1. What type of pest control uses an organism's natural enemies?
A. Cultural
B. Mechanical
C. Chemical
D. Biological

Answers

Answer 1
C chemical really get rid of them
Answer 2

Answer:Biological

Explanation:It’s a method of controlling pest such mites, insects and weeds.


Related Questions

At what power of ten are we able to view the entire Earth in space?

Answers

Answer:

If I remember correctly it should be 10^7 meters.

Explanation:

The power of ten are we able to view the entire Earth in space is 10^8. This is further explained below.

What power of ten are we able to view the entire Earth in space?

Generally, A telescope is simply defined as a device that magnifies views of faraway things

In conclusion, The power of the telescope will be at 10^8.

Read more about Earth

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What’s the order can someone help?

Answers

Foam, Paper, Tin

(That’s from lowest to highest don’t get confused) :)


Which of these is NOT evidence that a chemical change has taken place?

temperature rising when 2 substances are mixed

gas production

color change

melting

Answers

melting, that’s the sign on a physical change

What is the answer? Please

Answers

Cells is the answer can I have brainliest
The answer is living cells

In the electron dot diagram for sulfur monoxide, each atom of sulfur will have how many unshared pairs of electrons an each atom of oxygen will have how many unshared pairs of electrons.​

Answers

Answer:

Both sulphur and oxygen have two unshared pairs of electrons

Explanation:

The compound sulphur monoxide has the formula S=O. It is quite analogous to the diatomic molecules of the group 16 elements.

We must remember that each group element has six electrons in their outermost shell. Two of these are lone pairs leaving only two electrons available for bond formation.

These two electrons are used to form the sigma and pi bonds in S=O, leaving two lone pairs on each of sulphur and oxygen atoms.

how is black oxide converted into red oxide​

Answers

Answer:

The usual way of converting black oxide to red oxide involves treating the black oxide with sulphuric acid and then roasting the intermediate product thus formed. lt is known that the amount of acid can be considerably less than the stoichiometric amount needed to convert all the black oxide to a sulphate.

Hope it helps :9

Determine the molecular geometry for ClF3ClF3.

a. seesaw
b. trigonal bipyramidal
c. square pyramidal
d. octahedral

Answers

Answer:

The correct option is b

Explanation:

Firstly, the compound is ClF₃ and not ClF₃ClF₃. The name of the compound ClF₃ is chlorine trifluoride. It's electron geometry is trigonal bipyramidal (with the chlorine at the center and the atoms of the fluorine forming a triangular bipyramid around it) with a bond angle of 175° with an hybridization of sp³d.

You have two pure substance that you cannot identify. Each sample is solid at room temperature. Describe at least five steps in the appropriate sequence that you would take to be able to identify the substance. ​

Answers

Answer:

pue like ad

Explanation:

For the two pure substance that you cannot identified , The steps taken in the right sequence are:

When two pure substance are places before you. you have to visually anaylse the sample, note the various colors that they have. It can tell you if it's an anions or cations.

You can use reactants to precipitate the cations of the sample you have

We then add a reactant to the sample and you did not see any precipitate, it corresponds to any of the elements or compound. If you do not see a precipitate, you can add other reactant.

You then observe the color of this precipitate. example if the color changes to green, it will tell you that the substance is Ni(OH)₂ etc.

One can also find out through the melting and boiling point of the two substances.

Pure substance are regarded as substance that does not have impurities. one common way of finding out the purity of a substance is by its melting and boiling point determination.

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Which trophic level has the most calorie count

Answers

Answer:

producer

Explanation:

The trophic level with the most calorie count is the producer.

A trophic level is a hierarchical level of the food chain with each level consisting of organisms that share the same feeding role in the ecosystem. A typical trophic level consists of the producers which occupy the base level, the primary, secondary, tertiary consumers respectively, and the decomposers.

The highest amount of energy exists at the base of the trophic level and decreases as we move up the trophic level, forming a kind of pyramid at the end. The producers have the highest amount of energy by directly converting energy from the sun to chemical energy. The consumers at subsequent levels are only able to utilize only about 10% of the chemical energy in their own foods.

Draw the product or products that are obtained from the reaction of HCl with 1-butene and with 2-butene. Show the relative stereochemistry if the product has two or more stereocenters.

Answers

Delete me please!!!!!!

is pasta and water magnetism, state of matter, or solubility?
please helpp!!​

Answers

Answer:

solubility

Explanation:

Where do karst regions occur?

Answers

Answer:

Image result for Where do karst regions occur?

Karsts are found in widely scattered sections of the world, including the Causses of France; the Kwangsi area of China; the Yucatán Peninsula; and the Middle West, Kentucky, and Florida in the United States.

Explanation:

Answer:

Middle West Kentucky.

Explanation:

Karst are found in widely scatter sections of the world.

what is the number of each element and the total number of atoms for vinegar?

Answers

There 3 elements wich is
C =4
H=8
O=4
So the total atoms are 16

The volume of a gas with an initial pressure of 380 mmHg increases from 5.0 L to 8.0 L. What is the final pressure of the gas, in atm, assuming no change in moles or temperature?

a. 238 atm
b. 2.4 atm
c. 0.31 atm
d. 0.80 atm
e. 8.0 atm

Answers

It’s C. 0.31 atm

I hope this helped out! Have a nice day :)

determine moles of 1.5g of sodium carbonate.

Answers

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = [tex]\frac{1.5}{106}[/tex]   = 0.014mol

What would the molecular formula be if potassium and chlorine reacted to form a neutral compound?

Answers

compound is formed when potassium reacts with chlorine, which forms ions with a negative charge. The formula of this compound would therefore be KCl.

The molecular formula if potassium and chlorine reacted to form a neutral compound will be KCI.

What happens to potassium if it reacts to chlorine?Potassium metal,  K, will burn in the presence of chlorine gas,[tex]Cl_{2}[/tex], to form potassium chloride, KCl, an ionic compound.The chemical equation of this is [tex]2K_{aq}[/tex] + [tex]Cl_{2}[/tex]g→[tex]2KCL_{s}[/tex]We can also picture this reaction as being a redox reaction.When potassium metal is oxidized by chlorine gas to potassium cations, chlorine gas will be reduced to chlorine anions.The potassium cations and the chlorine anions will be combined to produce potassium chloride.  

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why is there not a corresponding drop in ionization energies between Bi and Po in the sixth period as N and O?

and why is there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B?

Answers

Answer:

See explanation

Explanation:

According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be  anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower  the ground state of Bi+ ..."

However, the involvement of  d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.

The same argument could be extended to explain the reason why  there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.

How many seconds are in 100 years(factor label conversion)

Answers

Answer:

0.0166

Explanation:

This conversion of 100 seconds to minutes has been calculated by multiplying 100 seconds by 0.0166 and the result is 1.6666 minutes.

I hope this helps,

even a little bit

0. 0166 is how many seconds are in the year

A runner wants to run 10.4 km k m . She knows that her running pace is 8.0 mi/h m i / h .

Answers

Answer:

Approximately 49 minutes.

Explanation:

1 mile = 1.6 km

So 8.0 x 1.6 km

Minutes required: [tex]\frac{10.4 times 60 }{8.0 times 1.6}[/tex]= 48.75 minutes

I hope this helped :)

What do chemical compounds want to obey?

Answers

Answer:

Their atoms obey the octet rule

Explanation:

Chemical compounds are formed when atoms combine with one another in order to comply with the octet rule. The octet configuration gives an atom stability in electronic structure.

When atoms become isoelectronic with noble gases, it confers a special stability on them. Therefore, to attain this state, they gain or lose electron or share their electrons with other species.

Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round it to significant digits.

Answers

Answer:

[tex]atoms \ H= 9.767x10^{24}atoms[/tex]

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

[tex]atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms[/tex]

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

the eye is a substance of which major body system

Answers

Answer:

the visual system would be the answer

A carbocation is an example of a(an) ____. Does a carbocation accept a pair of electrons, or does it donate a pair of electrons?
A. Electrophile. The carbocation accepts a pair of electrons.
B. Nucleophile. The carbocation accepts a pair of electrons.
C. Electrophile. The carbocation donates a pair of electrons.
D. Nucleophile. The carbocation donates a pair of electrons.

Answers

Answer:

Option A. The carbocation accepts a pair of electrons.

Explanation:

A carbocation is defined as a positively charged carbon, which is bound to 3 substituents. Since it has no electrons  nonbonding, it only has six electrons in its valence shell. With only six electrons in its valence shell, a carbocation is a powerful electrophile (and Lewis acid) and can react with any nucleophile that is found.

Carbocations are proposed as intermediates in many  organic reactions. They also work like free radicals, which are electron-deficient species.

Same as free radicals, the carbocations are stabilized by alkyl substituents.

A reaction has a theoretical yield of 124.3 g SF6, but only 113.7 g SF6 are obtained in the lab, what is the percent yield of SF6 for this reaction?

Answers

Answer:

Percent yield = 91%

Explanation:

Given data:

Theoretical yield of SF₆ = 124.3 G

Actual yield of SF₆ = 113.7 g

Percent yield of SF₆ = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield)× 100

By putting values,

Percent yield = (113.7 g/ 124.3 g) × 100

Percent yield = 0.91 × 100

Percent yield = 91%

Calculate the number of S atoms in 0.670 mole of S.

Answers

Answer:

4.03 × 10²³ atoms

Explanation:

The number of S atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.67 × 6.02 × 10²³

We have the final answer as

4.03 × 10²³ atoms

Hope this helps you

element is responsible for the color of light produced.
13
In a flame test, the
a Non-metal
b. Metal
c. Halogen
d. Noble Gas
1. Use the table to

Answers

Answer: d

Explanation:because it makes sence i think

The complete combustion of C4H10, will require how many moles of oxygen, O2? ________.​

Answers

Answer:

2

Explanation:

C⁴H¹⁰ + 2O² —> 4CH²O + H²

A tank contains 7.0 moles of a mixture of nitrogen gas and oxygen gas. The total
pressure exerted by the gas mixture is 530 kPa. The partial pressure exerted by the
oxygen is 140 kPa. How many moles of NITROGEN gas are present in the tank?

Answers

Answer:

5.2 mol

Explanation:

Step 1: Given data

Total number of moles (n): 7.0 molTotal pressure (P): 530 kPaPartial pressure of oxygen (pO₂): 140 kPa

Step 2: Calculate the mole fraction of oxygen

We will use the following expression.

pO₂ = P × X(O₂)

X(O₂) = pO₂ / P

X(O₂) = 140 kPa / 530 kPa

X(O₂) = 0.264

Step 3: Calculate the moles of oxygen

We will use the definition of mole fraction of oxygen.

X(O₂) = n(O₂) / n

n(O₂) = X(O₂) × n

n(O₂) = 0.264 × 7.0 mol

n(O₂) = 1.8 mol

Step 4: Calculate the moles of nitrogen

The total number of moles is equal to the sum of moles of the individual gases.

n(O₂) + n(N₂) = n

n(N₂) = n - n(O₂)

n(N₂) = 7.0 mol - 1.8 mol

n(N₂) = 5.2 mol

Balance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)

Answers

Explanation:

C3H8+5O2----->3CO2+4H2O

Answer:

C3H8+5O2----->3CO2+4H2O

Explanation:

Calculate the change in entropy when 10.0 g of CO2 isothermally expands from a volume of 6.15 L to 11.5 L. Assume that the gas behaves ideally.

Answers

Answer:

The change in entropy of the carbon dioxide is [tex]1.183\times 10^{-3}[/tex] kilojoules per Kelvin.

Explanation:

By assuming that carbon dioxide behaves ideally, the change in entropy ([tex]\Delta S[/tex]), measured in kilojoules per Kelvin, is defined by the following expression:

[tex]\Delta S = m\cdot \bar c_{v}\cdot \ln \frac{T_{f}}{T_{o}}+m\cdot \frac{R_{u}}{M}\cdot \ln \frac{V_{f}}{V_{o}}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the gas, measured in kilograms.

[tex]\bar c_{v}[/tex] - Isochoric specific heat of the gas, measured in kilojoules per kilogram-Kelvin.

[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperatures of the gas, measured in Kelvin.

[tex]V_{o}[/tex], [tex]V_{f}[/tex] - Initial and final volumes of the gas, measured in liters.

[tex]R_{u}[/tex] - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.

[tex]M[/tex] - Molar mass, measured in kilograms per kilomole.

If we know that [tex]T_{o} = T_{f}[/tex], [tex]m = 0.010\,kg[/tex], [tex]R_{u} = 8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K}[/tex], [tex]M = 44.010\,\frac{kg}{kmol}[/tex], [tex]V_{o} = 6.15\,L[/tex] and [tex]V_{f} = 11.5\,L[/tex], then the change in entropy of the carbon dioxide is:

[tex]\Delta S = \left[\frac{ (0.010\,kg)\cdot \left(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)}{44.010\,\frac{kg}{kmol} } \right]\cdot \ln \left(\frac{11.5\,L}{6.15\,L}\right)[/tex]

[tex]\Delta S = 1.183\times 10^{-3}\,\frac{kJ}{K}[/tex]

The change in entropy of the carbon dioxide is [tex]1.183\times 10^{-3}[/tex] kilojoules per Kelvin.

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