3. Which has the largest atomic radius? *
O Calcium
0 Iron
Gallium
O Bromine

Answer:

Final concentration = 0.019 M

Explanation:

Initial Concentration [A]o = 0.27M

Rate constant, k = 0.75 s^-1

Final concentration [A] = ?

Time, t = 1.5s

The relationship between the variables is given by the equation;

ln[A] = ln[A]o - kt

ln[A] = ln(0.27) - (0.75)(1.5)

ln[A] = - 1.309 - 1.125

ln[A] = - 2.434

[A] = 0.019 M

Answer:

With four rope segments, the ideal mechanical advantage is 4. This means that the compound pulley multiplies the force applied to it by a factor of 4.

Explanation:

B trust me please ..........

Answer:

both

Explanation:

depends on what type because there is fecal material dead tissue decomposing soooo both

Answer: they form at equal rates

Explanation:

By definition, at equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.

Answer:

A.Realesing contaminated waste into the water system

Explanation:

because if you you try it would really work

Color Change.

Production of an odor.

Change of Temperature.

Evolution of a gas (formation of bubbles)

Precipitate (formation of a solid)

Hope this helps!:)

Answer:

I believe that it is B. 1

Explanation: I could be wrong but I believe its 1

Answer:

9.62moles of NH₃

Explanation:

Given parameters:

Number of moles of nitrogen  = 4.81moles

Unknown:

Number of moles of  NH₃ = ?

Solution:

To solve this problem, we need to establish a balanced reaction equation:

            N₂  +  3H₂  →  2NH₃

Now, we can solve the problem by working from the known to the unknown.

          1 mole of N₂ produced 2 moles of NH₃

         4.81moles of N₂ will produce 2 x 4.81  = 9.62moles of NH₃

Answer:

c

Explanation:

Answer:

c

Explanation:

Answer:

0.12 mol O₂

Explanation:

Step 1: Write the balanced combustion reaction

C₂H₂ + 2.5 O₂ ⇒ 2 CO₂ + H₂O

Step 2: Establish the appropriate molar ratio

We want to know the moles of oxygen needed to produce 0.095 moles of carbon dioxide. The molar ratio of O₂ to CO₂ is 2.5:2.

Step 3: Calculate the moles of oxygen needed to produce 0.095 moles of carbon dioxide

0.095 mol CO₂ × 2.5 mol O₂/2 mol CO₂ = 0.12 mol O₂

Answer:

Groups 1 and 2.

Explanation:

The elements of Group 1 and Group 2 of the modern periodic table are called S block elements. The two types of s block elements are possible i.e. the elements with one electron (s1) or the elements with two electrons (s2) in their s-subshell.

Answer:

1

Explanation:

Answer: the non metal

Explanation:

Answer:

A. The tendency of the atom to pull on electrons

Explanation:

Took the quiz for  A⃣   p⃣   e⃣   x⃣  , its A

Answer:

Brainliest?

Explanation:

pls!!!!!

Answer:

[tex]ppth=1.2ppth[/tex]

Explanation:

Hello!

In this case, since the parts per thousand of a solute in a solute is defined in terms of its grams per kilogram of solution (unlike parts per million which are mg/kg) we can mathematically represent it via:

[tex]ppth=\frac{grams_{solute}}{kg{solution}}[/tex]

Now, since the whole human body acts as the solution and the chlorine in the form of ions as the solute, the required ppth turns out:

[tex]ppth=\frac{84.0g}{70.0kg}\\\\ppth=1.2ppth[/tex]

Best regards!

Answer:

Number 1 will be in the lowest molar quantity b/c formation of 1st order products are more difficult to form than secondary (#2) or tertiary (#3) substitution products.  

Explanation:

In general, if a substitution occurs such that it is attached to a carbon that's attached to only one carbon, it is referred to as a primary carbon substitution. If a substitution occurs on a carbon that is attached to two (2) carbons, it is a secondary carbon substitution. Finally, if a substitution occurs such that it is attached to a carbon that's attached to three (3) carbons it is a tertiary substitution. Typically, primary substitution products follow an Sn2 type reaction pathway. Such requires the formation of only one intermediate that difficult to form as compared to 2° or 3° intermediates. Once formed, however, they will be very unstable and proceeds to product very quickly. Such produce very low product yield. The intermediates for 2° and 3° form more easily and are more stable in the reaction environments. An example is tertiary butyl halogens (e.g., t-butyl chloride) follow and Sn1 type reaction pathway forming a tertiary carbocation which then reacts with a nucleophile of choice and forms much higher yields than the 1° carbon substitution reactions. Suggest reviewing Sn2 and Sn1 substitution reactions.

Answer:

D. Y will replace ions of X in a solution

Explanation:

If metal X is lower than metal Y on the activity series, then Y will replace ions of X in a solution.

This is the crux of single displacement reactions.

Answer:

oxidation, synthesis, polymerization

Explanation: I took the test

The three types of reactions are product that is a chemically bonded combination of reactants are oxidation, synthesis, polymerization

Conclusively, we can therefore say that the three types of reactions are product that is a chemically bonded combination of reactants are oxidation, synthesis, polymerization

Learn more from:

https://brainly.com/question/14197404

Answer:

5.56×10²² molecules of AlPO4

Explanation:

i think thats is the correct answer if its wrong im really sorry

Explanation:

60 times and it matters why they need to in order to divide

Answer:

An element is the simplest form of matter that cannot be split into simpler substances or built from simpler substances by any ordinary chemical or physical method. There are 110 elements known to us, out of which 92 are naturally occurring, while the rest have been prepared artificially. Elements are further classified into metals, non-metals, and metalloids.

Table 2.11.1: Characteristic properties of metallic and non-metallic elements:

Distinguishing luster (shine)

Non-lustrous, various colors

Nonmetals

Elements that tend to gain electrons to form anions during chemical reactions are called non-metals. These are electronegative elements. They are non-lustrous, brittle and poor conductors of heat and electricity (except graphite). Non-metals can be gaseous, liquids or solids.

Physical Properties of nonmetals:

Physical State: Most of the non-metals exist in two of the three states of matter at room temperature: gases (oxygen) and solids (carbon).

Non-Malleable and Ductile: Non-metals are very brittle, and cannot be rolled into wires or pounded into sheets.

Conduction: They are poor conductors of heat and electricity.

Luster: These have no metallic luster and do not reflect light

Conductivity: Poor conductors of heat and electricity

Melting and Boiling Points: The melting points of non-metals are generally lower than metals

Seven non-metals exist under standard conditions as diatomic molecules:

H2(g)

N2(g)

O2(g)

F2(g)

Cl2(g)

Br2(l)

I2(l) (volatile liquid - evaporates readily)

Chemical Properties of Nonmetals

Non-metals have a tendency to gain or share electrons with other atoms. They are electronegative in character.

Nonmetals, when reacting with metals, tend to gain electrons (typically attaining noble gas electron configuration) and become anions:

Nonmetal + Metal -> Salt

3Br2(l)+2Al(s)→2AlBr3(s)(2.11.4)

Compounds composed entirely of nonmetals are molecular substances (not ionic).

They generally form acidic or neutral oxides with oxygen that that dissolve in water react to form acids:

Physical Properties of Metalloids

State: They are all solid at room temperature.

Conduction: Some metalloids, such as silicon and germanium, can act as electrical conductors under the right conditions, thus they are called semi-conductors.

Luster: Silicon for example appears lustrous, but is not malleable or ductile (it is brittle - a characteristic of some nonmetals). It is a much poorer conductor of heat and electricity than the metals.

Solid Solutions: They can form alloys with other metals.

Chemical Properties of Metalloids

Their physical properties tend to be metallic, but their chemical properties tend to be non-metallic.

The oxidation number of an element in this group can range from +3 to -2, depending on the group in which it is located.

Trends in Metallic and Nonmetallic Character

Metallic character is strongest for the elements in the leftmost part of the periodic table, and tends to decrease as we move to the right in any period (nonmetallic character increases with increasing ionization values). Within any group of elements (columns), the metallic character increases from top to bottom (the ionization values generally decrease as we move down a group). This general trend is not necessarily observed with the transition metals.

2.10: Electron Affinities 2.12: Electronegativity

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2.2: Electron Configurations

2.3: Electron Configurations and the Periodic Table

2.4: Development of the Periodic Table

2.5: Effective Nuclear Charge

The calculation of orbital energies in atoms or ions with more than one electron (multielectron atoms or ions) is complicated by repulsive interaction...

The LibreTexts libraries are Powered by otherwise noted, LibreTexts content is licensed by CC BY-NC-SA 3.0. Have questions or comments? For mor

Explanation:

its D

Answer:

(A) Varying ability to conduct electric current.

Explanation:

The most useful property of metalloids is their varying ability to conduct electric current.

Metalloids are elements or substances that shares properties that transcends between those of a true metal and non-metal.

Answer:

D. All of the above are true.

Explanation:

All the given options in the problem are true.

According to Aufbau's principle, the sublevels with lower energy are filled before those with higher energies.

The order of filling according to their energies is;

1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p

We see that the 3d energy level is lower than 4f but higher than 2s.

Also, the 3d orbital has 5 subshells and each can hold a maximum of two electrons.

This gives a capacity of 10 electrons.

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

color of the substance

Answer:

color change

Explanation: