Is CO2
an atom or a molecule and is it a pure element or a
compound?
a. Atom, Compound
b. Molecule, Pure element
c. Molecule, Compound
Answer:
C
Explanation:
CO2 is a molecule because it is compose of atoms which made it a molecule, it can also be call a compound.
Answer:
I believe it is c. Molecule, Pure compound
Explanation:
this is because it is composed of atoms which create molecule.
If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
Answer:
[tex][Cu^{2+}]=0.041 M[/tex]
Explanation:
Hello!
In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:
[tex][Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}[/tex]
[tex][Cu^{2+}]=0.041 M[/tex]
Best regards!
A cook had a jar containing a sweet food and a jar containing a sour food. The image above shows the sweet and sour foods. At room temperature, both foods are liquids. The same amount of energy was transferred into both substances. Later, one of the foods had changed phase while the other had not. Which food changed phase, and how did it change? PLEASE ANSWER ASAP
Answer: One of the foods was sour and one was sweet
Explanation:
The sweet one has changed because it has more sugar then the sour one, It either got moldy or melted.
Could someone draw me electron dot diagrams? The Hydride Ion, Hydrogen Ion, Aluminum Ion, Nitride Ion, Oxide Ion, and Calcium Ion, and Sodium-Ion dot structures? Thanks!
Answer:
urorrr
Explanation:
hahhahahahahhaahah oki nam omy mymy mymy
Constants: A: MW = 150 g/mol; B: = MW 100 g/mol; C: MW = 200 g/mol. 2.0 g C was made from 4.5 g A and 4.0 g
a. Calculate the yield for the following reaction: 3A + B -> C
b. Calculate the yield for the following reaction: 2A + 3B -> C
c. Calculate the yield for the following reaction: A + B->3C
Answer:
a. 100%
b. 133%
c. 300%
Explanation:
To find yield first we need to determine theoretical yield converting each reactant to moles and find limitng reactant for each reaction:
Moles A:
4.5g * (1mol / 150g) = 0.03 moles
Moles B:
4.0g * (1mol / 100g) = 0.04 moles
a. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (1 mole B / 3 moles A) = 0.01 moles of B
As there are 0.04 moles of B, A is limiting reactant.
Theoretical moles and mass of C are:
0.03 moles A * (1 mole C / 3 moles A) = 0.01 moles of C.
0.01 moles of C * (200g / mol) = 2g are produced.
Yield is:
2g / 2g * 100 = 100%
b. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (3 mole B / 2 moles A) = 0.045 moles of B
As there are 0.04 moles of B, B is limiting reactant.
Theoretical moles and mass of C are:
0.04 moles B * (1 mole C / 3 moles B) = 0.0133 moles of C.
0.0133 moles of C * (200g / mol) = 2.67g are produced.
Yield is:
2.67g / 2g * 100 = 133%
c. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (1 mole B / 1 moles A) = 0.03 moles of B
As there are 0.04 moles of B, A is limiting reactant.
Theoretical moles and mass of C are:
0.03 moles A * (1 mole C / 1 moles A) = 0.03 moles of C.
0.03 moles of C * (200g / mol) = 6g are produced.
Yield is:
6g / 2g * 100 = 300%
Can gravity be considered a force? Explain your reasoning
Answer:
I think that gravity can be considered a force.
Explanation:
As the object falls, it moves faster and faster. Gravity is considered a universal force because it acts between any two masses anywhere in the universe. For example, there is a gravitational pull between the Sun and the Moon. Even small masses attract one another.
Hope this helped! :)
What is the wavelength of a photon with an energy of 3.50 x 10^-19 J ?
Answer:
λ = 5.68×10⁻⁷ m
Explanation:
Given data:
Energy of photon = 3.50 ×10⁻¹⁹ J
Wavelength of photon = ?
Solution:
E = hc/λ
h = planck's constant = 6.63×10⁻³⁴ Js
c = 3×10⁸ m/s
Now we will put the values in formula.
3.50 ×10⁻¹⁹ J = 6.63×10⁻³⁴ Js × 3×10⁸ m/s/ λ
λ = 6.63×10⁻³⁴ Js × 3×10⁸ m/s / 3.50 ×10⁻¹⁹ J
λ = 19.89×10⁻²⁶ J.m / 3.50 ×10⁻¹⁹ J
λ = 5.68×10⁻⁷ m
Like Earth, the moon
A rotates and waxes
B goes through a cycle of phases
Crevolves and rotates
O
Dwaxes and wanes.
100,000 years in the geologic history of Earth would be considered
Answer:
". It will mark the time since humans began altering Earth. Starting about 10,000 years ago, it is tentatively being called the Anthropocene."
i dont know if tht will help
100,000 years in the geologic history of Earth would be considered
as Anthropocene .
What is Anthropocene?
The first and most recent geological epoch in Earth's history when human life began to have a noticeable influence on the planet's climate, including ecosystems, and ecosystems, is referred to as the Anthropocene Epoch. This term refers to an undefined unit of geologic time.
It would be the first time since people started changing the planet. It must be tentatively referred to as the Anthropocene and began around 10,000 years ago.
To know more about Anthropocene
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which materials conduct heat most easily
Answer:
Metal, Copper, and Alluminum
Explanation: It is what it is
An aqueous solution of potassium hydroxide is standardized by titration with a 0.187 M solution of nitric acid. If 22.7 mL of base are required to neutralize 29.4 mL of the acid, what is the molarity of the potassium hydroxide solution?
Answer:
Explanation:
29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .
moles contained in nitric acid solution
= .0294 x .187 moles
= 5.5 x 10⁻³ moles
This must have been reacted with same amount of moles of base
moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10⁻³ moles
molarity of base solution = 5.5 x 10⁻³ / 22.7 x 10⁻³
= .24 M .
What are products of photosynthesis (2)
Answer:
Oxygen and simple sugars.
Explanation:
Water, sunlight and carbon dioxide is taken in to photosynthesise and the product would be oxygen that is breathed out through the stomata and simple sugars that are used as fuel for the plant.
Kidney stones are caused by the precipitation of either calcium oxalate, Ca(C2O4), or calcium phosphate, Ca3(PO4)2, in the kidneys. If the normal concentration of Ca2+ in the kidneys is 2.5 mM, at what concentration of oxalate ion will kidney stones begin to form?
Answer:
1.1 × 10⁻⁶ M
Explanation:
Step 1: Given and required data
Concentration of Ca²⁺ ([Ca²⁺]): 2.5 mM = 2.5 × 10⁻³ MCalcium oxalate solubility product constant (Ksp): 2.7 × 10⁻⁹Step 2: Write the balanced equation for the solution reaction of calcium oxalate
CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)
Step 3: Calculate the concentration of the oxalate ion to begin the precipitation of calcium oxalate
We will use the Ksp of calcium oxalate.
Ksp = 2.7 × 10⁻⁹ = [Ca²⁺].[C₂O₄²⁻]
[C₂O₄²⁻] = Ksp / [Ca²⁺]
[C₂O₄²⁻] = 2.7 × 10⁻⁹ / 2.5 × 10⁻³
[C₂O₄²⁻] = 1.1 × 10⁻⁶ M
Kidney stones are the calcareous stones formed in the kidney of the excretory system. The initial concentration of oxalate ion was [tex]1.1 \times 10^{-6} \;\rm M.[/tex]
What is concentration?Concentration is the amount of the substance present in the sample and can be calculated by the solubility constant of the products.
Given,
Concentration of calcium = 2.5mM
The solubility product constant = [tex]2.7 \times 10^{-9}[/tex]
The balanced chemical reaction for calcium oxalate can be written as:
[tex]\rm CaC_{2}O_{4}(s) \leftrightharpoons Ca^{2+}(aq) + C_{2}O_{4}^{2-}(aq)[/tex]
The concentration of oxalate ions by Ksp is calculated as:
[tex]\begin{aligned} [C_{2}O_{4}^{2-}] &= \rm \dfrac {Ksp}{[Ca^{2+}]}\\\\&= \dfrac{2.7 \times 10^{-9}}{2.5 \times 10^{-3}}\\\\&= 1.1 \times 10^{-6}\;\rm M\end{aligned}[/tex]
Therefore, [tex]1.1 \times 10^{-6} \;\rm M[/tex] is the concentration of oxalate ion.
Learn more about concentration here:
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What is the name of the product that forms when sodium hydroxide reacts with propanoic acid is?
Answer:
Propionic acid reacts with NaOH(aq) to form sodium propionate and water.
Explanation:
.
choose all the pairs of elements that will form a compound with an covalent/molecular bond
a. phosphorus and iodine
b. rubidium and fluorine
c. sulfur and chlorine
d. aluminum and bromine
Answer:
B
Explanation:
Please answer this question
Answer:
I'm not an expert at this, but I assume its mercury.
How are scientific questions answered? OA. Through feelings and guesses
B. Through likes and dislikes
C. Through beliefs and opinions
D. Through measuring and observing
PLEASE HURRY
Which input value produces the same output value for the two functions on the graph. f(x) = - x+
g(x) = ģx-2
.
x= -3
x= -1
X = 1
x= 3
Answer:
3
Explanation:
Your problem statement tells you .... f(x) passes through point (3, negative 1) g(x) passes through point (3, negative 1) This tells you the input value that produces the same output value for the two functions is 3, and that output value is -1.
7)
According to your lab procedure, identify the chemicals necessary to produce NH3(g).
Write a net ionic equation for the generation of NH3(g).
Answer:
Explanation:
Chemicals to produce NH₃ ( ammonia )
1 ) Ammonium chloride ( NH₄Cl )
2 ) Calcium hydroxide Ca(OH)₂
2NH₄Cl + Ca(OH)₂ = CaCl₂ + 2NH₃ + 2H₂O.
Net Ionic equation
2NH₄⁺ ( aq ) + 2OH⁻ (aq ) = 2NH₃(g) + 2H₂O .
Any science fair project ideas? Something for 7th or 8th grade level.
Answer:
maybe try to do something with electricity?
Explanation:
give me an update on when u find one :) cant wait to see it
Calculate the following equation (2.55 -0.7)*4.3
Answer:
-7.6755
Explanation:
Calculate
I calculate it
How many molecules are contained 9.6 mol C2H4?
Answer:
N = 5.8 × 10²⁴ molecules
Explanation:
Step 1: Given and required data
Moles of C₂H₄ (n): 9.6 molAvogadro's number (NA): 6.02 × 10²³ molecules/molStep 2: Calculate the number of molecules (N) in 9.6 moles of C₂H₄
To convert moles to molecules we need Avogadro's number: there are 6.02 × 10²³ molecules of C₂H₄ per mole of C₂H₄
N = n × NA
N = 9.6 mol × 6.02 × 10²³ molecules/mol
N = 5.8 × 10²⁴ molecules
digital divide,cyberbullying and computer addiction are the common problems that some people encountered.what did you know about it?
Answer:
this is not chemistry
Explanation:
not chemistry
Gas A: 5 liters at 20 °C
Gas B: 5 liters at 10 °C
Gas C: 5 liters at 40 °C
Gas D: 5 liters at 30 °C
Which gas has the greatest average molecular kinetic energy?
Gas A
Gas B
Gas C
Gas D
Answer:
Gas D
Explanation:
liters at 30 °C
The SI unit for pressure, the pascal (Pa), is shorthand for
A. m2
B. N/m2
c. N
The pascal is sorthand for N/m^2
What is the noble gas electron configuration of aluminum (Al)?
Answer:
[Ne] 3s² 3p¹
Explanation:
Which type of energy would running be?
Thermal
Light (solar)
Kinetic
Potential
Answer:
so here is the answer
Explanation:
Kinetic is the answer.
A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?
Answer:
5.7 moles of O2
Explanation:
We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:
2KClO3 —> 2KCl + 3O2
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.
Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.
Thus, 5.7 moles of O2 were obtained from the reaction.
The crust and upper mantle make up Earth's ____.
a. lithosphere
b. asthenosphere
c. core
d. continents
Answer:
a. the lithosphere
Explanation:
At a certain temperature, the solubility of aluminum hydroxide is (8.1x10^-13) M. What is the Ksp at this temperature?
Answer:
4.2x10⁻⁴ M or 0.032 g/L.
Explanation:
Hello!
In this case, for solubility product problems, we apply the concepts of equilibrium because an insoluble salt is ionized until a certain point limited by the solubility product constant, Ksp. Thus, we first write the ionization reaction of aluminum hydroxide at equilibrium:
[tex]Al(OH)_3(s)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)[/tex]
Next, we write the corresponding equilibrium expression:
[tex]Ksp=[Al^{3+}][OH^-]^3[/tex]
Which in terms of [tex]x[/tex], the reaction extent, is:
[tex]Ksp=x*(3x)^3[/tex]
Because [tex]x[/tex] also represents the molar solubility of aluminum hydroxide at the considered temperature; now, we can write:
[tex]8.1x10^{-13}=x*(3x)^3[/tex]
Which can be solved for x as follows:
[tex]x=\sqrt[4]{\frac{8.1x10^{-13}}{27} } \\\\x=4.2x10^{-4}M[/tex]
Thus, the solubility is 4.2x10⁻⁴ M or mol/L and in g/L we have:
[tex]4.2x10^{-4}\frac{mol}{L}*\frac{78g}{1mol} =0.032\frac{g}{L}[/tex]
Best regards!