[(4•(-2)+(-3)]•(4-2-(-3)

The following ordered pairs are the solutions to 5x+2y=-1 :

(1,-3) and (-3,7)

Given we have the ordered pairs and the equation.

To find out whether the ordered pair is a solution or not, we just need to replace the x and y values from the ordered pair (x,y) and check if both the sides equate.

a. (1,-3)

5x+2y=-1

5(1)+2(-3) = -1

consider L.H.S

5-6

= -1

Therefore, L.H.S = R.H.S

hence the ordered pair (1,-3) is a solution to 5x+2y=-1.

b. (2,8)

5x+2y=-1

5(2)+2(8) = -1

consider L.H.S

10+16

= 16

Therefore, L.H.S ≠ R.H.S

hence the ordered pair (2,8) is not a solution to 5x+2y=-1.

c. (-4,-6)

5x+2y=-1

5(-4)+2(-6) = -1

consider L.H.S

-20-12

= -32

Therefore, L.H.S ≠ R.H.S

hence the ordered pair (-4,-6) is not a solution to 5x+2y=-1.

d. (-3,7)

5x+2y=-1

5(-3)+2(7) = -1

consider L.H.S

-15+14

= -1

Therefore, L.H.S = R.H.S

hence the ordered pair (2,8) is a solution to 5x+2y=-1.

Therefore the ordered pairs which are solutions to 5x+2y=-1 are:

(1,-3) and (-3,7)

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Answer:

Formula for slope is given as (y2-y1)÷(x2-x1) or (y1-y2)÷(x1-x2).

Slope of line = (14-8)÷(7-10)

                     = 6÷(-3)

                     = -2

The slope of the parallel line to line MN -6

From the question, the line is given as

Line MN

Also, we have the slope of line MN to be

Slope of MN = -6

As a general rule in linear functions and parallel lines

The slopes of parallel lines are equal

This means that any line that is parallel to the line MN and the line MN would have the same slope of -6

Hence, the slope of the line segments that are parallel to line MN is -6

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Answer:

=[tex]\frac{78139}{5}[/tex]

Step-by-step explanation:

[tex]-\frac{3}{15}-(-3)+25^{3} \\=\frac{78139}{5}[/tex]

Answer:

slope = 0

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (7, - 6 ) and (x₂, y₂ ) = (6, - 6 )

m = [tex]\frac{-6-(-6)}{6-7}[/tex] = [tex]\frac{-6+6}{-1}[/tex] = [tex]\frac{0}{-1}[/tex] = 0

The relationship will be a solid line.

How many $4 meals you may purchase with a $100 school lunch card and how much money is still on the card.

Given that the slope is common and linear, the connection will be a solid line. The balance on the card will drop by $5 each time you purchase lunch.

Let x be the amount of lunches you purchase.

Let the balance on the card be = y.

Equation then becomes:

y= 105-4x

when x=1

y = 105 - 4(1) = 101

when x= 2

y= 105 - 4(2) = 97

when x=3

y= 105 - 4(3) = 93

We can see that the decline is gradual and same.

On the graph that is provided, you can also observe that a straight line is created.

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Answer:

0.375

Step-by-step explanation:

-3x+14-11+11x

-3x+11x = 8x

14-11 = 3

8x=3

÷8 on both sides

Answer:

$569.80

Step-by-step explanation:

She worked $12.95 per hour for 6 hours of overtime, meaning we would multiply $12.95 by 6 which is equal to $77.70, since she worked for 38 hours that week, we would multiply $12.95 by 38 which is $492.10, so now we add how much she earned for the total. Her overtime pay was $77.70 + her regular pay was $492.10 which adds up to $569.80

Answer:

[tex](1)\;\;\;\text{Slope }= \dfrac{3}{5}\\[/tex]

(2) Equation of line in slope-intercept form is
[tex]y = \dfrac{3}{5}x + 3[/tex]

(3) Equation of line in standard form is:
[tex]5y - 3x = 15[/tex]

Step-by-step explanation:

Equation of a line in slope-intercept form is
y = mx + b

where m = slope and b = y-intercept

Slope = [tex]\dfrac{y2 - y1}{x2-x1}[/tex]

where (x1, y1) and (x2, y2) are two points on the line.

y2 - y1 is known as the rise
x2 - x1 is known as the run
Slope is also defined as rise/run

We are given x-intercept = -5.
The ex-intercept is the point at which the line crosses the x-axis. At this point the y-value = 0.

So we get one of the points (-5, 0)

We are given y-intercept = 3
The y-intercept is the point at which the line crosses the y-axis. At this point the x-value is 0

So another point on the line is (0, 3)

Knowing this we can compute rise and run
rise = y2 - y1 = 3 - 0 = 3

run = x2 - x1 = 0 - (-5) = 0+5 = 5

[tex](1)\;\;\;\text{Slope = $\dfrac{3}{5}$}[/tex]

(2) Equation is
y = mx + b where m = slope and b = y-intercept
Slope = 3/5 from (1) and y-intercept = 3

So equation of line in slope-intercept form is
[tex]y = \dfrac{3}{5}x + 3[/tex]

(3) Equation in standard form
In (2) subtract (3/5)x from both sides.

[tex]y - \dfrac{3}{5}x = 3[/tex]

We can multiply both sides by 5 to get
[tex]5(y - \dfrac{3}{5}x )= 5 \times 3\\\\= 5y - 3x = 15[/tex]

In standard deviation, 120  is the percentile of this class.

Why is there a standard deviation?

Test statistic (z) = (weekly study time - average study time)/standard deviation

weekly study time = 2.3 hours

average study time =  .5 hours

standard deviation = 1.5 hours

z = (2.3 - 0.5)/1.5

   = 1.8/1.5 = 1.2 (to 2 decimal places)

Cumulative area of the test statistic is 1.2

Percentile = 1.2×100 = 120

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A
-------------------------------------------------------

bc it is an integer but not whole numbers

ANSWER

x - 6

EXPLANATION

We want to write an algebraic expression that matches the statement:

Six less than a number.

First, let that unknown number be x.

So, 6 less than x.

Since it means that we are taking 6 from x, we subtract 6 from x.

That will be:

x - 6

Answer: D (last bubble)

Step-by-step explanation:

slope of f is 2/3

inverse of 2/3 is 3/2

that is graph h

these graphs are symmetrical around the line y = x

Answer:

2nd one

Step-by-step explanation:

Hope I helped!

The time taken by the ball to reach the ground is 0.067 seconds

Given,

The initial velocity of the ball (speed) = 35 feet/second

The height of the ball (distance), h = -16t² + 35t + 6

We have to find the time, (t in seconds) taken by the ball to reach the ground.

Speed = distance/time

So, Time = distance/speed

Here,

Time = (-16t² + 35t + 6) / 35

We have to solve the equation first.

-16t² + 35t + 6 = 0 is in quadratic form. So, we can solve this by using quadratic formula.

Quadratic formula = [tex]\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}[/tex]

Here,

a = -16, b = 35, c = 6

Now,

[tex]\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}[/tex]

= [tex]\frac{-35(+-)\sqrt{35^{2}-4(-16)(6) } }{2(-16)}[/tex]

= [tex]\frac{-35(+-)\sqrt{1225 +384} }{-32}[/tex]

= (-35±√1609) / -32

= (-35±40.11) / -32

Now,

Solve for:

(-35 + 40.11) / -32 = 5.11/-32 = -0.15

Solve for

(-35 - 40.11) / -32 = -75.11 / -32 = 2.35

Lets take the height as 2.35 feet.

Now,

Time = distance/speed

Time = 2.35/35 = 0.067

Therefore, the time taken by the ball to reach the ground is 0.067 seconds.

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Answer: c=1

Step-by-step explanation:

Move the variable to the left side

2c+8−10c=0

Subtract the terms

−8c+8=0

Move the constant to the right side

−8c=0−8

Subtract the terms

−8c=−8

Divide both sides

−8c  = −8

−8       -8

Simplify

Answer:

540

Step-by-step explanation:

Answer:

0.325 as a fraction is expressed as 13/40

Step-by-step explanation:

What is a fraction ?

A fraction is a portion of any quantity out of a whole. It consists of a numerator and a denominator.

To convert a decimal number into a fraction, we write the given number as the numerator and place 1 in the denominator right below the decimal point followed by the number of zeros required accordingly. Then, this fraction can be simplified.

In this case, 0.325 has three numbers after the decimal, so, we place 1000 in the denominator and remove the decimal point.

⇒ 325/1000

After reducing this fraction we get,

⇒ (325 ÷ 25) / (1000 ÷ 25) = 13/40

So, 0.325 as a fraction is 13/40.

(Hi fyi this answer took a lot of time & effort to make sure it was accurate, precise and to the point to be produced, so if you could opt this answer as the brainliest it would mean the world to me,)

Stay positive and Take care,

A fellow mate,

Cheers !

Answer:

Thr equation is y=x-1

Step-by-step explanation:

The y intercept is negative 1 so that eliminates options 1 and 3 and the slope goes up which leaves only option 2 left

Answer:its 2

Step-by-step explanation:

Soyala travelled for 3 hours with a speed of 25 mph and 5 hours with a speed of 15 mph

We know that Distance = Rate x Time. The distance traveled to the library is assumed to be same as the distance traveled on the way to home from the library. Let t be the time it took to travel to the library after which (8 - t) = the time it took to travel back home. We can write following two equations using the formula for distance:

d = 25t ---------> (1)

d = 15(8 - t) = 120 - 15t -----------> (2)

Since the distance d is equal for both trips, let's set the two expressions of time t equal to each other.

25t = 120 - 15t

40t = 120

t = 3 hours

Therefore, Soyala travelled for 3 hours at 25 mph and for 8 - 3 = 5 hours at 15 mph. Each rate will yield a distance traveled of 125 miles.

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Answer:

Step-by-step explanation:

Equations:

Recall the identities:

Now find a and b, then find their product.

Coplanar lines are referred to as parallel lines because they may be extended indefinitely without ever intersecting. || is the sign meaning "parallel to." If two lines are drawn, they don't have to be parallel, and a third line runs across them as seen in the diagram below. We may obtain eight distinct angles by drawing two parallel lines, and then drawing a transverse line through them.

Four pairs of matching angles will be created from all eight angles. One of the pairings is represented by angles F and B in the preceding diagram. If the two lines are parallel, corresponding angles are congruent.

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First you need to ubicate those vertices in a plane as follow:

Then you link the vertices with lines to form the triangle:

Knowing that a right triangle must have one angle of 90º

The answer is that yes, it is a right triangle because it has an angle of 90º in the vertice H(8,5)

The postulate that could be used is the: linear pair postulate.

If two angles share a common side and also a common vertex lie on a straight line, they both form a special angle relationship that is called the linear pair.

Based on the linear pair postulate, it is proven that angles that form a linear pair add up to 180 degrees and are therefore regarded as supplementary.

Angle CAD and angle CAB have a common side, side CA, and a common vertex, angle A. They are also on the straight line, line AB.

Thus, it can be proved that the angles CAB and CAD are supplementary based on the linear pair postulate.

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Answer:

1 7/8 inches is 1.875 in decimal form.

Answer:  The difference in temperature is 45.9F.