Answer:
-6(x=4)(2x+1)
Step-by-step explanation:
Just multiply -2 x 3
Hope this helps! :)
I need help! In exchange for 100 points. Do not scam me or I will report you!
What is the sum for:
(2x−6)+4(x−3)
Answer:
6x - 18
Step-by-step explanation:
2x - 6 + 4x - 12 = 6x - 18
First, distribute the 4 and then combine the like terms to get 6x - 18.
Answer:
x=-2
Step-by-step explanation: First we can multiply 4 times anything in the parenthesis to get rid of it.
(2x-6)+4(x-3)
(2x-6)+4x-12
Then we combine like terms.
(2x-6)+4x-12
6x-6-12
6x-18
Finally we divide both sides by 6.
6x-18
6x/6-18/6
x=-2
Someone help me please :(
Answer:
ok, but i can't even see nothing, though ;-;
The school production of ‘Our Town’ was a big success. For opening night, 559 tickets were sold. Students paid $2.00 each, while non-students paid $4.00 each. If a total of $1498.00 was collected, how many students and how many non-students attended?
By copying and completing the working below, work out 3 + 1 16 Give your answer as a fraction in its simplest form.
Answer:
Assuming the question is: 3 + 1 16 [I see no "working below."
Step-by-step explanation:
3 + 1 16
48/16 + (16/16 + 1/16) [Make all numbers into fractions using 16 as the denominator. E.g. 48/16 = 3.
Add: 48/16 + (16/16 + 1/16)
(48+16+1)/16
=63/16
[Also equal to 3 15/16]
first three common factors of 3 and 9?
Answer:
The GCF of 3 and 9 is 3.
Step-by-step explanation:
Davina received 50 votes, Binh received 40 votes. What is the ratio of Binh's votes to Davina's votes in simples form?
Answer:
The answer is 4 hope this helps
| Solve for X
8x + 1 = 49
Which system of equations could be graphed to solve the equation below? log Subscript 0.5 Baseline x = log Subscript 3 Baseline 2 x
Answer:
Step-by-step explanation:
y 1 = StartFraction log x Over log 0.5 EndFraction, y 2 = StartFraction log 2 Over log 3 EndFraction + x
Please help! Also dont send any links; it doesn't work for me
Answer:
Step-by-step explanation:
-1 to 0 is divided in four parts.
similarly 0 to 1 is divided in four parts
so each fraction on either side is 1/4 onthe right of 0 and -1/4 on the left of 0.
A is 2 parts on the right of 0,A=2×1/4=1/2=0.5
Bis 1 part left of 0,B=1×(-1/5)=-1/5=-0.2
What is the solution of ?
Answer:
of what???????..???..
3/4 + 7/8 =??????????????????
Answer:
13/8
in decimal form it is 1.625
Step-by-step explanation:
Answer:
13/8 or 1 5/8
Step-by-step explanation:
2h(3m-4h)please help me
Answer:
6hm-8h^2
Step-by-step explanation:
2h(3m-4h)
2h*3m=6hm
2h*4h=8h^2
=6hm-8h^2
aidan runs every morning before he goes to work.on Sunday,he ran 0.54km, on Monday he ran 1.25km,on Tuesday he ran 1.50km, on Wednesday he ran 1.75km and on Thursday he ran 2.30km.His goal was to run10km in these five days.dis aidan meet his goal?how long did he run?estimate and find the solution.
Answer:
no
Step-by-step explanation:
0.54 rounded to the nearest one is 1
1.25 is 1
1.50 is 1
1.75 is 2
2.30 is 2
all that added would give you 7 which is less than 10
the exact number is also 7.34
Estella signed a one-year lease. She pays $720 per month in rent. If she wants to move out three months early, how much money will she owe when she moves out? I assume $2,160 ??
Answer:
$2160
Step-by-step explanation:
Since she moved out 3 months early, you would do 720x3, since she pays $720 every month. 3x720 = $2160
Calculating interest
Answer:
Simple Interest is calculated using the following formula: SI = P × R × T, where P = Principal, R = Rate of Interest, and T = Time period. Here, the rate is given in percentage (r%) is written as r/100. And the principal is the sum of money that remains constant for every year in the case of simple interest.
Step-by-step explanation:
hope this helps
The FM radio station KAMB broadcast from an antennae atop a 150 meter tall radio tower at a frequency of 90 MHz with a total radiated power of 40 kilowatts. Neighbors have complained about problems they attribute to excessive radiation from the tower, but the city engineer who measured the radiation level near the base of the tower found it to be well below the accepted standard. You have been hired by the HOA to assess the engineer's report. You know a few things about electromagnetic radiation and therefore conclude that we must find the optimum place on the ground to measure the maximum radiation emitted from the antennae. From your extensive knowledge in physics, you know that the intensity of radiation, I, is given by the formula:
I=12/32π*Psin2(θ)/r^2
where P is the power output, r is the distance from the top of the tower to the point on the ground, and θ is the angle measured from the tower to r.
Find the distance R from the base of the tower to the optimum location for taking the radiation reading. (m)
What is the maximum radiation reading from the ground in kw/m^2
If the city code requires that electromagnetic radiation be under 200 microwatts per square meter, is this antenna operating within city code? Yes or No
Answer: 150 m, 5.305*10^-5 kW/m^2, No
Step-by-step explanation:
See attachment, hope this helps
Using the radiation intensity formula we will have to:
a) [tex]150 m[/tex]
b) [tex]5.305*10^{-5} kW/m^2[/tex]
c)No
From the data informed, we have:
[tex]h=150m\\P=40KW[/tex]
Using the given formula and performing some mathematical operations:
[tex]I=\frac{12Psin^2(\theta)}{32(\pi)r^2} \\I= \frac{12(40)(R/r)^2}{32(\pi)r^2} \\= \frac{15R^2}{r^2\pi } \\= \frac{15R^2}{(R^2+150^2)^2\pi} \\[/tex]
deriving the given equation, we will have:
[tex]=\frac{(R^2+150^2)^22R-R^2(2(R^2+150^2))2R}{(R^2+150^2)^2}[/tex]
So from this equation we have that the answer of the letter A corresponds:
[tex]R=150[/tex]
For letter B we will have to develop this equation:
[tex]I= 5.30X10^{-5}[/tex]
As for the letter C, when converting the value found, it should give 200 microwatts, which is false.
Learn more: brainly.com/question/10148635
What is the area of this triangle
Answer:
A = 18 in²
Step-by-step explanation:
The area of a triangle can be calculated using the formula A = (bh)/2
where b = base length and h = height
Fortunately for us, the variables are already defined and given to us in the problem
All we have to do is plug in the values of h and b into the formula for area of a triangle
A = (bh)/2
b = 3 and h = 12
A = ((12)(3))/2
multiply 12 and 3
A = 36/2
divide 36 by 2
A = 18 in²
I need help fast please
About 8% of canada is covered in fresh water
the area of canada is approximately 9,970,000km
a calculate the area covered in fresh water
b how much of canada is not covered in fresh water
23%of canada is covered in tundra estamaite tundra covered area
thanks
Answer:
797600km, 9172400 km, 2293100 km
Step-by-step explanation:
a. to find the amount of canada covered in fresh water, multiply 9970000 by 0.08 to get 797600km
b. the amount not covered by fresh water is 9970000-797600 which equals 9172400 km
c. multiply area of canada by 0.23 which is 2293100 km
just in case you might want to double check the zeros to make sure i did it right
Answer:
a. 797,600 km²
b. 9,172,400 km²
c. 2,293,100 km²
Step-by-step explanation:
To find a percent of a number, multiply the percent by the number. First, change the percent into a decimal number by moving the decimal point of the percent 2 places to the left. For example, 42% = 0.42; 7% = 0.07
Part a.
8% of 9,970,000 km²
Step 1. Multiply the percent by the number
8% of 9,970,000 km² = 8% × 9,970,000 km²
Step 2. Change the percent into a decimal number by moving the decimal point of the percent 2 places left.
8% of 9,970,000 km² = 8% × 9,970,000 km² = 0.08 × 9,970,000 km²
Step 3. Use a calculator or long division to do the multiplication.
0.08 × 9,970,000 km² = 797,600 km²
Answer: a. area covered in fresh water is 797,600 km²
Part b.
Subtract the area of part a. from the total area of Canada.
9,970,000 km² - 797,600 km² = 9,172,400 km²
Answer: b. area not covered in fresh water is 9,172,400 km²
Part c.
Tundra is 23% of total area.
23% of 9,970,000 km²
Step 1. Multiply the percent by the number
23% of 9,970,000 km² = 23% × 9,970,000 km²
Step 2. Change the percent into a decimal number by moving the decimal point of the percent 2 places left.
23% of 9,970,000 km² = 23% × 9,970,000 km² = 0.23 × 9,970,000 km²
Step 3. Use a calculator or long division to do the multiplication.
0.23 × 9,970,000 km² = 2,293,100 km²
Answer: a. area covered in tundra is 2,293,100 km²
The value of a new car in 2015 was 40,000 dollar. It depreciates each year by 7%. How much will the car be worth in 2026?
Answer: $30,800
Step-by-step explanation: First you have to subtract 2026 - 2015, which is 11 years. Since it depreciates by 7% each year, you would multiply 7 by 11, which is 77. 77 is the percent of depreciation of the car. After that, you would divide 40000 by 100, which is 400. Then you multiply 400 by 77 to get you final answer.
Cindy saves 420 each month her monthly salary is 2100 what is the ratio of the amount Cindy saves to the amount she earns each month?
the ratio of 2100 salary to 420 saved is 15:3 each month
helpppppppppppppppppppppppppppppppp
Answer:
x ≤ -14
Step-by-step explanation:
Does the point (5, -1) lie on the line 2y + 3x = 13?
Answer: Yes
Step-by-step explanation:
You can find out by inputting your values
2y + 3x = 13
x = 5
y = - 1
2(- 1) + 3(5) = 13
- 2 + 15 = 13
13 = 13
One number is twice another number. The sum of their reciprocals is 6. What are the numbers?
Answer:
8 and 2
Step-by-step explanation:
Answer:
1/4 and 1/2
Step-by-step explanation:
One number is twice another number.
x and 2x
The sum of their reciprocals is 6
[tex]\frac{1}{x}[/tex] + [tex]\frac{1}{2x}[/tex] = 6
Use common denominator of 2x
[tex]\frac{2}{2x}[/tex] + [tex]\frac{1}{2x}[/tex] = 6
[tex]\frac{3}{2x}[/tex] = 6
multiply botn sides by 2x
3 = 12x
Divide both sides by 12
1/4 = x
x = 1/4
2x = 1/2
The numbers are
1/4 and 1/2
? Question
Emma also wonders how long it will take her balance of $300 to reach $450, assuming she doesn't make
any payments toward it. Write the equation to represent the situation, and solve it using the inverse
relationship between exponential and logarithmic expressions.
Type the correct response in the box. Use numerals instead of words. Round your answer to the nearest
tenth.
It will take about
years for Emma's balance to reach $450.
Part D
Using an exponential equation, supposing a rate of 5%, it is found that it will take about 2.9 years for Emma's balance to reach $450.
An increasing exponential function is modeled by:
[tex]A(t) = A(0)(1 + r)^t[/tex]
In which:
A(0) is the initial value.r is the growth rate, as a decimal.In this problem:
Her initial balance is of $300, hence [tex]A(0) = 300[/tex].The growth rate is of 15%, hence [tex]r = 0.15[/tex]Then:
[tex]A(t) = A(0)(1 + r)^t[/tex]
[tex]A(t) = 300(1 + 0.15)^t[/tex]
[tex]A(t) = 300(1.15)^t[/tex]
It will reach $450 after t years, for which A(t) = 450, hence:
[tex]A(t) = 300(1.15)^t[/tex]
[tex]450 = 300(1.15)^t[/tex]
[tex]1.15^t = \frac{450}{300}[/tex]
[tex]1.15^t = 1.5[/tex]
[tex]\log{(1.15)^t} = \log{1.5}[/tex]
[tex]t\log{1.15} = \log{1.5}[/tex]
[tex]t = \frac{\log{1.5}}{\log{1.15}}[/tex]
[tex]t = 2.9[/tex]
It will take about 2.9 years for Emma's balance to reach $450.
A similar problem is given at https://brainly.com/question/14773454
Answer:
It will take about 2.9 years for Emma’s balance to reach $450.
on a map, 1 inch equals 25 miles. If two cites are 4 inches apart on the map, how far are they actually apart?
Answer: They are 100 miles apart
Step-by-step explanation:
1 inch = 25 miles
4x25=100
Answer: 100 miles
Step-by-step explanation:
Since we have 25 miles per inch. and there are 4 inches, you would multiply 25 by 4 to get to your answer of 100 miles.
25x4=100
Brett made oat bars for his school's bake sale. For his first batch, Brett mixed 1 cup of caramel chips and 4 cups of oats. To make sure he had enough, he made a second batch, and mixed 2 cups of caramel chips and 8 cups of oats. Which batch of oat bars was more caramelly?
Answer:
They would be equally caramelly, the ratio of oats:caramel is equal
Step-by-step explanation:
The following for loop prints the numbers 1 to 20 on one line with a space between.
for (int i = 1; i <= 20; i++)
{
System.out.print(i + " " ); // prints each value of i followed by a space on one line
}
Question
Consider the for loop example above. Assume you want to adjust the loop to print only the even values from 1 and 20. What must the loop elements - counter initialization, conditional statement, and counter modification - be set to in order to accomplish the goal.
Review all options listed below carefully. You MUST select 3 answers; one for each element/category:
Counter initialization
Conditional statement
Counter modification
a. int i = 0;
b. int i = 1;
c. int i = 2;
d. i < 20;
e. i <= 20;
f. i > 20;
g. i++;
h. i+=1-;
i. i+=2;
Answer:
Counter initialization: [tex]\verb!int i = 2![/tex].
Conditional statement: [tex]\verb!i <= 20![/tex].
Counter modification: [tex]\verb!i += 2![/tex].
Step-by-step explanation:
In the current Java for-loop in this question:
The counter initialization statement [tex]\verb!int i = 1![/tex] in this for-loop would initialize the counter variable to integer [tex]1[/tex]. The conditional statement [tex]\verb!i <= 20![/tex] holds as long as the counter is less than or equal to [tex]20[/tex]. Thus, the largest possible value for the counter would be [tex]20\![/tex].The counter modification statement [tex]\verb!i++![/tex] is equivalent to [tex]\verb!i += 1![/tex]. This statement would add [tex]1[/tex] to the value of the counter in each iteration.The even integers between [tex]1[/tex] and [tex]20[/tex] includes [tex]2,\, 4,\, \dots,\, 20[/tex]. It would be necessary to add [tex]2[/tex] each time to get to the next number.
Since the list of even integers starts at [tex]2[/tex], it would be necessary to initialize the counter variable to [tex]2\![/tex] rather than [tex]1[/tex]. Thus, replace the counter initialization statement [tex]\verb!int i = 1![/tex] with [tex]\verb!int i = 2![/tex].
The maximum integer that this loop should print is still [tex]20[/tex]. Thus, the conditional statement [tex]\verb!i <= 20![/tex] does not need to be changed.
The for-loop should add [tex]2[/tex] to the counter each time to get to the next even integer. Thus, the counter modification statement [tex]\verb!i++![/tex] (or equivalently, [tex]\verb!i += 1![/tex]) should be replaced with [tex]\verb!i += 2![/tex].
Overall, the for-loop should be:
[tex]\begin{aligned}& \verb!for (int i = 2; i <= 20; i += 2) {!\\ &\quad \verb!System.out.print(i + " ");! \\ &\verb!}!\end{aligned}[/tex].
Help me
Will mark brainliest
Do not give the answer like this
‘answer in a file’ otherwise I will report
More points will be given
My question is Q7.
here u go! sorry I didn't give an exact answer but i hope this works bc it did for me
HELP ASAP
Solve for the measure of ∠PMR. Show your work and explain how you got your answer.
Answer:
[tex]gy78093 x^{2} 67[/tex]
Step-by-step explanation: