3. The number of zeroes in the end of perfect square is never_______​

Answers

Answer 1

(vi) The cube of a two digit number may have seven or more digits. (vii) The cube of a single digit number may be a single digit number. Q. The number of zeroes at the end of a perfect square is always odd.

I hope it will be helpful for you.


Related Questions

Simplify the expression 7(6t+2)+3-5(t-1).

Answers

We are given the following expression:

[tex]7(6t+2)+3-5(t-1)[/tex]

To simplify the expression, we will first use the distributive property on the parenthesis, like this:

[tex]7\times6t+7\times2+3-5\times t+5\times1[/tex]

Solving the operations:

[tex]42t+14+3-5t+5[/tex]

Now we add like terms:

[tex](42t-5t)+(14+3+5)[/tex]

Solving the operations:

[tex]37t+22[/tex]

This is the most simplified form of the equation

Al got an estimate for repairs on his bike. Theparts will cost $17.50, and the parts and labortogether will not be more than $40. Whatinequality shows the possible labor costs, L?

Answers

Let's list down the pieces of information given the scenario:

Cost of bike parts = $17.50

Bike parts and labor together = not more than $40/ lesser than or equal to $40.

Let's now generate the equation based on the given information,

Let,

L = Labor cost

[tex]\text{ Cost of parts+Labor Cost }\leq\text{ \$40 ;since the total must not be more than \$40}[/tex][tex]\text{ \$17.50 + L }\leq\text{ \$40 ; inequality showing the possible total cost}[/tex]

Let's now generate the inequality showing the possible labor cost, L

[tex]\text{ \$17.50 + L }\leq\text{ \$40 }\rightarrow\text{ L }\leq\text{ \$40 - \$17.50}[/tex][tex]\text{ L }\leq\text{ \$22.50}[/tex]

Therefore, the cost of labor must not be more than $22.50.

Complete both transformations below.
Then enter the final coordinates of the figure.
A(-1,3)
B(2,1)
C(1-1)
1) <2,3>
2) Dilate K = 2
A" ([?], [])
B" ([][])
C" ([],[])
Enter

Answers

Answer:

A" (2, 12)

B" (8,8)

C" (6, 4)

Step-by-step explanation:

For each point P(x, y) of the image, the translations are as follows:

Translate P(x, y) by <2, 3> [tex]\longrightarrow[/tex] P'(x + 2, y + 3) [tex]\longrightarrow[/tex] P'(x', y')

Dilate P'(x', y') by 2 [tex]\longrightarrow[/tex] P'' (x'', y'') [tex]\longrightarrow[/tex] P(2x', 2y')

Point      [tex]\longrightarrow[/tex]           Translate <2, 3>                   [tex]\longrightarrow[/tex]       Dilate by 2

A(-1, 3)    [tex]\longrightarrow[/tex]         A'(-1 +2, 3 + 3) =>  A'(1, 6)       [tex]\longrightarrow[/tex]            A''(2, 12)

B(2, 1)     [tex]\longrightarrow[/tex]         B'(2 + 2, 1 + 3) =>  B'(4, 4)       [tex]\longrightarrow[/tex]           B"(8, 8)

C(1, -1)    [tex]\longrightarrow[/tex]          C'(1 + 2, -1 + 3) =>  C'(3, 2)     [tex]\longrightarrow[/tex]            C"(6, 4)

Write an equation describing the relationship of the given variables

Answers

[tex]\begin{gathered} y=k\cdot\frac{x^2z^2}{\sqrt{w}\sqrt{t}} \\ \text{when, x=}2\text{,z=3,w=16,t=}3\text{ the value of y is 1} \\ 1=k\cdot\frac{(2)^2(3)^2}{\sqrt{16}\sqrt{3}} \\ 1=k\cdot\frac{(4)(9)}{(4)(\sqrt{3})} \\ 1=k\cdot\frac{9}{\sqrt{3}} \\ \text{Solving k} \\ k=\frac{\sqrt{3}}{9} \\ \text{Hence } \\ y=(\frac{\sqrt[]{3}}{9})\cdot\frac{x^2z^2}{\sqrt[]{w}\sqrt[]{t}} \\ y=\text{?, when x=}3\text{,z=}2\text{,w=}36\text{, t=1} \\ y=(\frac{\sqrt[]{3}}{9})\cdot(\frac{(3)^2(2)^2}{\sqrt{36}\sqrt{1}}) \\ y=(\frac{\sqrt[]{3}}{9})\cdot(\frac{(9)^{}(4)^{}}{(6)(1)}) \\ y=(\frac{\sqrt[]{3}}{9})\cdot(\frac{36}{6}) \\ y=(\frac{\sqrt[]{3}}{9})\cdot(6) \\ y=\frac{6\sqrt{3}}{9} \\ y=\frac{2\sqrt[]{3}}{3} \\ \text{The value of y is }\frac{2\sqrt[]{3}}{3}\approx1.1547 \end{gathered}[/tex]

Simplify the expression 5(-7 + 3k)

Answers

The given expression is,

[tex]5(-7+3k)[/tex]

Opening the brackets and multiplying each term inside the bracket with 5, we get,

[tex]\begin{gathered} \lbrack5\times(-7)\rbrack+(5\times3k)=-35+15\text{ k} \\ 15k=35 \\ k=\frac{35}{15}=2.33 \end{gathered}[/tex]

The simplified expression is 15k = 35 and the value of k is 2.33.

how far apart is -1 1/3 and 4 2/5 on a number line

Answers

-3.07 is the difference between them

URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100
POINTS!!!!!

Answers

The given statement is false: vertical angle do not depend on the line being parallel. A pair of vertical angles are always congruent.

Vertical angle:

Vertical angle means that the angles opposite each other when two lines cross.

Given,

Here we have the diagram and we also know that angle 7 is congruent to angle 5.

Now we need to find the given statement is true or not.

Through the given diagram, we have identified that, the eight angles will together form four pairs of corresponding angles.

Angles 1 and 5 constitutes one of the pairs.

We know that all the corresponding angles are congruent.

All angles that have the same position with regards to the parallel lines and the transversal are corresponding pairs e.g. 3 + 7, 4 + 8 and 2 + 6.

Through that we know that basically, the vertical angles are always congruent, which means that they are equal. So, it is not necessary for them to be parallel.

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calcula la suma de los quince primeros multiplos de 9

Answers

Answer:

Step-by-step explanation:

9*(15/2)[2+14] = 9*15*16 = 2160.

Consideremos la recta y=6x-4.
¿Cuál es la pendiente de una recta paralela a esta recta?
¿Cuál es la pendiente de una recta perpendicular a esta recta?
Pendiente de una recta paralela:
Pendiente de una recta perpendicular:

Answers

Slope of a parallel line: 6

Slope of a perpendicular line: -1/6

What is Slope ?

slope, The inclination of a line with respect to the horizontal is measured numerically. The ratio of the vertical to the horizontal distance between any two points on a line, ray, or line segment is known as its slope in analytical geometry ("slope equals rise over run").

Given equation,

y=6x-4

The equation of a line with slope  m  is given as:

y=mx+c

Rearranging the given equation:

y=(6)x+(-4)

By equating the equations we get,

m= 6

Which is slope of a parallel line

Now any parallel line would have the same slope.

And slope of a perpendicular line would be  −1/m.

i.e.  m(perpendicular)= -1/6

Hence, Slope of a parallel line is 6 and Slope of a perpendicular line is -1/6

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can you help me find the answer to this question find the area of this figure round your answer to the nearest hundredth use 3.14 to approximate tt. a= ? ft 2

Answers

First, let's calculate the area of the triangle.

[tex]A=\frac{1}{2}b\cdot h[/tex][tex]A=\frac{1}{2}\cdot6\cdot8=\frac{48}{2}=24\text{ ft2}[/tex]

Now let's calculate the area of the semicircle.

[tex]A=3.14\cdot\frac{r^2}{2}[/tex][tex]A=3.14\cdot\frac{4^2}{2}=25.12\text{ ft2}[/tex]

The total area of the figure is:

24+25.12 ft2 = 49.12 ft2

3/9 - 6/9 = ?
,,,,,,,,,,,,,,,,,,,,,,,

Answers

Answer:

-3/9 or -1/3

Step-by-step explanation:

:]

Answer:   -1/3

Step-by-step explanation- To subtract fractions, you first make the the denominators the same. The denominator is the bottom number. To make the denominator the same, you look for the lowest common denominator. Making the answer -1/3

1messageJosh wants to estimate the mean age in a population of trees. He'll sample n trees and build a 95% confidence interval for the mean age. He doesn't want the margin of error to exceed 3 years. Preliminary data suggests that the standard deviation for the ages of trees in this population is 16 years.Which of these is the smallest approximate sample size required to obtain the desired margin of error?11 trees110 trees144 trees43 trees87 trees

Answers

The formula for the margin of error is

[tex]\begin{gathered} \text{MOE}=SE\times critical\text{ value} \\ SE\Rightarrow\text{standard error} \end{gathered}[/tex]

The critical value for 95% confidence interval is 1.96

The standard error is

[tex]\begin{gathered} SE=\frac{\sigma}{\sqrt[]{n}} \\ \sigma\Rightarrow standard\text{ deviation} \\ n\Rightarrow\text{sample size} \end{gathered}[/tex]

To know which of the list of options will yield approximately the desired margin of error, we will have to calculate the margin of error with the following values

For 110 trees, n= 110, standard dev. =16

[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{110}}=1.53 \\ \text{MOE}=1.53\times1.96=2.9988 \end{gathered}[/tex]

For 144 trees, n=144, standard dev=16

[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{144}}=\frac{16}{12}=1.33 \\ \text{MOE}=1.33\times1.96=2.61 \end{gathered}[/tex]

For 43 trees, n=43 , standard dev.=16

[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{43}}=2.44 \\ \text{MOE}=2.44\times1.96=4.782 \end{gathered}[/tex]

For 87 trees, n= 87, standard dev=16

[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{87}}=1.72 \\ \text{MOE}=1.72\times1.96=3.3712 \end{gathered}[/tex]

Hence, from the above calculations, the most prefered is the sample size of 110 trees (because the margin of error of 2.9988 is approximately 3 )

Answer is 110 trees

Help?
(ii) Not sure what scale factor is
(ii) And I’ve never learnt this

Answers

This video from khan academy should clear up your confusion on scale factors.

https://www.khanacademy.org/math/7th-engage-ny/engage-7th-module-1/7th-module-1-topic-d/v/identifying-scale-factors

In gym class, a student can do 40 sit-ups in 60 seconds and 100 sit-ups in 150 seconds.

Graph the proportional relationship.

graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 60
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 30
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 50
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30

Answers

Answer:

  (a) graph with line through (90, 60)

Step-by-step explanation:

You want a graph of the proportional relationship between sit-ups and seconds if a student can do 40 sit-ups in 60 seconds.

Graph

Seconds are plotted on the x-axis, and sit-ups are plotted on the y-axis The graph will match that shown in the attachment.

<95141404393>

How much interest is earned in an investment if $720 is deposited monthly at 7.8% compounded monthly if the term of the investment is 6 years?$__________Round to the nearest cent

Answers

Given:

The initial investment is, P = $720.

The rate of interest is, r = 7.8% = 0.078.

The number of years of investment is, t = 6 years.

Explanation:

The general formula to find the compound interest is,

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Here, n represents the number of times compounded in a year. It is given that the amount is compounded monthly, so the value of n = 12.

To find total amount after 6 years:

Now, substitute the given values in the general equation.

[tex]\begin{gathered} A=720(1+\frac{0.078}{12})^{12(6)} \\ =720(1+0.0065)^{72} \\ =1147.95 \end{gathered}[/tex]

Thus, the total amount earned is $1147.95.

To fnd interest amount:

Now, the amount of interest can be calculated as,

[tex]\begin{gathered} I=A-P \\ =1147.95-720 \\ =427.95 \end{gathered}[/tex]

Hence, the interest amount earned is $427.95 and the total amount earned is $1147.95.

damion started solving this equation in an even different way what did he do first

Answers

With the help of Linear equation we can say that  Damion added 12 on both sides.

What is linear equations?Equations with variables whose maximum power is 1 are said to be linear equations. A linear equation has a straight line as its graph.

The given equation was,

12x + 4 = 20x-12

If we will add 12 on both sides ,

12x + 16= 20x

Hence we can say that Damion added 12 to both sides.

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Capital Gate Tower is
150 meters tall
(measured vertically
from the ground) and
makes a 72° angle
with the ground. If
you were to climb to
the top and then
accidently drop your
keys, how far from
the base of the tower
would they land?

Answers

Answer:

Step-by-step explanation:

[tex]\frac{150}{x} =tan72 \\x=150 cot~72=150 cot(90-18)=150 ~tan ~18 \approx 48.74 ~meteres[/tex]

Towson Corporation issued $150,000 of 7% ten year bonds at 103 on the semi-annual interest date. Towson uses the straight line method to amortize any bond premium or discount. What is the amount of bond amortization for each six month period? Answer in whole dollars (no cents).

Answers

The amount of bond amortization for each six month period is [tex]\$225[/tex].

In the given question,

Towson Corporation issued [tex]\$150,000[/tex] of [tex]7\%[/tex] ten year bonds at [tex]103[/tex] on the semi-annual interest date.

Towson uses the straight line method to amortize any bond premium or discount.

We have to find the amount of bond amortization for each six month period.

Cash issued [tex]=\$150,000[/tex]

Rate [tex]=7\%[/tex] ten year bond at [tex]103[/tex] n the semi-annual interest date.

So the cash proceed on issue of bond = Cash issued [tex]\times103[/tex] [tex]/100[/tex]

Cash proceed on issue of bond [tex]=\$150,000\times\frac{103}{100}[/tex]

Firstly simplifying ratio

After simplification of ratio

Cash proceed on issue of bond [tex]=\$150,000\times1.03[/tex]

Now simplifying after multiplication

Cash proceed on issue of bond [tex]=\$154,500[/tex]

Hence, the cash proceed on issue of bond is [tex]\$154,500[/tex].

Now we find the premium that issued in the bond.

Premium on issue of bond [tex]=\$154,500-\$150,000[/tex]

Simplifying

Premium on issue of bond [tex]=\$4,500[/tex]

Hence, the premium on issue of bond is [tex]\$4,500[/tex]

Now finding the amount of bond amortization for each six month period.

Bond Amortization = (Premium on issue of bond/10 years) * 1/2

Bond Amortization [tex]=(\frac{\$4500}{10})\times\frac{1}{2}[/tex]

Simplifying the ratio

Bond Amortization [tex]=\$450\times0.5[/tex]

Bond Amortization [tex]=\$225[/tex]

Hence, the amount of bond amortization for each six month period is [tex]\$225[/tex].

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Write 92.5% in a fraction or mixed number in simplest form

Answers

92.5% as a fraction is 92 1/2%.

I know this because 5 tenths can be turned into 5/10. 5/10 divided by 5 is 1/2. Add the 92 and you get 92 1/2%.

Lottery numbers in a particular state consist of 5 digits. Each lottery cube that is drawn/rolled has six sides, numbered 1-6. How many different lottery numbers are possible? O 720 lottery number O 7776 lottery numbers

Answers

As per the concept of probability, there are 7776 different lottery numbers are possible.

Probability:

Probability means the concept that is based on the possible chances of something to happen.

Given,

Lottery numbers in a particular state consist of 5 digits. Each lottery cube that is drawn/rolled has six sides, numbered 1-6.

Here we need to find how many different lottery numbers are possible.

Through the given question we know that,

The number of digits in a lottery ticket = 5

Side in cube = 6

So, in each time they will roll the dice 5 times to get one number.

So, the possible options of that event are,

For the first time we have 6 options

Second time we got 6 options

Third time also we got six option

Fourth time = 6 options

Fifth time = 6 options.

Therefore, it can be written as,

=> 6 x 6 x 6 x 6 x 6

=> 6⁵

=> 7776.

Therefore, there are 7776 different lottery numbers are possible.

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Explain how you can use addition of groups to show that 4 x ( -3) = 12

Answers

The technique of repeated addition involves combining equal groups.

4 x ( -3) = 12.

Repeated addition is the combining of equal groupings. It offers a basis for comprehending multiplication. For instance, 3 x 5 can be expressed as 5 + 5 + 5 to represent 3 groups of 5 counters.

We have been given that

4 x ( -3) = 12

By using repeated addition for multiplication

Add 4 three times or add 3 for times ..

In question negative 3 is given so we add negative 4 , three times

(-4) + (-4) + (-4)

-12.

Or

Add negative 3 , four times

(-3) + (-3 )+ (-3) + (-3)

-12.

Hence, we solved given multiplication by the using repeated addition method.

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In isosceles triangle ABC,AB=BC. AB and Bc are called_____a.bases b.verticesc.hypotenused. legs

Answers

In an isosceles triangle, there are

2 legs (equal sides)

1 base

The 2 legs are the equal sides

The base is the third side

In the isosceles triangle ABC:

Since AB = BC, then

AB and BC are the legs of the triangle, then

AB and BC are called legs

The answer is d

In triangle DEF, m∠D = (2x + 19)°, m∠E = (3x + 24)°, and m∠F = 87°. Determine the degree measure of the exterior angle to ∠D.

54°
39°
141°
126°

Answers

The value of x is equal to 10 and the exterior angle to angle d is equal to 141 degrees.

Exterior Angles

To solve this problem, we have to recall that the sum of angles in a triangle is equal to 180 degrees.

Applying that formula here;

[tex]m < d + m < e + m < f = 180^0\\(2x + 19) + (3x + 24) + 87 = 180\\x = 10[/tex]

But the exterior angle to angle D can be found assuming the angle lies on a straight line, then the sum of angle D and it's exterior angle would be equal to 180 degrees.

Let y = exterior angle

[tex]m < d + y = 180\\2x + 19 + y = 180\\x = 10\\2(10) + 19 + y = 180\\20 + 19 + y = 180\\39 + y = 180\\y = 141^0[/tex]

The value of the exterior angle to d is equal to 141 degrees.

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Answer: its C

Step-by-step explanation: i got it right

identify the mapping diagram that represents the relation and determine whether the relation is a function

Answers

F is the correct answer (option A) that is, the relation is like many to one. So, it is a function.

Given mapping diagram that represents the relation.

We have to determine whether the relation is a function.

(-8, -6), (-5, 2), (-8, 1), (7, 3)

Here,

Domain = (-8, -5, 7)

Range = (-6, 2, 1, 3)

A function is a relation where each input has only one output.

Here,

F. The relation is like many to one. So, it is a function.

G. The relation is many to one. So, it is a function.

H. The relation is one to many. It is not a function.

G. The relation is one to many. It is not a function.

So, F is the correct answer (option A) that is, the relation is like many to one. So, it is a function.

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question 1.P(A)=0.25 P(B)=0.65 P(A or B)=?a.0.45b.0.2c.0.65d.0.9question 2P(A)=0.45 P(B)=0.35 P(A or B)=?a.0.75b.0.85c.0.8d.0.35

Answers

Given,

1)P(A) = 0.25

P(B) = 0.65

The value of P( A or B) is,

[tex]\begin{gathered} P(A\cup B)=P(A)+P(B)_{} \\ P(A\cup B)=0.25+0.65 \\ P(A\cup B)=0.90 \end{gathered}[/tex]

Hence, option d is correct.

2)P(A) = 0.45

P(B) = 0.35

The value of P( A or B) is,

[tex]\begin{gathered} P(A\cup B)=P(A)+P(B)_{} \\ P(A\cup B)=0.45+0.35 \\ P(A\cup B)=0.80 \end{gathered}[/tex]

Hence, option c is correct.

The safe load, L. of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth, d. and inversely as the length. I. A wooden beam 8 in. wide. 6 in. deep, and 10 ft long holds up 1966 lb. What load would a beam 3 in. wide 9 in. deep and 11 ft long of the same material support? (Round off your answer to the nearest pound.)

Answers

The safe load, L of a wooden a beam 3 in. wide 9 in. deep and 11 ft long of the same material support is 307.17

Analyzing the given conditions in the question, we get

The safe load, L is directly proportional to width (w) and square of depth (d²)

also,

L is inversely as length (l) i.e L = k/l

combining the above conditions, we get an equation as:

L = k(wd²/l)

now, for the first case we have been given

w = 8 in

d = 6 in

l = 10 ft

L = 1966 lbs

thus,

1966 lb = k ((8 × 6²)/10)

or

k = 68.26 lbs/(ft.in³)  

Now,

Using the calculated value of k to calculate the value of L in the second case  

in the second case, we have

w = 3 in

d =9 in

l = 11 ft

Final Safe load L' =  68.26 × (6 × 3²/12)

or

L' =307.17 lb

Therefore, The safe load, L of a wooden a beam 3 in. wide 9 in. deep and 11 ft long of the same material support is 307.17

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A 250 N force acts on a 20 kg object. What would be the acceleration of the object?

Answers

Answer:

a = 12.5 m/s2

Step-by-step explanation:

anwser 12.5

The cranes shown in the figure are lifting an object that weighs 20,290 pounds. Find the tension in the cable of each crane. (Round your answers to the nearest whole number.)TL= lbsTR= lbs

Answers

we have that

TLy+TRy=20,290 ------> equation A

and

sin(24.3)=TLy/TL

TLy=TLsin(24.3) ------> equation B

sin(44.5)=TRy/TR

TRy=TRsin(44.5) ------> equation C

and

TLx=TRx

TLcos(24.3)=TRcos(44.5)

TL=TRcos(44.5)/cos(24.3) --------> equation D

substitute equation B and equation C in equation A

TLsin(24.3)+TRsin(44.5)=20,290 -------> equation E

substitute equation D in equation E

(TRcos(44.5)/cos(24.3))sin(24.3)+TRsin(44.5)=20,290

solve for TR

factor TR

TR[cos(44.5)/cos(24.3))sin(24.3)+sin(44.5)]=20,290

TR=19,835 pounds

Find TL

TL=(19,835)cos(44.5)/cos(24.3)

TL=

6 to the negative 3rd power times 6 to the 2nd power times 6 to the 5th power times 6

Answers

The value of 6 to the negative 3rd power times 6 to the 2nd power times 6 to the 5th power times 6 is 6^5.

What is an exponent?

The exponent is the number of times that a number is multiplied by itself. It should be noted that the power is an expression which shows the multiplication for the same number. For example, in 6⁴ , 4 is the exponent and 6⁴ is called 6 raise to the power of 4.

Based on the information given, the numbers will be expressed as:

6^-3 × 6^2 × 6^5 × 6

= 6^5

It's important to note that they've the same base. Therefore, the powers will be added thus:

= -3 + 2 + 5 + 1

= 5

This gives 6^5. This illustrates the concept of exponents.

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10. A recipe calls for 5 cups of flour. If you only have a ½ cup to measure, how many ½ cups will you need for
the recipe?

Answers

Answer: 10 1/2 cups

Explanation: 1/2 goes into one twice. So, if you have 5 cups, you need to multiply it by 2 to account for every 1/2 a cup
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