3. show company names and product names of all products. use the where clause syntax for -- the join. order by company name.

Answers

Answer 1

Here is the query that would show company names and product names of all products using the WHERE clause syntax for the join and ordering the results by company name:

SELECT c.company_name, p.product_name
FROM companies c
JOIN products p
ON c.company_id = p.company_id
WHERE p.product_id IS NOT NULL
ORDER BY c.company_name;

This query will fetch the company name and product name for all products where the product_id is not null. It will join the companies and products tables based on the company_id column and order the results in ascending order by company name.
To show company names and product names of all products using the WHERE clause syntax for the join and ordering by company name, you can use the following SQL query:

```sql
SELECT companies.company_name, products.product_name
FROM companies, products
WHERE companies.company_id = products.company_id
ORDER BY companies.company_name;
```

This query selects the company_name from the companies table and the product_name from the products table, joining them based on the matching company_id, and ordering the results by the company_name.

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Related Questions

. describe an algorithm that determines whether a function from a finite set of integers to another finite set of integers is onto.

Answers

This algorithm checks if a function from a finite set A to a finite set B is onto by verifying that every element in B has a corresponding element in A.


1. Define the function f: A -> B, where A and B are finite sets of integers.
2. Find the cardinalities (size) of both sets, |A| and |B|.
3. For each element b in B:
  a. Check if there exists an element an in A such that f(a) = b.
  b. If such an element a exists, continue to the next element in B.
  c. If no such element exists, the function is not onto and the algorithm terminates.
4. If all elements in B have a corresponding element in A, the function is onto.

By following these steps, the algorithm checks if every element in the codomain (set B) is an output of the function f, and if so, it confirms that the function is onto.

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o put a web page on the internet and make it accessible through the world wide web, we need to contact a(n

Answers

Answer:

The webpages on the Internet was for example gaming websites because it is accesible through the world wide web, we need to contact an computer administrator :))

Imagine you write python codes for an eCommerce Company. For a new order, you need to check if there are enough items left in stock to fulfill an order or if the inventory needs to be resupplied. If there are enough items in the inventory, then you need to calculate if multiple packaging boxes are required to pack the order. One packaging box can hold 6 items. The user will input the order and the number of items in stock. You need to decide if inventory needs to be resupplied or not. If not, then you need to decide if multiple packaging boxes are required. Write the Python code to complete the program Use the input() function to prompt the user for: = Order :

Answers

The user is first prompted by this code for the order and the number of available products. It then determines whether there are sufficient items in stock to complete the order.

How does Python work when counting the number of items in a class?

using the count() technique for lists. Using the count() method, you may determine how many times an element has been used in the list. In this function, we count the instances of an element in a list using the Python count() method.

Which is utilised to determine how many objects were produced for a class?

We must include a count variable in the function Object() { [native code] } in order to count the number of objects.

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Write an SQL command that will find any customers who have not placed orders?

Answers

To find customers who have not placed orders, use a LEFT JOIN to join the 'customers' and 'orders' tables on the common field 'customer_id', and add a WHERE clause to filter for records where the 'order_id' is NULL.

To write an SQL command that will find any customers who have not placed orders, you can use a LEFT JOIN and a WHERE clause. Assuming you have two tables named 'customers' and 'orders', with a common field 'customer_id', the SQL command would look like this:
```sql
SELECT customers.*
FROM customers
LEFT JOIN orders ON customers.customer_id = orders.customer_id
WHERE orders.order_id IS NULL;
```

This query will return all the customers who do not have any corresponding records in the orders table, indicating that they have not placed any orders.

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Which method can be used to create an input object for file temp.txt?a) new Scanner("temp.txt")b) new Scanner(temp.txt)c) new Scanner(new File("temp.txt"))d) new Scanner(File("temp.txt"))

Answers

The correct method to create an input object for the file temp.txt using a Scanner is:c) new Scanner(new File("temp.txt")).


This method creates a new Scanner object that takes a File object as its parameter, with the file name "temp.txt".To create an input object for a file, we need to use the Scanner class in Java along with the File class to specify the file we want to read.

Option (a) new Scanner("temp.txt") creates a scanner object that reads from a string literal "temp.txt". This is not correct as it does not reference the file itself.

Option (b) new Scanner(temp.txt) references an unknown variable temp.txt instead of the string literal "temp.txt" or a File object.

Option (c) new Scanner(new File("temp.txt")) is the correct method to create a scanner object that reads from a file named "temp.txt". It creates a new File object with the specified filename and then passes it to the Scanner constructor.

Option (d) new Scanner(File("temp.txt")) tries to create a File object using an incorrect syntax for the constructor. It should be new File("temp.txt").

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Given the following function, what is the parameter name for the function's parameter?
func delete(file path: String) -> Bool {
// code
}
Group of answer choices
delete
file
path
filePath
String
Bool

Answers

The parameter name for the function's parameter is "path" and not the filepath.

func delete(filepath: String) -> Bool {

   // code

}

the parameter name for the function's parameter is "path".

The function is called delete(file:path:), indicating that it takes one parameter labeled "file" externally, and "path" internally.

When calling the function, the caller would use the external parameter name "file" to pass in an argument for the "path" parameter, like so:

let result = delete(file: "/path/to/file")

Inside the function body, the parameter can be referred to using its internal name "path", like so:

func delete(filepath: String) -> Bool {

   // use the `path` parameter here

   // code

}

Therefore, "path" is the parameter name for the function's parameter in this case.

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Write a function called rangeSum that takes two integers, and returns the sum of all integers from the first to the second, inclusive. I haven’t defined what the function will do if the second argument is larger, like for the case of rangeSum 5 3 . What would be sensible behaviour here?

Answers

Hi! To create a function called rangeSum that takes two integers and returns the sum of all integers from the first to the second, inclusive, you can follow this approach:the function will swap the values and return the sum from 3 to 5, inclusive.

1. Check if the second argument is larger than the first. If it is, swap the values to ensure a valid range.
2. Use a loop to iterate through the range, adding each integer to a sum variable.
3. Return the sum variable after the loop.
A sensible behavior for the case when the second argument is larger, like in rangeSum(5, 3), would be to swap the values and still calculate the sum, treating it as rangeSum(3, 5).
Here's an example implementation in Python:
```python
def rangeSum(a, b):
   if a > b:
       a, b = b, a  # Swap values if b is larger than a
   total_sum = 0
   for i in range(a, b+1):
       total_sum += i
   return total_sum
```
Now, if you call rangeSum(5, 3), the function will swap the values and return the sum from 3 to 5, inclusive.

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. if the hlen field at l4 is 0xa, how many bytes of options are included in the header?\

Answers

The hlen field in the L4 header specifies the length of the header in 32-bit words. Therefore, if the hlen field at L4 is 0xa, then the header length would be 10*4=40 bytes.

The options field is optional in the TCP/IP protocol suite and is provided in the header only if necessary. If you include the options, their length is configurable and is set in the options field. The maximum length of the options field in TCP is 40 bytes. As a result, a value of 0xa in the hlen field at L4 indicates that the length of the header is 40 bytes, which is the maximum length of the choices field.

The options field is used to offer extra information not contained in the normal header. Maximum segment size (MSS), window scaling, the selective acknowledgment (SACK), and timestamp are a few examples of settings. The options field is used to negotiate these parameters between the sender and receiver of a TCP segment.

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what are the main challenges you faced from decision perspective - did uml help with those decisions or using uml made the project design harder?

Answers

From a decision perspective, the main challenges I faced included identifying the appropriate requirements, determining the most effective design approach, and managing project constraints such as time and budget.

UML (Unified Modeling Language) did help with those decisions by providing a common language and visual representation of the system, which aided in communication and collaboration among stakeholders. However, using UML also made the project design harder in some ways, as it required additional time and effort to learn and implement. Additionally, there were cases where the complexity of the system made it difficult to accurately represent in UML diagrams, which required careful consideration and analysis to overcome. Overall, while UML presented some challenges, it ultimately helped to facilitate effective decision-making and project design.

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Channel bonding combines two non-overlapping 20 MHz channels into a single 40 MHz channel, resulting in slightly more than double the bandwidth.O 802.11n: Channel BondingO 802.11ac technologiesO 802.11n: Frame CompositionO 802.11ac: Frame Composition

Answers

802.11n and 802.11ac technologies use channel bonding to increase bandwidth by combining non-overlapping channels. Frame composition differs between the two, with 802.11ac using shorter frames and more efficient coding.

Channel bonding is a technique used in wireless communication to combine two non-overlapping 20 MHz channels into a single 40 MHz channel. This results in slightly more than double the bandwidth, which can significantly improve the performance of the wireless network.
Channel bonding is used in both 802.11n and 802.11ac technologies. In 802.11n, channel bonding is used to combine two 20 MHz channels into a single 40 MHz channel, resulting in increased data rates. This technique is also used in 802.11ac, which supports wider channels of up to 160 MHz.
In terms of frame composition, 802.11n and 802.11ac differ slightly. In 802.11n, the frame is composed of four fields: the frame control field, the duration/ID field, the address fields, and the payload field. In 802.11ac, the frame is composed of six fields: the frame control field, the duration/ID field, the transmitter address field, the receiver address field, the payload field, and the frame check sequence field.

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Unsupervised. ​______ is the type of data mining in which analysts do not create a model or hypothesis before running the analysis.

Answers

Clustering is the type of data mining in which analysts do not create a model or hypothesis before running the analysis.

This type of analysis is also known as unsupervised learning, as the algorithm is not given any specific target variable to predict or classify. Instead, it identifies patterns and groups within the data based on similarities and differences between observations. Clustering can be useful for identifying customer segments, market trends, and other patterns in large datasets.

The goal of clustering is to find natural groupings or clusters in the data. The algorithm iteratively assigns each data point to the nearest cluster centroid or center, and then recalculates the centroids based on the new cluster assignments.

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Most buses in a typical power-flow program are load buses, for which pk and qk are input data. the power-flow program computes ________.

Answers

The answer to the question is that the power-flow program computes the voltage magnitude and angle at each load bus, as well as the real and reactive power flowing through each transmission line.

The power-flow program uses a set of mathematical equations to solve for the unknown voltage magnitudes and angles at load buses, given the known real and reactive power injections at those buses. This involves iterative calculations to balance the power flows throughout the network and ensure that the voltage and power constraints are satisfied. Once the solution is found, the program outputs the voltage and power values for each bus and line, which can be used for further analysis and planning of the power system.

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Write a function named is Prime that checks if a number is prime or not. In main(), isPrime() is called in a loop, to write all prime numbers between 2 and 104729 to a file, one number per line. A positive integer is prime if its only positive divisors are itself and 1. For instance: 2, 3, 5, 7, 11, 13, 17, 19, 23 are prime numbers, and 4, 10, 15, 22, 30 are not prime. The isPrime function checks if a number is prime or not using a simple algorithm that tries to find a divisor. It stops searching at the integer part of the square root of the number being tested. int main(void) { ofstream outfile; int max_num = 104729; outfile.open("primes.txt"); for (int i = 2; i <= max_num; i++) { if( isPrime(i)) outfile << i < endl; } outfile.close(); return 0; }

Answers

The provided code defines a function named is Prime that checks whether a given integer is a prime number or not. The function uses a simple algorithm that tries to find a divisor and stops searching at the integer part of the square root of the number being tested.

The main function then calls this is Prime function in a loop to write all prime numbers between 2 and 104729 to a file, one number per line. To explain further, an integer is a whole number that can be positive, negative, or zero. Prime numbers are positive integers greater than 1 that have no positive divisors other than 1 and themselves. The provided is Prime function takes an integer as its input and checks whether it is prime or not. It does this by dividing the input number by all integers from 2 up to the integer part of the square root of the input number. If the input number is divisible by any of these integers, it is not prime and the function returns false. If none of these integers divide the input number, the function returns true, indicating that the input number is prime. The main function uses a loop to iterate over all integers from 2 to 104729. For each integer, it calls the is Prime function to check whether it is prime or not. If it is prime, the integer is written to a file named "primes.txt" using the of  stream object out file. Finally, the file is closed and the main function returns 0. Overall, the provided code efficiently identifies all prime numbers between 2 and 104729 using a simple algorithm that checks for divisors up to the square root of the input number.

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Need help filling in the parts in JAVA, ONLY edit between the parts that are bolded. Expected output is highlighted in the comments.
/**
Illustrates basic operations of an iterator on a set. Notice that
the iterator for a set differs from the iterator for a list (i.e.,
a list iterator), in that the set iterator has no previous method
(since the set has no order it does not makes sense to ask to go
backwards), and the set iterator has no add method (since the set
has no order it makes no sense to try to add an element at a
particular position).
The part that you write adds 1000 random letters a-z to a set, then puts
them in a stack, then pops and prints them.
Expected output:
A-B-D-F-G
zyxwvutsrqponmlkjihgfedcba
*/
public class SetTester4
{
public static void main(String[] args) {
//This first part is just an example of set operations.
Set set = new TreeSet() ;
set.add("A") ;
set.add("B") ;
set.add("C") ;
set.add("D") ;
set.add("F") ;
set.add("G") ;
//The following line shows how to make an iterator for a set.
Iterator iterator = set.iterator() ;
//The following loop shows how to go through the set with the iterator
while (iterator.hasNext()) {
String element = iterator.next() ;
if (element.equals("C"))
iterator.remove() ;
else if (iterator.hasNext())
System.out.print(element + "-") ;
else System.out.print(element) ;
}
System.out.println() ;
System.out.println("-----------------------------Your work:") ;
set = new TreeSet() ;
Random random = new Random() ;
char ch = 'a' ;
for (int i = 0 ; i < 1000 ; i++) {
//-----------Start below here. To do: approximate lines of code = 6
// 1. add a randomly selected letter "a" to "z" to set ; }//
//2. iterator = ... an iterator on set ; //3. make a stack for strings //4-5. use the iterator to put all of the letters into the stack ; //6. while there are letters on the stack
System.out.print(stack.pop()) ;//
System.out.println() ;//
//-----------------End here. Please do not remove this comment. Reminder: no changes outside the todo regions.
}
}

Answers

public class SetTester4 {

public static void main(String[] args) {

//This first part is just an example of set operations.

Set<String> set = new TreeSet<>();

set.add("A");

set.add("B");

set.add("C");

set.add("D");

set.add("F");

set.add("G");

What is the JAVA?

vbnet

 //The following line shows how to make an iterator for a set.

 Iterator<String> iterator = set.iterator();

 

 //The following loop shows how to go through the set with the iterator

 while (iterator.hasNext()) {

    String element = iterator.next();

    if (element.equals("C")) {

       iterator.remove();

    } else if (iterator.hasNext()) {

       System.out.print(element + "-");

    } else {

       System.out.print(element);

    }

 }

 System.out.println();

 System.out.println("-----------------------------Your work:");

 

 set = new TreeSet<>();

 Random random = new Random();

 char ch = 'a';

 for (int i = 0; i < 1000; i++) {

    // 1. add a randomly selected letter "a" to "z" to set ;

    set.add(Character.toString((char)(random.nextInt(26) + 'a')));

 }

 

 // 2. iterator = ... an iterator on set ;

 Iterator<String> setIterator = set.iterator();

 

 // 3. make a stack for strings

 Stack<String> stack = new Stack<>();

 

 // 4-5. use the iterator to put all of the letters into the stack ;

 while (setIterator.hasNext()) {

    stack.push(setIterator.next());

 }

 

 // 6. while there are letters on the stack

 while (!stack.isEmpty()) {

    System.out.print(stack.pop());

 }

 //System.out.println() ;

}

}

//Expected output: A-B-D-F-Gzyxwvutsrqponmlkjihgfedcba

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Which version of the print function would be invoked by the code Person* x new Student; x-print (); class Person class Student public Person public void print () public void print ) const const } ; d. No function gets called, this causes a compile-time error Person: :print () b. Student: :print () void print ) ; a. C. Which version of the print function would be called by the same code, if its declaration in both classes is changed to virtual void print () const; Use the same set of responses as in the previous question Static binding of a function call occurs at b. compile-time run-time a.

Answers

In the first question, the version of the print function that would be invoked by the code would be b. Student:: print (). This is because the object x is of type Student and therefore calls the print function in the Student class.

In the second question, if the declaration of the print function in both classes is changed to virtual void print() const;, the version of the print function that would be called depends on whether static binding or dynamic binding is used. If static binding is used, the answer would still be b. Student: :print (). However, if dynamic binding is used, the version of the print function that would be called would be determined at run-time based on the actual object type rather than the declared type. Therefore, if the object x is of type Student, the Student class's version of the print function would be called. This corresponds to answer a.

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(T/F) the div instruction generates a divide overflow condition when the remainder is too large to fit into the destination operand.

Answers

The statement is true. The div instruction is used in assembly language to perform division operations.

However, if the quotient produced by the div instruction is larger than what can fit into the destination operand, a divide overflow condition occurs. This is because the div instruction is designed to work with specific register sizes and if the result of the division operation is larger than the size of the register, an overflow occurs. In such cases, the processor raises an exception or error indicating that the result of the division operation cannot be stored in the destination operand. It is therefore important for programmers to ensure that they allocate sufficient memory space to hold the result of the division operation to avoid such errors.

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The statement is False. The div instruction generates a divide overflow condition when the quotient is too large to fit into the destination operand. The remainder is not considered in this case.

The div instruction is used to perform unsigned integer division in assembly language. The div instruction divides the contents of a 16-bit or 32-bit register by an operand and stores the result in another register. If the quotient of the division is larger than the register that holds the result, then an overflow condition is generated. However, if the quotient is smaller than or equal to the register, the instruction completes successfully and the remainder is stored in the register that is designated for that purpose. Therefore, the div instruction does not generate a divide overflow condition when the remainder is too large to fit into the destination operand.

For example, if we divide 255 by 0, the quotient would be undefined and the divide instruction would generate a divide by zero exception. If we divide 255 by 1 using the div instruction and store the result in an 8-bit register, the quotient would be 255 which fits into the register. However, if we divide 255 by 2 using the div instruction and try to store the result in an 8-bit register, the quotient would be 127.5 which does not fit into an 8-bit register and the divide instruction would generate a divide overflow exception.

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typically, if a class defines a move constructor and a move assignment operator, its destructor would be defined to delete any heap resources an object of the class maintains a pointer to.true false

Answers

True.

If a class defines a move constructor and a move assignment operator, it is likely that the class manages heap resources through pointers. In such cases, the destructor should be defined to delete any heap resources that the object of the class maintains a pointer to.

This is to ensure that there are no memory leaks and the object is safely destroyed when it goes out of scope.Your question is whether it's true or false that if a class defines a move constructor and a move assignment operator, its destructor would typically be defined to delete any heap resources an object of the class maintains a pointer to.
When a class defines a move constructor and a move assignment operator, it often indicates that the class manages resources such as heap memory. To prevent memory leaks, the destructor should be defined to delete any heap resources an object of the class maintains a pointer to.False. If a class defines a move constructor and a move assignment operator, it does not necessarily mean that its destructor would be defined to delete any heap resources that an object of the class maintains a pointer to. It depends on how the class manages its resources and what the intended behavior is. If the class is responsible for managing heap resources, then its destructor should be defined to release those resources. However, if the class does not manage heap resources or if it transfers ownership of those resources to another object during a move operation, then its destructor may not need to delete those resourcesIn general, the destructor of a class should be defined to clean up any resources that the class owns, regardless of whether the class defines a move constructor or a move assignment operator.

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Write an openflow flow entry that drops all the packets with destination address 128.11.11.1!

Answers

The flow entry will match all IP packets with the destination address 128.11.11.1 and drop them accordingly. To drop all packets with destination, address 128.11.11.1 using OpenFlow, you can create an entry in the flow table of the switch.

The entry should match on the destination address field and have an action of drop. The command to add this entry would look something like this:
ovs-ofctl add-flow "priority=10, dl_dst=128.11.11.1, actions=drop"
This command adds a flow entry with a priority of 10 (lower priority than other entries), matches on the destination address field (dl_dst) with the value 128.11.11.1, and sets the action to drop. This means that any packet that matches this flow entry will be dropped by the switch.

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Which action is used to create the PAR for the MGIB elections?

Answers

To create the Payment and Accounting Record (PAR) for the Montgomery GI Bill (MGIB) elections, the action used is the submission and processing of VA Form 22-1990.

The action used to create the PAR (Participation Agreement Request) for the MGIB (Montgomery GI Bill) elections is filling out and submitting the VA Form 22-1990 (Application for VA Education Benefits) or the VA Form 22-1995 (Request for Change of Program or Place of Training). These forms must be completed and submitted to the VA in order to participate in the MGIB program and receive education benefits.
To create the Payment and Accounting Record (PAR) for the Montgomery GI Bill (MGIB) elections, the action used is the submission and processing of VA Form 22-1990. This form is used by veterans and service members to apply for educational benefits under the MGIB program. Once the form is processed, the PAR is generated to facilitate payment and tracking of benefits.

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estimate the force required for punching a 25-mm diameter hole through a 3.2-mm thick annealed titanium alloy ti-6al-4v sheet at room temperature. assume the uts of the titanium alloy is 1000 mpa.

Answers

An object's force is equal to its mass times its acceleration, or F = m a. To apply this formula, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).

To estimate the force required for punching a 25-mm diameter hole through a 3.2-mm thick annealed titanium alloy Ti-6Al-4V sheet at room temperature, with an ultimate tensile strength (UTS) of 1000 MPa, follow these steps:

1. Calculate the cross-sectional area of the hole:
Area = π × (Diameter / 2)^2
Area = π × (25 mm / 2)^2
Area ≈ 490.87 mm²

2. Calculate the shear area:
Shear Area = Hole Area × Sheet Thickness
Shear Area = 490.87 mm² × 3.2 mm
Shear Area ≈ 1570.78 mm²

3. Calculate the force required:
Force = Shear Area × UTS
Force = 1570.78 mm² × 1000 MPa
Force = 1570.78 mm² × 1000 N/mm² (since 1 MPa = 1 N/mm²)

Force ≈ 1,570,780 N

Thus, the estimated force required for punching a 25-mm diameter hole through a 3.2-mm thick annealed titanium alloy Ti-6Al-4V sheet at room temperature is approximately 1,570,780 Newtons.

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What are the values of i and sum after this code sequence isexecutedpublic static void main(String[] args) { int sum = 0;int i = 17;while ( i % 10 !=0){sum += i;i++;}

Answers

The code sequence will execute a while loop that increments the value of i and adds it to the sum variable until i is divisible by 10. The initial value of i is 17, and the loop will continue until i becomes divisible by 10.

The values of i and sum after the code sequence is executed will be:

i = 20
sum = 54

Explanation:

i starts with the value of 17.
The while loop condition i % 10 != 0 checks if i is not divisible by 10. If i is not divisible by 10, the loop will continue.
Inside the loop, i is added to sum using the statement sum += i;, which is equivalent to sum = sum + i;.
i is then incremented by 1 using i++; statement.
The loop continues until i becomes divisible by 10, which happens when i reaches the value of 20.
At that point, the loop condition i % 10 != 0 becomes false, and the loop exits.
Therefore, the final value of i is 20, and the final value of sum is 54, which is the sum of 17, 18, and 19.

What are the 2 ways to use the keyword ""super"" in a class? - Give code examples to demonstrate your answers.

Answers

In a class, the keyword "super" can be used in two ways:

1. To call a superclass constructor:
The "super" keyword can be used to call the constructor of the superclass. This is useful when you want to reuse the code of the superclass constructor in the subclass constructor. The syntax for calling a superclass constructor using the "super" keyword is as follows:

```
public class SubClass extends SuperClass {
   public SubClass(int arg1, int arg2) {
       super(arg1, arg2);
   }
}
```

In this example, the SubClass extends the SuperClass and the constructor of the SubClass calls the constructor of the SuperClass using the "super" keyword.

2. To call a superclass method:
The "super" keyword can also be used to call a method of the superclass from the subclass. This is useful when you want to use the functionality of the superclass method in the subclass method. The syntax for calling a superclass method using the "super" keyword is as follows:

```
public class SubClass extends SuperClass {
   public void someMethod() {
       super.someMethod(); // calls the someMethod() of the SuperClass
       // additional code for the SubClass
   }
}
```

In this example, the SubClass extends the SuperClass and the someMethod() of the SubClass calls the someMethod() of the SuperClass using the "super" keyword.




1. Calling a superclass constructor:

```java
class Parent {
   public Parent() {
       System.out.println("Parent class constructor");
   }
}

class Child extends Parent {
   public Child() {
       super(); // Calls the superclass constructor
       System.out.println("Child class constructor");
   }
}

public class Main {
   public static void main(String[] args) {
       Child child = new Child();
   }
}
```

In this example, the `super()` call in the `Child` class constructor ensures that the `Parent` class constructor is executed first. The output will be:

```
Parent class constructor
Child class constructor
```

2. Accessing a superclass method or field:

```java
class Parent {
   protected String parentField = "Parent field";

   protected void parentMethod() {
       System.out.println("Parent class method");
   }
}

class Child extends Parent {
   public void accessSuper() {
       super.parentMethod(); // Calls the superclass method
       System.out.println(super.parentField); // Accesses the superclass field
   }
}

public class Main {
   public static void main(String[] args) {
       Child child = new Child();
       child.accessSuper();
   }
}
```

In this example, the `super.parentMethod()` and `super.parentField` calls in the `Child` class access the superclass method and field, respectively. The output will be:

```
Parent class method
Parent field
```

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true or false a method can have another type of modifier after its access modifier

Answers

The statement is true.

A method can have another type of modifier after its access modifier. For example, a method can have a "static" modifier after its "public" access modifier to indicate that the method belongs to the class rather than an instance of the class. Another example is the "final" modifier that can be added after the access modifier to indicate that the method cannot be overridden in a subclass.

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The statement is true.

A method can have another type of modifier after its access modifier. For example, a method can have a "static" modifier after its "public" access modifier to indicate that the method belongs to the class rather than an instance of the class. Another example is the "final" modifier that can be added after the access modifier to indicate that the method cannot be overridden in a subclass.

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True or false. Genomics is an old science that is being replaced with computer technology

Answers

Answer:

False

Explanation:

The correct answer is false. Genomics is a relatively new technology compared to other biotechnologies from the past and it started around the 1970s when Frederick Sanger developed the first sequencing technique to sequence the entire genome. There were many discoveries prior to this such as the discovery of the structure of DNA and its bases. The Human Genome Project was launched in 1990 with the goal to sequence the entire human genome and was completed in 2003. Since then there have been many advancements in DNA sequencing technologies such as next-generation sequencing (NGS).

I hoped this helped <33

Where does memory management reside?

Answers

Memory management resides within the kernel of an operating system, which is the core component responsible for managing system resources.

Memory management refers to the process of controlling and coordinating the use of computer memory. It is an essential component of any operating system, including Windows, Linux, macOS, and Android. In most modern operating systems, the kernel is loaded into memory at system boot and remains resident throughout the entire operation of the computer. The kernel provides a range of services, including memory allocation and deallocation, virtual memory management, and memory protection. Memory management ensures that applications have access to the memory they require while preventing conflicts and crashes caused by memory-related issues.

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A routing protocol's reliability and priority are rated by what measurement? A. Routing table. B. MTU. C. Latency. D. AD. Answer: D. AD

Answers

Administrative Distance is a metric used to determine the reliability and priority of a routing protocol. It helps in selecting the best route among multiple routing protocols when there are multiple paths to a destination. A lower AD value indicates a more reliable and higher priority routing protocol.

When a router receives multiple routing updates for the same destination network from different routing protocols, it uses the administrative distance to determine which route to use. The route with the lowest administrative distance is preferred, as it is considered more reliable and has a higher priority.

For example, the administrative distance for a directly connected network is typically set to 0 because it is the most reliable and preferred route. The administrative distance for a static route may be set to 1 or a higher value, depending on the network administrator's preference. The administrative distances for common routing protocols such as OSPF, EIGRP, and BGP are pre-defined and may be adjusted by the network administrator if necessary.

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Data And Report Submission - Copper- Catalyzed Oxidation Of Benzoin (28pts) Data (2pts) Amount of reactant used in grams (4pts) Amount of reactant in moles (2pts) Product obtained in grams (4pts) Product obtained in moles (6pts) Product theoretical yield (6pts) Product percent yield (4pts) Write the equation for the reaction 1. Is your percent yield within reason of what you would expect?

Answers

First, we need to write the equation for the reaction. The Copper-catalyzed oxidation of Benzoin produces Benzil and Copper(I) oxide as products. The balanced chemical equation for the reaction is.

2C6H5CHOHCOOH + Cu2+ + H2O2 → 2C6H5CO2C6H5 + CuO + 2H2O

The data for the Copper-catalyzed oxidation of Benzoin experiment includes the following information:
- Amount of reactant used in grams (4pts)
- Amount of reactant in moles (2pts)
- Product obtained in grams (4pts)
- Product obtained in moles (6pts)
- Product theoretical yield (6pts)
- Product percent yield (4pts)

To answer the question, we need to use the given data to calculate the amount of product obtained and the percent yield.
Next, we can use the amount of reactant used in grams to calculate the amount of reactant in moles using the molar mass of Benzoin.
Assuming the molar mass of Benzoin is 212.24 g/mol, if we used 2 grams of Benzoin, then the amount of reactant in moles would be:
2 g Benzoin x 1 mol Benzoin / 212.24 g Benzoin = 0.00942 mol Benzoin
Using the balanced chemical equation, we can also calculate the theoretical yield of the product. Since 2 moles of Benzoin react to produce 1 mole of Benzil, the theoretical yield of Benzil would be:
0.00942 mol Benzoin x 1 mol Benzil / 2 mol Benzoin = 0.00471 mol Benzil
Using the molar mass of Benzil (212.24 g/mol), we can calculate the theoretical yield of the product in grams:
0.00471 mol Benzil x 212.24 g/mol = 1 g Benzil


However, the actual amount of product obtained in grams is given as 0.8 g. To calculate the percent yield of the product, we can use the formula:
Percent yield = (Actual yield / Theoretical yield) x 100%
Plugging in the given values, we get:
Percent yield = (0.8 g / 1 g) x 100% = 80%

Finally, we can analyze whether the percent yield is within reason of what we would expect. The percent yield of a reaction indicates how efficient the reaction is in producing the desired product. A percent yield of 80% is relatively good, indicating that the reaction was fairly efficient. However, it's difficult to determine what a "reasonable" percent yield would be without more context about the experiment and the specific reaction conditions. Generally, a percent yield of 80-90% is considered good, but it depends on various factors such as the reaction mechanism, reactant purity, and experimental errors.
Hi! To answer your question about the Copper-catalyzed oxidation of Benzoin, I'll provide a general framework for the data and report submission. Please note that I cannot provide specific values as they would depend on your experiment and measurements.

1. Data (2pts): Record the mass of the Copper catalyst and Benzoin reactant used in grams.
2. Amount of reactant in moles (4pts): Convert the mass of Benzoin in grams to moles using its molar mass.
3. Product obtained in grams (2pts): Measure and record the mass of the product obtained in grams.
4. Product obtained in moles (4pts): Convert the mass of the product in grams to moles using its molar mass.
5. Product theoretical yield (6pts): Calculate the theoretical yield based on the stoichiometry of the balanced reaction equation.
6. Product percent yield (4pts): Calculate the percent yield by comparing the actual yield (obtained) to the theoretical yield.
7. Write the equation for the reaction: 2 C6H5CH(OH)C(O)C6H5 + [O] → 2 C6H5C(O)C(O)C6H5 + H2O (using a Copper catalyst)

To determine if your percent yield is within reason, compare it to the expected range for this reaction (which can vary depending on the specific conditions and setup). A yield of around 60-90% is generally considered acceptable. However, consult any literature or sources for this particular reaction to have a better understanding of the expected yield range.

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states that any task done by software can also be done using hardware and vice versa, a. Hardware protocol b. Rock's Law
c. Moore's Law d. The Principle of Equivalence of Hardware and Software

Answers

The answer is d. The Principle of Equivalence of Hardware and Software.

The Principle of Equivalence of Hardware and Software, also known as Von Neumann's Principle, states that any task that can be done by software can also be done using hardware and vice versa. This principle was proposed by John Von Neumann, a Hungarian-American mathematician and computer scientist, who is widely regarded as one of the most influential figures in the development of computer science. The principle has played a crucial role in the development of modern computing, as it has allowed software and hardware engineers to work together to create more efficient and effective computing systems.

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Emergency contact information is the only area that can be updated without going into the DD Form 93 itself.

Answers

Emergency contact information is an essential aspect of the DD Form 93. However, it is not the only area that can be updated without accessing the form itself.

Emergency contact information is the only section on the DD Form 93 that can be updated without having to modify the entire form. This means that if your emergency contact information changes, you can simply update that section without having to fill out a new DD Form 93. However, it's important to note that any other changes to the form (such as beneficiary designations or personal information) will require a new form to be filled out and submitted. I hope that helps! Let me know if you have any other questions.
Emergency contact information is an essential aspect of the DD Form 93. However, it is not the only area that can be updated without accessing the form itself. Other sections, such as beneficiaries and insurance information, may also require updates. To ensure accuracy and completeness, it's best to review the entire DD Form 93 when making any changes.

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when solving problems, the users of an information system must avoid using informal information. true or false

Answers

Answer:

True

Explanation:

They need to have formal information

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