28. Write the equation of the line that has a slope of zero and passes through the point (2, -3). [A] y=-3x+2 [B] y=-3 [C] y=2 C] y=2x-3 [D] y=2x + 2​

Answer:

1/5

Step-by-step explanation:

rise = 2 ft

run = 10 ft

slope = rise/run = 2/10 = 1/5

Answer: 1/5

Answer:

1/5

Step-by-step explanation:

The slope is the rise over the run

Y / x

2/10

1/5

Answer:

I'm going to use the following as an example.

[tex]2x + 4y = 8[/tex]

To find the y-intercept, set x equal to 0 then solve for y.

[tex]2(0) + 4y = 8[/tex]

two times zero is zero, so we have the following equation.

[tex]4y = 8[/tex]

Solve for y

[tex] \frac{4y}{4} = \frac{8}{4} \\ y = 2[/tex]

Your first point you will graph is (0, 2).

Now solve for the x intercept. To do this, set y = 0.

[tex]2x + 4(0) = 8[/tex]

4(0) = 0, so you can remove it, and solve for x.

[tex]2x = 8[/tex]

[tex] \frac{2x}{2} = \frac{8}{2} \\ x = 4[/tex]

Now the next point you have is (4, 0). plot that point. Connect the two points with a line and you are done.

Answer:

Step-by-step explanation:

We know the hypotenuse and legs of 45° right triangle have ratio:

Substitute given values and find x:

Answer:

2.45 g/cm3

Step-by-step explanation:

It's a cube, so all the side lengths are the same. It's volume is [tex](5cm)^3[/tex] = [tex]125 cm^3[/tex].

At this point, we apply the definition of density [tex]\rho = \frac mV[/tex] where m is the mass and V the volume.[tex]\rho = \frac{306.25g}{125 cm^3} = 2.45 g/cm^3[/tex]

Answer:

1 3 6 10 15

Step-by-step explanation:

brainliest plz

Step-by-step explanation:

the general slope intercept formula is

y = ax + b

a is the slope of the line.

b is the y-intercept (the point, where the line crosses the y-axis, meaning the y value when x=0).

we get b by using the point coordinates in the equation and solve for b :

-2 = (1/4)×0 + b

b = -2 (as expected)

the full line equation is

y = (1/4)x - 2

-2+x+(-5) > 0  <=> x-7 > 0 <=> x > 7

ok done. Thank to me :>

Answer: 500 i think

Step-by-step explanation:

Answer:

i think the answer is 50 if not im sorry if there is another go for that one.

Step-by-step explanation:

Answer:

14.75

Step-by-step explanation:

56/4 = 14, 3/4 = .75

add them together

Answer: 14.75

Step-by-step explanation: yeah its 14.75  but if you want to simplify it, then its 14.8

Answer:

3 2 /5 ×3

change 3 2 /5 into an improper fraction

then you will get 17 /5

after that you say 17/5 ×3/1

=(17×3)/ (5x1)

=51/5 (51÷5)

=10.2/ 10 1/5

[tex]3 \frac{2}{5} \times 3 \\ = \frac{17}{5} \times 3 \\ = \frac{51}{5} \\ = 10 \frac{1}{5} [/tex]

[tex]10 \frac{1}{5} [/tex]

Hope it helps.

Do comment if you have any query.

Answer: 6.45 x 10^10

Step-by-step explanation:

Because 10^5 and 10^4 both have 10, we can add the exponents to get 10^9.

Multiplying 7.5 and 8.6 gets you

7.5 * 8.6 = 64.5

We can move the decimal up a place to get 6.45 and add another power to 10^9 to get 10^10

Your final answer should be 6.45 x 10^10

Answer:

C 6.45x 10 to the power of 10

Step-by-step explanation:

10 to the power of 5 is 100,000. 7.5x100,000 is 750,000.

10 to the power of 4 is 10,000.

10,000x8.6 is 86k

now we do 750,000x86,000 which is 64,500,000,000

10 to the power of 10 is 10 billion times 6.45 is 64,500,000,000

3/6 = 1/2 fph = .5fph

Answer:

1.2875 × 10^4

Step-by-step explanation:

[tex]2 \times + 3y = 5x - y[/tex]

[tex]2 \times + 3y = 5x - y

[/tex] Move the variables to the left

[tex]2 \times + 3y - 5 \times + y = 0[/tex]

Collect like terms

[tex] - 3 \times + 4y = 0[/tex]

Change the signs

[tex]3 \times - 4y = 0[/tex]

The lines that are parallel continuously have equal distances from each

other and perpendicular lines form 90° angle at their intersection.

The correct responses are;

Reasons:

Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel where; Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex]

[tex]\displaystyle \overline{AB} \ and \ \overline{CD} \ are \ perpendicular\ where; \ Slope \ of \ \overline{AB} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex]

[tex]1. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{13 - 3}{-2 - 0}} = \frac{10}{-2} = -5[/tex]

[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{3 - 0}{10 - (-5)} = \frac{1}{5}[/tex]

[tex]\displaystyle \mathbf{Slope \ of \ \overline{AB}} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]2. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{7- 1}{3 - (-6)}} = \frac{6}{9} =\frac{2}{3}[/tex]

[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{-5 - (-1)}{-6 - 0} = \frac{-4}{-6}=\frac{2}{3}[/tex]

Slope of [tex]\mathbf{\overline{AB}}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel

[tex]3. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{ \frac{2- 4}{-6 - (-2)} = \frac{-2}{-4}} =\frac{1}{2}[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{11 - (-7)}{-1 - 5} = \frac{18}{-6}=-3[/tex]

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular

[tex]4. \ \displaystyle Slope \ of \ \overline{AB} = \frac{8- 3}{-3 - 2} = \frac{5}{-5} =-1[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{6 - 2}{-4 - (-8)} = \frac{4}{4}=1[/tex]

[tex]\displaystyle Slope \ of \ \overline{AB} = \mathbf{-\frac{1}{Slope \ of \ \overline{CD}}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]5. \ \displaystyle Slope \ of \ \overline{AB} = \frac{-1 - 2}{-8 - (-4)} = \frac{-3}{-4} =\frac{3}{4}[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-3 - 6}{0 - 12}} = \frac{-9}{-12}=\frac{3}{4}[/tex]

Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel

[tex]6. \ \displaystyle Slope \ of \ \overline{AB} = \frac{5 - (-1)}{6 - 3} = \frac{6}{3} =2[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-5 - 7}{2 - (-4)}} = \frac{-12}{6}=-2[/tex]

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular

Directions: To determine if the equations are parallel or perpendicular

Solution:

The equations are parallel if when expressed in the form, y = m·x  + c, the value of m are equal

The equations are perpendicular, when we have;

[tex]\displaystyle The \ value \ of \ \mathbf{m} \ in \ one \ equation = -\frac{1}{The \ value \ of \ \mathbf{m} \ in \ the \ other\ equation }[/tex]

7. First equation

3·x + 2·y = 6

Therefore; [tex]\displaystyle y = -\frac{3}{2} \cdot x + 3[/tex]

Second equation; [tex]\displaystyle y = \mathbf{-\frac{3}{2} \cdot x + 5}[/tex]

The value of m which is the coefficient of x are both equal to [tex]\displaystyle -\frac{3}{2}[/tex]

Therefore, the equations are parallel

8.  Equation 1; 3·y = 4·x + 15

Therefore;

[tex]\displaystyle y = \frac{4}{3} \cdot x + 5[/tex]

Equation 2; 9·x + 12·y = 12

[tex]\displaystyle y = -\frac{9}{12} \cdot x + 1 = 1 - \frac{3}{4} \cdot x[/tex]

The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular

9. Equation 1: 8·x - 2·y = 4

Therefore;

y = 4·x - 2

Equation 2: x + 4·y = -12

Therefore;

[tex]\displaystyle y = -\frac{1}{4} \cdot x - 3[/tex]

The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular.

10. Equation 1: 3·x + 2·y = 10

Therefore;

[tex]\displaystyle y = -\frac{3}{2} \cdot x - 5[/tex]

Equation 2: 2·x + 3·y = -3

[tex]\displaystyle y = -\frac{2}{3} \cdot x -1[/tex]

The slopes of the equation 1 and 2 are not equal, and are not  the negative inverse of each other, therefore, the equations are neither parallel nor perpendicular.

Learn more about parallel and perpendicular lines here:

https://brainly.com/question/7197064

Answer:

The "possible" rational zeros are:

±

1

,

±

2

,

±

4

,

±

8

The actual zeros are:

−

1

,

4

,

±

√

2

Explanation:

f

(

x

)

=

x

4

−

3

x

3

−

6

x

2

+

6

x

+

8

By the rational root theorem, any rational zeros of

f

(

x

)

are expressible in the form

p

q

for integers

p

,

q

with

p

a divisor of the constant term

8

and

q

a divisor of the coefficient

1

of the leading term.

That means that the only possible rational zeros are:

±

1

,

±

2

,

±

4

,

±

8

We find:

f

(

−

1

)

=

1

+

3

−

6

−

6

+

8

=

0

So

x

=

−

1

is a zero and

(

x

+

1

)

a factor:

x

4

−

3

x

3

−

6

x

2

+

6

x

+

8

=

(

x

+

1

)

(

x

3

−

4

x

2

−

2

x

+

8

)

Notice that the ratio between the first and second terms of the remaining cubic is the same as that between the third and fourth terms. So this cubic will factor by grouping:

x

3

−

4

x

2

−

2

x

+

8

=

(

x

3

−

4

x

2

)

−

(

2

x

−

8

)

x

3

−

4

x

2

−

2

x

+

8

=

x

2

(

x

−

4

)

−

2

(

x

−

4

)

x

3

−

4

x

2

−

2

x

+

8

=

(

x

2

−

2

)

(

x

−

4

)

Finally we can factor the quadratic as a difference of squares:

x

2

−

2

=

x

2

−

(

√

2

)

2

=

(

x

−

√

2

)

(

x

+

√

2

)

So the zeros are:

−

1

,

4

,

±

√

2

Answer:

17+7=24

Step-by-step explanation:

I hope this help you

Answer

10

Step-by-step explanation:

Subtract 7 from both sides of the equation.

n=17−7

Subtract 7 from 17.

n=10

BRAINLIEST?

Answer:

8 months

Step-by-step explanation:

12/3 = 4, 1/3 is 4 so 1/3 + 1/3 = 2/3 or 8

Area of circle = A = πr2 = π × 42 ≈ 50.26548 yard²

- BRAINLIEST answerer

Answer:

Hello. The answer is : rectangle, rhombus

I cant think of a third one as yet.

Answer:

look at the picture .................

Answer:

$760

Step-by-step explanation:

950 x 0.8 = 760

Answer:

25 this is a write answer

Answer:

Multiply

Step-by-step explanation:

To raise a power to a power means to raise one exponent to another. Whether the exponents are real, imaginary, monomials or polynomials, to simplify these problems, all we have to do is multiply the exponents together.

- BRAINLIEST answerer