1. carbohydrates, lipids, proteins, and nucleic acids.
2. a is protein b is sugar c is starch and d is nuclear acid
3. What is the difference between saturated and unsaturated fat? it's that Saturated fats have the maximum number of hydrogens possible, while unsaturated fats have a double bond between two of the carbons. part 2. Why are partially hydrogenated fats useful for making potato chips but not particularly healthy for humans to eat? I was not able to find a different answer for it than part 1.
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MULTIPLE CHOICE QUESTION
If a simple machine has a MA of 5 and you lift an object UP 2 m, how far must you push the
object along the ramp's surface?
0.5 m
10 m
0.2 m
1 m
Answer:
0.5
Explanation:
I think it is this beacause if u have the answer you have that
what is the formula to calculate area of sphere
An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before
takeoff?
A. 1.6 x 103 meters
B. 1.7 x 103 meters
C. 3.1 x 103 meters
D. 3.3 x 103 meters
Answer:
A
Explanation:
d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m ~ 1.6 x 10^3
What is the Einstein Rosen Bridge Theory? Is it possible why or why not? (IN YOUR OWN WORDS ANYTHING ELSE WILL BE DELETED)
That states that the blackhole ends are working like bridges between one space to another.
And you can travel through them in 5-10s The distance is thousands of lightyears but we can travel it..This may be possible
A proton has a charge , what gives it a charge?
Answer:
The charge is believed to be from the charge of the quarks that make up the nucleons (protons and neutrons). A proton is made of two Up quarks, with 2/3 positive charge each and one Down Quark with a negative 1/3 charge (2/3 + 2/3 + -1/3 = 1).
Explanation:
Hope this helps :)
Compute g at a height of 7 RE above the surface of Earth (RE=6.4E+6m, ME=6.0E+24kg).
The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
What is acceleration due to gravity?It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.
The acceleration due to gravity is related to the distance as
g =GM/R²
where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
Given is the height R = 7 x 6.4 x 10⁶ m and mass of Earth M = 6 x 10²⁴ kg
Substitute the values into the expression to find the acceleration due to gravity.
g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²
g = 8.933 m/s²
Thus, the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
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3. A female minke whale has a core body temperature of 35°C and a core/blubber interface temperature of 29°C, with an average blubber thickness of 4.0 cm and thermal conductivity of 0.25 W/mK. At what rate is energy lost from the whale's core by conduction from the core/blubber interface through the blubber to the skin? Assume a skin temperature of 12°C and a total body area of 22 m².
The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
Rate of conduction of core/blubber interfaceThe rate of conduction of core/blubber interface is calculated as follows;
[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]
where;
k is thermal conductivity = 0.25 W/mkA is the total body area = 22 m²d is thickness of blubber = 4 cm = 0.04 mΔT is change in temperature[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]
Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
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Two metal conducting spheres are fixed in place and have charges of 0.00025C 0.00015 C.They are separated by a distance of 0.85 meters. What is the electric force between them
Arrangement is used to increase the resistance in a circuit.
Resistors connected in parallel
Resistors connected in alternate
Resistors connected in series
Resistors connected in combination
Answer:
Resistors connected in series
Calculate the de moglie Wavelength of election having kinetic energy of 400 ev
Answer:
613.5 pm
Explanation:
We know that de Broglie wavelength of an electron :
λ = 1.227 / √E nm
λ = 1.227 / √400 nm
λ = 1.227 / 20 nm
λ = 0.6135 nm
λ = 0.6135 x 10⁻⁹ m
λ = 613.5 x 10⁻¹² m
λ = 613.5 pm
Wavelength of election having kinetic energy of 400 ev.
Solution:WE = 1.227 / √election nmWE = 1.227 / √e400nmWE = 1.227 / √20nmWE = 0.6136nmWE = 0.6136 x 10-⁹mWE = 613.5 x 10-¹²mWE = 613.5A wave that requires a medium through which to travel
chemical wave
mechanical wave
pitch
electromagnetic wave
Answer:
Explanation:
Answer: B mechanical waves.
Waves that do require a medium are called mechanical waves.
How many hydrogen atoms can bond with this oxygen atom?
Answer:
2
Explanation:
there are two lonely pairs
2 hydrogens
Explanation:
oxygen has 3 lone pairs of electrons which do not take part in the bonding leaving two electrons in the outermost shell to be part of it, hydrogen has only one electron in it's outermost shell it needs one electron to be stable so two atoms of hydrogen bonds with one oxygen atom to to share there electrons to be stable.
Derive the Schrödinger's Time independent wave equation using kinetic energy and momentum.
Consider,
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}[/tex]
Multiply both sides by ih and simplification will yield
[tex]{:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}[/tex]
Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for [tex]{\bf x\to \pm \infty}[/tex] will yield:
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}[/tex]
Integrating by parts and knowing the same fact by some simplification will yield:
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}[/tex]
The momentum is thus contained within the wave function, so we can then deduce that:
[tex]{:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}[/tex]
[tex]{:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}[/tex]
[tex]{:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]
Now the kinetic energy
[tex]{:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]
The classical formula for the total energy
[tex]{:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}[/tex]
Multiplying this equation by [tex]{\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}[/tex] and use the above equations and simplify it we will be having
[tex]{:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}[/tex]
This is the Famous Time-Independent Schrödinger wave equation
Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer
Which landscape feature can be caused by chemical
weathering?
OU-shaped valley
O Basalt columns
O Limestone caves
Answer: Limestone Caves
Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.
If an object is moving with a constant velocity of 700 cm/s and starts at an initial position of 20 cm at t=0, what will be the position at t= 0.9 s?
PLEASE HELP
Which of the following is best determined by applying the principles of
relativity and uncertainty, rather than Newtonian physics?
A. The speed of a truck
B. The length of an object at rest
C. The position of a bird flying overhead
D. The position of an electron
By applying the principles of relativity and uncertainty, rather than Newtonian physics, the position of an electron is best determined. The correct option is D.
What is principle of uncertainty?It states that position and the velocity of an object can't be measured exactly at the same time. One of them may have the approximate value, using the principle of uncertainty.
Every object is moving relative to some frame of reference. So, exact velocity and at what position an object is, can't be find by theory of Newtonian physics. Speed of a truck, length of object at rest and position of a flying bird flying overhead can be found using the Newtonian physics.
An electron is very minute particle whose velocity is unpredictable at any location. So, the position of an electron is best determined by the theory of relativity and uncertainty.
Thus, The correct option is D.
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A fish pond appears to be 1m deep but when vewed vertically above the refractive Index of the Water on the pond is 1.5. calculate the real depth formed
Answer:
real depth / apparent depth = R.I.
Real depth = 1.5 x 1 = 1.5 m
The diagram shows two liquid-in-glass thermometers.
Which has the greatest range? Explain how can you tell?
(Image attached)
Answer:
thermometer A
Explanation:
The range of a thermometer is the difference between the minimum and maximum temperatures that the thermometer can read.
∴ Range of thermometer A = 110° - (-10)° = 120°
Range of thermometer B = 50° - (-10)° = 60°
∴ Range of thermometer A is greatest.
Hope this helps!
what is the main function of a diode
Answer:
acts as a one-way switch for current
What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?
Answer:
1.48kg
Explanation:
Here,
potential energy (P.E) = 29j
height (h) = 2m
acceleration due to gravity(g) =
[tex]9.8m {s}^{ - 2} [/tex]
mass(m) = ?
we know,
P.E = mgh
or, 29 = m×9.8×2
or, 29/19.6 = m
or,m = 1.48kg
What is standard one kilogram?
Explanation:
Standard one kilogram is the mass of a platinium- iridium cylinder having equal diameter at the height kept at 0⁰C at the International bureau of Weights and Measures, held in paris in France. The accurate copies of atandard one kilogram are prepared to Measures mass in different countries.....
[tex]....[/tex]
It is defined as the mass of a particular international prototype made of platinum-iridium and kept at the International Bureau of Weights and Measures. It was originally defined as the mass of one liter (10-3 cubic meter) of pure water. At the Earth's surface, a mass of 1 kg weighs approximately 2.20 pounds (lb).
A tree is at a distance of 50 meters from a place on earth. From this place, the Angle of the tree's peak is 30. Find out the height of the tree.
sine's law
h/sin 30 = 50/sin 60
h/0.5 = 50/(0.5√3)
h=28.9 m
In the text "White House Press Release Announcing the Bombing of Hiroshima August 6, 1945" by President Truman, in which country was the atomic bomb developed?
A. Germany
B. The United States
C. The United Kingdom
D. Japan
In the text "White House Press Release Announcing the Bombing of Hiroshima August 6, 1945" by President Truman, the atomic bomb was developed by the United States. Therefore, the correct answer is B. The United States.
During World War II, a top-secret project known as the Manhattan Project was conducted by the United States. The goal of this project was to develop an atomic bomb. The research and development efforts were led by American scientists, engineers, and military personnel. The project involved numerous facilities across the United States, including Los Alamos, New Mexico, where the final design and testing of the atomic bomb took place.
President Truman's press release announcing the bombing of Hiroshima on August 6, 1945, indicates that the United States successfully developed and deployed the atomic bomb. This historical event marked the first use of atomic weapons in warfare and had a significant impact on the outcome of World War II.
Therefore, based on the context of President Truman's press release and the historical record, it is clear that the atomic bomb was developed by the United States. Therefore, the correct answer is B.
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a 90 N force is applied to a 65 kg mass. the mass will accelerate at
F=m.a
a = F/m
a = 90/65
a = 1.385 m/s²
Answer:
solution
here,
Explanation:
weight = 90N
mass=65kg
acceleration due to gravity (g)=??
Now,
w=m×g
90=65×g
90/65=g
:g=1.38m/s^2
Venus and Earth may be regarded as behaving as black bodies. The mean temperature at the surface of Venus is about 600 K and at the surface of Earth is about 300 K. Which of the following is the best estimate for the ratio \frac{\text{power radiated per unit area on Earth}}{\text{power radiated per unit area onVenus}} power radiated per unit area onVenus power radiated per unit area on Earth
The best estimate for the ratio of Power radiated per unit Area on Earth and Power radiated per unit Area on Venus is 1/16. The correct option is D.
What is power radiated?Power radiated is directly proportional to the fourth power of Temperature at the surface and also to the cross-section area.
P = σ A T⁴
For 600 K at Venus, σ A T⁴ = σ A (600)⁴
For 300 K at Earth , σ A T⁴ = σ A (300)⁴
Comparing, we get
[σ A (300)⁴/ σ A (600)⁴ ] = 1/16
Thus, the the best estimate for the ratio is 1/16. The correct option is D.
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The average reaction time is 1.5 seconds?
True
False
Answer:
false
Explanation:
The average reaction time for humans is 0.25 seconds to a visual stimulus, 0.17 for an audio stimulus, and 0.15 seconds for a touch stimulus.
1. An athlete runs 18 Kilometers in 2.5 hours, bicycles 150 Km in 4 hours, swims 10 Km in 3 hours.
Calculate:
a) the average speed for each leg of the triathlon
b) the average speed for the entire competition
The average speed is 18.73 km/hour.It is found as the ratio of the total distance and the total time taken.
What is the average speed?The total distance traveled by an object divided by the total time taken is the average speed.
The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.
The given data in the problem is;
Distance (d₁) = 18 Kilometers
Time (t₁) = 2.5 hours
Distance (d₂) = 150 Km
Time (t₂)= 4 hours
Distance (d₃) =10 Km
Time (t₃)=3 hours.
The average speed is found as;
[tex]\rm v_{avg}= \frac{Total \ distance }{Total \ time } \\\\ V_{avg}=\frac{18+150+10}{2.5+4+3} \\\\ v_{avg}= 18.73 \ km/hours[/tex]
Hence, the average speed is 18.73 km/hour.
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Question 9
2 pts
At a stop light, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at
constant velocity and the car accelerates at 3 m/s². How much time does the car take to catch up
to the truck?
O 15 s
O 10 s
05 s
O 25 s
20 s
the car take to catch up to the truck = same distance
d truck = d car
vt = vot+1/2 at² (vo=0, from rest)
vt = 1/2at²
15t=1.5t²
1.5t²-15t=0
t(1.5t-15)=0
t = 0 or
1.5t=15⇒ t=10 s
How much work would a child do while pulling 12kg wagon distance of 4.3m with a 22N force?
[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]
94.6J
Explanation:
Force (F) = 22N
mass (m) = 12kg
distance (S) = 4.3m
While
[tex] \sf Work \: done = Force \times distance[/tex]
This means
W = FS
while mass has no role in equation
Now substituting the required values
[tex] \sf W = 4.3 \times 22 \\ \\ \sf W = 94.6J[/tex]
A spherical convex mirror has a radius of 30 cm. An object with a height of 0.30 m is placed 20 cm from the mirror. Note that in +/- sign conventions, f is negative (–) if the mirror is a convex mirror. a. Calculate the image distance. b. Calculate the image height. c. Calculate the magnification. d. Summarize the properties of the image formed in terms of its LOST (location, orientation, size, and type). e. Draw the set-up using graphical methods (ray diagramming). Apply scale drawing. Make sure that your illustration matches well with what you have calculated and presented in a-d.
a)A spherical convex mirror form the image at image distance is 8.57cm.
b) Mirror forms the image of height is 12.855 cm.
c)The magnification of the spherical convex lens is 0.4285.
What is convex mirror?The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.
The focal length of convex lens, f = R/2
Given , the radius of mirror is R =30cm, the focal length will be
f =30cm/2 = 15cm
a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.
1/15 = 1/20 + 1/v
v= 8.57 cm
Thus, the image distance is 8.57cm.
b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.
Substitute the values into the expression, we get the image height as
h(image) = 8.57/20 x 30
h(image) = 12.855 cm
Thus, the image height is 12.855 cm.
c) The magnification is the ratio of image height to the object height.
Putting the values, we have
= 12.855/30
= 0.4285
Thus, the magnification is 0.4285.
d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.
e) The setup drawing is attached.
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