Answer: The egg will get sucked into the bottle. To get the egg out of the bottle, turn the bottle upside down and blow into it, so that the egg acts as a one-way valve. The increased air pressure in the bottle will cause the egg to pop back out.
Explanation:
Quickly place the egg over the mouth of the bottle. The egg will get sucked into the bottle. To get the egg out of the bottle, turn the bottle upside down and blow into it, so that the egg acts as a one-way valve. The increased air pressure in the bottle will cause the egg to pop back out.
The brake shoes of your car are made of a material that can tolerate very high temperatures without being damaged. Why is this so
they have rubber and meatal so its going to get hot of course cause it a engine pushing and the gasoline is just all coming together but damage wise I still it the protection on that part to keep it from damage and life risk
I hope this may help
A ship moves 330 m after 40,000 j of work is done on it. What force is used to do this work?
Explanation:
F=w/s
F=40,000j/330m
F=121.212N
g You decide to play fetch with your dog, who is sitting nextto you, so you throw a ball down a narrow hallway. The ballcomes to a stop 3.9 m down the hallway. The dog, startingfrom rest, runs after the ball with a constant acceleration of0.70m/s2until she reaches the ball. She grabs the ball whilestill running down the hallway uniformly accelerating(slowingdown) for 4.7 more seconds until she comes to a stop. What isthe total distance the dog travels to grab the ball and come toa final stop, starting from rest
You decide to play fetch with your dog, who is sitting nextto you, so you throw a ball down a narrow hallway. The ballcomes to a stop 3.9 m down the hallway. The dog, startingfrom rest, runs after the ball with a constant acceleration of0.70m/s2until she reaches the ball. She grabs the ball whilestill running down the hallway uniformly accelerating(slowingdown) for 4.7 more seconds until she comes to a stop. What isthe total distance the dog travels to grab the ball and come toa final stop, starting from rest
Harper suffers from nearsightedness equally severely in both eyes. The focal length of either of Harper's eyes is 16.7 mm in the relaxed state. What lens strength (a.k.a., lens power) of contact lenses should be prescribed to correct the nearsightedness in Harper's eyes
The lens strength or lens power of contact lenses that m should be prescribed to correct the nearsightedness is 59.9 diopters.
What is focal length of a lens?The focal length of a lens is the distance from a lens to the focal point of that lens.
It is a measure of how strongly a lens converses or diverges light.
The power of a lens is the inverse of the focal length when given in metres.
Power of a lens = 1/focal length (m)
The focal length = 16.7 mm = 0.0167 M
Power of lens required = 1/0.0167 = 59.9 diopters
Therefore, the lens strength or lens power of contact lenses that m should be prescribed to correct the nearsightedness is 59.9 diopters.
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A 6 kg ball experiences a 5 m/s^2 acceleration. What is the strength of the force felt by the ball?
a: 0.83kg
b: 30 newtons
c: 30 kg
d: 1.2 newtons
Answer:
30 newtons
explanations
data given
mass=6kg
acceleration=5
f=m×a
6×5=30
With explanation pls
Answer:
[tex](x \times 1) = (400 \times 2.5) \\ x = 1000 \: newtons[/tex]
[tex]y = 0[/tex]
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Answer: The correct statements are:
The atoms are very attracted to one another.The atoms are held tightly together.Explanation:
Solid state: In this state, the molecules are closely packed and cannot move freely from one place to another that means no space between them and the intermolecular force of attraction between the molecules are strong.
In solid substance, the particles are very close to each other due to this the intermolecular forces of attraction are strongest.
The key point about solid are:
The atoms are very attracted to one another.The atoms are not moving freely.It will not spread out evenly to fill any container.The atoms are held tightly together.The forces of attraction are strong to bring molecules together.The atoms are close and in fixed positions.Describe two 'beneficial' aspects from the last 10,000 years of humanity, as well as two 'dis-advantageous' aspects. Agriculture should be your guiding point here.
Answer:
Two beneficial aspects of the last 10,000 years of mankind have been the development of writing and the development of civilized communities.
Thus, writing has allowed the recording of the different historical events that have taken place during the development of humanity, setting precedents for subsequent generations, allowing documenting the progress that humanity has been achieving. On the other hand, the development of civilized communities around urban systems has allowed for greater economic and social development on the part of human groups, which through cooperation have been acquiring an increasingly higher quality of life.
On the other hand, two negative aspects of these years have been the world overpopulation and the pollution of the planet.
Thus, the amount of the world's population has been getting closer and closer to the limit of our planet's carrying capacity, which could lead humanity to a point where resources are definitely scarce, causing famines and various catastrophes. On the other hand, the pollution arising from the development of industrial societies has notably undermined the health of individuals and has damaged their standard of living, while causing irreparable damage to the natural environment.
What is gravitational force?
-,-
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The volume of an ideal gas changes from 0.40 to 0.55 m3 although its pressure remains constant at 50,000 Pa. What work is done on the system by its environment
Answer:
w= p∆v 50000 ( 0.55-0.40) and calculate and you get it
The work done on the system by its environment is 7,500J.
To find the work done, we need to know about the work done on an ideal gas during isobaric process.
What is isobaric process?When the pressure is remained constant throughout a process, then the process is called isobaric process.
What is the work done on a system in the isobaric process?For a isobaric process, the work done is pressure × (final volume of the system - initial volume)Here, Final volume= 0.55 m³
Initial volume= 0.40 m³
Pressure= 50,000 Pa
Work done = 50,000 × (0.55 - 0.40)
= 7,500 J
Thus, we can conclude that 7,500 J of work is done on the system by its environment.
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If the light energy passes through material in straight lines they are __?___ to light.
Answer:
transparent
Explanation:
If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m/s2, what is the mass of the box
Answer:
The correct solution is "14.6875 kg".
Explanation:
Given values:
Force,
F = 47.0 N
Acceleration,
a = 3.20 m/s²
Now,
⇒ [tex]Force=Mass\times Acceleration[/tex]
or,
⇒ [tex]F=ma[/tex]
⇒ [tex]47.0=m\times 3.20[/tex]
⇒ [tex]m=\frac{47.0}{3.20}[/tex]
⇒ [tex]=14.6875 \ kg[/tex]
3. Sally (45 kg) and Stan (90 kg) and arrive at Michigan Adventure and climb the stairs to ride the big
Shivering Timber coaster that is nearly 40 m tall and reaches speeds of 65 mi/hr.
a) Compare the potential energies of Sally and Stan as they wait in line at the top of the stairs.
Explain your reasoning.
[3 marks]
A particle of mass 100 g executes simple harmonic motion about x = 0 with angular frequency ω = 10 s-1. Its total mechanical energy is Etot = 0.45 J. Find the displacement of
the particle when its speed is 2 m/s. [3 marks]
Answer:
22.4 cm
Explanation:
The total mechanical energy of the particle Etot = K + U where K = kinetic energy = 1/2mv² where m = mass of particle = 100 g =0.1 kg and v = speed of particle = 2 m/s and U = potential energy = 1/2kx² where k = spring constant and x = displacement
Etot = K + U
U = Etot - K
U = Etot - 1/2mv²
Since Etot = 0.45 J, substituting the values of the other variables into the equation, we have
U = Etot - 1/2mv²
U = 0.45 J - 1/2 × 0.1 kg × (2 m/s)²
U = 0.45 J - 1/2 × 0.1 kg × 4 m²/s²
U = 0.45 J - 0.1 kg × 2 m²/s²
U = 0.45 J - 0.2 J
U = 0.25 J
Now U = 1/2kx² and the angular frequency ω = √(k/m) ⇒ ω²m = k
So, U = 1/2ω²mx²
x² = 2U/ω²m
x = (√2U/m)/ω
since ω = 10 rad/s, substituting the values of the variables into the equation, we have
x = (√2U/m)/ω
x = (√2 × 0.25 J/0.1 kg)/10 rad/s
x = (√0.5 J/0.1 kg)/10 rad/s
x = (√5 J/kg)/10 rad/s
x = 2.24/10 m
x = 0.224 m
x = 22.4 cm
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 15 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 65 cm .
Required:
What is the wavelength of the sound?
Answer:
100 cm
Explanation:
It is given that there are two loudspeakers that produces [tex]$\text{sound waves }$[/tex] along x-axis.
The maximum intensity of the sound is [tex]$\text{when the speakers are}$[/tex] at a distance of = 15 cm apart.
The sound intensity becomes zero when the separation between the speakers are increased and becomes 65 cm.
Therefore, the sound waves are in the phase, [tex]$\Delta x_1=15 \ cm$[/tex]
The sound waves are out of phase when [tex]$\Delta x_2=65 \ cm$[/tex]
Therefore,
[tex]$\Delta x_2 - \Delta x_1 = \frac{\lambda}{2}$[/tex]
[tex]$\lambda= 2(\Delta x_2 - \Delta x_1)$[/tex]
= 2 (65 - 15)
= 2 x 50
= 100 cm
Hence the wavelength of the sound is 100 cm.