__________________________1. She is caught in a wind that blows toward the
equator from about 30° N and 30° S of the
equator. She is in the_______________
This is science

Answer:

Explanation:

Answer : D that’s the answer

Area of  circular ripple is increasing after 2sec is 6400π cm²/s,

after 3 sec is 9600π cm²/s and after 6 sec is 19200π cm²/s

An individual who throws a pebble into a body of water will likely see a splash and hear the booming plop of the pebble. He might observe a center point where the stone struck the water, with concentric circles spreading outward from it. Other outcomes of the tossed pebble could include frightening a nearby duck that jumps out of the water, hitting another rock and rebounding, or frightening a school of fish as it sinks into the pond. The individual who throws the rock is linked to the pebble, the water, and the duck and fish through his deeds. Through a single, straightforward action, he has sparked change. The ripple effect is the term used to describe this idea in education.

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The correct answer is -4.937284m/s^2 constant deceleration is required to stop the car in time to avoid colliding with the vehicles ahead.

u= 80km/h= 22.22m/s

s= 50m

a=? , v=0

According to newton's third equation:

2as= v^2-u^2

a= v^2-u^2/2s

a= 0-(22.22)^2/2*50

a= -493.7284/100

a= -4.937284m/s^2 (solution)

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Answer:

6.23kg

Explanation:

61.1/9.8 = 6.23kg

9.8 is the amount of gravity acting on the object so divide the weight by the gravity to get mass.

Sound waves have entered Natalie’s ear and traveled through to her auditory nerve. The process of perception took place in which she identifies what the sound is.

Perception is the ability to see, hear and become aware of something through the senses.

Sound waves from the environment enter the outer ear and are directed to the ear drum

The eardrum vibrates when sound waves are received, and the vibrations are sent to the oval window through the ossicles of the ear, .

From the oval window, these vibrations are transmitted to the fluid of the cochlea, where waves are generated in the lymph.

These waves generate vibrations in the basilar membrane that bends the hair cells and push them against the tectorial membrane, and hence are sent to the brain which gives signal to the organ to react.

Hence perception is used by Natalie to react.

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Kinetic energy is a type of energy that is present in a particle or object in motion. When work, which entails the transfer of energy, is done on an object by applying a net force, that object acquires kinetic energy.

The energy of motion is known as kinetic energy, and it can be observed in the motion of a particle, an object, or a collection of particles. A person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field are all examples of moving objects that consume kinetic energy.

There are five different types of kinetic energy:  radiant, thermal, acoustic, electrical, and mechanical.

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Answer: 1280 J

Explanation: Work is calculated by multiplying the displacement (8m) by the force (160 N) which will give you 1280 J (joule)

  D = 15 cm , b)  λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e)    v = 80.43 cm / s , v = -80.43 cm / s, f)   D₂= 7.5 cm

Standing waves form when two waves of the same frequency traveling in opposite directions,

A) in the waves the distance of the nodes and antinode is the same since the wavelength is constant

         D = 15 cm

B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is the lamina of the wavelength.

       D = λ / 2

        λ=  15 2

        λ = 30.0 cm

C) the amplitude of each wave is 0.0850 cm, and the amplitude of the standing wave is double A = 0.17 cm

D) Let's use the speed ratio

       v =  λ f

       f = 1 / T

       v =  λ / T

      v = 30.0 /0.0750

      v = 400 cm / s

E) the transverse speeds are the speed of the oscillatory movement

      y = A cos (wt)

     w = 2π f = 2π / T

     w = 2π / 0.0750

     w = 83.78 rad / s

     y = 0.850 cos (83.78 t)

Speed ​​is

     v = dy / dt

     v = -A w cost wt

     v = - 0.850 83.78 cos (83.78 t)

     v = -80.43 cos (83.78 t)

The maximum speed when the cosine values ±1

      v = 80.43 cm / s

      v = -80.43 cm / s

F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength

     D₂ = ¼  λ

     D₂ = 30.0/4

     D₂= 7.5 cm

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Answer:

2 x 10^(-5)

Explanation:

The linear expansivity α can be calculated using the following equation:

Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:

Then, solving for α, we get:

Therefore, the linear expansivity of the metal is 2 x 10^(-5)

7.15 x 10^17 photons strike the leaf every second if solar radiation is 1190 w/m2 strike .

Solar radiation intensity = 1200 W/m2

= 1200 J/m2 s-1 (1 W = 1 J/s)

Area of leaf = 2.35 cm2

= 2.35 x 10-4 m2 (1 cm2 = 10-4 m2)

Total energy striking leaf per second = intensity x area x time

= 1200 J/m2 s-1 x 2.35 x 10-4 m2 x 1 s

= 0.282 J

Wavelength λ = 504 nm = 504 x 10-9 m (1 nm = 10-9 m)

Energy of 1 photon E = hc/λ

= 6.626 x 10-34 x 2.998 x 108/504 x 10-9

= 3.9414 x 10-19 J

where h is Planck constant and c is speed of light

Number of photons striking leaf per second = total energy/energy of 1 photon

= 0.282/3.9414 x 10-19

= 7.15 x 10^17 photons

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If the mass of earth is 5.98 x 10 ^24 Then magnitude of the earths acceleration towards the apple 6.56 * 10^(-25) m/s²

A key concept in science is the concept of magnitude in physics. The general quantity or distance is referred to as magnitude. When it comes to the elements of movement, we can tie magnitude to an object's size and motion speed.

A particular object's magnitude is determined by its size or quantity. For instance, when it comes to speed, if a car is moving at a quicker rate than a nearby motorcycle, the magnitude of the automobile's speed is greater than the speed of the motorcycle. Although they contain directions as well as magnitude, vector quantities. Vector quantities include things like force, acceleration, speed, velocity, and many others. A vector's absolute value is referred to as its magnitude.

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After 11 seconds the tangential acceleration becomes equal to the centripetal acceleration.

What is tangential acceleration?

Similar to linear acceleration, tangential acceleration is directed only in that direction. This has to do with rotational motion. As a result, tangential acceleration is the rate at which a particle's tangential velocity changes in a circular orbit. It always points in the direction of the body's tangent.

ac, also known as centripetal acceleration.

at is acceleration along a tangent.

The frictional force between the car wheel and the road surface supplies the necessary centripetal force when the vehicle moves in a circular motion over a curved path.

at=1.2m/sec2

The centripetal acceleration equation is given by,

ac=V2r

V2r=at

V2=at×r

V=√at×r  ... (1)

Think of the equation for motion.

V=u+at×t

V=0+at×t

V=at×t

t=Vat

t=√at×ra2t

t=√rat

t=√1451.2

t=11seconds

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The resultant forces in each case is;

a) 22.3 Km

b) 158 Km

c) 15.7 Km

Let us note that the resultant force is the force that would have the same effect in magnitude and direction as the the two force that are acting together.

In this case we have been asked to find the resultant of the forces and we would use the triangle method.

a) R = √(10)^2 + (20)^2

R = 22.3 Km

b) R = √(150^2) + (50)^2

R = 158 Km

c) R = √(7)^2 + (14)^2

= 15.7 Km

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A.) Runway has to be 181.5 long.

B.) Plane takes 11 second for the plane to take off.

Change in velocity (Δv) divided by the change in time (Δt), is called acceleration that can be represented by the equation

a = Δv/Δt.

This lets you measure how fast a  velocity changes in (m/s^2). Acceleration a vector quantity, that is it has both magnitude and direction

Meter per second squared is the SI unit of acceleration.

Given, a small plane must reach a speed of 33m/s for takeoff, starting from rest and constant acceleration is 3.0m/s^2

Let the  time be 't'

hence,

(33-0 )/t = 3

33 = 3t

t = 11 sec

Time taken by the plane to take off is 11sec.

Average velocity = (33 + 0)/t

= 16.5 m/sec

Distance = speed * time

= 16.5 * 11

= 181.5 m

Runway has to be at least 181.15 meters long.

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The change in the speed of the automobile occurred at points A to B.

The change in the speed of an object is the rate at which the distance traveled by the object changes with time.

The change in speed of the object from point O to A is calculated as follows;

ΔV = Δx/Δt

where;

ΔV = (5 - 0) / (15 - 0)

ΔV = 0.333 km/min

The change in speed of the object from point A to B is calculated as follows;

ΔV = (15 - 5) / (30 - 15)

ΔV = 0.67 km/min

From this we can conclude that speed of the automobile changed at points O to A, A to B and B to P.

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Answer: The velocity of the bird is 7m/s

Explanation: Since momentum is the total quantity of the motion which is contained in the body.

It is defined as the multiply of mass and velocity of the body

It is given in the question that mass of bird is 2.5 kg and momentum is 17.5 kg/s.

Answer:

See below

Explanation:

East is   70 cos 133 = -47.7 m/s   East

North is  70 sin 133 = 51.2 m/s   North

$10,350 is the amount of money that has been collected mangoes are sold by Anya and Lauren at $15.

Number of mangoes of Anya's = 115 mangoes

Number of mangoes of Lauren's = 5 × 115 = 575 mangoes

Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has

= 115 + 575

= 690 mangoes

Amount each mango sold = $15

The total amount of money collected = Total number of mangoes × Amount each mango were sold

= 690 × 15

= $10,350

So, therefore, Anya and Lauren sold their total mangoes for $10,350.

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velocity of the first car will decrese after the collision.

Momentum is conserved so when the mass of the moving system is increased by the addition of the second car the velocity will be less than that of the first car before the collision.

Most often, the collision between the objects is described in terms of conservation of momentum. In the event of an isolated system interacting with the objects, the momentum is preserved. The starting and ultimate momentum of an isolated system will be the same since there is no external force operating on the system.

When a collision happens between the two objects in the isolated system, the total momentum before the collision and the total momentum after the collision are identical. Elastic and inelastic collisions are the two forms of collision.

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The relationship between Linear Expansivity and Cubic Expansivity is as follows: Cubic / Volume expansivity = 3 Linear expansivity

Now, consider a sheet of metal of Length (l), Breadth (b), and Height (h). Let the initial Length be (l₁), the initial Breadth be (b₁) and the initial Height be (h₁). Let the final Length be (l₂), the final Breadth be (b₂) and the final Height be (h₂) after the metal is heated through a temperature change of θ.

Considering,

the initial volume of the metal be V₁ = l₁*b₁*h₁

and, the final volume of the metal be V₂ = l₂*b₂*h₂

Then,

Using the formula of linear expansivity,

l₂ = l₁ (∝∆θ + 1 )

b₂ = b₁ (∝∆θ + 1 )

h₂ = h₁ (∝∆θ + 1 )

Remember that Volume = l * b*h

Therefore,

V₁ = l₁*b₁*h₁

V₂ = l₂*b₂ *h₂

V₂ =l₁ (∝∆θ + 1 ) * b₁ (∝∆θ + 1 ) * h₁ (∝∆θ + 1 )

V₂ = l₁* b₁*h₁ (∝∆θ + 1 ) * (∝∆θ + 1 ) * (∝∆θ + 1 )

V₂ = l₁* b₁*h₁ ((∝∆θ * (∝∆θ + 1 ) + 1 * (∝∆θ + 1 ) ) * (∝∆θ + 1 )

Let's open the brackets, now we get,

V₂ = l₁* b₁*h₁(∝²(∆θ)² + ∝∆θ + ∝∆θ + 1 ) * (∝∆θ + 1 )

V₂ = l₁* b₁*h₁(∝²(∆θ)² + 2∝∆θ +1 ) * (∝∆θ + 1 )

V₂ = l₁* b₁*h₁(∝²(∆θ)² * (∝∆θ + 1 ) + 2∝∆θ * (∝∆θ + 1 ) +1* (∝∆θ + 1 ) )

V₂ = l₁* b₁*h₁(∝³(∆θ)³ +∝²(∆θ)² + 2∝²(∆θ)² + 2∝∆θ +∝∆θ + 1 )

V₂ = l₁* b₁*h₁(∝³(∆θ)³ +∝²(∆θ)² + 2∝²(∆θ)² + 3∝∆θ + 1 )

V₂ = V₁(∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 )

Remember that ,

V₂ = V₁ ( ϒ * ∆θ + 1 )

Let us substitute for V₂ in the above formula. Then we will get,

V₁ ( ϒ * ∆θ + 1 ) = V₁(∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 )

ϒ * ∆θ + 1 = ∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 (V₁ canceled V₁ and the brackets are removed)

ϒ * ∆θ = ∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ ( 1 cancelled 1 )

At this point,∝ tends to be zero because its value starts from 0.0000... Upward. Therefore,∝² and ∝³ are approximately zero. i.e. ∝² and ∝³ are = 0.

Therefore, we put zero in place of ∝² and ∝³. Now we get,

ϒ * ∆θ = 0*(∆θ)³ + 2*0*(∆θ)² + 3∝∆θ

ϒ * ∆θ = 0 + 0 + 3∝∆θ

ϒ * ∆θ = 3∝∆θ

ϒ = 3∝ ( ∆θ cancelled. ∆θ )

Therefore,

Cubic / Volume expansivity = 3 Linear expansivity

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According to the given statement:

a)It take time to reach the ground is 3.69 s.

b)The helicopter when the package lands far above the ground is 144.18 m.

Constant speed refers to a speed that remains constant throughout the duration of the motion. Constant speed is demonstrated in our example of using cruise control while driving a car.

Using this formula:

t= √(h/g)  

h= 125m

g= 9.2 m/s

t = √(125/9.2)

t = √13.59

t= 3.69 s

The package must touch the ground in 3.69 seconds.

From equation of motion  s = u t + 1/2 a t².

Here a= 0, then s= ut

s= 5.2x 3.69 = 19.18 m.

Total height = 19.18 + 125 = 144.18 m.

Helicopter is 144.18m far above from the ground when the package lands.

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The coordination of the rocket relative to its firing point is 688.32m and 277.44m.

What is coordination?

The purpose of organizing people or groups so they work together properly.

Sol-

The X and Y coordinates of the rocket relative of firing

As per the given question

Velocity (vi)=100ms-1

Angle=55.0

Time (t)=12

The horizontal range of projectile at X is

X=vxi×t

x=vi×cos×t

Now substituting the required value we get

X=300×cos 55×12

X=100×0.5756×12

X=688.32 m

Now substituting the recauird value

We get

Y= 983.04-705.6

Y=277.44m

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1.29×10^-4 m/s is the drift speed of the electrons in the wire.

volume=molar mass/density= 26.98g/2.7g/cm3 = 9.99 cm3

n=(6.02E23 electron/volume)*(1.00E6 cm3/ 1 m3) = 6.024E28 m3

V= I/neA= 7.50 A/(6.024E28 m3)×(1.60E-19 C)×(5.60E-6 m2))

V= 1.29×10^-4 m/s

Electrons and other subatomic particles constantly migrate in arbitrary ways. When exposed to an electric field, electrons do travel randomly, but they do so slowly in the direction of the applied electric field. The drift velocity refers to the overall speed of these electrons.

M/s is the SI unit for drift velocity. It can also be expressed in m2/ (V.s). The relationship between the electrons' current density and their drift velocity is straightforward. Additionally, when the strength of the electric field grows, the drift velocity and current flowing through the conductor do as well.

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Answer:

59, 720 Joules

Explanation:

[tex]q = mc(t2 - t1) + m(lf) + mc(t2 - t1)[/tex]

first term=ice to 0 degrees

second term=water to ice

third term-water to 30 degrees

[tex]q = 0.12 \times 2100 \times 20 + 0.12 \times 3.36 \times {10}^{5} + 0.12 \times 4200 \times 30[/tex]

[tex]q = 59720 \: joules[/tex]

The value of the Acceleration at the given speed of 262 m/s will be 0.245 m / s²

Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has acceleration.

Given that:

Mass of car = 2 Tonnes = 2000 kg.

Wheel's power transfer = Efficiency * b.P.

Power = 0.9 * 57000

Therefore, Power = 51300 W

Wheel's angular velocity = (2[tex]\pi[/tex]N  / 60) * (1 / rear-axle ratio)

Angular Velocity = (2[tex]\pi[/tex] * 4000) / 60 * (1 / 4.4)

Therefore, Angular Velocity = 95.15 rad / sec

Wheel:

Power = Torque * Angular Velocity

P = F * Tyre Radius * W

⇒ 51300 = F * 0.33 * 95.15

F = 51300 / (0.33 * 95.15)

F = 51300 / 31.4

Therefore, Force = 1633.76 (by the engine)

Resistance:

Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N

F₁ = 360N

Gradient Resistance:  

tanθ = 1 / 25

θ = 2.2906°

Fg = mg * sinθ

Fg = 2000 * 9.84 * sin (2.2906)

Fg = 783.37 N

Acceleration (a):

Net force = Mass * Acceleration

F - (Fr + Fg) = 2000 * a

1633.76 - (360 + 783.37) = 2000 * a

a = 490.39 / 2000

Therefore, Acceleration = 0.245 m / s²

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Answer:

Explanation:

Given:

M = 9*M₃

R = 3*R₃

g₃ =9.8 m/s²

_______

g - ?

g₃ = G*M₃ / R₃²

g = G*M / R² = G*9·M₃ / (3*R₃)² =  G*9·M₃ / (9*R₃²)  = G*M₃ / R₃² = g₃

Accelerations are the same

The acceleration the block if the incline is frictionless is 3.28m/s² and the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.11 is 2.26 m/s².

what is newtons law of motion?

Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.

given:

mass of the block (m) = 5.3kg

angle of incline (x)= 21°

force exerted on the block up the incline (F) = 36 newtons

coefficient of kinetic friction = 0.11 u

a)

the sine component of the weight will act as the resistive force and will act against the 36 newtons force that is acting parallel to the incline.

i.e.

net force = 36 - (m × g × sin 21°)

m × net acceleration = 36 - 18.6

net acceleration = 17.4/5.3

net acceleration = 3.28 m/s²

b)

now in this case similarly the friction will also act against the intention of motion, such that:

net force = 36 - (m × g × sin 21°) - coefficient of kinetic friction ×m × g × cos 21°

net force = 36 - 18.6 - 5.33

net force = 12

net acceleration = 12/5.3

net acceleration = 2.26 m/s²

therefore, the acceleration the block if the incline is frictionless is 3.28m/s² and the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.11 is 2.26 m/s².

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A 14.0-kg bucket is vertically dropped by a rope with 163 n of tension at any given time. The acceleration of the bucket is upward-directed and has a value of 2.06 ms^-2.

Let's imagine that two bodies are attached by a rope, causing the system to move with an acceleration an in opposition to the force of gravity acting on one of the bodies. By dividing a body's mass (m) by the net force (F n e t) exerted on it, one can calculate the acceleration (a) of the body.

Please direct the bucket's acceleration in an upward direction.

The tension T supplied to the bucket is resisted by the weight mg acting downward, which causes the bucket to rise with an acceleration.

Applying the force balance we have as a result,

ma = T-mg

14a = 163-14 x 9.8

   a = 1.84 m/s²

We can see that the acceleration is 1.84 m/s² times larger than the speed and since a has a positive sign, we can infer that the direction is upward.

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Answer: pingus

Explanation: pingus

A spring with  a damping constant 5 (kg/s) can be held stretched 1 meters beyond its natural length by a force of 2 newtons. The mass m = 3.12 kg that would produce critical damping

From hooke's law, force required to stretch the spring is

                            k (1) = 2

          Spring Constant, k = 2

For critical damping, c²-4mk =0

                              m = c² / 4 k

                c= damping constant (from question)

                m = Mass to produce critical damping

There fore, m = (5²/4*2) =   3.12  kg  

According to Hooke's law, the restoring force is equal to -kx, where k is a positive number known as the spring constant. Since c is a positive constant that is also known as the damping constant, we assume that the damping force is -c(dx/dt). Robert Hooke, an English scientist, developed the law of elasticity in 1660. According to Hooke's law, for relatively minor deformations of an item, the displacement or amount of the deformation is directly proportional to the deforming force or load.

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