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An electron on an energy level has an energy of 16.32 x 10−19 J. It moves to another level by releasing 5.4 x 10−19 J of energy. Which of the following descriptions mostly likely explains what occurred?


The electron moved down to an energy level and has an energy of 10.92 x 10−19 J.

The electron moved down to an energy level and has an energy of 21.72 x 10−19 J.

The electron moved up to an energy level and has an energy of 10.92 x 10−19 J.

The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.

i d k

Step-by-step explanation:

   Option (A) will be the answer.

        (Example: Translation, Rotation and Reflection)

Given in the question,

Since, image quadrilateral MOPS is formed by the translation of quadrilateral CAWT by 7 units right and 5 units down,

It's a rigid transformation having measures of all interior angles unchanged.

By the definition of rigid transformation → ∠M ≅ ∠C

          Therefore, option (A) will be the answer.

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Answer: 10

Step-by-step explanation:

Step-by-step explanation:

[tex]y = \frac{4}{x} + \sqrt{x + 0.2} - 5x[/tex]

[tex]x = \frac{4}{5} [/tex]

[tex]y = \frac{4}{1} \div \frac{4}{5} + \sqrt{ \frac{4}{5} + 0.2} - 5 \times \frac{4}{5} [/tex]

[tex] \frac{4}{1} \times \frac{5}{4} + \sqrt{0.8 + 0.2} - 4[/tex]

[tex]5 + \sqrt{1} - 4[/tex]

[tex]5 + 1 - 4 \\ 6 - 4 = 2[/tex]

Answer:

square root of 4 is 2, 1/2 of 2 is 1

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

[tex]\frac{18}{2a}[/tex]

a = 3

[tex]\frac{18}{2(3)}[/tex]

multiply 2 and 3

2 * 3 = 6

[tex]\frac{18}{6}[/tex]

simplify

18/6 = 3

Answer:

a 31. w 55. X 60 y 46

Step-by-step explanation:

Answers in angles

Answer:

  a.  2/5; reduction

Step-by-step explanation:

It appears that C is the center of dilation, so C' and C are coincident. The scale factor is ...

  P'C'/PC = 4/10 = 2/5 . . . scale factor

The scale factor is less than 1, so the dilation is a reduction in size.

Answer:

1.5 as decimal, 1 1/2 as a fraction

Step-by-step explanation:

1. convert 2 5/6 & (-1 4/12) to a improper fraction.

17/6 and  -16/12

2. multiply 17/6 by 2 to match -16/12's denominator

17/6 * 2 = 34/12

We now have

34/12 + -16/12

A positive number plus a negative number is the same thing as subtraction so we remove the negative sign and replace the plus with a minus sign.

We have:

[tex]\frac{34}{12}-\frac{16}{12}[/tex]

Now solve. 34-16 = 18

our answer is 18/12

Answer:

Area of the shaded region is 104.96 m².

Step-by-step explanation:

Firstly, finding the area of circle with radius 8 cm by substituting the values in the formula :

[tex]{:\implies{\tt{A_{(Circle)} = \pi {r}^{2}}}}[/tex]

[tex]{:\implies{\tt{A_{(Circle)} = 3.14{(8)}^{2}}}}[/tex]

[tex]{:\implies{\tt{A_{(Circle)} = 3.14{(8 \times 8)}}}}[/tex]

[tex]{:\implies{\tt{A_{(Circle)} = 3.14{(64)}}}}[/tex]

[tex]{:\implies{\tt{A_{(Circle)} = 3.14 \times 64}}}[/tex][tex]{:\implies{\tt{A_{(Circle)} = 200.96 \: {m}^{2} }}}[/tex]

Hence, the area of circle is 200.96 m².

[tex]\begin{gathered}\end{gathered}[/tex]

Secondly, finding the area of rectangle with length and breadth by substituting the values in the formula :

[tex]{:\implies{\tt{A_{(Rectangle)} = l \times b}}}[/tex]

[tex]{:\implies{\tt{A_{(Rectangle)} = 12 \times 8}}}[/tex]

[tex]{:\implies{\tt{A_{(Rectangle)} = 96 \: {m}^{2}}}}[/tex]

Hence, the area of rectangle is 96 m².

[tex]\begin{gathered}\end{gathered}[/tex]

Now, finding the area of shaded region by substituting the values in the formula :

[tex]{:\implies{\tt{A_{(Shaded)} = A_{(Circle)} - A_{(Rectangle)}}}}[/tex]

[tex]{:\implies{\tt{A_{(Shaded)} = 200.96 - 96}}}[/tex]

[tex]{:\implies{\tt{A_{(Shaded)} = 104.96 \: {m}^{2}}}}[/tex]

Hence, the area of shaded region is 104.96 m².

[tex]\rule{300}{2.5}[/tex]

Answer: 36/5= 7.2 days to complete sanaya work day

Step-by-step explanation:

Answer:

it something i know that much

Step-by-step explanation:

Solution:

We know that the formula to write the equation of a circle is (x – h)² + (y – k)² = r², where:

First, let's find the radius of the circle. We know that the diameter of the circle is ten units. The radius is half of the diameter. This means that the radius is five units because it is half the diameter, which is ten units.

Creating the equation:

Hence, the equation to form a circle with center (-6, 2) and diameter 10 is (x + 6)² + (y – 2)² = 5².

Image attached~

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Answer:

ok so frog a travels at a rate of 1 ft every 30 seconds

which frog b travels 2 feet every second so

Frog A: 1/30

Frog B: 2/1 or 2

so Frog B will win

Hope This Helps!!!

Answer:

The volume of the cylinder is 785.4 cubic feet.

Answer:

Exact: 3 2/9

Estimated: 3

Step-by-step explanation:

1/3=3/9, so just convert it to that, then do some simple subtraction.

Answer:

a

Step-by-step explanation:

5/3 is 1.6666667

8/5 is 1.6

therefore 5/3 > 8/5

The required length of side OQ is given as 80 units, as of the given conditions.

In a right-angled triangle, its sides, such as hypotenuse, perpendicular, and base are Pythagorean triplets.

here,
From the figure,
Applying Pythagoras' theorem,
OQ² = OR² + RQ²
OQ = √[48² + 64²]
OQ = 80 units

Thus,  the required length of side OQ is given as 80 units, as of the given conditions.

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Answer:

2 : 3

Step-by-step explanation:

bananas to apples = 8 : 12

simplify by dividing both values by highest common factor of 4:

8 ÷ 4 : 12 ÷ 4 = 2 : 3

Answer:

sin theta = .923

Step-by-step explanation:

see image. An angle in standard position has one side glued to the x-axis, and the other side-the terminal side- rotating around the origin. When it gets to (-5, 12) in your problem, it stops there. 5, 12are the legs of a right triangle and they are recognizable as part of a pythagorean triple 5,12,13. So the hypotenuse is 13. Sin is OPP/HYP. So that is 12/13. Its in the 2nd quadrant, so it should be positive. We used the reference angle, bc the actual angle is the >90° angle from the positive x-axis to thru (-5,12). It calcs the same tho.

sin theta = 12/13

= 0.923

Answer:

  (c)  0.923

Step-by-step explanation:

The coordinates of a point on the unit circle are (cos(θ), sin(θ)). That is, the y-coordinate of a point on the terminal ray will have the same sign as the sine of the angle. Here, the sign of the sine is positive, eliminating the first two answer choices.

We know that cos(θ) < sin(θ) for reference angles greater than 45°, where both values are √2/2 ≈ 0.707. Since 5 < 12, that means the angle of interest here will have a sine that is more than 0.707. Only one of the positive answer choices is in this range: sin(θ) ≈ 0.923.

_____

Additional comment

The value of sin(θ) is precisely ...

  sin(θ) = y/√(x²+y²) = 12/√(25+144) = 12/13

  sin(θ) = 0.923076...(6-digit repeat)

Answer:

276.25

Step-by-step explanation:

37.50 x 5.5 = 206.25

206.25+ 70 = 276.25

Answer:

m<C = 62°

Step-by-step explanation:

[tex]m[tex]m [tex]x+20+3x=180[/tex]

[tex]4x=160,[/tex]  [tex]x=40[/tex]

[tex]m [tex]118+m [tex]m [tex]m

Answer:

$240000

Step-by-step explanation:

[tex]p = 200000[/tex]

[tex]t = 4[/tex]

[tex]r = 5 \: percent\: per \: anum[/tex]

[tex]si = \frac{p \times r \times t}{100} [/tex]

[tex] = \frac{200000 \times 5 \times 4}{100} [/tex]

[tex] = 2000 \times 5 \times 4[/tex]

[tex] = 2000 \times 20[/tex]

[tex] = 40000[/tex]

[tex]amount = si + principle[/tex]

[tex] = 200000 + 40000 = 240000[/tex]

The total amount after 4 years is $240,000

Simple interest rate is the interest that is paid only on the principal portion of a the amount that is saved.

Total amount = principal + interest

Interest = principal x time x interest rate

200,000 x 0.05 x 4 = $40,000

Total amount = 200,000 + 40,000 = $240,000

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Answer:

Second quadrant

Step-by-step explanation:

Quadrant I ranges from [tex]0^\circ<\theta<90^\circ[/tex]

Quadrant II ranges from [tex]90^\circ<\theta<180^\circ[/tex]

Quadrant III ranges from [tex]180^\circ<\theta<270^\circ[/tex]

Quadrant IV ranges from [tex]270^\circ<\theta<360^\circ[/tex]

Answer:

1) slope form
2) standard form

3)slope form

4)standard form

5) none of theese

6)point slope form

Step-by-step explanation:

The value for the given right triangle of [tex]x[/tex] is [tex]\pm \sqrt{2}[/tex].

By Pythagorean theorem and some algebraic handling, we have the following second order polynomial:

[tex](x-1)^{2}+(x+1)^{2} = 2.5^{2}[/tex] (1)

Where [tex]x[/tex] is the desired variable.

[tex](x^{2}-2\cdot x +1)+(x^{2}+2\cdot x +1) = 2.5^{2}[/tex]

[tex]2\cdot x^{2}+2 = 2.5^{2}[/tex]

[tex]2\cdot x^{2}-4.25= 0[/tex]

[tex]x = \pm \sqrt{2}[/tex]

The value for the given right triangle of [tex]x[/tex] is [tex]\pm \sqrt{2}[/tex]. [tex]\blacksquare[/tex]

The statement is incomplete. Correct form is shown below:

Suppose you are given a triangle with hypotenuse of length 2.5 and legs of length [tex]x-1[/tex] and [tex]x+1[/tex]. Determine the value of [tex]x[/tex].

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Answer:

I believe that's the solution!

sorry for my letters...

taking a peek at the picture, we can see that the U-turn or vertex occurs at the point (2 , -9), and we can also see that the graph passes through the point say (5 , 0).

[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{vertex}{(2~~,~-9)}\qquad y=a(x-2)^2-9\qquad \qquad \textit{we know that} \begin{cases} x=5\\ y=0 \end{cases} \\\\\\ 0=a(5-2)^2-9\implies 9=9a\implies \cfrac{9}{9}=a\implies 1=a~\hfill \\\\\\ y=1(x-2)^2-9\implies \boxed{y=(x-2)^2-9}[/tex]

Answer:

C 30 degrees

Step-by-step explanation:

Sum of interior angles of a triangle = 180°

⇒ ∠UST + 78 + 72 = 180

⇒ ∠UST = 180 - 78 - 72

⇒ ∠UST = 30°

Explanation:

When x is zero or larger, then |x| = x.

An example: |9| = 9

This applies to |3x| as well, so |3x| = 3x when [tex]x \ge 0[/tex]

The equation of a line that is tangent to the graph of f and parallel to the given line is; y = 3x + 2 and y = 3x - 2

The given equation of the line is 3x - y + 3 = 0

In slope intercept form, this can be rewritten as;

y = 3x + 3

Therefore, the slope of this line will be 3 since in y = mx + c, m is the slope. Thus, the slope of the parallel line will be  3

We will be looking for the value of x when the derivative of f(x) equals 3.

f(x) = x³ and so f'(x) = 3x²

Thus;

3x² = 3

x² = 3/3

x² = 1

x = 1 or -1

Thus;

y = 1³ or y =-1³

y = 1 or -1

Equation of tangent is;

y - 1 = 3(x - 1)

y - 1 = 3x - 3

y = 3x - 2

or y - (-1) = 3(x - (-1))

y + 1 = 3x + 3

y = 3x + 2

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