To determine if ink is a pure substance or a mixture, you can perform various tests and observations. One approach is to analyze the ink using chromatography, which separates the components of a mixture based on their different affinities for a stationary phase. By comparing the results with known pure substances, you can determine if the ink is composed of a single component or a mixture of substances.
Chromatography is a widely used technique to analyze the composition of mixtures. In the case of ink, you can apply a small sample onto a chromatography paper and allow it to migrate in a solvent. As the solvent moves up the paper, it carries the ink components with it. Different components of the ink will have varying affinities for the paper and the solvent, leading to their separation. If the ink contains only one component, such as a single dye, you will observe a single spot or band on the paper.
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A solution is made by mixing 140. g of water and 91. g of methanol (CH3OH) Calculate the mole fraction of water in this solution. Be sure your answer has the correct number of significant digits.
The mole fraction of water in the solution is 0.62.
To calculate the mole fraction of water in the solution, we need to determine the moles of water and methanol present.
Mass of water = 140 g
Mass of methanol = 91 g
Molar mass of water (H2O) = 18.015 g/mol
Molar mass of methanol (CH3OH) = 32.04 g/mol
Step 1: Calculate the number of moles of water and methanol.
Moles of water = Mass of water / Molar mass of water
Moles of water = 140 g / 18.015 g/mol ≈ 7.773 mol
Moles of methanol = Mass of methanol / Molar mass of methanol
Moles of methanol = 91 g / 32.04 g/mol ≈ 2.840 mol
Step 2: Calculate the total moles of the solution.
Total moles = Moles of water + Moles of methanol
Total moles = 7.773 mol + 2.840 mol = 10.613 mol
Step 3: Calculate the mole fraction of water.
Mole fraction of water = Moles of water / Total moles
Mole fraction of water = 7.773 mol / 10.613 mol ≈ 0.732
The mole fraction of water in the solution is approximately 0.732.
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Why might changes to an environment cause an organism’s population to decrease?
um...id.k how to do chemistry...help please?
Answer:
NaBr
Explanation:
Answer:
um...id.k how to do chemistry...help please?
Explanation:
NaBr
AQRS is an isosceles triangle. What is the length of RT
? Round to the nearest hundredth. Enter your answer in the box.
11 cm
a
T 6cm s
Answer:
Length of RT = 9.22 cm to the nearest hundredth
Explanation:
Considering the image up in the attachment, ΔRST is a right-angled triangle.
The length of two sides of ΔRST is given as 11cm and 6 cm. The length of the third side which is RT can be obtained using Pythagoras ' rule which says that the sum of the squares of two sides of a right-angled triangle is equal to the square of the hypotenuse.
This rule is given as: c² = b² + a² where c is the hypotenuse and a and b are the other two sides of the right-angled triangle.
In ΔRST, the length of the hypotenuse = 11 cm, the length of one of the two sides = 6cm, length of RT = x
Solving for x: (11 cm)² = (x cm)² + (6 cm)²
(x cm)² = 121 cm² - 36 cm²
(x cm)² = 85 cm²
x cm = √85
x = 9.22 cm to the nearest hundredth
Therefore, length of RT = 9.22 cm to the nearest hundredth
The kidneys help the body preserve water. When an animal has not had enough to drink, the kidneys signal the body to absorb water. The animal produces little urine, so it loses less water. During this process, the kidneys work in conjunction with which body system?
Answer:
This regulatory mechanism is in conjunction with the endocrine system, particularly in the posterior pituitary gland. This is related in the secretion of vasopressin or antidiuretic hormone (ADH). In the event of dehydration or extreme thirst, the body will conserve as much fluid as possible and the posterior pituitary will secrete more ADH that will signal the kidney to reabsorb more water in the collecting tubules.
Calculate the number of grams of solute in 500.0 mL of 0.179 M KOH. A) 5.02 g B) 1.60 g C) 5.02 x103 g D) 157 g
The mass (in grams) of solute in 500 mL of 0.179 M potassium hydroxide, KOH solution is 5.02 grams (option A)
How do i determine the mass of KOH?First, we shall obtain the mole of KOH in the solution. Details below:
Volume = 500 mL = 500 / 1000 = 0.5 LMolarity = 0.179 MMole of KOH =?Mole of solute = molarity × volume
Mole of KOH = 0.179 × 0.5
Mole of KOH = 0.0895 mole
Finally, we shall determine the mass of solute, KOH in the solution. Details below:
Mole of KOH = 0.0895 moleMolar mass of KOH = 56.1 g/molMass of KOH = ?Mass = Mole × molar mass
Mass of KOH = 0.0895 × 56
Mass of KOH = 5.02 grams
Therefore, the mass of KOH present in the solution is 5.02 grams (option A)
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why is there most absorbance when the solution and beam colors are different?
The reason behind the most absorbance when the solution and beam colors are different is due to the absorption spectrum.
The absorption spectrum is the range of electromagnetic radiation that a substance can absorb, and it's unique to every substance. When a beam of light passes through a substance, the substance's molecules absorb some of the light's energy.
This means that some of the light is lost, and the rest is transmitted. The amount of energy absorbed by the substance is dependent on the wavelength of the light and the substance's properties.The color of a substance is due to its ability to absorb some wavelengths of light and reflect others.
For example, a blue object reflects blue light and absorbs all other colors of light. When a blue solution is exposed to a beam of orange light, the blue solution will absorb the orange light, causing the solution to appear darker and resulting in high absorbance.
This phenomenon is known as complementary colors and is seen when a solution and a beam of light are different colors, leading to high absorbance of light.
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Please help I'm so confused!! Turn the following Aufbau Diagrams into Ions
Guys please help me ill give brainily points
When an apple is cut open and left out on a table in your kitchen it turns brown over
time when oxygen reacts with the apple. Describe what happens to oxygen atoms in
order to make O2 instead of 0 +2 i
Answer:
Alright, We all know fruits contains enzyme, so there is a reaction name enzymic browning! Actually what happens when we cut the apple and keep it open the organic enzyme molecules starts reacting with oxygen of surroundings and oxidises it!
hi trying this again :D What are ALWAYS the products of the complete combustion of a hydrocarbon? Check all that apply.
- oxygen
- water
- carbon dioxide
- hydrogen
- sulfur trioxide
it should be carbon dioxide and water
6. Calculate the molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3).
The molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3) is 180.157 g/mol.What is molecular mass Molecular mass is the sum of the masses of all the atoms in a molecule. The unit of molecular mass is grams per mole the are (g/mol).Acetylsalicylic acid molecular
mass calculation In acetylsalicylic acid, HOOC-C6H4-OOCCH3, add the mass of each atom:Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/ (C) = 9 x 12.01 g/mol = 108.09 g/mol Hydrogen (H) = 8 x 1.01 g/mol = 8.08 g/molAdd the masses of all the atoms to calculate the molecular mass:32.00 g/mol + 108.09 g/mol + 8.08 g/mol = 148.17 g/molThe molecular mass of acetylsalicylic acid is 180.157 g/mol (approximately)
Molecular mass is the mass of a molecule measured in atomic mass units (amu). The molecular mass is the sum of the atomic masses of all the atoms present in the molecule.The molecular mass formula can be written as: Molecular mass = (mass of first element × number of atoms) + (mass of second element × number of atoms) + ...The molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3) can be calculated by adding the mass of each atom. Here's how to calculate the molecular mass of acetylsalicylic acid:Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/molCarbon (C) = 9 x 12.01 g/mol = 108.09 g/molHydrogen (H) = 8 x 1.01 g/mol = 8.08 g/molAdd the masses of all the atoms to calculate the molecular mass:32.00 g/mol + 108.09 g/mol + 8.08 g/mol = 148.17 g/molThe molecular mass of acetylsalicylic acid is 180.157 g/mol (approximately) the formula to calculate molecular mass.
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Balance the chemical equation for the following redox reaction under acidic aqueous conditions with the smallest whole-number coefficients possible using the half-reaction method. On which side does H2O(l) appear, and what is its coefficient?
MnO4^-(aq)+NH3(aq)---->Mn^2+(aq)+NO2(g)
Water ([tex]H_{2}O[/tex]) appears on the product side with a coefficient of 8. To balance the given redox reaction, we can use the half-reaction method. Let's begin by balancing the reduction half-reaction and the oxidation half-reaction separately.
Reduction half-reaction: [tex]MnO_{4}^{-aq}[/tex] + [tex]8H^{+aq}[/tex] + [tex]5e^{-}[/tex] → [tex]Mn^{2+}[/tex](aq) + [tex]4H_{2}O[/tex](l)
Oxidation half-reaction: [tex]NH_{3}[/tex](aq) → [tex]NO_{2}[/tex](g) + [tex]3H^{+}[/tex](aq) + [tex]2e^{-}[/tex]
Next, we need to balance the number of electrons transferred in both half-reactions. To do this, we multiply the oxidation half-reaction by 5 and the reduction half-reaction by 2:
[tex]2NH_{3}[/tex](aq) → [tex]2NO_{2}[/tex](g) + [tex]6H^{+}[/tex](aq) + [tex]4e^{-}[/tex]
[tex]2MnO_{4}^-[/tex](aq) + [tex]16H^{+}[/tex]+(aq) + [tex]10e^{-}[/tex] → [tex]2Mn^{2+}[/tex](aq) + [tex]8H_{2}O[/tex](l)
Now, we can combine the two half-reactions and cancel out the common species:
[tex]2MnO_{4}^-[/tex](aq) + [tex]16H^{+}[/tex](aq) + [tex]10NH_{3}[/tex](aq) → [tex]2Mn^{2+}[/tex](aq) + [tex]2NO_{2}[/tex](g) + [tex]8H_{2}O[/tex](l)
From the balanced equation, we can see that water ([tex]H_{2}O[/tex]) appears on the product side with a coefficient of 8.
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A coffee cup calorimeter with a heat capacity of 6. 70 J/∘ C was used to measure the change in enthalpy of a precipitation reaction. A 50. 0 mL solution of 0. 360 M AgNO3 was mixed with 50. 0 mL of 0. 540 M KSCN. After mixing, the temperature was observed to increase by 4. 06∘C. Calculate the enthalpy of reaction, ΔHrxn, per mole of precipitate formed (AgSCN). Assume the specific heat of the product solution is 4. 11 J / (g⋅∘C) and that the density of both the reactant solutions is 1. 00 g/mL. Calculate the theoretical moles of precipitate formed from AgNO3 and KSCN. Moles of precipitate formed from AgNO3: mol moles of precipitate formed from KSCN: mol Calculate the heat change experienced by the calorimeter contents, ????contents. ????contents= J Calculate the heat change expierenced by the calorimeter contents, ????cal. ????cal= J Calculate the heat change produced by the solution process, ????solution. ????solution= J Calulate ΔHsolution for one mole of precipitate formed. ΔHsolution= kJ/mole
A coffee cup temperature with a heat capacity of 6. 70 J/∘ C was used to measure the change in enthalpy of a precipitation reaction.The value of ΔHrxn was found to be 61.9 kJ/mol.
Calculate the enthalpy of reaction, ΔHrxn, per mole of precipitate formed (AgSCN). Assume the specific heat of the product solution is 4. 11 J / (g⋅∘C) and that the density of both the reactant solutions is 1. 00 g/mL.1. Calculation of Moles of precipitate formed from AgNO3:To find the value of ΔHrxn, we used the formula ΔHrxn = Qsolution/n, where Qsolution is the heat change produced by the solution process and n is the number of moles of AgSCN formed.
To find the value of n, we first calculated the number of moles of AgNO3 and KSCN used in the reaction using the formula n = M × V.To find the heat change produced by the solution process, we used the formula
Q = m × c × ∆T,
where Q is the heat change, m is the mass of the product solution, c is the specific heat capacity of the product solution, and ∆T is the change in temperature of the solution.The value of ΔHrxn was found to be 61.9 kJ/mol.
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Predict whether or not the following compounds would be more soluble in an acidic solution, a basic solution, or whether pH would have little to no effect on its solubility. A. AgBr Select] B. LiF [Select] C. Ca(OH)2 [Select ] D. Fel: [Select ]
Answer: A. AgBr: pH would have little to no effect on its solubility.
B. LiF: pH would have little to no effect on its solubility.
C. Ca(OH)2: more soluble in a basic solution.
D. FeI3: more soluble in an acidic solution.
Explanation:)
Solubility of AgBr, LiF, Ca(OH)2, FeI2 based on acidic, basic, or neutral pHThe pH of the solution has an effect on the solubility of several compounds. Salts of weak acids or bases dissolve more in a basic or acidic environment, respectively, than in neutral water.
On the other hand, salts of strong acids and bases are mostly soluble in water and are not affected by the pH of the solution. The solubility of the given compounds will be affected as follows:AgBr: AgBr will dissolve more in an acidic solution because it is an ionic compound of a weak acid HBr. The equation for the dissociation of HBr is HBr⇌H+ + Br-. When the pH is reduced, H+ concentration increases, leading to the reaction moving to the left, ultimately resulting in the formation of more HBr. LiF: LiF is a salt of a strong acid (hydrofluoric acid) and a strong base (lithium hydroxide). Its solubility will not be affected by pH since it is mostly soluble in water.Ca(OH)2: Calcium hydroxide is a salt of a strong base (calcium oxide) and a strong acid (water). Its solubility will not be influenced by pH since it is mostly soluble in water.FeI2: Iron (II) iodide is an ionic compound with a weak acid (HI) and a strong base (Fe(OH)2). Its solubility would increase in an acidic environment. Since I- is a weak conjugate base of HI, the equation for the dissociation of HI would shift to the left in the presence of H+ ions in the acidic solution. Hence FeI2 will dissolve more in an acidic environment.
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Calcular una solución que contiene 250 g de cloruro de calcio en 1500 mL de solución y tiene una decidad de 1,2gr/ml
Answer:
13.89% p/p
Explanation:
El porcentaje peso a peso de una solución (%p/p) es definido como cien veces la relación entre la masa del soluto (En este caso, cloruro de calcio) y la masa de la solución. La ecuación es:
%p/p = Masa cloruro de calcio (250g)/ Masa solución * 100
Para hallar la masa de la solución debemos usar el volumen y la densidad de este:
1500mL * (1,2g / mL) = 1800g
Así, el %p/p será:
250g / 1800g * 100
13.89% p/p
Which would be the best starting question to determine
the composition of the Outer Core and the Inner Core?
A) Are the Outer Core and the Inner Core composed of
large amounts of iron?
B) How much rock do the Outer Core and the Inner Core
contain?
C) How deep in the Earth are the Outer Core and the
Inner Core?
D) Are the Outer Core and the Inner Core composed of
large amounts of metal?
If you have 35 moles of sodium hydroxide (NaOH) in a 5000 mL solution, what is the concentration of the NaOH in the solution?
Answer:
7 mol.dm^3
Explanation:
formula for calculating concentration: C = n/v
Start by changing 5000ml solution to dm^3 because volume is in dm^3
1 ml = 1cm^3
then from a cm^3 to dm^3 you divide by 1000
5000ml = 5000cm^3
5000÷1000= 5dm^3
c = n/v
= 35/5
= 7mol.dm^3
What does the word Microbial mean?
Answer:
relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.
Explanation:
ex: "skin is a major source of microbial contamination during a surgical procedure"
◕‿↼ Hey There!
Answer → Microbial means, relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.
✨Hope This Helps!✨
The shark and remora have a relationship that benefits the remora but neither helps nor harms the shark. What type of relationship is this?
commensalism
or
predation
or
mutualism
or
parasitism
Answer:
commensalism
Explanation:
It's not parasitism as the shark is not harmed in the relationship
please help me i need this good grade
Which organisms are decomposers?
Select all correct answers.
mushrooms
snake
bacteria
grass
mold
Answer:
mushrooms bacteria mold
Explanation:
An unknown piece of metal absorbs 1350 J of heat as 55.0 g of the metal heats up from 20.0 oC to 47.0 oC
Answer:
[tex]C=0.91\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it is possible to recall the equation to calculate the heat, Q, in these calorimetry problems as shown below:
[tex]Q=mC(T_f-T_i)[/tex]
Thus, given the absorbed heat, mass and temperatures, we can easily calculate the specific heat of the metal as shown below:
[tex]C=\frac{Q}{m(T_f-T_i)}[/tex]
Then, by plugging in we obtain:
[tex]C=\frac{1350J}{55.0g(47.0\°C-20.0\°C)} \\\\C=0.91\frac{J}{g\°C}[/tex]
Best regards!
Choose all the nucleophiles.
Choose one or more:
CH3SNa
NaNH2
H3O+
CH3OH
CH3CH2CH3
NH4+
OH-
(CH3)3CLi
Answer:
CH3CH2CH3
(CH3)3CLi
CH3SNa
Explanation:
A direct current power supply of low voltage (less than 10 volts) has lost the markings that indicate which output terminal is positive and which is negative. A chemist suggests that the power supply terminals be connected to a pair of platinum electrodes that dip into 0.1-molar KI solution. Which of the following correctly identifies the polarities of the power supply terminals? (A) A gas will be evolved only at the positive electrode. Correct or incorrect? Explanation: (B) A gas will be evolved only at the negative electrode. Correct or incorrect? Explanation: (C) A brown color will appear in the solution near the negative electrode. Correct or incorrect? Explanation: (D) A metal will be deposited on the positive electrode. Correct or incorrect? Explanation: (E) None of the methods above will identify the polarities of the power supply terminals.
A direct current power supply of low voltage (less than 10 volts) has lost the markings that indicate which output terminal is positive and which is negative. A chemist suggests that the power supply terminals be connected to a pair of platinum electrodes that dip into 0.1-molar KI solution. Only (B) A gas will be evolved only at the negative electrode correctly identifies the polarities of the power supply terminals.
When the power supply terminals are connected to a pair of platinum electrodes dipping into a 0.1-molar KI solution, the electrolysis of the solution will occur. In the process of electrolysis, the positive electrode (anode) attracts negatively charged ions (anions) and the negative electrode (cathode) attracts positively charged ions (cations).
In this case, when a gas is evolved, it indicates that reduction is occurring at the electrode. The gas evolved will be hydrogen gas (H₂) from the reduction of H⁺ ions in the KI solution.
Since hydrogen gas is evolved only at the negative electrode (cathode), the correct identification of the polarities of the power supply terminals is that a gas will be evolved only at the negative electrode.
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HELP ME WOTH QUESTION BELOW PLEASE
tip
this is just a tip not the true answer but try to add the given number
What is the relationship between the valence electrons of an atom and the chemical bonds the atom can form?
Answer:
Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.
A boy is skating down the street, hits a curb, and files off the board. Why did this happened? Can y’all plz help me it’s due today!
Answer:
to much sause
Explanation:
which of the following elements has the lowest first ionization eneygy A, potassium B, sodium C, calcium D, Argon
Answer:
Argon
Explanation:
Because, it is positioned down on the periodic table
Answer:
Argon
Explanation:
how many moles of oh−(aq) (hydroxide ions)are present in the balanced redox reaction?
A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process. The number of moles of hydroxide ions in the given balanced equation is 2.
A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and charge are both equal.
The numbers which are used to balance the given chemical equation are known as the coefficients.
Here the balanced equation is:
2NO₃⁻(aq) + 3ClO⁻(aq) + H₂O(l) → 2NO(g) + 3ClO₂⁻(aq) + 2OH⁻(aq)
The moles of OH⁻ required is 2.
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calculate the linear atomic density in atoms per millimeter for the following directions in bcc tantalum, which has a lattice constant of 0.33026nm: (a) [100], (b) [110], (c) [111]
The linear atomic density in atoms per millimeter can be calculated for different crystallographic directions in bcc tantalum, which has a lattice constant of 0.33026 nm. The linear atomic density for the [100], [110], and [111] directions can be determined by dividing the number of atoms along the direction by the length of the direction.
The linear atomic density in atoms per millimeter can be calculated by dividing the number of atoms along a specific crystallographic direction by the length of that direction. In bcc (body-centered cubic) crystals, there are specific arrangements of atoms along different crystallographic directions.
(a) For the [100] direction, there is one atom per unit cell. The length of the [100] direction can be determined using the lattice constant, which is 0.33026 nm. Therefore, the linear atomic density for the [100] direction is 1 atom / (0.33026 nm) = 3.027 atoms/nm or 30.27 atoms/mm.
(b) For the [110] direction, there are two atoms per unit cell. The length of the [110] direction can be calculated by multiplying the lattice constant by the square root of 2. Therefore, the linear atomic density for the [110] direction is 2 atoms / (0.33026 nm √2) = 6.054 atoms/nm or 60.54 atoms/mm.
(c) For the [111] direction, there are three atoms per unit cell. The length of the [111] direction can be calculated by multiplying the lattice constant by the square root of 3. Therefore, the linear atomic density for the [111] direction is 3 atoms / (0.33026 nm √3) = 9.090 atoms/nm or 90.90 atoms/mm.
Thus, the linear atomic density in atoms per millimeter for the [100], [110], and [111] directions in bcc tantalum are approximately 30.27 atoms/mm, 60.54 atoms/mm, and 90.90 atoms/mm, respectively.
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