T - T

Now, we need to find the value of t1 when t0 = 200. For this, we need to substitute the value of t0 and Y* in T = t0 + t1YSo, 300 = 200 + t1Y* ⇒ t1 = (300 - 200) / Y* ⇒ t1 = 0.1

Therefore, the value of the marginal tax rate t1 is 0.1.

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In this hypothesis testing scenario, the null hypothesis (H) states that the mean (μ) weight of a product is equal to 30 grams.

The one-sample t-test is computed using the formula t = (x - μ) / (s / √n), where x is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size. In this case, the calculated t-value is -0.3.

Based on the decision rule, since the calculated t-value of -0.3 falls within the non-critical region (-1.96 to 1.96), we do not reject the null hypothesis.

Therefore, the conclusion is that there is not enough evidence to support the claim that the mean weight of the product is 30 grams. The data does not provide sufficient statistical evidence to conclude that the mean weight significantly differs from 30 grams.

It's important to note that in hypothesis testing, the result does not prove that the null hypothesis is true; rather, it suggests that there is not enough evidence to reject it based on the given data and significance level.

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Answer: The correct answer will be 4

Step-by-step explanation:

Answer:

21 and 6

Step-by-step explanation:

a will be the larger, b the smaller:

a - b = 15

2b + 3a = 75

First, we'll solve the first equation for a in terms of b:

a = b + 15

Then substitute that in for a in the second equation to get a numerical value for b:

2b + 3(b + 15) = 75

2b + 3b + 45 = 75

5b = 30

b = 6

Next, we'll get a numerical value for a:

a - b = 15

a - 6 = 15

a = 21

Check the math:

2(6) + 3(21) = 12 + 63 = 75

Please lmk if you have questions.