Answer:
O Option 1
Explanation:
IF ENERGY IS RELEASED, THEN ENERGY RELEASED SHOULD BE SUBTRACTED FROM ORIGINAL.
(16.32 X 10^-19) - (5.4 X 10^-19)
10.92 X 10^-19
Carbon substances can have very different properties because...
O A. carbon is almost never found as an element
O B. carbon atoms are very unstable
O c. carbon atoms can be arranged in different ways
O D. carbon atoms are not attracted to each other
Answer:
Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL ... Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar ... g of glucose in enough water to make 500.0 mL of solution. • Step 2: Transfer 18.6 mL of the
Explanation:
How many moles (of molecules or formula units)
are in each sample?
75.83 g CF2Cl2
A radioactive isotope that can be followed through a chemical reaction or industrial process is called a/an what? (needs answer asap!!!!!)
The rate of the given reaction is 0.840 M/s.
A +4B - 2C
What is the relative rate of change of each species in the reaction?
This problem is providing the rate of the given reaction as 0.840 M/s and asks for the relative rate of change of each species. At the end, the results turned out to be -0.840 M/s, 0.210 M/s and 0.420 M/s for A, B and C respectively.
Relative rate of changeIn chemical kinetics, when chemical reactions take place, it turns out possible for us to quantify in what extent a reaction is proceeding over time, by overseeing the change in the concentration as the time goes by.
In such a way, when given the rate of reaction, one can calculate the relative rate of change of each species by using the following equation, involving their stoichiometric coefficients in the reaction:
[tex]r_A=\frac{r}{-1} \\\\r_B=\frac{r}{-4} \\\\r_C=\frac{r}{2}[/tex]
Where these coefficients are negative for reactants and positive for products. In such a way, one can plug in the given rate of reaction to obtain each species' as follows:
[tex]r_A=\frac{0.840M/s}{-1} =-0.840M/s\\\\r_B=\frac{0.840M/s}{-4} =0.210M/s\\\\r_C=\frac{0.840M/s}{2}=0.420M/s[/tex]
Learn more about chemical kinetics: brainly.com/question/26351746
There are 3 reactions of Calcium Carbonate, CaCO₃, that can be formed in this particular problem:
Reaction 1: Calculate the ΔH₁
Reaction 2: ΔH₂ = -635.1 kJ
Reaction 3: ΔH₃ = 178.3 kJ
ΔH₁ = ΔH₂ - ΔH₃
ΔH₁ = -635.1-(178.3) KJ
ΔH₁ = -813.4 KJ
CaCO2=CaO + CO₂
How do I balance this equation?
please help, i will mark you as brainliest
Which chemicals are only present at point “x”?
what is the conversion factor for in^3 to cm^3
Please help! THIS IS DUE IN A HOUR!
I will give you brainliest if you help me! I’ll vote and heart it.
1. Calculate the energy of an X-ray photon if the wavelength is 5.00x10^-10m?
2. (use picture) Determine the energy related to an electron occupying the ground state a Hydrogen atom given its bright-line spectrum below (the one to the left with least frequency):
3. A laser used to detach retinas produces radiation with a frequency of 4.6x10^14 Hz. What is the wavelength of this light?
[tex]\bold{\huge{\pink{\underline{ Answer }}}}[/tex]
Concept Used :-Here, we will use the concept of planks quantum theory .
According to planks quantum theory :-
The radiant energy is emitted discontinuously in the form of small packets of energy called quantaIn case of lights, It is called photons The amount of energy with each quantum of radiation is directly proportional to the frequency of light That is, E = hv or E = hc/ λThe total amount of energy emitted or a absorbed will be whole number multiple of quantum That is, E = nhv or nhc/λAnswer 1 :-Here,
We have to calculate the energy of an X photon
The wavelength is 5.00 × 10^-10The value of planks constant h is 6.626 × 10^-34 .According to the planks quantum theory of radiation :-
[tex]\bold{\pink{ E = hv }}[/tex]
[tex]\sf{ E = h}{\sf{\times{\dfrac{c}{λ}}}}[/tex]
The value of c is 3 × 10^8Subsitute the required values,
[tex]\sf{ E = 6.626 × 10^{-34} }{\sf{\times{\dfrac{3 × 10^{8}}{5 × 10^{-10}}}}}[/tex]
[tex]\sf{ E = }{\sf{\dfrac{19.87× 10^{-26}}{5 × 10^{-10}}}}[/tex]
[tex]\sf{ E = 3.974 × 10^{-36}}[/tex]
Hence, The energy of an X ray photon is 3.974 × 10^-36
Answer 2 :-We have ,
Frequency = 4.57 × 10^14 HzPlanks constant = 6.626 × 10^-34According to the planks quantum theory,
[tex]\bold{\pink{ E = hv }}[/tex]
Subsitute the required values,
[tex]\sf{ E = 6.626 × 10^{-34}× 4.57 × 10^{14}}[/tex]
[tex]\sf{ E = 30.28 × 10^{- 20}}[/tex]
[tex]\sf{ E = 3.028 × 10^{ - 19}}[/tex]
Hence, The energy related to an electron occupying the ground state of hydrogen atoms is 3.028 × 10^-19
Answer 3 :-We have ,
Frequency = 4.6 × 10^14 HzWe know that,
[tex]\bold{\pink{ v = }}{\bold{\pink{\dfrac{ c }{λ}}}}[/tex]
[tex]\sf{ λ = }{\sf{\dfrac{ c }{v}}}[/tex]
Subsitute the required values,
[tex]\sf{ λ = }{\sf{\dfrac{ 3 × 10^{8} }{4.6 × 10^{-14}}}}[/tex]
[tex]\sf{ λ = 0.65 × 10^{22}}[/tex]
Hence, The of this light is 0.65 × 10^22 .
[ Note :- Kindly refer answer in the app]
1) How many moles of gas occupy 58 L at a pressure of 2.2 atmospheres and a temperature
of 313 K?
Here, we need to solve this problem using Ideal gas law ( PV=nRT).
Where –
P = Pressure in atmV = Volume in Ln = moles R = Ideal gas law constant T = Temperature in KNow, according to the question –
V = 58 L P = 2.2 atmT = 313 KR = 0.0821 atm L/ mol KCalculation –
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf PV = nRT}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n = \dfrac{PV}{RT}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n = \dfrac{ 2.2 \: \:\times 58 \: } {0.0821 \times 313}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n = \dfrac{ 2.2 \times 58}{0.0821 \times 313} [/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n =\dfrac{127.6}{25.7}[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf n = 4.9656 \: moles }[/tex]
_______________________________________
Given Information ,
Volume ,V = 58 LPressure ,P = 2.2 atmTemperature ,T = 313We have to find the number of moles .
We use here " Ideal Gas Equation" which is
PV = nRTwhere
n is number of moles
R is universal gas Constant
T is temperature
P is pressure
V is volume
On substituting the value we get
➣ 2.2 × 58 = n × 0.0821 × 313
➣ 127.6 = n × 25.70
➣ 127.6/25.70 = n
➣ 4.96 = n
➣ 5 ≈ n
So, the number of moles are 5 .
true or false: chemical reactions are usually written left to right
the inner part of the ovary that contains an egg is the ovule
true or false
Answer:
The answer is true
Explanation:
the ovary is a tubular structure and contains ovules
Solve for the molecular/formula mass of the following compounds.
1. Silicon dioxide, SiO2
2. Sodium hydroxide, NaOH
3. Calcium carbonate, CaCO3
4. Sodium carbonate, Na2Co3
5. Silver nitrate, AgNO3
6. Iron oxide, FeO.
7. Phosphoric acid, H2PO4
8. Sodium bicarbonate, NaHCO3
9. Acetic acid, CH3COOH
10. Sodium fluoride, NaF
Answer:
what you need to do is,
you take the relative atomic mass of each element and multiply it by the no of atoms it has. do this for all the elements present, and add the values. that's it!
Explanation:
try to do the last one by yourself, it is easy and you will be using the molecular/formula mass mostly everywhere in chemistry.
what kind of weather would you associate with a high pressure system? how does the density, humidity, and air motion compare to that of a low pressure system
type your answer here:
Answer:
High pressure and low pressure have two distinct types of weather associated with them...typically. High pressure often means dry weather with sunshine. Low pressure often means clouds and precipitation. High pressure is associated with sinking air.
Explanation:
High-pressure systems are usually called Fair Weather Systems because the 7 types of weather in a high-pressure zone are generally comfortable and clear. Keep in mind that high and low pressures mean the air is under higher or lower pressure relative to the surrounding air.
How are water particles affected by the movement of a wave?
•
The wind pushes the water particles down to deeper depths.
O The wave pushes the water particles back and forth.
•
The water particles move in an upward motion through the wave.
The water particles move in a circular pattern.
Answer:
The water particles move in an upward motion through the wave.
Explanation:
When water particles become part of a wave they start to move up or down.
Answer:
u deleted my answer before so
Explanation:
Fill in the reaction type and predicted products for:
Fe3O4 (s) → ??
Type in the IUPAC name or formula for each product.
Write subscripts as normal numbers.
If there is no second product, type "nothing".
The reaction type is
Question Blank 1 of 3
.
The correct products are:
Question Blank 2 of 3
and
Question Blank 3 of 3
can you please help me out with this
Answer:
Explanation:uum i cant see anything but yeah I think its c
What’s (CH3)2CHCCCH3.
Answer:
4-methly-2-pentyne
Explanation:
Given that for Fe2O3 (s) the standard enthalpy of formation is −824.2 kJ/mol and the enthalpy of reaction is −851.5 kJ/mol, what is the enthalpy of formation for Al2O3 (s)?
This problem is providing us with the enthalpy of formation of Fe2O3 (s) and the enthalpy of reaction when it reacts with Al to form Al2O3 (s) and Fe. Thus, the enthalpy of formation of Al2O3 (s) is required and found to be -1675.7 kJ/mol as follows.
Enthalpy of reaction.In chemistry, the heat involved in a chemical process can be quantified via the difference in the overall enthalpy of products minus that of reactants:
[tex]\Delta H_r=\Delta H_{products}-\Delta H_{reactants}[/tex]
Now, with the given reaction:
[tex]Fe_2O_3 (s) + 2 Al (s) \rightarrow 2 Fe (s) + Al_2O_3 (s)[/tex]
One can see both Al and Fe have zero as their enthalpies of formation for they are elements. In such a way, one can rearrange the previous formula as:
[tex]\Delta H_r=\Delta H_{Al_2O_3}-\Delta H_{Fe_2O_3}[/tex]
And hence plug in the given energies in order to find the required:
[tex]-851.5kJ/mol=\Delta H_{Al_2O_3}-(-824.2kJ/mol)\\\\\Delta H_{Al_2O_3}=-851.5kJ/mol+(-824.2kJ/mol)\\\\\Delta H_{Al_2O_3}=-1675.7kJ/mol[/tex]
Learn more about enthalpy of reaction: https://brainly.com/question/8055290
In the reaction A+B - C+D, if element B is in excess, then-
Answer:
Explanation:
Determining the Limiting Reagent
One reactant (A) is chosen, and the balanced chemical equation is used to determine the amount of the other reactant (B) necessary to react with A. If the amount of B actually present exceeds the amount required, then B is in excess, and A is the limiting reagent.
i’m trying to figure out how to convert 6 moles KCL to particles.
Answer:
How many moles KCl in 1 grams? The answer is 0.013413582325
1 mole is equal to 1 moles KCl, or 74.5513 grams.
447.3078 is the answer
Explanation:
~Cornasha_Weeb
According to the following reaction, how many grams of oxygen gas are required for the complete reaction of 21.2 grams of hydrogen sulfide?
hydrogen sulfide (g) + oxygen (g) water (l) + sulfur dioxide (g)
_____grams oxygen gas
Answer:
29.9g please refer to the picture for work
What is the mass in grams of 3.01 X 1023 atoms of the element chlorine, Cl? (Please show step by step)!
Answer: the mass of 3.01 atoms of chlorine is 35.46/2 = 17.73 g.
Explanation: hope its correct
step by step: molar mass: (2 x 35.46) g/mol = 70.92 g/mol
1 mole chlorine = 6.02 x 10^23 molecules of chlorine.
Mass of 6.02 x 10^23 molecules chlorine = 70.92 g
Mass of 3.01 x 10^23 molecules chlorine = 70.92 x(3.01 x 10^23)/(6.02 x 10^23)g
= 35.46 g
If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical formula
he required empirical formula based on the data provided is Na2CO3.H2O.
What is empirical formula?The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.
We have the following;
Mass of sodium = 37.07-g
Mass of carbonate = 48.39 g
Mass of water = 14.54-g
Number of moles of sodium = 37.07-g/23 g/mol = 2 moles
Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole
Number of moles of water = 14.54/18 g/mol = 1 mole
The mole ratio is 2 : 1: 1
Hence, the required empirical formula is Na2CO3.H2O
Learn more about empirical formula : https://brainly.com/question/11588623
Identify the following reactions as combination, decomposition, or combustion reactions
C7H8 + 9O2 → 7CO2 + 4H2O ______________
2NaHCO3 → Na2CO3 + H2O + CO2 ___________
CH4 → C + 2H2O ________________
P4O10 + 6H2O → 4H3PO4 ______________
FeSO4 → FeO + SO3 _______________
CaCO3(s) → CO2(g) + CaO(s) _________________
Answer:
1. combustion
2. decomposition
3. decomposition
4. combination
5. decomposition
6. decomposition
Explanation:
combination of a reaction is when 2 more or elements/ compounds combine to form a compound. example: (A+B→AB)
decomposition of a reaction is when a chemical breakdown. example: (AB→A+B)
a combustion reaction is when an element/ compound reacts with oxygen to form the product of water and carbon dioxide.
example: ( [tex]C_{x}[/tex] [tex]H_{y}[/tex] + [tex]O_{2}[/tex] → [tex]H_{2}[/tex]O + [tex]CO_{2}[/tex] )
1. Consider the following reaction where Kc = 1.29×10-2 at 600 K.
COCl2(g) CO(g) + Cl2(g)
A reaction mixture was found to contain 9.87×10-2 moles of COCl2(g), 2.19×10-2 moles of CO(g), and 3.79×10-2 moles of Cl2(g), in a 1.00 liter container.
Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?
The reaction quotient, Qc, equals _____
The reaction:
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.
2. Consider the following reaction where Kc = 55.6 at 698 K.
H2(g) + I2(g) 2HI(g)
A reaction mixture was found to contain 2.59×10-2 moles of H2(g), 4.38×10-2 moles of I2(g) and 0.294 moles of HI(g), in a 1.00 liter container.
Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?
The reaction quotient, Qc, equals ____
The reaction:
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.
Answer:
Consider the following reaction where Kc = 1.29×10-2 at 600 K:
COCl2(g) <=> CO(g) + Cl2(g)
A reaction mixture was found to contain 9.85×10-2 moles of COCl2(g), 2.61×10-2moles of CO(g), and 3.71×10-2 moles of Cl2(g), in a 1.00 Liter container.
Indicated true (T) or false (F) for each of the following:
An engine cylinder contains 175 mL of gas at a pressure of 1.0 atm. As the engine runs, it compresses the cylinder, reducing the volume of the gas to 15 mL. What is the new pressure of the gas at this volume?
This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.
Boyle's lawIn chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.
Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:
[tex]P_1V_1=P_2V_2[/tex]
Thus, we solve for the final pressure, P2, to get:
[tex]P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm[/tex]
Learn more about ideal gases: brainly.com/question/8711877
Calculate the mass of aluminium oxide which contains double the number of oxygen atoms in 192 g of oxygen gas.
Answer:
648
Explanation:
what you're going to do your first is to convert the 192g to number of atoms
firstly you are going to convert 192 to moles using the formula reacting mass all over molar mass, into it that you're going to get 12 as your answer, you Dey multiply the 12 to avocados constant
in doing that you have I've gotten the number of atoms present in 192 g of oxygen
hi everyone, I am getting stuck in this question can you tell me it please ,what are the property's of a metal and a non-metal
Answer:
Explanation:
Properties of Metal
1. Metals are ductile. ...
2. Metals are a good conductor of heat and electricity.
3. Metals have high tensile strength. .
4. Metals are sonorous.
5. Metals are hard.
Properties of non metal
1. High ionization energies.
2. High electronegativities.
3. Poor thermal conductors.
4. Poor electrical conductors.
5. Brittle solids—not malleable or ductile.
6. Little or no metallic luster.
7. Gain electrons easily.