3.65 is greater than or less than 3and1/5​

Answers

Answer 1
3.65 is greater than 3 1/5 since if you put 1/5 in decimals, it would be 3.20.
Answer 2

Answer:

Greater

Step-by-step explanation:

It is greater because 3 & 1/5 is technically 3.20 which obviously results with 3.65 being greater than 3.2. Also if you go into detail with it 3.65 is kinda 3 & 3/5. Thanks. Let me know if you find any fault in my answer. Have a good day!


Related Questions

giving brainliest!! easy*

Answers

Answer:

1584mm^2

Step-by-step explanation:

20 x20 = 400 and there are 3 of them

400+400+400 = 1200

1/2(16x24 ) =192 and there are 2 of them

192+192 = 384

1200+384

Answer:

1408

Step-by-step explanation:

20·16+24·16+20·16+12·﹣204+2·(20·24)2+2·(20·20)2﹣244+2·(24·20)2﹣204=1408

if i did something wrong please let me know

(i might have done it wrong, please use the answer above which would be 1584mm^2)

ANSWER !!
ILL GIVE 40 POINTS !!
DONT SKIP :((
PLUS BRAINLIEST !

Answers

Answer:

24 square kilometers

Step-by-step explanation:

Well, this is a trapezoid. The formula for the area of a trapezoid is 1/2 the height times base one plus base two. In other words, 1/2 h x (base 1 + base 2)

So in this case, the two bases are 4 and 12. So we would add the two bases to get 16. Now, we have to half the height. 3 divided by 1/2 is 1.5. So we then do the last step which is multiplying the height by the two bases. So in other words, 1.5 times 16. And 1.5 times 16 is 24. Therefore, the answer is 24 sqaure kilometers.

Answer:

Step-by-step explanation:

John used AABC to write a proof of the Centroid Theorem. He began by drawing medians AK and CL,

intersecting at Z. Next he drew midsegments LM and NP, both parallel to median AK.

Given: AABC with medians AK and CL, and midsegments LM and NP.

2

Prove: Z is located of the distance from each vertex of AABC to the midpoint of the opposite side.

3

Answers

Answer:

Hello your question is poorly written attached below is the complete question

answer :  attached below

Step-by-step explanation:

To Prove: Z is located 2/3 of the distance from each vertex of ΔABC to the midpoint of the opposite side. we will apply ; property of bisecting a line , equality theorem , transitive property and similarity theorem

Attached below is the proof

85.82 rounded to the hundredths place

Answers

Answer:

85.80

Step-by-step explanation:

85.82 is closet to 85.80 snice 2 is a low number

7 1/3 ÷ 4
Please help

Answers

Answer:

1.833333333

Step-by-step explanation:

7⅓ ÷ 4

=¹¹/6

= 1.833333333

The radius of a circle is 16 cm. Find its area in terms of \piπ

Answers

Answer256pi

Step-by-step explanation:

Area=pi*r^2

=pi*16^2

256pi

What is the standard form of an equation with p = 3/2 and phi=300 degrees?
A. x-sqrt3y-3=0
B. sqrt3x-y-3=0
C. x+sqrt3y-3-0
D. sqrt3x + y + 3=0

Answers

The standard form of an equation with p = 3/2 and phi=300 degrees is; x(√3) + y - 3 = 0

What is the Standard form of the equation?

The standard form of this type pf equation has the general format as;

x(cos Ф) + y(sin Ф) = p

where;

p is perpendicular distance from origin

Ф is the angle between perpendicular and the positive x-axis.

Now, we are given;

p = 3/2

Ф = 30°

Thus, the equation of these given values will be expressed as;

x(cos 30) + y(sin 30) = 3/2

We know, that;

cos 30 = (√3)/2

sin 30 = 1/2

Thus, we have;

x((√3)/2) + y(1/2) = 3/2

Multiply through by 2 to get;

x(√3) + y = 3

⇒ x(√3) + y - 3 = 0

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A roadside assistance company gets millions of requests per year, with about a quarter of the requests in
summer and a quarter in winter. Suppose that 12% of all of the summer requests and 15% of the winter
requests are for help with a lockout. A data analyst pulls separate random samples of 200 summer and winter
requests and will look at the difference (summer winter) between the proportion of requests for help with
a lockout in each sample.
What are the mean and standard deviation of the sampling distribution of the difference in sample
proportions?

Answers

Answer: -0.03

sqrt ((0.12 (0.88) / 200) + (0.15)(0.85)/200)

Step-by-step explanation:

The mean of the sampling distribution of the difference in sample proportions is -0.03, and the standard deviation is 0.0321.

What is the standard deviation?

A standard deviation (σ) is a measure of the distribution of the data in reference to the mean.

The proportion of lockout help requests in the summer population is 12% or 0.12, and the proportion in the winter population is 15% or 0.15. The sample sizes are both 200.

Using these values, we can calculate the mean and standard deviation of the sampling distribution of the difference in sample proportions:

Mean = p₁ - p₂ = 0.12 - 0.15 = -0.03

Standard deviation = √[ (p₁ (1 - p₁) / n₁) + (p₂ (1 - p₂) / n₂) ]

= √[ (0.12 (1 - 0.12) / 200) + (0.15 (1 - 0.15) / 200) ]

= √[ (0.000504) + (0.000525) ]

= √[ 0.001029 ]

= 0.0321

Therefore, the mean of the sampling distribution of the difference in sample proportions is -0.03, and the standard deviation is 0.0321.

Learn more about the standard deviation here:

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I need someone to write me a narrative on how to solve this problem please!

Answers

DONT TRUST LINKS PEOPLE GIVE YOU!! It is used to steal personal information.

3x+5y=30 complete the table of values​

Answers

Answer:

O

Step-by-step explanation:

A rectangle with a width of 2.5 cm and a length of 3 cm is dilated by a scale factor of 4. Which statements about the new rectangle are true? Check all that apply.
The dimensions of the new rectangle will be 10 cm by 12 cm.
The dimensions of the new rectangle will be 40 cm by 48 cm.
The new perimeter will be 4 times the original perimeter.
The new perimeter will be 16 times the original perimeter.
The new area will be 4 times the original area.
The new area will be 16 times the original area.
The new perimeter will be 44 cm.
The new area will be 30 square cm

Answers

The statements about the new rectangle are true are:

The dimensions of the new rectangle will be 10 cm by 12 cm.

The new area will be 16 times the original area.

Here, we have,

given that,

A rectangle with a width of 2.5 cm and a length of 3 cm is dilated by a scale factor of 4.

area = 7.5 cm^2

now, we get,

the new  dimensions of the new rectangle will be:

width = 4 * 2.5 cm = 10cm

length = 4* 3 cm = 12cm

so, area = 120 cm^2

so, we get,

statements about the new rectangle are true are:

The dimensions of the new rectangle will be 10 cm by 12 cm.

The new area will be 16 times the original area.

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4(x + 1) + 8 = 24
how do i solve this

Answers

Answer: x = 3

First, you can multiply the 4 with the x and the 1:

4x + 4 + 8 = 24

Now, you just add the 4 and the 8 together:

4x + 12 = 24

Subtract 12 from both sides:

4x = 12

Now you divide by 4 from both sides

x = 3

^ and that's your final answer!

Answer:

x=3

Step-by-step explanation:

4x+4+8=24

4x+12=24

4x=12

4x/4=12/4

(x=3)

Vincent began his weekly chores on Saturday morning at 11:20 he worked for 1 hour and 15 minutes with a 10 minute break at what time did Vincent finish his chores

Answers

Answer:

12:45

Step-by-step explanation:

Step One: An hour after 11:20 is 12:20, plus 15 minutes is 12: 35.

Step Two: Just add 10 minutes, because it doesn't matter when you add the ten minutes.

Need the answer to x and y !

Answers

Answer:

x=5, y=3

Step-by-step explanation:

7x-11=24: 7x=35: x=5

3(5)+9=8x: 24=8x: x=3

How high is the end of the ladder against a building

Answers

Is there a picture or no?

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

697.5 ft squared

Step-by-step explanation:

Divide into top two squares and rectangle on bottom so...

(10×7.5)+(8×7.5)×(12.5×45)=area

75+60+562.5=697.5 ft squared

697.5! Should be correct the one above me explains perfectly!❤️

Point M is on line segment LN. Given LN=4x, MN= x, and LM=3, determine the numerical length of LN.

Answers

Answer:

LN = 4 units

Step-by-step explanation:

Since M is on LN , then

LN = LM + MN , that is

4x = 3 + x ( subtract x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Then

LN = 3 + x = 3 + 1 = 4

The required length of the line LN = 4.

Given that,
Point M is on the line segment LN. Given LN=4x, MN= x, and LM=3,  to determine the numerical length of LN.

What is a line?

The line is a curve showing the shortest distance between 2 points.

LN = LM + MN
4x = 3 + x
4x - x = 3
3x = 3
x = 3 / 3
x = 1

Length of LN
LN = 4x
     = 4 * (1)
     = 4

Thus the required length of the line LN = 4.

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Josiah earns $8.00 per hour at his job.

Write and solve an inequality that represents how many hours it will take him to earn at least $120.

Answers

Answer:

15 hours

so, 8 x y = 120

Step-by-step explanation:

[tex]8\sqrt{120} =[/tex] 15

the difference between the squares of two numbers is 32. twice the square of the first number increased by the square of the second number is 76. find the numbers.​

Answers

Answer:

The numbers are 6 and 2

6 squared = 36

2 squared = 4

So 36-4 = 32

And 36 x 2 = 72 + 4 = 76

Which sign makes this number sentence true?

|866| __ |-866|
A. >
B. <
C. =
D. +

Answers

Answer:

>

Step-by-step explanation:

Answer:

c for me

Step-by-step explanation:

hope that helps you

Which is greater 3/5 or 7/10

Answers

Answer:

7/10

Step-by-step explanation:

Use the butterfly method:

3/5 7/10

multiply the denominator and numerator to each other sides:

3 * 10 = 30

5 * 7 = 35

35 > 30

35 belongs to 7/10 so:

7/10 is greater

Help please question in the picture

Answers

Answer:

17.5

Step-by-step explanation:

The area of a triangle is (height*base)divided by two

(the eight is really unnecessary)

so 7=base

8=height

7*5=35

35/2=17.5

Is the following relation a function? *
{(-3, 2), (1, 8), (-1, 5), (3, 11)}
Yes
No
Why or why not?

Answers

Answer:

No.

Step-by-step explanation:

Well at first glance it might seem so but there are two points particularly that can tell you that these points cannot be within a function.

The points (3,2) and (3,-2) will yield an undefined slope (a straight vertical line). There is no possibility that the other points can be in this line (as their y - values are different) and there is no possibilty that this is a function at all according to the vertical line test (the test is that if you draw a vertical line that there shouldn't be more than one point on it).

surface area of a pyramid
WILL GIVE BRAINLIEST TO FIRST TO ANSWER CORRECTLY
Find the surface area of the pyramid. Round to the nearest tenth if necessary.
12.25 in.
15.75 in.
15.75 in.
in^2 = ?

Answers

Answer:

633.9 in.²

Step-by-step explanation:

Surface Area = Base Area + ½(Perimeter of Base)(slant height)

Base area = s² = 15.75² = 248.0625 in.²

Perimeter = 4(15.75) = 63 in.

Slant height = 12.25 in.

Surface area = 248.0625 + ½(63)(12.25)

= 633.9375 ≈ 633.9 in.² (nearest tenth)

Local versus absolute extrema. If you recall from single-variable calculus (calculus I), if a function has only one critical point, and that critical point is a local maximum (or say local minimum), then that critical point is the global/absolute maximum (or say global/absolute minnimum). This fails spectacularly in higher dimensions (and thereís a famous example of a mistake in a mathematical physics paper because this fact was not properly appreciated.) You will compute a simple example in this problem. Let f(x; y) = e 3x + y 3 3yex . (a) Find all critical points for this function; in so doing you will see there is only one. (b) Verify this critical point is a local minimum. (c) Show this is not the absolute minimum by Önding values of f(x; y) that are lower than the value at this critical point. We suggest looking at values f(0; y) for suitably chosen y

Answers

Answer:

Step-by-step explanation:

Given that:

a)

[tex]f(x,y) = e^{3x} + y^3 - 3ye^x \\ \\ \implies \dfrac{\partial f}{\partial x} = 0 = 3e^{3x} -3y e^x = 0 \\ \\ e^{2x}= y \\ \\ \\ \implies \dfrac{\partial f}{\partial y } = 0 = 3y^2 -3e^x = 0 \\ \\ y^2 = e^x[/tex]

[tex]\text{Now; to determine the critical point:}[/tex]- [tex]f_x = 0 ; \ \ \ \ \ f_y =0[/tex]

[tex]\implies e^{2x} = y^4 = y \\ \\ \implies y = 0 \& y =1 \\ \\ since y \ne 0 , \ \ y = 1, \ \ x= 0\\\text{Hence, the only possible critical point= }(0,1)[/tex]

b)

[tex]\delta = f_xx, s = f_{xy}, t = f_{yy} \\ \\ . \ \ \ \ \ \ \ \ D = rt-s^2 \\ \\ i) Suppose D >0 ,\ \ \ r> 0 \ \text{then f is minima} \\ \\ ii) Suppose \ D >0 ,\ \ \ r< 0 \ \text{then f is mixima} \\ \\ iii) \text{Suppose D} < 0 \text{, then f is a saddle point} \\ \\ iv) Suppose \ D = 0 \ \ No \ conclusion[/tex]

[tex]Thus \ at (0,1) \\ \\ \delta = f_{xx} = ge^{3x}\implies \delta (0,1) = 6 \\ \\ S = f_{xy} = -3e^x \\ \\ \implies S_{(0,1)} = -3 \\ \\ t = f_{yy} = 6y \\ \\[/tex]

[tex]\implies t_{0,1} = 6[/tex]

[tex]Now; D = rt - s^2 \\ \\ = (6)(6) -(-3)^2[/tex]

[tex]= 36 - 9 \\ \\ = 27 > 0 \\ \\ r>0[/tex]

[tex]\text{Hence, the critical point} \ (0,1) \ \text{appears to be the local minima}[/tex]

c)

[tex]\text{Suppose we chose x = 0 and y = -3.4} \\ \\ \text{Then, we have:} \\ \\ f(0,-3.4) = 1+ (-3.4)^3 + 3(3.4) \\ \\ = -28.104 < -1[/tex]

[tex]\text{However, if f (0,1) = 1 +1 -3 = -1 \\ \\ f(0,-3.4) = -28.104} < -1} \\ \\ \text{This explains that} -1 \text{is not an absolute minimum value of f(x,y)}[/tex]

,........................................................................................l

Answers

No ...................,,,,,,,,..........

The following data show the average retirement ages for a random sample of workers in the United States and a random sample of workers in Japan. Perform a hypothesis test using α = 0.05 to determine if the average retirement age in Japan is different from the United States. Calculate the test-statistics (round to 3 decimals - report the absolute value).

Answers

Answer:

[tex]t \approx 2.639[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {USA\ 1} & {Japan\ 2} & {\bar x} & {64.6} & {67.5} &{n} & {30} & {30} & {\sigma} & {4.0} & {4.5} \ \end{array}[/tex]

See attachment for data

Required

Determine the test statistic

The test statistic is calculated using:

[tex]t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}[/tex]

So, we have:

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{4.0^2}{30} + \frac{4.5^2}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00}{30} + \frac{20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00+20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{36.25}{30}}}[/tex]

[tex]t = \frac{-2.9}{\sqrt{1.2083}}[/tex]

[tex]t = \frac{-2.9}{1.099}[/tex]

[tex]t \approx -2.639[/tex]

The absolute value is:

[tex]t \approx 2.639[/tex]

4
Brad goes to bed at 21 25.
He is in bed until 0708 the next day.
Work out the length of time that Brad is in bed.​

Answers

Answer:

 

Step-by-step explanation:

round off all answer in to two decimal places A=p(1+in) Steven won a portion of the local lottery.the price money is to the value of R18000.he wants to invest the money but does not know which bank to choose. FNB offers Steven 5,6/% for 8 years simple interest per annum, Nedbank offers Steven 6,6% for 6 years simple interest per annum and standard bank offers 7,2% for 5 years simple interest determine each bank future value to help Steven decide which bank he should choose FNB NEDBANK STANDARD BANK​

Answers

Answer:

FNB bank

Step-by-step explanation:

FNB = 18000 * 0.056* 8 = 8064

Nedbank = 18000*0.066* 6 = 7128

Standard = 18000*0.072*5=6480

FNB is the best choice for Steven

Select the option that best describes the relationship
between the variables on the scatter plot.
35
positive, linear association
30
25
no association
20
15
positive, non-linear association
10
5
negative, linear association
10
12
Activate Windows

Answers

Answer:

4th one its negative,linear association

Step-by-step explanation:

The option that best describes the relationship between the variables on the scatter plot is negative, linear association.

What is a negative linear association?

Variables have a negative association when the line of best fit is downward sloping. Variables have a linear association when the line of best fit is a straight line. Variables have a positive association when the line of best fit is upward sloping.

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