37:28
Chin canned a number of quart jars and a number of pint jars of tomatoes from his garden. A pint is 16 ounces and
a quart is 32 ounces. The number of pints he canned is represented by p, and the number of quarts he canned is
represented by q. Which equation models the scenario if Chin canned a total of 1,280 ounces?
1,280+16p=32q
1,280+32q=16p
32q-16p=1,280
16p+32q = 1,280

Answers

Answer 1

The equation that models the scenario is 16p+32q = 1,280.

Which equation models the scenario?

Addition is the mathematical operation that is used to determine the sum of two or more numbers.

The equation that would model the scenario can be determined by adding the total pints and total quarts Chin has :

Total pint + total quart = total ounces

16p+32q = 1,280.

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Related Questions

Helppppppppppppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


what is 100+24/4*12?????????????? due is 5 minutes plsssssssssssssss

Answers

Answer:

172

Step-by-step explanation:

100 + 24 ÷ 4 × 12

Remember PEMDAS

100 + 6 × 12

100 + 72

172

Hope this helps!

Odette made this jewelry box by combining two rectangular boxes.

What is the total surface area of this jewelry box?

PLS HURRY WILL GIVE BRAINLIEST

Answers

382in^2

Adding the sides up we get, 36+36+72+24+24+24+32+48+48+48

a tractor driver plowed 1/5 of a field on the first day, and 1/4 on the second day. How much did he plow in the first two days? How much does he still need to plaw?

Answers

Answer:

1) (9/20)x  2) (11/20)x

Step-by-step explanation:

x = total area of the field.

In the first two days he plowed (1/5)x + (1/4)x = (9/20)x

He still needs to plow x - (9/20)x = (11/20)x

(Refer to the attached image)​

Answers

Explanation:

Provided 2 length sides and one angle also need to find one missing side.

So, use cosine rule:

a² = b² + c² - 2bc cos(A)

Part 1

c² = 9² + 11² - 2(11)(9) cos(57)

c² = 94.16147

c = √94.16147 = 9.70 cm

Part 2

d² = 5² + 7² - 2(5)(7) cos(48)

d² = 27.16

d = √27.16 = 5.21

Part 3

5² = 7² + 9² - 2(7)(9) cos(H)

-126cos(H) = 25 - 49 - 81

cos(H) = -105/-126

cos(H) = 5/6

H = cos⁻¹(5/6) = 33.56°

Part 4

8² = 4² + 7² - 2(4)(7) cos(J)

-56cos(J) = 64 - 16 - 49

cos(J) = -1/-56

J = cos⁻¹(1/56) = 88.98°

Passcode: 3142

Think about the function f(x) = 3 - 2x.

What does the notation f(0) mean?

Answers

in order to find this you have to replace any x with zero therefore we will have
3 - (2*0) => 3-0 = 3
so the answer is 3

Answer:

the answer is 3

Find and label the measures of each of the three missing angles, A, B and C, below.
Lines I and M are parallel.

Answers

Hello, the detailed solution is given below.

Lines L and M are parallel. That's why [tex]B[/tex] angle and [tex]50^{o}[/tex] are equal.

What's the Co-Interior Rule? (Known as U Rule)

Co-interior angles lie between two lines and on the same side of a transversal. If the two lines are parallel, then co-interior angles add to give [tex]180^{o}[/tex] and so are supplementary.

After that, [tex]C[/tex] angle found as [tex]85^o[/tex].

As [tex]A[/tex] angle and [tex]C[/tex] angle must be equal due to the parallel, the missing angles as;

[tex]A=85\\B=50\\C=85[/tex]

Good luck! If you have any questions, then feel free to ask in comments!

00B0J0DD:
TIME REMAINING
57:39
The head of the math department compared the scores of students in two classes on the Chapter 2 test. He found that
the mean score of both classes was the same. He also found that there was greater variability in the scores of Ms.
Biren's students than in the scores of Mr. Hayes's students. Which quality of the data sets would lead the department*
head to that conclusion?
The median score i Ms. Biren's class is greater than the median score in Mr. Hayes's class.
The
median score in Ms. Biren's class is less than the median score in Mr. Hayes's class.
The range of scores in Ms. Biren's class is greater than the range of scores in Mr. Hayes's class.
The range of scores in Ms. Biren's class is
less than the range of scores in Mr. Hayes's class. The median score

Answers

Answer: B.

Explanation and reasoning:

A father is 30 years older than his son.Three years ago he was 3 times as old as his son.How old are both of them ​

Answers

Answer:

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Question

A father is 30years older than his son. In 12years, the man will be three times as old as his son. Find their present ages.

Medium

Open in App

Solution

Verified by Toppr

Let the present age of the son be x years

Then father's age will be (x+30) years

Given after 12 years father will be three times as old as his son

Therefore,

(x+12)3=x+30+12

3x+36=x+42

3x−x=42−36

2x=6

x=3

x+30=3+30=33

So, the present age of son is 3 years and present age of the father is 33 years

(Computer science)

The CPU fan rotation rate (R) was directly proportional to the ambient temperature (T). At a temperature of 25 degrees C, the CPU fan was rotating at 1150rpm. What would the rotation rate be for an ambient temperature of 30 degrees C?

Answers

Answer:1380

Step-by-step explanation: proportionality constant equals 1150/25=46. 46x30=1380

Which graph can be used to find the solution(s) to x2 – 4x + 4 = 2x + 1 + x2?

Answers

The solution to the equation x² – 4x + 4 = 2x + 1 + x² is x = 2.5 and the graph is shown in the picture.

What is a function?

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have an equation:

x² – 4x + 4 = 2x + 1 + x²

After solving:

-4x + 4 = 2x + 1

6x = 3

x = 1/2 = 0.5

Thus, the solution to the equation x² – 4x + 4 = 2x + 1 + x² is x = 2.5 and the graph is shown in the picture.

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which is the greatest 30000 millimeters 1 kilometer 5000 meters or 6000 centimeters?

Answers

5000 meters because it is equal to 5 kilometers which is greater than every other option
1 kilometer = 1 kilometer, 30000 millimeters = .03 kilometers, 5000 meters = 5 kilometers, 6000 centimeters = .06 kilometers. Hope this helps!

I don’t know how to do this please help

Answers

Answer:

  84 cm²

Step-by-step explanation:

The figure has a uniform horizontal cross section, so its area is the product of that cross section length and its vertical dimension.

__

  A = bh

  A = (6 cm)(14 cm) = 84 cm²

The area of the shape is 84 square centimeters.

_____

Additional comment

You could decompose the figure into a rectangle with base 6 and height 8, and a parallelogram with base 6 and height 14-8=6. The area formula is the same for each: A = bh, so the area of the composite figure is ...

  A = 6×8 +6×(14 -8)

  = 6×(8 +(14 -8))

  = 6×14 . . . . same as above.

HELP ME PLEASE I WILL MARK BRAINLIEST

Answers

Answer:

A) -4, -2

Step-by-step explanation:

The translation vector is the distance

point A: (3, 1)

point A': (-7, -3)

3 + (-7) = -4

1 + (-3) = -2

Find Measure of angle B (m
18. a = 7 m, b = 5 m, m∠A = 45°

Answers

The value of the variable a is 19.66 and the value of the valriable b is 20.21.

What is the law of sines?

For any triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c,

we have, by the law of sines,

[tex]\rm \dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b} = \dfrac{sin\angle C}{c}[/tex]

Remember that we took

The sine angle is the length of the side opposite to that angle.

Then the third angle of the triangle will be

x + 75 + 35 = 180

                x = 70

[tex]\rm \dfrac{\sin 75^o}{b} = \dfrac{\sin 35^o}{12} = \dfrac{\sin 70^o}{a}[/tex]

From the first two-term, we have

sin 75 / b = sin 35 / 12

b = 20.21

From the last two-term, we have

sin 70 / a = sin 35 / 12

a = 19.66

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In a diving contest five judges score each dive. the highest and lowest scores are discarded and then the arithmetic average of the remaining scores is taken as the diver's score. if the five judges score a dive as 6.0, 6.3, 6.2, 6.8, and 6.1, then the diver's score is?


Answers

Using the given information, the diver's score is 6.2

Calculating average score

From the question, we are to calculate the diver's score

From the given information,

The five judges score a dive as 6.0, 6.3, 6.2, 6.8, and 6.1.

Since the highest and lowest scores are discarded

Then, we will discard 6.8 and 6.0

The remaining scores are 6.1, 6.2, and 6.3

Now, the diver's score will be the average of the remaining scores

∴ The diver's score = (6.1 + 6.2 + 6.3) /3

The  diver's score = 18.6 / 3

The diver's score = 6.2

Hence, the diver's score is 6.2

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given m
m FS =




pls help me this is due tomorrow

Answers

Answer:

arc FS = 84°

Step-by-step explanation:

the inscribed angle QRF is half the measure of its intercepted arc QF , then

arc QF = 2 × 48° = 96°

the sum of the arcs on a semicircle = 180° , that is

QF + FS = 180°

96° + FS = 180° ( subtract 96° from both sides )

FS = 84°

Write the equation of the trigonometric graph.

Answers

Answer:

[tex]f(x)= \sin(6x)+3[/tex]

Step-by-step explanation:

The parent function of this graph is:  y = sin(x)

The sine function is periodic, meaning it repeats forever.

Standard form of a sine function:

[tex]f(x) = \sf A \sin (B(x + C)) + D[/tex]

A = amplitude (height from the mid-line to the peak)2π/B = period (horizontal distance between consecutive peaks)C = phase shift (horizontal shift - positive is to the left)D = vertical shift

The parent function y = sin(x) has the following:

Amplitude (A) = 1Period = 2πPhase shift (C) = 0Vertical shift (D) = 0Mid-line:  y = 0

From inspection of the given graph:

Amplitude (A) = 1[tex]\sf Period=\dfrac{\pi}{12}-\dfrac{-\pi}{4}=\dfrac{\pi}{3}[/tex]Phase shift (C) = 0Vertical shift (D) = +3  (as mid-line is y = 3)

[tex]\sf If\:Period=\dfrac{\pi}{3} \implies \dfrac{2 \pi}{B}=\dfrac{\pi}{3}\implies B=6[/tex]

Substituting the values into the standard form:

[tex]\implies f(x) =1 \sin (6(x + 0)) + 3[/tex]

[tex]\implies f(x) = \sin (6x) + 3[/tex]

Therefore, the equation of the given trigonometric graph is:

[tex]f(x)= \sin(6x)+3[/tex]

Answer(s):

[tex]\displaystyle y = cos\:(6x - \frac{\pi}{2}) + 3 \\ y = -sin\:(6x \pm \pi) + 3 \\ y = sin\:6x + 3[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{12}} \hookrightarrow \frac{\frac{\pi}{2}}{6} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{3}} \hookrightarrow \frac{2}{6}\pi \\ Amplitude \hookrightarrow 1[/tex]

OR

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{3}} \hookrightarrow \frac{2}{6}\pi \\ Amplitude \hookrightarrow 1[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cos\:6x + 3,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{12}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{12}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{12}} = \frac{\frac{\pi}{2}}{6}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = cos\:(6x - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-\frac{5}{12}\pi, 2],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{12}, 2],[/tex]they are obviously [tex]\displaystyle \frac{\pi}{3}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{3}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

An exponential function contains the points (1, 0.9) and
(2, 1.62). What is an exponential function that contains
these points?

Answers

Answer:

Hi,

Step-by-step explanation:

Let's say y=a*b^x the equation of the exponential function.

0.9=a*b^1 (1)

1.62=a*b² (2)

(2)/(1) ==> b=1.62/0.9=1.8

and

0.9=a*1.8 ==> a=0.5

y=0.5*1.8^x

Mrs. Rykus does a survey of her 85 students.
​20 say math is awesome
​35 say math is the best
​30 say math is fun

​Based on these results, if Mrs. Rykus asks the whole student population 900 students what they think of math, what is the best approximation for how many students will say math is awesome?
A 400
B 212
C 200
D 315

Answers

Answer:

212

Step-by-step explanation:

85 here is 100%

And 900 is also 100%

That's for the different comparisons. So now, what we do is, we should divide 85 by 900, and then, whatever is our answer, multiply that by 20.

That is surely going to equal how many students are going to say that Math is Awesome for 900 student survey.

Step 1

85/900=10.5882352941

Let's round that to make it

10.5

Step 2

10.5x20=210

That means, if we go exactly, like multiplying all of those numbers, then our answer should be 212 or 200.

Just to be sure that our answer is correct, we will do it with 10.58 now.

Step 3

10.58x20=211.6

So now it looks like it's most probably going to be 212

But still, let's do 10.588 now.

Step 4

10.588x20=211.76

Okay, let's do it again, with 10.5882

Step 5

10.5882x20=211.764

Okay, so I just multiplied the whole number this time, and I still got a decimal, so that means that your answer is 212 basically.

what is 2x-45y=22 when y=21

Answers

answer:

483.5

step by step explanation:

2x-45y=22

2x-45(21)=22

2x-945=22

2x =22+945

2x=967

x=483.5

Volume of pyramids cones and spheres

Answers

Answer:

48 cm³

Step-by-step explanation:

Volume = (1/3) * base_area * height

1/3 * 4 * 4 * 9 =

48 cm³

A basket contains six apples, three oranges, ten corn, four pears and six peaches, You randomly select a fruit. What is the conditional probability of selecting a fruit that it is a orange?

Select one:

a.
15.8%


b.
15%


c.
17.5%


d.
10.3%

Answers

Answer:

b. 15%

Step-by-step explanation:

because it is 3 oranges and 3 is equal to 15%

Northlake High School has two lunch periods. Students can eat their lunch in
the cafeteria or on an outside patio. About 35% of students who have first
lunch eat outside. Compare this with the percentage of second-lunch
students who eat outside.

Answers

Answer:

Based on the data given on Northlake High School, we can infer that B. A greater percentage of second-lunch students (39%) eat outside.

What does the data on the First and Second lunches show?

The percentage of second-lunch students who eat outside is:

= Second lunch students who eat outside / Second lunch students

Solving gives:

= 0.18 / 0.46 x 100%

= 0.3913 x 100%

= 39%

This shows that the percentage of students eating their second lunch outside is 39%.

so the answer is B

Step-by-step explanation:

solve for K
7K-6
2K+14

Answers

Answer:

[tex]k=4[/tex]

Step-by-step explanation:

Using the diagram, we can conclude that the given angles are vertical angles. Vertical angles are opposite angles that are formed when two lines intersect. Vertical angles are always congruent.

Using this information we can set up an equation.

[tex]7k-6=2k+14[/tex]

Subtract 2k from both sides.

[tex]7k-2k-6=2k-2k+14\\5k-6=14[/tex]

Add 6 to both sides

[tex]5k-6+6=14+6\\5k=20[/tex]

Divide both sides by 5

[tex]\frac{5k}{5}=\frac{20}{5}\\k=4[/tex]

CHECK:

7(4) - 6 = 28 - 6 = 22

2(4) + 14 = 8 + 14 = 22

22 = 22

Please help me

Find the value of x

Answers

Answer:

x = 5 and y = 22

Step-by-step explanation:

See attached image.

This line plot shows the estimated amount of glue needed for summer projects at a camp. eric chose to complete a project with the greatest estimated amount of glue needed. the actual amount of glue he used was 3/4 of the estimated amount. how much glue did eric use for his project? enter your answer in the box as a mixed number in simplest form.

Answers

The amount of glue that eric used for his project is [tex]\mathbf{ 1\dfrac{11}{16}}[/tex]

How to interpret the line plot?

The interpretation of the line plot involves a careful approach to how a series of data points are connected on coordinate planes.

From the Glue for summer project line plot:

The greatest estimated amount of glue needed can be seen at = 2 (1/4)The actual amount of glue needed = 3/4 of 2 (1/4)

The amount of glue Eric used for the project is;

[tex]\mathbf{=\dfrac{3}{4}\times 2\dfrac{1}{4}}[/tex]

[tex]\mathbf{=\dfrac{3}{4}\times \dfrac{9}{4}}[/tex]

[tex]\mathbf{=\dfrac{27}{16}}[/tex]

[tex]\mathbf{= 1\dfrac{11}{16}}[/tex]

Therefore, we can conclude that the amount of glue used by Eric for this project is: [tex]\mathbf{ 1\dfrac{11}{16}}[/tex]

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Which of the following could be the equation of a line perpendicular to the line 2x−5y=7?

Answers

Answer:

B.

Step-by-step explanation:

First convert the equation to slope-intercept form:

2x - 5y = 7

-5y = -2x + 7

y = 2/5 x - 7/5

So the slope of the given line  is 2/5.

So the slope of a perpendicular line will be -1/ 2/5 = -5/2.

Take B:

5x + 2y = 3

2y = -5x + 3

y = -5/2.

So its B.

Jessie invests $33 in the stock market. Over the 3 years she has this invested she gets an average return of 7,8%. How much will her investment be worth after the 3 years?

Answers

Answer:

it would end up being about $40.73

Step-by-step explanation:

multiply 0.078 by 3 then multiply that by 33

Answer:

hope you can understand

What is the measure of angleq to the nearest whole degree? 43° 49° 53° 58°

Answers

Based on the calculations, the measure of angle Q to the nearest whole degree is equal to 53°. The correct answer is option C.

The complete question is attached with the answer below.

How to calculate the measure of angle Q?

The angle is defined as the span between two intersecting lines or surfaces at or close to the point where they meet.

Based on the triangle attached in the image above, we can deduce the following parameters:

Side QM = 18 units.

Side MN = 17 units.

Side QN = 20 units.

In this scenario, we would apply the cosine trigonometry function to determine the measure of angle Q:

MN² = QM² + QN² - 2(QM)(QN)cosθ

17² = 18² + 20² - 2(18)(20)cosθ

289 = 324 + 400 - 720cosθ

720cosθ = 724 - 289

720cosθ = 435

θ = cos⁻¹(435/720)

θ = cos⁻¹0.6042

θ = 52.8 ≈ 53°.

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Based on the data in this two-way table, which statement is true?

Type of Flower/Color Red Pink Yellow Total
Rose 40 20 45 105
Hibiscus 80 40 90 210
Total 120 60 135 315
A.
A flower being pink and a flower being a rose are independent of each other.
B.
A flower being pink is dependent on a flower being a rose.
C.
A flower being a rose is dependent on a flower being pink.
D.
A flower being pink and a flower being a rose are the same.

Answers

A.A flower being pink and a flower being rose are independent of other.
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