Answer:
False
Step-by-step explanation:
It is False. 1 is the identity element for multiplication, because if you multiply any number by 1, the number doesn’t change. Identity elements are specific to each operation (addition, multiplication, etc.). So while 1 is the identity element for multiplication, it is NOT the identity element for addition.
2. Draw 3 different polygons that have only 2 lines of symmetry
Answer:
Hello. The answer is : rectangle, rhombus
I cant think of a third one as yet.
please help and show work
[tex]x=0=>0^{5} +32 = ( 0 +2 ) ^ 5[/tex]
P/s: [tex]0^5+32=32 , (0+2)^5=2^5 =32[/tex]
[tex]x=-2=> (-2)^5 + 32 = ( -2 +2 )^5[/tex]
P/s: [tex](-2)^5 +32 = -32+32=0, (-2+2)^5=0^5=0[/tex]
ok done. Thank to me :>
helppp,no links or spam
Answer: 6.45 x 10^10
Step-by-step explanation:
Because 10^5 and 10^4 both have 10, we can add the exponents to get 10^9.
Multiplying 7.5 and 8.6 gets you
7.5 * 8.6 = 64.5
We can move the decimal up a place to get 6.45 and add another power to 10^9 to get 10^10
Your final answer should be 6.45 x 10^10
Answer:
C 6.45x 10 to the power of 10
Step-by-step explanation:
10 to the power of 5 is 100,000. 7.5x100,000 is 750,000.
10 to the power of 4 is 10,000.
10,000x8.6 is 86k
now we do 750,000x86,000 which is 64,500,000,000
10 to the power of 10 is 10 billion times 6.45 is 64,500,000,000
illustrated Go Math solution to the problem of 4x as many spaniels as retrievers and there are 30 dogs, how many are spaniels
Answer:
24 spaniels
Step-by-step explanation:
4 many spaniels as retriever means that if you put the dogs in the correct order, every 5 animals you will have one retriever and 4 spaniels, then one retriever and four more spaniels. That is, there are groups of 5 dogs with that ratio. If there are 30 dogs, you can make 6 of these groups. It means that you have 24 spaniels and 6 retrievers.
(3x-6)/(x^2+2) what is the answer
When raising a power to a power you________ the exponents.
Answer:
Multiply
Step-by-step explanation:
To raise a power to a power means to raise one exponent to another. Whether the exponents are real, imaginary, monomials or polynomials, to simplify these problems, all we have to do is multiply the exponents together.
- BRAINLIEST answerer
2. Select all of the trips that would take 4 hours. a. Drive 40 miles per hour between Gotham City and Smallville, which are 160 miles apart. Take a plane going 900 kilometers per hour from Town A to Town Z. which are 3,600 kilometers apart. c Walk 3.2 miles per hour to the grocery store, which is 8 miles away.
Answer:
i think the answer is 50 if not im sorry if there is another go for that one.
Step-by-step explanation:
Q8. the distance between two villages is 12875km. Express the distance in standard form.
Answer:
1.2875 × 10^4
Step-by-step explanation:
A plane flies from San Francisco to New York City at 600 miles per hour and returns along the same route at 400 miles per hour. What is the average flying speed for the entire route (in miles per hour)
Answer: 500 i think
Step-by-step explanation:
read sddddddddd
dxfcgvhbjnkml,
Answer:
1/5
Step-by-step explanation:
rise = 2 ft
run = 10 ft
slope = rise/run = 2/10 = 1/5
Answer: 1/5
Answer:
1/5
Step-by-step explanation:
The slope is the rise over the run
Y / x
2/10
1/5
A glass cube of side length 5cm has a mass of 306.25g.
Calculate the density of the glass in glcm3.
You must show you working’s
Answer:
2.45 g/cm3
Step-by-step explanation:
It's a cube, so all the side lengths are the same. It's volume is [tex](5cm)^3[/tex] = [tex]125 cm^3[/tex].
At this point, we apply the definition of density [tex]\rho = \frac mV[/tex] where m is the mass and V the volume.[tex]\rho = \frac{306.25g}{125 cm^3} = 2.45 g/cm^3[/tex]
Pls help I will put brainlist if u help me told nd thank u
Answer:
17+7=24
Step-by-step explanation:
I hope this help you
Answer
10
Step-by-step explanation:
Subtract 7 from both sides of the equation.
n=17−7
Subtract 7 from 17.
n=10
BRAINLIEST?
Rene’s driveway is a rectangle 45 feet long by 20 feet wide. What is the area of the driveway?
Answer:
25 this is a write answer
How do you graph an equation using x and y intercepts.
Answer:
I'm going to use the following as an example.
[tex]2x + 4y = 8[/tex]
To find the y-intercept, set x equal to 0 then solve for y.
[tex]2(0) + 4y = 8[/tex]
two times zero is zero, so we have the following equation.
[tex]4y = 8[/tex]
Solve for y
[tex] \frac{4y}{4} = \frac{8}{4} \\ y = 2[/tex]
Your first point you will graph is (0, 2).
Now solve for the x intercept. To do this, set y = 0.
[tex]2x + 4(0) = 8[/tex]
4(0) = 0, so you can remove it, and solve for x.
[tex]2x = 8[/tex]
[tex] \frac{2x}{2} = \frac{8}{2} \\ x = 4[/tex]
Now the next point you have is (4, 0). plot that point. Connect the two points with a line and you are done.
What’s the algebraic expression for this
tn tv
1. 1
2. 3
3. 6
4. 10
5. 15
Someone plz help me
Answer:
1 3 6 10 15
Step-by-step explanation:
brainliest plz
A rectangular pool 12 meters by 8 meters is surrounded by a walkway of width x meters. At what
value of x will the area of the walkway equal the area of the pool?
Explain. (don’t send file)
ANSWER CORRECT FOR BRAINLIEST
Answer:
3 2 /5 ×3
change 3 2 /5 into an improper fraction
then you will get 17 /5
after that you say 17/5 ×3/1
=(17×3)/ (5x1)
=51/5 (51÷5)
=10.2/ 10 1/5
[tex]3 \frac{2}{5} \times 3 \\ = \frac{17}{5} \times 3 \\ = \frac{51}{5} \\ = 10 \frac{1}{5} [/tex]
Answer:[tex]10 \frac{1}{5} [/tex]
Hope it helps.
Do comment if you have any query.
Write an equation in slope intercept form for the line that has a slope of 1/4 and passes through the point (0, -2)
Step-by-step explanation:
the general slope intercept formula is
y = ax + b
a is the slope of the line.
b is the y-intercept (the point, where the line crosses the y-axis, meaning the y value when x=0).
we get b by using the point coordinates in the equation and solve for b :
-2 = (1/4)×0 + b
b = -2 (as expected)
the full line equation is
y = (1/4)x - 2
What is the value of x
Answer:
12Step-by-step explanation:
We know the hypotenuse and legs of 45° right triangle have ratio:
h ÷ l = √2 ÷ 1Substitute given values and find x:
x ÷ 6√2 = √2x = 6√2 × √2 x = 12Question 8
The original price of a snowblower is $950. A sign states that all snowblowers are 20% off the original price. Find the sale price of the
snowblower.
Answer:
$760
Step-by-step explanation:
950 x 0.8 = 760
a garden snail moves 1/6 foot in 1/3 hours. Find the speed of the snail in feet per hour
3/6 = 1/2 fph = .5fph
I'll mark brainliest for the first correct answer
Area of circle = A = πr2 = π × 42 ≈ 50.26548 yard²
- BRAINLIEST answerer
59 divided by 4=? PLEASE HELP!
Answer:
14.75
Step-by-step explanation:
56/4 = 14, 3/4 = .75
add them together
Answer: 14.75
Step-by-step explanation: yeah its 14.75 but if you want to simplify it, then its 14.8
Mr. Johnston spends 2/3 of every year in Florida how many months does he spend in Florida each year
Answer:
8 months
Step-by-step explanation:
12/3 = 4, 1/3 is 4 so 1/3 + 1/3 = 2/3 or 8
2x+3y=5x-y solutions
[tex]2 \times + 3y = 5x - y[/tex]
Solution:[tex]2 \times + 3y = 5x - y
[/tex] Move the variables to the left
[tex]2 \times + 3y - 5 \times + y = 0[/tex]
Collect like terms
[tex] - 3 \times + 4y = 0[/tex]
Change the signs
Answer:[tex]3 \times - 4y = 0[/tex]
How many times does it intersect on the graph? y=x^2+3x-2, y-x=4
Write the equation of the line with two given points
(-12, 14) and (6,-1)
Unit 4 linear equations homework 9 parallel and perpendicular lines (day1) activity
Directions if segments AB and CD are parallel,perpendicular, or neither
The lines that are parallel continuously have equal distances from each
other and perpendicular lines form 90° angle at their intersection.
The correct responses are;
Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular, ⊥Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel. ║Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neitherSegment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular, ⊥Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular, ⊥Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neitherThe equations are parallel, ║The equations are perpendicular, ⊥The equations are perpendicular, ⊥The equations are neither parallel or perpendicularReasons:
Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular
[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel where; Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex]
[tex]\displaystyle \overline{AB} \ and \ \overline{CD} \ are \ perpendicular\ where; \ Slope \ of \ \overline{AB} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex]
[tex]1. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{13 - 3}{-2 - 0}} = \frac{10}{-2} = -5[/tex]
[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{3 - 0}{10 - (-5)} = \frac{1}{5}[/tex]
[tex]\displaystyle \mathbf{Slope \ of \ \overline{AB}} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular
[tex]2. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{7- 1}{3 - (-6)}} = \frac{6}{9} =\frac{2}{3}[/tex]
[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{-5 - (-1)}{-6 - 0} = \frac{-4}{-6}=\frac{2}{3}[/tex]
Slope of [tex]\mathbf{\overline{AB}}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel
[tex]3. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{ \frac{2- 4}{-6 - (-2)} = \frac{-2}{-4}} =\frac{1}{2}[/tex]
[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{11 - (-7)}{-1 - 5} = \frac{18}{-6}=-3[/tex]
[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular
[tex]4. \ \displaystyle Slope \ of \ \overline{AB} = \frac{8- 3}{-3 - 2} = \frac{5}{-5} =-1[/tex]
[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{6 - 2}{-4 - (-8)} = \frac{4}{4}=1[/tex]
[tex]\displaystyle Slope \ of \ \overline{AB} = \mathbf{-\frac{1}{Slope \ of \ \overline{CD}}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular
[tex]5. \ \displaystyle Slope \ of \ \overline{AB} = \frac{-1 - 2}{-8 - (-4)} = \frac{-3}{-4} =\frac{3}{4}[/tex]
[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-3 - 6}{0 - 12}} = \frac{-9}{-12}=\frac{3}{4}[/tex]
Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel
[tex]6. \ \displaystyle Slope \ of \ \overline{AB} = \frac{5 - (-1)}{6 - 3} = \frac{6}{3} =2[/tex]
[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-5 - 7}{2 - (-4)}} = \frac{-12}{6}=-2[/tex]
[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular
Directions: To determine if the equations are parallel or perpendicular
Solution:
The equations are parallel if when expressed in the form, y = m·x + c, the value of m are equal
The equations are perpendicular, when we have;
[tex]\displaystyle The \ value \ of \ \mathbf{m} \ in \ one \ equation = -\frac{1}{The \ value \ of \ \mathbf{m} \ in \ the \ other\ equation }[/tex]
7. First equation
3·x + 2·y = 6
Therefore; [tex]\displaystyle y = -\frac{3}{2} \cdot x + 3[/tex]
Second equation; [tex]\displaystyle y = \mathbf{-\frac{3}{2} \cdot x + 5}[/tex]
The value of m which is the coefficient of x are both equal to [tex]\displaystyle -\frac{3}{2}[/tex]
Therefore, the equations are parallel
8. Equation 1; 3·y = 4·x + 15
Therefore;
[tex]\displaystyle y = \frac{4}{3} \cdot x + 5[/tex]
Equation 2; 9·x + 12·y = 12
[tex]\displaystyle y = -\frac{9}{12} \cdot x + 1 = 1 - \frac{3}{4} \cdot x[/tex]
The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular
9. Equation 1: 8·x - 2·y = 4
Therefore;
y = 4·x - 2
Equation 2: x + 4·y = -12
Therefore;
[tex]\displaystyle y = -\frac{1}{4} \cdot x - 3[/tex]
The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular.
10. Equation 1: 3·x + 2·y = 10
Therefore;
[tex]\displaystyle y = -\frac{3}{2} \cdot x - 5[/tex]
Equation 2: 2·x + 3·y = -3
[tex]\displaystyle y = -\frac{2}{3} \cdot x -1[/tex]
The slopes of the equation 1 and 2 are not equal, and are not the negative inverse of each other, therefore, the equations are neither parallel nor perpendicular.
Learn more about parallel and perpendicular lines here:
https://brainly.com/question/7197064
How to find unique prime factorization of 10 factorial.
Find all of the rational zeros of the function. f(x)=x 4 −3x 3 −6x 2 +6x+8
Answer:
The "possible" rational zeros are:
±
1
,
±
2
,
±
4
,
±
8
The actual zeros are:
−
1
,
4
,
±
√
2
Explanation:
f
(
x
)
=
x
4
−
3
x
3
−
6
x
2
+
6
x
+
8
By the rational root theorem, any rational zeros of
f
(
x
)
are expressible in the form
p
q
for integers
p
,
q
with
p
a divisor of the constant term
8
and
q
a divisor of the coefficient
1
of the leading term.
That means that the only possible rational zeros are:
±
1
,
±
2
,
±
4
,
±
8
We find:
f
(
−
1
)
=
1
+
3
−
6
−
6
+
8
=
0
So
x
=
−
1
is a zero and
(
x
+
1
)
a factor:
x
4
−
3
x
3
−
6
x
2
+
6
x
+
8
=
(
x
+
1
)
(
x
3
−
4
x
2
−
2
x
+
8
)
Notice that the ratio between the first and second terms of the remaining cubic is the same as that between the third and fourth terms. So this cubic will factor by grouping:
x
3
−
4
x
2
−
2
x
+
8
=
(
x
3
−
4
x
2
)
−
(
2
x
−
8
)
x
3
−
4
x
2
−
2
x
+
8
=
x
2
(
x
−
4
)
−
2
(
x
−
4
)
x
3
−
4
x
2
−
2
x
+
8
=
(
x
2
−
2
)
(
x
−
4
)
Finally we can factor the quadratic as a difference of squares:
x
2
−
2
=
x
2
−
(
√
2
)
2
=
(
x
−
√
2
)
(
x
+
√
2
)
So the zeros are:
−
1
,
4
,
±
√
2